0 like 0 dislike
5.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.1k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
** **** * * ** *** * **** * * ** *** *** ***
** * * * * *** * ** ***
* ** ** * ** * * * * ** ** *
** * * ****** ** *** * *** * **** * ** * ** ***
* * *** * * *** ** ********** ***** ****** * * * *


* ** ** *** ** ** (a-c!=0)
**** ** * * * * *** * ****** **
* *** * * ** * * * * * **** ** **
*** ** * * * ** * ** * ***** * * *
* * * *** * *** * * *** *** ** *
** * ****** ** * * **
* **** ** * ** ** ** * (a-c==0)
* * ** * * * ** **** *
** **** ** * ***** * ** * * * * ** ** * ** * *
* * **** ** * ****** * ** **** ** * * *** * * *
** * *** ******** ** ** **** ** * ** *** **** * **
* ** ** * ** *** * * *
* * ** ** * *** ("%.6f ",e);
* *** ** **** ("%.6f ",g);
** * *** ***** * * ("%.6f",f);






** * ** ** ***** *** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* **** * * ** ** *




**

{
*** * *****
** *** * * ** %f %f *** * * ** ** * ** * * ***
** ****** * - x2 == 0)
** * * ***
*** * ** ** **** ** ** * = x1;
* * ** *** * ** ** = 0;
* ***** * ** ** **** * * = -x1;
* **** *** ****** ** *** ******* %f * ** * *
****** **
*** * ** * if(x1 - x2 != 0,y1 != 0)
**** ** *
** * * ** = (y1 - ** - x2);
*** * * * * * *** = y1 - (a * x1);
** * *** ****** * = -((a * x1) + c) / y1;
**** ******** *** ***** ***** %f ** **
** * *
* ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** *

int main (void)

{
* * ** * * ** ** ** ******* x1,y1,x2,y2;


*** ****** ** ** ** * ** ** * a,b,c;


* * ***** *** ******** * **** %f * * * * ** * * * *** * * * *
* * **** * ***** * ** * * **
** * **** *** **** * * * **
**** * * ** * * *** ** * * * * ** *




* * * * * * **** * * %6f %6f",a,b,1);
* * *** ** * ** *** * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * * * * *
** * * * ** * *** *

#include<math.h>



int main()

{
* **** ** *** * * * *** x1,x2,y1,y2,m,a,c0;
*** ** * ** * * * *** ** * **** *
* * *** * ** * * ******** *** * ** *
* * *** ** ** *** ******* ** **** ****** ** *
* * ** *** * ** ** * ********* ** * * * *****
*** *** * *** ****** = (y1-y2)/(x1-x2);
** * * *** *** *** ** * * ***
* * ** *** * *** ** ** *** ** ** * * **
** ** ** * * * **** * %f * **** * * * * *** * * ***

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * ** * * * * * ***


* * * * **


* *** * * * * * **


** ***** * * *




* ** ** ( ** )

{
* * **
* * ***** %f %f * * * * * *** ** * * * ** *** **
* = d -
= c -
** = f * b - a * e ;
* *** * * * * ***
** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
***** * * * ****
** ** ** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
** * * ** *** * * ** i, j, k, l;
* ** * * * *** * a,b,c;
** ** ***** * * * *** * %4f %4f **** * * * *** **** * ** **
*** *** **** * ** ** * **** ** *
* * ** ** * ** **** * * %6f ** * * *


* ** * ** ** * ** ** *
******* ** ** * * 0;

}
*** ** * *********** rect(int x,int y,int z,int w,int *p1,int *p2)
** *** * *** *** * * ** ******** a,b,c;


** * * * * ********* ****** ** ** *** *
** ** ** * *** *** * ** ** * * *** *


* ** * *** ** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
*** ** * **


* *
** * * * * * * *** * * * * * * **** a, b, c;


** * ** *** ** **** ** * %f %f * ** * * *** * ** * * ** ** * *


** * * * * * * * = y2 - y1 / * * * y2 - x2 * * *
** ** * * * * * ** * * = x1 - / * * y2 - x2 * *
** * * ** ** ** = - ** * - * * *
** ** ***** * * *** * * *** * * * * ** a, *


** **

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * ** **
** ** ** *****
** *** * * *****
**** ** * ** *






** ** **

{


* ** *** ** *** *** **** * * * ** *


** * ** **** * ** *** * ** * * ***** *** * ***** * ** * *** * *



** ** * * dx = (x1 - *


* * * ******* dy = (y1 - *
**** * * * * *

* ** * * *** m = dy /
*** *** *

*** * * h = y1 - *
*** * * * *

* **** a = b * h;

* *** * *

* ** * ** b =



**** * * c = b * h;


* * * * * * ** * *** ** ** * * * *** ** * * **




* 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
**** * * ** *



int main(void)

{
** ****** * ** x1,y1,x2,y2;
** ** * ** * *** a,b,c;
* * ** *** * ** * * * **** *** ** * ** ** ** * ***** * *
*** * * *
* * * ** *** * *** * ** ** * * *** ** ** * = y2 - y1;
* ** **** * ***** * ********** ** ** * ** = x1 - x2;
** *** * * ** *** ** * ** **** * ** ** ** = -x1 * (y2-y1) + y1 * (x2-x1);
**** ** * * ** *** **
* * ** **** *** %f %f",a,b,c);






* ** ** ** ** * *** ** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * *** ** * *
* * ** * ** *

int main(void)

{
**** * *** * * *** x1,y1,x2,y2;
** ** * * * * a,b,c;
* ** * * ****** *** * ***** ** ** * * ** ****** *** **
* ** ** * * * * *
* * * * * ** * ** * * ** * *** * * * * = y2 - y1;
* * * ** ** * * * * * *** * ** **** **** = x1 - x2;
* * * ** ** * * * ** * ** * * * * *** * * * ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** * ****** * *
** * * * **** * **** ** ** %f %f",a,b,c);






** * *** ** ******* * ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.158.126.44
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users