0 like 0 dislike
7.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.9k views

49 Answers

0 like 0 dislike
Hidden content!
** * * * *


** * * *** * ******


* * ** *** *


** ***** ****




** ** ( *

****
** ***** * * * * * **** * * ** **** * ****
** = d - *
* = c - **
* = f * b - a * e ;
** = 0 - **
** **** *

*** ** * * * ** ** ** ** = - * * * *



**** ** * * * **
** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** * * * *


****
* *** * * ** *** * * * * * t = 0, a, b, c, a1 , *


* * ** *** * **** **** * * * **** ** %f %f ** *** *** * * ** * * ** * * **




*** * * * ** **** ** * * = ** - / * * y2 - x2 * *
*** * * ** * * * * = - / * - * * *
* **** ****** * * ** = - * * ** - * *


* *** * * ** ** * * * * ** *** ** * * **


**

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ** *** * **





int main(void)

{
*** ** * *****
* * * * %f %f **** * * * * * **** * * * *
*** ** * - x2 == ** ** * * * * != 0)
* ** * **
* ***** * * ** * = x1;
***** ** *** * **** ** = 0;
** * * ** *** ** ** ** * * = -x1;
* * * * * * ** * * ** * %f * * ******* *
** ** * * *
***** if(x1 - x2 != ** * != 0)
*
* ** ***** ** **** * = (y1 - y2)/(x1 - x2);
* ** *** * ** * = y1 - (a * x1);
** ** * ** * = -((a * x1) + c) / y1;
* ** * * * **** *** * ** * ** %f ** *****
***
* ** ** * if(x1 - x2 != **** * * == 0)
** *** *
*** * * * *** = x2;
* * ** ** *** **** ** = 0;
* *** * * *** * * * * = -x2;
* ** * * **** * ** * ** * * ** ** %f *** ** ** **
* *
* *** if(x1 - x2 == * ** ** == 0)
**** ** *
* **** * ** * * * = 1;
* * * * *** * ** = 0;
** **** * *** ***** ** = 0;
* ****** * * * ******* %f **** * * ** *

 }
* ***** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * *** *** ** * *


**** ** * * ** ****


* **** * ***


** * ** * ***




** ( *
*
* * * *
** ** * ** ** * ****** ** ** * * ** **
* = d - *
* = c -
* = f * b - a * e ;
= 0 - *
* * * *
*
* ** **** ** ** **** = * - * * * * * *
*


* * * * ** * * * *
**
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* **** *** ****


*
* * * **** ** * * * * ** ** * *** ** * t = 0, a, b, c, a1 , *


* * * * ***** * ** ** * * %f %f * * *** * * * *** ** * ****




**** * ** * ** * * ** = *** - * / * * y2 - x2 * *
* * *** * *** ** * * * *** = * - * / * * y2 - * * *
** * ** ** * * ** * *** = - * - ** * *
**** ** * *** ****** ** * ** = a * -
* ** ***** *** *** * * * = b * -
* **** *** ***** * *** ** * * ** ** ** ** **


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ** * * * ***** *


** *** *
*** * * * * * *** * * ** * * * t = 0, a, b, c, a1 , *


* * *** ** **** * * ** ** * * %f %f ** * **** ** * * * ****** *** ***




* * *** * * * * **** ** = - / * * y2 - x2 *
* * *** **** * ** ******** = * - *** / * y2 - * *
** * * * ** ** = - ** * ** - ** *
* *** ** * ** ** * * * * = a / -
* * * *** * * *** * = b / -
* * ** *** ***** * * * * * ****** * ***** ** * *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * * * ***


* ******
**** * * ** * ***** * * * * * * * t = 0, a, b, c, a1 , *


** * * * * ** ** * * * * **** %f %f **** ** * * * * ****** * *****




** *** * * ** = *** - / * * y2 - x2 * *
** *** ** *** * * * ** = * - * / * y2 - * *
** * ** * * ** * * ** * = - * * - * *
* *** ** * ** * = a / -
* * *** ** ** * ** * = b / - *
* *** * **** **** *** *** * * ** * *** * * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** ** ** * **





int * **

{
**** ***** * * * *
* ** * ***** **** %f %f ** * * *** ** *** *** * * * *
* * * - x2 == 0,y1 != 0)
* ****** * **
* * *** **** ** * ** = x1;
*** *** * * * * * = 0;
* * * ** ** * * ** *** *** = -x1;
*** * * ** ** * ** * **** * ** ** %f ** * * **
** * *
* * * * * * if(x1 - x2 != 0,y1 != 0)
* **
** * * ** ***** = (y1 - y2)/(x1 - x2);
**** ********* * = y1 - (a * x1);
* * * ** * = -((a * x1) + c) / y1;
* * * ** * * * * * *** %f * *
** * **
* * *** * if(y1 == 0)
** * *
* ** *** * ** * ** **** * = x2;
* * *** ** ** ** ** = 0;
** * ***** = -x2;
*** * *** * **** ** ****** ** * %f ** * ***
** *
** *** ** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
**** *** ****


** * * *** *


**** * * ** * **


* ** ** ****** *




** * ** * ( *
**
* ** **
*** ** * ***** **** * * * ** *** ** * **
* = d -
* = c -
= f * b - a * e ;
= 0 -
* * * **

* * * * *** ** * * = - * *



* ***** ** ** ** * ** *
** * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
* ******* **** ** ** ** x1,x2,y1,y2,m,a,b,c,c0;
* ** ** *** * **** * ** * ** * ** * * **** *
**** ******* * * * ** ***** ** ***** *** * **
* * ** ** ******** * **** * ** *** *****
***** * ** * * * ** * * * **** * *** ** *

    m = (y1-y2)/(x1-x2);
*** ** * * *** ** * * *** **** ** * **
* *** ** * * **** ** ** **
* *** * **** *** * ** * * *
** ** **** *** ** * *** *** ** * *
*** * * *** * *** * **** * ** * **
* ** *** * ** * * * ** ***** ** *** ** ** *** * * %f %f",m,-1.000000,c0);
* * ** * *** * **** * if((y1-y2)%(x1-x2)!=0.000000)
*** * * ** *** ** **** *** **** * * ** * *** ***
* ** * * ** * * * * ** *** * ** * *
* * * * ** ** ** * * * * * *** ** ** ** *** * * *
** * ** ** ** * ** * * * * * * * * ** * * *** * * * *** * * * * ** ****** **** * *
** * ** * * ** * **** **** * *** * * ** ** *** *** * *** * * * * **** * *** **** ** **** **
**** * * * * ** ** * * * ** *** * * * *


***** **** ** *** ***** * * *


* * ***** *** * **** * **** *** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 13.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users