0 like 0 dislike
3.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.4k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
*** **** **** ***** * *** ** *** * *** * **** **
**** * *** * **** * *** ** * * **
** **** * *** ** * * **** ****
* * * * *** * * ** ** * ** * *
* *** ** **** *** ** * ** * * ** * **** * * * ** **** **


* * * * * * * * * * * (a-c!=0)
** **** *** ** * * *
** * * * ** * * ** * ****
* * ** *** * ****** * **** *
* * * *** *** * * * * ** * *
*** * ** * ** * *
*** * * * ** * * *** ** (a-c==0)
* *** * **** * **** ***** *
* ***** **** * * ** * * *** * ** * * ** *
* ** ** ** * ** * **** * ** **** * * *** ******
* * *** * * * ** * * * * ** * * *** * *** **** * * * * ** *****
* * ** * ** * * * *
** * ** * * ****** * ("%.6f ",e);
*** * **** * * ("%.6f ",g);
* * * * * * *** * * * ("%.6f",f);






*** ** * ** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * * *** ** **




* * *

{
*** * * * ** * * *
* ** * ** * *** %f %f *** ** *** ** *** ** ** ****
**** ** * - x2 == 0)
* * * ** *
* * ** ** * ** = x1;
**** * * * * ** * = 0;
** * * ** *** * * ** = -x1;
** * * * ***** * * * %f * ** **
** **** *****
* * * * if(x1 - x2 != 0,y1 != 0)
** **
* ** ** *** ** **** = (y1 - * - x2);
* * * ** ** * = y1 - (a * x1);
* *** * * * * *** = -((a * x1) + c) / y1;
**** * ** *** ** ** * ** ** ** %f * ** * *
* ***
* * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** * *** * ** * *

int main (void)

{
* * *** ** * *** *** * ** x1,y1,x2,y2;


* *** * ** * * * **** a,b,c;


*** * * **** ** ** ** ** * %f * **** * *** *** ** * * **** ** ** ***
* * * * ********** ** * ****** *
* * ***** *** * ** ***** ****** **
* ** ** * *** * *********** *******




** ***** *** *** *** * * ** ** ** %6f %6f",a,b,1);
** ** ** * *** ** *** * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** ** ** *
* * **** *** **

#include<math.h>



int main()

{
** ** * ** * x1,x2,y1,y2,m,a,c0;
* * * * ** * * ***** ****** * ** **** ** *
** ** *** ***** * *** ** ** * *** * ****
** ** ** ** * **** ** * * ** ******** ** * ***
*** ** * *** *** *** ** * *** * * * * * * *
* ** * ****** ****** ** = (y1-y2)/(x1-x2);
*** ** * *** ** * ******* * ** * *
* ****** * ** *** ** ** * ** ***** * *
** * * * * * *** *** * *** *** * %f * **** * ** *** * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ** ** * **


* ** * **** * * * *


** ** **** ***


* ** * **




* ** ( )

{
* * * *
* ** *** %f %f * **** ** **** * * * *
= d -
** = c - **
* = f * b - a * e ;
* ***** ** * * ** * *
**
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* *** ** ****
** * * ** * * ****

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* **** ** ** * ** * i, j, k, l;
* ** ****** **** * * * * a,b,c;
****** * * * * *** * * ** %4f %4f * * *** *** *** * * * * *
* * *** ****** ***** ** * ** *
**** * ****** ** * * *** *** %6f * *** *** ****


** ** *** * * * **** * * ** ** ** * **
* * * ** * ** * 0;

}
** ** * * ** * ** rect(int x,int y,int z,int w,int *p1,int *p2)
** ** * * *** * ** **** ** a,b,c;


***** * * ** **** ** * * *****
** ** ******* ** * * * ***** ** ******** **


* ** * * * ** ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * *** ** * * *


*
* **** ****** * * ** ** * *** * * * * * * * a, b, c;


*** **** ******** ** * *** * ** * * * %f %f *** ** * * * * *** *


* **** * ***** *** = y2 - y1 / * y2 - x2 * **
**** * *** ** * ** ** = x1 - * / ** * y2 - x2 * * *
* ** * ** * ** ** = - * * * - * *
* ** * ** * ** * **** ** * ** * * * a, *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** * **** *
* * * **** * **
* * * * * **** *
** * * * * **** *****






* ***

{


* *** * ** * * *** *** ***** *


*** * * ** ** * * * * * ** ******* * ** * ** * * * ** *



* ** * *** dx = (x1 - * *


** ** ** * * dy = (y1 - *
* * * ** ***

** * * m = dy / *
* * ** * *

** **** h = y1 - **
* *** **** *

** *** * * a = b * h;

* * * * ** *

* ** ** ** * b =



* * * *** c = b * h;


** * * ** * *** **** ** ** * * * * ** ** *****




** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * *** ** * * * *



int main(void)

{
* * * *** * * x1,y1,x2,y2;
*** *** ******* ** * a,b,c;
* **** *** *** *** * ** ** * ** * **** ***********
** ** * * ***
* * *** ****** * ****** *** *** * ** * = y2 - y1;
* * * * * * * ** * ** ** *** *** * = x1 - x2;
* ** ** * *** * ****** * ** * * * * **** * ** * = -x1 * (y2-y1) + y1 * (x2-x1);
** * ** *** *
* * * *** ** * ** * * %f %f",a,b,c);






* * ** * ** *** * * ****** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * * * ** * * *
*** ** * **** *

int main(void)

{
**** ** * * ** ** x1,y1,x2,y2;
* **** * *** * a,b,c;
* ** *** *** * ** ** * * * * **** * * ** ** * *** *
* **** *** * * *
** ** ** * * **** * *** ** ** * ** * ** *** * = y2 - y1;
**** * **** * * * * * * * * * ** ** * * * * = x1 - x2;
* * * *** * *** **** * * ** * ******** = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * ** * *
* ** * * * ** **** * * * %f %f",a,b,c);






** ***** ** * ** *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.160
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users