0 like 0 dislike
6.6k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.6k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
** *** ** ** * * * ** *** * *** **** * * **
** * ** * * * * *** ***** **
* *** *** * * * ******* * * ** **** *
** *** **** * ** ** * * ** **** **** * *
* *** * * * ** ** **** *** * * * * ** *** ** * **


*** *** * * * ** ***** (a-c!=0)
******* ** ****** **** *
** ** * * * *** * * * ** ** ** *
* * ** * ** ** * *** ** *** * ** ***
** * ** ** ** * * * * ** ** *
* * **** * ** * * ** *
** ** * ***** * * * ***** * (a-c==0)
** ** * **** **** ** * * ** *
* ** * * ** ** ** * ** *** * * * ***** * * * * *
* * ****** ** * ** * * ** **** ***** * ** **** * * ** *
* *** * *** **** ** **** * * *** ***** * ** *** * * ** *** * *
* ** * * ** * * ** *
******** * * ** * ("%.6f ",e);
*** ** * *** ("%.6f ",g);
****** **** * *** ("%.6f",f);






* ** * * * * *** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * * * * ** *




*

{
* ** * *** ***** ** *
* *** ** * * * * %f %f * * * *** * * **** *
***** *** - x2 == 0)
* * ** ** **
* *** * *** *** * *** = x1;
* * *** *** * * * = 0;
**** ** ** ** *** = -x1;
* * **** * * * * * *** *** * * ** %f *** ***
* * **
** * ** ** if(x1 - x2 != 0,y1 != 0)
** ** ***
* * *** * ******* ** = (y1 - **** - x2);
*** ***** ** ** * = y1 - (a * x1);
* * ** * = -((a * x1) + c) / y1;
* * *** **** ** * * %f ** * ** *
*** * *
* ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * * * ** *

int main (void)

{
** ** * * *** *** ** * * x1,y1,x2,y2;


* **** ******* ** * ** * a,b,c;


****** * * ** * * * ** **** %f * * * **** ** * * * **** * * * **
****** ** ** ** *** * ****** * *
*** *** * * ** * * * * * *** ***
**** * ** * * ** * ** ** ** * **** **** *




* *** *** * * *** ******** ** *** ** * %6f %6f",a,b,1);
**** *** ** ** *** * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** *** * * **
* ** ** *** * * *

#include<math.h>



int main()

{
*** ***** * * *** * * x1,x2,y1,y2,m,a,c0;
*** * * * * * ** * *** * * * * *** ** *
* * * * ***** * ** ***** ***** *** ** *** **
* *** * *** * **** ***** * * ** * ** *
****** **** * *** ** * *** * *** * * *** * * ** * **
* * * * ** ** ** = (y1-y2)/(x1-x2);
* * * *** ******** * * ** **
** ** **** * * ** * * * * ** *
* * * ** ** ** * * *** * * * * * * %f **** * * * **** ** * * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
**** * ** **


** * *** * * ** **


** * *** ***


** * * * * *** * **




* ( **** )

{
*** * * *
**** * ** %f %f * ** * ** * * * ** * *** * ***
= d - *
= c - *
* = f * b - a * e ;
** **** * *** * *** * * *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** * ***
** **** **** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
*** * * *** *** i, j, k, l;
* * * *** ** * a,b,c;
** * *** *** ****** ** ***** * ** ** %4f %4f ******* *** * * *** * ** ***
*** *** * ** * * **** ** *
**** * ** ** ********* ** %6f * * * ** ****


** *** *** ** ***** *** * *****
**** ** *** ** * ** * 0;

}
* * **** * ** * *** * rect(int x,int y,int z,int w,int *p1,int *p2)
*** ** ** * * ** * * ** * * a,b,c;


* * ******** ** *** * * * ** * ** * * *
** * * ***** ** * *** ** ***** **** * ** *


** * * * * * ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
*** * * ** * * ***


** * ***
* * * ** * * ** * * * * * ** a, b, c;


* * * * * * ** * * ** *** ***** %f %f ** * * * * ** * * * * * * * **


* **** ** ** *** * = y2 - y1 / * y2 - x2 *
* ** ** *** * * ** = x1 - / * y2 - x2 * **
* ** * *** *** * * = - ** * - * * * *
* ** *** * ***** * * * * **** * * ** * a, * **


*

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ** *** * **** ***
** * *** * *
* * * * * *
** **** **






* ****

{


*** * *** *** * * * **** * ** *


* ** * *** **** ***** * * * * * * ******** * **** ***** *** * ** **



*** * ** * dx = (x1 - *


* **** dy = (y1 - **
** * ** *

* **** **** m = dy / **
*** ** *** * *

* * * * **** h = y1 - * **
** **** *** ****

**** ** a = b * h;

* **** * *** *

**** ****** b =



* * * c = b * h;


*** * * * * *** * * *** *** *** ** *** * **** *** * * * **




*** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
** * ** ** *



int main(void)

{
* * * * ** * * x1,y1,x2,y2;
** * * ** * *** * a,b,c;
** ** * ** * * * *** ** * * *** * ** * * ** *** **
*** ***** *** **
** * *** * ** * ** ***** ** * * * ** ** = y2 - y1;
*** * * ***** * * * * * *** ** ***** *** * *** * = x1 - x2;
** ** * * * ** * ** * * *** * * **** * = -x1 * (y2-y1) + y1 * (x2-x1);
* ** * ******* ***** *
* ** * * * ** * * * *** ** %f %f",a,b,c);






* * ** * ** ** * *** * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** * ***** ** *
** * * *** ***

int main(void)

{
* * **** *** * **** x1,y1,x2,y2;
** * * *** *** ** * * a,b,c;
** *** * * ** * *** ** **** * * **** * * * * * ** * *
** *** **** *******
* * * ** * ** * ** ** * * ** * * **** * * = y2 - y1;
* ***** ** * ** * *** ** * * * * * **** * * = x1 - x2;
* * *** ** ** * * * * ** **** **** * * * * * *** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * * * ****
* **** * ** **** * ** * *** %f %f",a,b,c);






* * ** ** * * **** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.135
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users