0 like 0 dislike
6.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.2k views

49 Answers

0 like 0 dislike
Hidden content!
**** * *** ** ***


* *** **** ***


** * * * *** ***


* * ** * * *** * *




** ** ( * *
*
** * * * **
**** * ** * * * ***** * ** ** *** *
* = d - *
= c - *
= f * b - a * e ;
* = 0 - **
** * * **
*
*** ** * ***** * = * - * * *



*** *** * * ** **
* * *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * *** * * **


* * **
** ***** * * * * *** * * * ** * * t = 0, a, b, c, a1 ,


* * * ****** * * *** ** ** * * * %f %f *** ** ** ** * * ** * *** * * * * **




* * ******* * *** * = * - * / * * y2 - x2 * *
** * ***** ** ** ** ** * = ** - * / * - * *
* * ******** ***** * *** * = - * * * - *


* * * ** ** ******** * ***** *** **** **** * * ** * *


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** **** *





int main(void)

{
* * *** * * **** *******
* *** * * ***** *** %f %f * * * * ***** ***** * ** * ****** * *
* - x2 == * * ** * != 0)
* * * *
* ***** * * * ** ** = x1;
* ****** ** **** * = 0;
** *** **** * ** * * ** ** = -x1;
*** * * ** * ** *** * * %f ** ** *
*** * * * * *
** ** * * if(x1 - x2 != * ** ** ** * * != 0)
* * *
******* * ** * * = (y1 - y2)/(x1 - x2);
** * ** * *** * ** ** = y1 - (a * x1);
* *** ****** ** ** ** ** = -((a * x1) + c) / y1;
** *** * * * ** * * * * %f ** **** *
** **
* * ** *** if(x1 - x2 != *** ** **** == 0)
***
*** * * * * ** = x2;
** **** *** * * * * *** * = 0;
** * * **** ** ** = -x2;
*** * ** * * ** ** * * ** %f * * * * *
*** ***
** * * if(x1 - x2 == ** *** * == 0)
**
*** * ** * * *** * * = 1;
*** * ** * * ** ** = 0;
**** ** *** * * * * * = 0;
*** * * * * ** *** *** **** * ** %f *

 }
** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** *** *


* ***** * * ** **


* * ** * * * **


* **** ** * * *




* ( *

** * **** *
* * * *** ** ** * ** *** * * * *
* = d - *
* = c -
* = f * b - a * e ;
* = 0 - **
* * ** *
**
* * * ******* * * * * = - * * * *



* ** * *** ********* *
* * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** *** ** * **


*
** ** ***** **** * * ** * ** ** t = 0, a, b, c, a1 , *


** * * ** * *** *** ** * ** %f %f *** *** ** * * * * *** * ******* *




** ** * * * ** = ** - * / * * y2 - x2 * **
** * * ***** ** ** = *** - * / * * y2 - * * *
* ** *** * * ******* = - * - * * *
*** * *** * * * ** **** = a * - *
*** * * * *** **** * = b * - *
******* ** * * ****** * *** ** * ** * * *** ** **


**** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* **** * * *


* ***
**** *** ** ** *** * * * *** * t = 0, a, b, c, a1 ,


** **** **** * * * * ** %f %f ** *** * * ** ** ** ** * ** * **




* * **** *** ***** = * * - * / ** * y2 - x2 * *
* * ** *** *** *** ** = * - *** / * * y2 - * *
** * * *** * * ** * * * = - * ** - ** * *
*** * ** * * ***** * = a / - *
* *** * *** *** * * * = b / - *
**** ***** * * * ** **** ** * ** ** * **** * * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * ** ** ** **


* ** *
* * * *** * * * * **** ** ** * t = 0, a, b, c, a1 , *


* * * * * ***** * ** * * %f %f * *** *** ** ** ** ** ** * * * *




* ** * * * *** * *** = - ** / * * y2 - x2 * ***
******* * ** * ** * * * = * - * / * y2 - * **
* * ** * **** *** * = - * - * *
* * * ** * * * **** * ** * * = a / - *
** ** ** * ** * = b / -
*** **** * ** **** * ** ** * ** * * *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * ** ** * *





int **

{
** ** ** ** * * *
* *** **** * %f %f ** *** * * *** * ** * * * * *** *
* *** * - x2 == 0,y1 != 0)
* *** ***
** ** * * **** * *** * = x1;
** * * ** ** **** * = 0;
***** ** *** ** * * *** = -x1;
* * * ** * * * * * * * * * ** %f * **** ****
* ** ***
**** * * if(x1 - x2 != 0,y1 != 0)
*** *
*** ** ** * = (y1 - y2)/(x1 - x2);
* * ** ******* * *** = y1 - (a * x1);
* * * *** ** ** * = -((a * x1) + c) / y1;
** *** ** ***** *** * ** * %f * * * * *
** *
** *** if(y1 == 0)
*** *
* * * * ** * ****** * = x2;
* * **** ** * ** ** * = 0;
***** * * * ****** ** ** = -x2;
* * * * * * ** * ***** * * %f * * * * **
** * *
*** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** ******* * *


** ** * * *****


** * * *** * ** *


* * * **** * *




* * ( *
**
* * * ***
** ** ** * * * * * *** *** ******* *** * * *
= d -
= c -
* = f * b - a * e ;
* = 0 - *
*** ** *** **
*
** * ** * * * * ** ** = - * * * *
**


**** * ** ** * *** * * **
** *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
*** * * * ** * * *** *** x1,x2,y1,y2,m,a,b,c,c0;
* **** *** ** * * ** ** * ** ** * ****** *** *
* * * ****** ** * ****** ** * * * *****
*** * * * ***** ** *** * *
** ****** *** ** ** * *** ** ** * **** * ** * * ***

    m = (y1-y2)/(x1-x2);
** * ** **** * *** * * * ***
** * * * *** ** *
** ** ******** *** * *
**** **** *** ** * ** * * ***
* ************ ** * * **
* * * * *** ** * * * *** * * * * ** * **** * * %f %f",m,-1.000000,c0);
****** ** ***** * * * if((y1-y2)%(x1-x2)!=0.000000)
* **** * ** ** * * ** *** ** * ***** * ** * ** * ** **
*** *** **** ** * ** * ** * *** **
* * **** ** * * *** * *** * * ** * * * * ***** ** * ** * * ** * * * **
* * ** ** *** ** ** *** *** ** ** * * ** * ** * ** * * ** ** * ** * * * *** * **
** ** * * * ** **** ** ** *** ** * *** **** *** ** * ** * * ** * ***** ** * ** ***
** *** ** ** * * * * ** * *** ** * * *** **


** * * ** * * * * ***** **** ** *** ****


* * * * * * * *** *** * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.164
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users