0 like 0 dislike
3k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* **** ** * ** ** ** * ** ***** * * ***
* *** * * ** * *** *** ** **** *

    {
* *** **** * ***** * *** ** * * * *
* * * **** * * ** * * *** * **** * ***
* ** * ** * ***** * *** * * * * ** ** * * *** * ** * *** * *** ** ****
* **** * * * **** * **** * * * *** * *** * ******** ** * * * ****** * ** ** = a[n] + b[n];
* * * * * ** ** * * * * ** * ** ** ** * * *** * ** *** * *** if(a[n]+b[n]>='10')
** ** *** * ** ** * * * *** ******** * ** *** *** ****
*** * * * * ***** * *** * * * ** * * ** ** * * *** * * ** * * ** * *** ** ** *** * = a[n] + b[n] - '10';
* * * ** * ** ** ****** **** **** * * * ** * * * *** *** ** * ** * ******* * * ** * **
**** ** *** *** * * * * * * ** ** * * * * *** **** ** ****
** * * * * * *** * ** *** ** *** **** *
*** * * *** *** *** ** * * **** **** *** ** **** if(t == 1)
* ** * ***** ** * * * ** * * ** * * *** *
** *** **** ** ** ** **** * ** *** * ****** ** ** * **** *** * ** * ** *** * * * * ***
* ** * * * * * * * ** **** * ** * * ** * * * * *** * * * * * * * ** * *** * = a[n] + b[n] + '1';
** ******* *** * ** ***** * * ** * * ** * * * *** * * * ** * *** if(a[n]+b[n]>='9')
** ***** * * * * * * ** ** * *** ***** ** *** * ** *** * * **
* * *** **** * * **** * ********** * *** ** ** ***** *** ** ** * *** **** * * * *** * * * = a[n] + b[n] - '9';
**** * ***** * * ** * ******* ** * * * * **** * * * * * * *** *** * ** ****** * * *
** **** ** * ** * **** ** * * ** * ** *** *********** * * ** * *
* ****** ******** * * * ** *** * * * * **** **

    }
* ** *** **** * * * * ** ** **

    {
*** * ** *** * ** ** ** * * ** *** *** * * * ** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
**** * * ****
* * * * * *** * *

int main ()

{

int ****


* *** ** * **** * *** * * ** *
** * ** ** ** *


** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * *** * *** * * **

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
** * *** * ** * * * * * * a[100],b[100];
* ** * * ** ** * * * * sum[200];
** ** ** * ** * ** * la,lb,lm,i,j,k;
***** ** * ** * ** **** * * * *** %s",a,b);
*** * * * ***** * *** = strlen(a);
** *** *** ** ** * = strlen(b);
** * *** ***** * *** * * * * ****** * ** *
* ** * ***** * * * * * **** ** *** * * * * = a[i];
**** * ** * * ** * ** * ** ** ** * * ** * ** **********
*** ** * ** * * *
*** * **** *** ** * ** *** * *
* ** **** * ** ** * *** * ** * ** * * += b[i]-48;
* ** * * ** * * * * * * ** * * * * * * * **** ** *** * *
* *** * *** * *
* * *** ** * ** ** *** * = strlen(sum);
*** ** **** * ** * ** *
** * * * * * * * * * ** * * * **** * * * *** * ** * *
****** *** * *** *
** *** * ***** ** * * * * * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* * **** ***** ***
** * * ** * * ****





int main ()

{
** a , b ;
** * ** ** * **** , ***
** * * * *** , * **
** * * ** * * ** * ,a+b);
** **** * * *** * ** * ** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
*** * ** ** ***** *** *** ** ** * * *** **
** * *** * ** ** * ** * * ** *****

