0 like 0 dislike
6.6k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 6.6k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** **** *** ** * * * * *** i=0;
* * * * ** *** * ** *
* *** * * ** * ** ** * ** * *
* ** ** ** * ** * **** * * *** ** *** * * * *
* * *** ** * * * * ****** ** * *
* * ** * *** * * * i;

}



int check2(char c)

{
* * * ****** * * ** * * j=0;
* * ** * *** * ******* **** **
* *** ** * * * * ** *** *** * **** *
* ** **** * ** * ***** **** * * **** ** ** * * * ** *
* *** * * * * *** *** * * * * * **** ******
** * ** ** * * ** j;

}

int main()

{
** ** * * * ** ** * c;
******** * **** * i=0,j=0;
*** *** **** * * *** * ** * ** * ** * **

    
**** ** * ** * * ** * c!='.')
* * ** * * *** *


*** ** ** ** *** * * *** *** * ** **
* * * **** * **** * *** * * * *** * * *
* **** * **** ** **** * ** * * * *** * ****** *** *** * * ** **
*** ** * * *** * **
* **** ** * * ** * * * *** * ** * * * * ** ** * *** * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** **** * * * **** *
* *** * ** ****

int main (void)
** *

char c;

int i = 0;

void c)

{
**** *

i++;
*** **

i++;
**** * * ******
* *** ** * * * * * ** * ** * * ** **
***** * **** ** * ** * * 0;

}
* * ;

}
*** * *** * ** * ***** ** **
***** **** * ** *** * * *** **
* *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * * *** * *** ** ** a1=0,a2=0,a3=0,a4=0,in;
** * * ** **** *** ** * *** ** && c[in];in++)

    {
* * *** * ** ** * * * * * ** * * * * ** (48<=c[in] && c[in]<=57)
* * ***** ** * * * * * *** ** * ** * **
* * **** * ** * ** * * * * * * * ** ** * **** **** ** ** * * *** ** ** **
** * ** * * *** * ** * *** ** * * ** *** ** ** * *
* ** * * * * ***** * * ** ***** * * * * if(65<=c[in] && c[in]<=90)
** ** ** ** **** ** ** * * ******* * * **
***** ** * ** * *** * * * * * * ** * ** * * * *** * ** ** **** * *
** ** ** *** ***** * ** ** * ***** **** ** ** * * **
* * ** * * * * * ** ** * * * * if (97<=c[in] && c[in]<=122)
* * ** * ** * **** *** *** ** * ** * *** *
* ** * * ** * * ** ** ** * ***** **** ** *** *** * **
* *** *** ** *** ******** ** * * ** ** *
* ** ** *** * * * ** ****** * * * ** * * * ** * if(39<=c[in] && c[in]<=46)
* **** ** ***** ** * *** ** * * *** * ** *
* * * ** * * ** * ** * ** ** ** * **** **** ** **** * *** * ** *** ** *
*** * * ** ******* * ** * * * * * * ** * * * **
* * * * * * * * ** * * ** *** *** ** * *
* * ** * * * *** * * * ** * ** * * **** * ****
* **** ** * * * *** *** *** **** * * * *** * * ** * ****
** * * ** *** ** * * ******* *** * * * **** * **
** ** ***** * * *** * * * ***
* *** ** * ** * ***** ** ** *** ******* ** * *

 }

 

 int main()

{
* * * * ** *** *** ***** * c[100];
** **** * ** * * ** * *
*** ** * ***** * **** * * *

    
* * * *** * * * **** ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * ** * i=0;
**** * ** ** *** * ***
* *** ***** ** * * ** * * ******
** * **** * * * *** * **** * * *** *** ** * * *
** * ***** * * * ****** ****** *** ***
* ** * *** ** * ****** * ** i;

}



int check2(char c)

{
* ** ** * * ** ** * *** * ** j=0;
********* ****** * * * * *** * *
* * * *** *** * **** **** ** ** * * ****** * ** ***
*** * * ** * *** * *** ** * ** ** ** ***** **
**** ****** ** * ** ** * * ** ***
*** * * ** * ** ** * ** j;

}

int main()

{
* ** * *** ** * ** *** *** c;
** * *** ** ** ** ** i=0,j=0;
***** * ** * ** * ** * *** * ** * ** *

