0 like 0 dislike
5.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.4k views

49 Answers

0 like 0 dislike
Hidden content!
* ***** *** * ** ** *


* * ** * * ****


* *** * ** * **


** ** * * * *




( * * *

* * *** **
** * ** ******** * *** * ** ** * *
= d -
= c -
= f * b - a * e ;
= 0 - *
**** **** *
*
** ** ** *** ***** * *** * = - ** * * * **



* * ** * **** * **
** **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * ** *


*
* * ***** * * * * ** * * * * * * ** t = 0, a, b, c, a1 , *


*** *** ** ** *** * ** * * * ** *** %f %f *** **** * *** * * * * ** * ** * *




* ** *** **** ***** ** = * - / * * * y2 - x2 * *
* *** * ** * * **** = * - / * - * *
*** * * ** ** *** * ** * = - * * ** - * **


* * **** *** * ** * * * *


**

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * ***** *





int main(void)

{
* **** *** ** ***** *
* * ** * * **** %f %f **** **** * * * ** * ** ** * *
*** * * - x2 == *** * * *** ** != 0)
*** * **
* * *** * * ** * **** = x1;
***** * *** * *** * * ** = 0;
*** ** * * * = -x1;
* ** ** * **** ** ** * ** ** * * %f ** * **** ***
** * *** *
* ******* if(x1 - x2 != *** * ** != 0)
* ** *
* * * * *** * = (y1 - y2)/(x1 - x2);
***** *** * * * = y1 - (a * x1);
* * ** * * * * * * * = -((a * x1) + c) / y1;
* ** * * * * * * ** ** * %f ** * **
* * *
* * ***** if(x1 - x2 != * * * * ** == 0)
* * *
* * ** ** ** * ** = x2;
** * * * * * ** ** * = 0;
*** * * * * * * * = -x2;
* * * * * * ** *** *** ***** * * * ** %f ******
*** *** *
*** **** if(x1 - x2 == ** ** * * == 0)
* ***
* * * * * * ***** * ** * * = 1;
* ***** ** * *** * ** = 0;
* ** * *** ** * **** * = 0;
* * ***** * * *** **** *** * ** *** * ** %f ** * * *

 }
* *** **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * * *** *** *


* * ** ***** ** **


*** * * * ****


* * ** *** * * *




*** ** ( *** *
**
* *****
* *** ** * * *** * *** ** * *** ** * * ** *
* = d -
= c - **
* = f * b - a * e ;
* = 0 - *
* * * *** *

*** ** ** ** **** * * * = * - * * ** *



* * * * * * * ** *** * * **
** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
**** * * **


** * **
* ** **** **** ** * * ** ** * *** *** * * t = 0, a, b, c, a1 , **


*** * * ** * ** *** * ** * * * *** %f %f ** **** ** * ** * * * * ** ****




* * ** ** ** ** = - / *** * y2 - x2 * *
* ** *** ** ** ** ** * = * * - ** / * * y2 - * * *
** **** ** ** * ** * ** * = - * * - * *
**** *** * *** * * **** * = a * - *
** ** *** ** * * ***** = b * - *
** ** * ** * * **** * * * *** * **** * ** ***


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * *


* ** **
* * * * ***** * * * ** * * t = 0, a, b, c, a1 ,


* ***** * ** ** **** **** %f %f *** ** *** ** * **** * ** * * ** * *




* ** * * ** *** * * = ** - * / * y2 - x2 * *
** * * ** * ***** * * = - ** / * y2 - *
* *** * * * * * ** **** = - * * - * * *
* * ** * * ** = a / -
* *** * * ** = b / -
* ** *** * ***** *** *** * *** * * * * * * *


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * *


*** ** *
** * * ******* * * *** ** * ** *** t = 0, a, b, c, a1 ,


* * ****** ** ** **** * * * %f %f *** * * * * ** ** * *** *




* * **** * ** * *** * = * - * / * y2 - x2 *
*** ** **** ** ** * = - * / * * y2 - ** * **
**** ** *** * *** = - * * - * *
*** *** * * = a / - *
* ** ** * *** * ** * = b / - *
** * ** ****** * ***** **** *** * *** * * * * ** * *


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** *** * * * ***





int ** ****

{
** ** *** * * *** *****
** * ***** * %f %f ** * * * * ***** **** * * *
*** ** - x2 == 0,y1 != 0)
*** * * *
** ** *** * ** * * * = x1;
**** ** * * * * * * *** = 0;
* * ** ** ******** * * = -x1;
** ** * ** * ** ** *** * * %f ** * *** *
****** ** ** *
* * ** * * if(x1 - x2 != 0,y1 != 0)
* ** **
** * **** * * = (y1 - y2)/(x1 - x2);
* ** ** * **** = y1 - (a * x1);
**** * * ** **** ** = -((a * x1) + c) / y1;
* ************ * ***** ** * %f * * * **
**
** **** if(y1 == 0)
* **** ****
* * * ** *** * *** = x2;
* * ** ** ****** ** * = 0;
* * ** *** ** ***** * *** = -x2;
******* * ** * * ** ** * * * * **** %f * ** * * *
* *
* ** *** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** ** * * *** ** *


** ** *** * ** *** **


** ** **


* * * * **** * * *




* * (
*
* * ***
*** ** * ** ** * ** * * *** * * * * * **
= d - *
= c -
= f * b - a * e ;
** = 0 -
** * **
*
**** *** * * * * * = - ** * *
*


** * * * * * *** ** * *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
* * * ** **** * * * x1,x2,y1,y2,m,a,b,c,c0;
**** ** ** *** * **** **** ** * *** * ** **
* ** * ** ** * ** * ** ** ** ** ** * * **
**** ** ** *** ** * * ** ** * * * * *** *
* ** * ** ** ** ** * * * ** * * * **

    m = (y1-y2)/(x1-x2);
** ******* ****** ** ****** * ** *** *
* ** * ** * * *** *** ** * *
** * **** *** * * * * * * ** ***
* *** ** * **** * * * * *
*** *** *** ** * * * ** ** * * * * * *
* * *** * * * * *** ** * ** ** ** ** * ** ** ** * %f %f",m,-1.000000,c0);
** * * *** **** *** ** **** * if((y1-y2)%(x1-x2)!=0.000000)
** *** *** * * *** * **** ** ** ***** * ** ** ** *** **
** ** * * * ** **** *** **** *** **
* ***** * * **** * *** * **** *** * *** **** *** * * ** ***** **
* * * * * *** ** * ******* ** * ** * *** ** ** ** * * *** * * * **
** * * ** * *** * ** * ***** ** ******* ** * ** *** * ** * * * **** ****** ** ** * ***
*** **** * * * ***** ******* * * * * * * ** ***


****** * * * **** * * *** * * *** *


* ** ** * ** *** ** ** * ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.26
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users