    {
*** * * * **** * * ** * ** * ** ** ** *
** *** * * **** * * * ** * * * **
* ** * ** * ** ** * **** ***** * *** * *** * * ** * ** **** * * * *** * * ***
** * *** *** * * ** * *** * **** ** * * * * * * ****** * **** ** * * *** * ** * = a[n] + b[n];
* * *** * ** ** ** * * * * * * ** * * ** * **** * ** * ** * if(a[n]+b[n]>=10)
******* ** ** ** **** * * * * * ** ** * ** * * ** * ***** **** *
** * *** ** * * ** **** * ***** *** *** ** **** * ** **** ** * ******* * ** ** ** * ** ** ** * * * = a[n] + b[n] - 10;
* **** ** * * * * ** * * * *** ** *** ** ** ** * *** * * *** * ****
*** * * ** ** * *** * * *** * * * ** * *** * ** * ** **
* ***** * * *** ** * * ****** ** * ** *
** ** ** * * * **** ** * **** * ** * * ***** *** if(t == 1)
** *** ** ** ** ** * ** ** ** * * * * * * *
*** * **** * ** *** ** * * * ** ** ** * *** * * * ** * *** * ******
** ** *** * **** * ** * ** ** ** * ** *** * * * ** ** *** *** * *** * * * *** * *** = a[n] + b[n] + 1;
** ** ** ****** **** * * *** * * * **** * **** **** ** * * ** * * ** * if(a[n]+b[n]>=9)
* * * * ** * *** **** ******* * ** **** ** * * * * * **** *** **
*** ** *** * ****** *** ** ** * ** * * * * * ** *** * *** *** * * * *** ** ** * **** * * = a[n] + b[n] - 9;
** * * * * **** ** * * * * * ** * ** ** * * * * ** ** * ** **** * * * *
*** * *** * ** * * * * * ** ** * * ** * *** ***** ****** * *
** * * ***** ** * *** * ** **** * * *

    }
* **** ** **** * * ** * **

    {
* ** ** * * * ** * *** * ** *** ** *** ** * **** ** *** *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
***** * * * ** *** * data[2];
*** *** ** ***** * ** sum;
* ** * ** ** ** i;
**** ** * * ***** **** * *** **
*** ** ** * ** * *
** ** * * ***** *** ** * * * * ** * ** * **** * ** ***
** ** * * ** ** * *
** * * ***** *** ** ** ** **** **
* ********* * * ** * *** ** * ** * **
* * *** * ** ****

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include *** ** *** **
*** **** ** * **
* * * * * ** ***
***** * * * * * * **







int *** * *

{


* * * int * *** * **
** * * * **

* * * * scanf ** * ** ** * * * * **
* * * * * * *

** ** ******* while (a[i]!= ' ')

{
* **** **

* * ** * * * * i++;
* * *

*** *** scanf * *** *** ** *** * ***** * *** **

* ** ****

}


**** ** scanf *** * * *** ** ****


* * ** *** while * * ** **** * * ****
** *

****** * * {
* * * * ** ***** * ***

** * * ****** ** * ** * ** j++;
*** ** *** ** ** * *

*** ** ** * ** ** * * **** scanf * * ** * * * * *** ***** *

* *** * * * * ** ** *

** ** * ** * }
** * * * **

}
* ***** * **

** *** ** *** for (i = 0,j = 0;;i++)
***** *

** * * *** * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include * ** ***** ** *

int main()

{
* ****** *** * * ** a,b,c;
* ** ** ***** ** * * * * **** * * *
** * ****** ** ** = a + b;
* ** ** *** * ** ** * *** * * ** ** * ** * **** **
** ** * * **** * ** * ** * * *
* * ** ***** **
* * * * * ********* * ** * * **
** ** * *** *** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include *** *** ** *

int *** * ** y=999999999;

int main()

{
* ** *** ** * * * **** **** * * * * *
* **** *** **** *
* * ** * ** ** ** ***** **** ** ****

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** * *** * * *

int main(){
**** ** ** ** * * * * a,b,c=0;
***** ******** * *** * *** * * ***** *** *
** ** *** *** ** *** ** ** * ** ***** *** ** **
* *** * ** * * * *
** * * ** * * * ***** *** ** * * * ***
* *** * **** * * ** * * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.205
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users