0 like 0 dislike
6.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.2k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
** * *** * *** ** ** * ** *
*** ** * * ** * * * *** ** *** * * *
* * * ** *** * **** * * *** ****** * *****
*** ** * **** * * *** * ** *** * * ** **
*** * * *** ** ** * * ***** **** * * ** **


****** * **** **** * ***** (a-c!=0)
* ** * *** ** **
*** * ***** *** * ** ** * **** *** *
* * * ** ** ** * ** ** * * * *****
**** * ******* ** * * * **
** *** * **** ***** * ** **
** * ** *** **** * * ** * * (a-c==0)
* * * **** ** * * * * * *** *
****** ** ** **** * * ** * * **** ***** ***** *** * *
* ** * *** ** ** ** ** * *** * ** * * *** *
* ** *** ** **** ***** * * *** * *** ** * * ** *** * **** *** ** *
* ***** **** ** **
** * * ** * * * * * * ("%.6f ",e);
* *** * ** ** * ("%.6f ",g);
****** *** * ** ("%.6f",f);






**** * * ** ****** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * * **** ** ** *




**

{
** * * * * *
***** * * * * %f %f ***** * * ** *** ** * ** ****** ****** *
* *** ** * - x2 == 0)
** ** * *
** ** ** ** ** * * = x1;
* * * ** ** ** **** * = 0;
** ** **** ** ** = -x1;
** ** * * ** * ** * * **** * * * %f * * ** *
* ** * * ** *
** * * * if(x1 - x2 != 0,y1 != 0)
* *
* * ** ** ** * **** = (y1 - *** - x2);
** ** * = y1 - (a * x1);
* * * **** *** * * = -((a * x1) + c) / y1;
* ** * * * ** * * ** %f * * ****
* ** ***
* * * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** * *** * *

int main (void)

{
* * * * * ** * x1,y1,x2,y2;


** * ** ** ** **** ** * a,b,c;


** * * * *** **** * * * ** ** %f * ** * ** * *** ** ***** * ** **
* * ** *** ** * *** * **
* * * ** **** * * ***** * ** **
* *** ** ** * ** * * * ****** *




**** ** * * * **** * *** * ***** %6f %6f",a,b,1);
* *** ******* * * * ** * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * * *********
* ** * * * *** * *

#include<math.h>



int main()

{
*** ** ** * **** * x1,x2,y1,y2,m,a,c0;
**** * ***** ** ** * * ** * * *** *** *
* **** ** ***** * **** * * * * * * ***
* * **** ** ** * * * *** * ** * * ** **** **
**** * * * **** * * * * ** ** *** * ** *****
* ** * * * ** * * * * = (y1-y2)/(x1-x2);
*** * ** * *** ***** **** ** * *
***** * * * ****** ** ** ** ** * **
** * * ** * ** * * * ** %f * * * * *** * *****

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * * **


* * *** * * * *


** *****


* ** * * * *******




* ( * * )

{
** **
** * *** %f %f ** ***** * *** *** **** *
* = d - *
* = c -
* = f * b - a * e ;
** **** ** ****** *** * *
* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ****** * **** *
* *** **** * **

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
** * * * * * i, j, k, l;
** **** ** * **** * ** a,b,c;
* **** *** * * * %4f %4f * *** * * * **** * * *
* ** * * ********* ***** ** * * ** * ** * ** *
***** * ** * ** *** ** * %6f *** *


*** **** ** *** * * ** ** ** * ** *
* ** ** **** ** * * 0;

}
* ** ** * * ** rect(int x,int y,int z,int w,int *p1,int *p2)
* * ** * ** **** * * * ****** * a,b,c;


* **** *** * ** ** * ** * ******** * * *
* ****** * ******** *** * * * * * ***** *


* **** ** * * **
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * *** ** **


* * ** *
* * * ***** ** * * ** * ** ** a, b, c;


* *** * ** * * ****** *** %f %f * *** * * * * * ** * ** ** *


*** * ***** * *** ** ** * = y2 - y1 / * y2 - x2 * *
*** *** * **** *** ** * * * = x1 - ** / * * y2 - x2 * ****
**** * * ** ***** * ** = - * * * - * *
** ******** * * * ******** * *** *** * ** ** a, * *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** ** * ****
** * ** * *******
* ** ** * *
** ** *** ** * *






** *

{


* *** ** *** * * ** ****** * **


* * * ** * * ** * * * * * ***** ** * ** *** ** *** **



** *** * * dx = (x1 -


* * * dy = (y1 - *
* * * * ** *

*** * * m = dy / *
** * * * *

* ** *** h = y1 - * * *
* * * *

* * ** * a = b * h;

**** *** ***

* * * ** * b =



* ** ** ** c = b * h;


***** ** * * * ** * * * * ******* * * *** * *




* * 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* ** * *** * ***



int main(void)

{
**** ** * * ** **** x1,y1,x2,y2;
* ***** ** ** ** ** a,b,c;
* *** * ** **** * * *** *** ***** * *** * ** ** * **** * **
* ** * ** * **
*** *** * * *** ** * * * ** * *** * = y2 - y1;
* * * *** ** ***** * ****** * * ***** = x1 - x2;
* * * ** *** *** ** ** *** * *** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * ***** * * * * *
* ** ** ** ** ** * **** %f %f",a,b,c);






* * **** * ** *** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * ** *** ***
* * ** * * * *

int main(void)

{
***** * ** * * x1,y1,x2,y2;
* *** * * * ** a,b,c;
** * ** ************ ** * *** * * * * * * * * * * * * *** *** ***
* * * ** ** **
** * ** * * * * * * * * * * *** ** ** * * * * *** = y2 - y1;
** * * * * ** ** * *** * * * ** ** ** ** = x1 - x2;
***** ** ** ****** * ** * * * ** * **** ** = -x1 * (y2-y1) + y1 * (x2-x1);
* * ** * * **
** *** * ** ** *** * * * %f %f",a,b,c);






** ** * *** * * **** * * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.60
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users