    
* * ** * *** * c!='.')
***** *** **


* * * * * * **** ** * * * * ** *** * **
** * * * *** **** ** * *** * * *** * **** * ** ***
* *** ** ****** * * * *** * ***** * ** * * * ** * * ** *
*** * * * ** * * * * ***
* * * ******** * * *** * * * * ** * * ** * **** * ****



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * * ** ** * * * *** * i=0;
* * * ***** * ** ** ** **
* * ***** * ** * ** * **
* **** * ***** **** *** ** ** ** ** ** * * * * **
* ** * * * ** * ** * * * ** * * *** *** **
*** * * ** ** * * ** * * i;

}



int check2(char c)

{
** ****** **** ** ***** * * * j=0;
** * * ** * ** *** *****
* * * * ** * ** *** ** ** *** ***** **
* * *** ** * * * * **** ** **** * *** * * *
* * *** * * * * * ** ** **** * * *
* *** ** *** * * ** * j;

}

int main()

{
** ***** **** ** ** * * * c;
** ** * * * * ***** i=0,j=0;
**** ** * ** * * * * ** * * * **** **
* * ** * ** ** **** *** * ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* ** * ** *** * **** * ** *
* * * ** *** **** ****** ********* * * * * * ** * * * **
** * * **** * ** *
** * * * ***** ** * c!='.')
* * ***** ** ***


*** * * * ** * * * * * * ** * * ** *
********** * ***** * * ** * * * ** * * **
** * ** * ** ** * * ** * * *** *** * * ** **** **
* * * * * * ** ** *
* * * ** * * ** **** *** * * * * * * * * * ***** ** *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * * ** *
***** * * * ** *

int main * *
**

char c;

int i = 0;

void **** c)

{
******
*
** ** *
**
* ***** *******
** *** * ***** *** ** *** 0;

}
** * ;

}
******* **** * * *** * * ***
** *

}
* * * * ****** **
*** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* ** ** *** ** * ***** * ** * **** c;


* ****** * * ** * ** *** i = 0,b = 0;


** ** *** **** ** *** ** * * * * * &c);
** * ** * * * *** ***** c != '.')
*** **** * *****
** ** * **** ** ** * * ** * *** ***** * * * * ** *






* * ** * *** * * ** ** **** * **** **** += 1;


* * ** ** * * **** ** * *** *** * ** * * **** &c);
* * * * * * *** * *** *** * * *
**** * * ** * * * * * ** * **** ** ****** ** **


** ** * * ** ** *** * * ** **** * * i);


* * *** ** * *** ** ** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* ****** ****
* **** **** * ** *****
** main ***
* **
*** c;

int i = 0;
*** *** * c)

{
** **** *
*
* * ***
***
*** ;

}
** *** ***** * * ***** ***
***

}








** * * * * ****
** ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* * * * * * * **** i=0;
* ** * ** ** *** * ** *** * ***
** * **** *** ** ** * * ** * *** * * *
* * ** *** * ** ****** ** ***** **
* ** * * ** * * *** ** * ** *** ** *
* * * * * * ********** *** i;

}



int check2(char c)

{
** ** ** * ** * *** ** j=0;
* *** ** ** * ** * *** ***
* ** ** * *** *** ** * **** ** ** * *
** ****** **** ***** ** *** * *** * ** ** * *****
*** ** * **** * * ** * * * *** ****
* ** **** * ** * ** * *** *** j;

}

int main(void)

{
*** * **** ** * * c;
* ** * * ** * ** i=0,j=0;
* ** *** * * *** *** * * **** * *
* ** ** * * *** * * c!='.')
**** * ** ** ** *


* ** **** * ** * * * ** *** * * * ** * *** ** *
*** * * * ** *** * ** * ** * ***
* * * * ** * ** * * * **** * * ** * *** ** ** * *

    }
*** ** * *** ** * * *** * ** ** * ***** ** ** *** ***** * ***



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* *** ** * * *
* * * * ****** **

int main **
* * ****
* * c ;

int i = 0;
** *** **** **** * *
** ***


* * ** ** c)

{
* *** *** *
*
** *****

* * ;

}




* * * *** * ** * *
** * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.63
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users