0 like 0 dislike
4.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.1k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
** * * ** * * *** ** * *** * * * *
** * * * **** *** * * ** * **
***** * * * * *** ** * ***
* *** ***** * **** * ***** **** ** *** * **** * * ***
** ** * ** ** * * * * * * ******* ******* ** *


** ** **** *** * * *** ** *** (a-c!=0)
*** ** ******* * ** * * *
* * *** * ** * * *** * * * * ***
* *** * ** * *** * ** ** * ***** **
* **** * *** * * *** ** ** * *
** ***** ** ** * *** ** *
*** * *** ** ** * *** (a-c==0)
**** ** * ** * **
***** *** * * * *** * ** **** *** * * *** ******** *
** * * * * ** * ** *** ** ** * * *** * ** * ** *
* ** * ** ** ***** ** * * * *** * ** ** ** * *** ** ** ** ***
**** *** ** *** ** ***
* * * * **** ** * * ("%.6f ",e);
* ** **** ** ** *** * ("%.6f ",g);
* ** * * *** ("%.6f",f);






** *** *** * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
** * * **** * *




**

{
**** * * ** * *****
* * ** * %f %f * * * * **** * ** * ** * ****** *
* * * * - x2 == 0)
*** * ***
** *** **** * * ** *** = x1;
* * * * * * *** * * = 0;
* * * * * ** * ** ** ** * = -x1;
* *** * * * * * * ** * * * %f * ** * *
* * **
* * * * if(x1 - x2 != 0,y1 != 0)
* *** *
*** ** * * * * * = (y1 - ** - x2);
** * ** * ** ******* = y1 - (a * x1);
* * * ** * = -((a * x1) + c) / y1;
* * * ** *** ** * * * %f *** * ***
* *
** **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ***** * * *** **

int main (void)

{
* * * * ** ** * * * * * * x1,y1,x2,y2;


* *** **** * * **** ******* a,b,c;


** * * **** * ***** ** * * ***** ** %f * ** * **** **** * *** * * ** *** *
* * ***** * **** * ** * * *** * **
**** * ** * ** **** * **** * ***
* * * * * * ** ** *** *** * * **




* * * **** * * ***** ** * * %6f %6f",a,b,1);
* *** *** *** * * * **** * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * **** ** ***
** * * ** * * * **

#include<math.h>



int main()

{
*** * **** * * ** * ** ** ** x1,x2,y1,y2,m,a,c0;
**** * * ** * * ** * ** *** * * * * * * ** ***
*** ** * * *** **** **** ** * * * * **** *
**** * *** * *** ** * * * * * * **** * *
** ** ** ** * *** ** * * * ** ** ** * *** ** *
* * ********** * *** *** = (y1-y2)/(x1-x2);
* * * ** * *** ** * * ** * * * * *
*** * *** * *** * *** ** * *
* * *** * ** * * *** * ** ** %f * ** * *** ***** ** *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* *** **** * *


* * * ** ** ** *


*** ** * * * * *


* * * ** *****




* ** ( * )

{
* *** *****
** * ** %f %f * ** ********** ***** *
= d -
* = c - *
* = f * b - a * e ;
** * * ** *** ** ** ******
** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ***** ***
* **** * ****

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
** ** * *** ** * i, j, k, l;
* * * ** * * *** a,b,c;
* **** ********* *** * * ** %4f %4f ** ** ** * **** * *** * * *
* * ** ** ** ** * * * *** ** * * *** ***
**** * * ** * ** *** * ** %6f ** ** ***** **


* *** * * * * *** * ***** * *** ** * ******
* * ** * * ** * 0;

}
* * * * ** ** rect(int x,int y,int z,int w,int *p1,int *p2)
* *** *** * ** *** * * * **** * a,b,c;


* ** ****** * ** * ** *** **** ** ** **
* * * ** *** ** * * **** * * * * * ** ** ** *


* ** * ** ** **** ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
** **** ** **


* *** *
** ** ** **** * ** ** * * * ** * * * * a, b, c;


*** ** * *** * **** *** ** ** * %f %f * * ** * ** * * * * * ** ** ** *


*** * * * ***** ** *** * ** = y2 - y1 / * * y2 - x2 * * *
* **** * **** = x1 - / ** * y2 - x2 *
* **** * ****** = - * * - * * *
**** * ** * **** ** ** * **** ** *** a, *


** * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * **** * * **
* * * * *** *** ** **
* ** ** * ** *
* * *** ** * * **






** * * *

{


* ** ***** * * * * * * * **


* * **** ** * *** * ** *** * * ** * * * * * ** * ** * **



** ** * * dx = (x1 -


* * * * **** dy = (y1 - *
* *** *

* * * * * * m = dy / **
* *** * ***

* *** * * * h = y1 -
* * * * ****

** ** ** ** a = b * h;

** * ** * * *

** ***** *** b =



* * * c = b * h;


*** ***** ** * * * ** * * * * **** * * ** * *** * * *




* * 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* *** * **** *



int main(void)

{
* * ** ** x1,y1,x2,y2;
* * * ** *** * * a,b,c;
* * **** *** * * ** * * * * * *** * ** * * ** * ** *
* *** ******* *
* * * * * * * * * * * ** * * * * * * **** *** = y2 - y1;
** * * * * * * * * ** *** * ** * = x1 - x2;
* **** ** * *** * * * *** *** * *** = -x1 * (y2-y1) + y1 * (x2-x1);
*** * ** ** * *
** ** ********** * ** %f %f",a,b,c);






*** *** * *** ** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* ** *** * * * **
** ** **** * * * ****

int main(void)

{
*** *** **** * ** * x1,y1,x2,y2;
****** * **** * * * * a,b,c;
***** * * ** *** ** ********* * ******* ******* ** *** ** * *
** *** * * *
***** ** ** ** * * * * * ** *** ** * = y2 - y1;
* * * ** * *** * * * * *** **** *** * ** * ** = x1 - x2;
* * *** * * * * ** * ** * ** ** * ** = -x1 * (y2-y1) + y1 * (x2-x1);
** ** *** * ****
** ** ** * * * ** ** %f %f",a,b,c);






**** ** ** * * * * * *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.166
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users