0 like 0 dislike
4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * * ** * ** * ** ** * ****
* * **** * * *** ** * * * * *
**** * *** * * *** ** * ** * * * *
* * *** * ** ******* ** ** * ****** ** * ****
* * ** * * * * * * * * ** * ** ** *** **** *


* ** * * *** * * (a-c!=0)
** *** * ** ** **** *** ** **
*** ** * ** ** ** ** *** * ** * *
* ** ** * * * *** ** *** *
**** * ** ** * * **** * ****** * *
* ** ** *** ** ** * ** * *****
** * ** * * * * * ** ** (a-c==0)
** ** *** * ** * **
* * * *** ***** ** * *** ** * * * * * * ** ** *
* ** * * * * ** * ** **** * * **** * * ** ** ** *
* ** * * **** ** * **** * * * * * ***
* *** ** * * * * * * * **
**** *** ** *** ***** ("%.6f ",e);
* *** * * *** * * ("%.6f ",g);
* ** ** ** ** * * ("%.6f",f);






** * *** * ** * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
** * ***** ** * *




*

{
* ***** * ****** *
* ** * ***** ** %f %f * * *** * *** ** ***** ***
*** * ** * - x2 == 0)
** * * * * **
** *** * * ******* = x1;
** ** ** * ** ** * * ** ** * = 0;
** ** * * * * * = -x1;
* ** * ****** ** *** %f ** ** ** *
* **** **
* ** if(x1 - x2 != 0,y1 != 0)
* ** *
* * ** *** = (y1 - * **** - x2);
***** * **** ** = y1 - (a * x1);
*** * *** ** * = -((a * x1) + c) / y1;
* ** * ***** ** * ** ***** %f * ** ***
* * ****
* * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * ** * *

int main (void)

{
** * * ** * * * * *** x1,y1,x2,y2;


** * *** * * ** * a,b,c;


** ** ** ** ** ** * * *** * %f ** * *** * ** *** ***** * ** ***
** ******* ** ** ** *** * *
* * * * ** * ** ** * * * ****
** **** ** * * * * * * * * **




** ** ** * * * * ** * %6f %6f",a,b,1);
** * * ** * ** *** ** * * * ** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** *** * ** *
* * ** * ** *** *

#include<math.h>



int main()

{
* *** * ** * * *** ***** x1,x2,y1,y2,m,a,c0;
* ** * ** * *** * ** ******** * ****
* *** * **** *** * * * * ** * ** *** ** *
** * * * * * ** ***** * * ** * * * ***
** * * *** * ** **** ** * **** * * ** *** *** *
** * * * * * * ** = (y1-y2)/(x1-x2);
* * * * * * ** ** * ** ** ***
***** *** ** * * ** * * * * * * * *
** *** * ** * * ***** ** * **** * %f * **** ** ** ** **

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** * ** *** *


* * ** * * ** **


** * * * *


* ** ** *** **




* * * ( )

{
* * ** ****
*** * ** %f %f * * ** * ** * * * **** ** * ** **
* = d - *
* = c - *
= f * b - a * e ;
* ** * * * *** *
*** * **
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * ** *** **
* * * * * ** ***

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
** ** * * *** * **** * * i, j, k, l;
* * *** **** ** * * a,b,c;
** * * ** * * ** **** ** * ** %4f %4f ** *** ** * **** ** * ** * *** *
* * * ** ** ** * *** ** *** *
** * **** *** ****** *** * %6f ** ** * * * **


******* * **** * * * ** * * * * *
** **** * * *** 0;

}
** * * ** * * * *** rect(int x,int y,int z,int w,int *p1,int *p2)
** * ** ** ***** *** * * a,b,c;


* * ** ** * * ***** * * *** ** * ** * *** ** *
** *** ***** ** * ******* * * **** ** * *


* **** *****
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * ** * * ****


* *
* * * * * ** *** ** ** ** * * * a, b, c;


* *** * ** ** * ** * ** ** %f %f * * * * ** * ** * * * ** *** ** *


** ** ***** * * *** = y2 - y1 / * y2 - x2 * *
*** * **** *** * **** = x1 - / * * y2 - x2 * *
* * ** **** ** **** *** * = - * * * - * **
** * ** * * * ***** * *** * * * a, * **


**

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * *****
* * * * * ***
* * ** * ** **
** * ***** *** * *** *






* * ** *

{


** * * * * * * ** * **** * * * **


* *** **** * ** ** ** ** * **** * * * *** * * ** * ** *** * * *



* * * ** dx = (x1 - *


* **** * ** dy = (y1 - *
* **** * *

** * * * m = dy /
** * * * *

** *** *** h = y1 - ** *
* *

** * * ** a = b * h;

** *

* **** ** b =



* * * * ** c = b * h;


* * ** * * *** * * * ** * ***** *** * **




* 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
** ** ** * ** ** **



int main(void)

{
* * ** ** * x1,y1,x2,y2;
*** * * * *** a,b,c;
****** ** ** ** *** *** * * *** *** ******* ****** * * **** **
* * ** * ** *
** * **** ** ** ** * * *** * ** ** ** = y2 - y1;
** **** *** * ** ********** * ** * ** ** **** = x1 - x2;
* *** * ** * ** *** * * ** ** ** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * *** ** *** *
* * ** ****** ** * * *** * %f %f",a,b,c);






*** * ** * * * *** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * ** **
**** * * **** * * * **

int main(void)

{
** * *** *** * * *** x1,y1,x2,y2;
* ** ****** ** * a,b,c;
* * *** *** * ** ** ** ** ***** *** * ** * ** ** * * *
** ** ** * **** * *
********** * **** *** ** *** ** *** ** ** ** = y2 - y1;
** * * * * ** *** ** *** * * * **** = x1 - x2;
**** * * ** *** *** ** * * * * ** *** = -x1 * (y2-y1) + y1 * (x2-x1);
******* *** *
** ** * * *** ** * * * * * ***** %f %f",a,b,c);






** ** ****** ** * * * * * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.125
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.4k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users