0 like 0 dislike
7.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.2k views

49 Answers

0 like 0 dislike
Hidden content!
** **** * * * *


*** * * * * * *


*** *** * ** *


* ** ** ******* *




* * ( ***

* * **** *
* ** * *** ** * **** * ** *** * ** * * ** ** ** *
* = d - *
= c - **
** = f * b - a * e ;
** = 0 -
** *
*
* ***** ******* ** **** * = * - * * * * *



*** * * * * * ** * * *
* * **
answered by (-276 points)
0 like 0 dislike
Hidden content!
****** ** * *


** ****
* * **** **** * * ** **** ** * * * * * * ** t = 0, a, b, c, a1 , * * *


** ****** ** ****** *** * * %f %f * ** * * ** * *** * ***** *** ****




*** ** ** * ****** *** * = ** - * / ** * y2 - x2 * ***
* ** * ** **** **** * = * - / ** * * - * * *
** * **** * * *** * ** = - * * - *


* **** * ** ******* * *** * *** * ** *** ** ** *** * ** *


*

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * * *





int main(void)

{
****** * * * * *
*** * ** * * %f %f ** * * ***** *** * * **** ********
* * - x2 == * * ** ** ** != 0)
* * * * **
* * * ** * *** *** = x1;
*** * ****** * * * ** = 0;
* ** ** ** ***** * * = -x1;
**** * * ** * ** * * * ** * **** ** %f ** * *** *
*** ** *
* ** if(x1 - x2 != *** ** ** *** != 0)
** ****
** * *** *** ** ** = (y1 - y2)/(x1 - x2);
* *** * * * *** * ** = y1 - (a * x1);
*** * ** ** **** = -((a * x1) + c) / y1;
** * * **** * * ** * ** ** * %f * ** ** * *
* ***
***** if(x1 - x2 != * ** * * == 0)
**
*** * ** ** ** * * = x2;
** * * ** * * *** * = 0;
*** ** * * * ** * ** = -x2;
* * * * * * * ***** * * ** %f * * ** * *
****
** * * if(x1 - x2 == * ** ** * * == 0)
* **
* * ** ********* **** *** = 1;
** ** * *** ** **** = 0;
* ******** * * ** * **** = 0;
** ** **** ** *** ** ** %f * * * * * **

 }
** * ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
*** * ** ** * **


**** * **** ** *


* * * ** ** ** * *


* ** * *** * * *




( ***
**
*** ** **
** **** * * * * ******* ** ** * ** ** ***
* = d -
* = c - *
* = f * b - a * e ;
= 0 -
* **
*
**** ** * * **** * = - * * * *
*


* * * * * **** **** **
**** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** ** ** *** **


* * **
** ** * * * ** * ** * * * ** * * t = 0, a, b, c, a1 , ***


* ***** ** * ** ** * * * ** * * %f %f **** ** * ** * * * ** * * *** * **** ***




* * * ** * * * * * ** = - * / * * * y2 - x2 * *
* * ****** * * * * * ** * = * - * * / * y2 - * **
* * * ** ***** * * * = - * * - ** * *
* * * * ** * *** ** ** * * = a * -
* * ***** * * * * ** ** * = b * -
**** * ** * *** * * ** **** * * * * * * * *


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * *** * *


** *****
* ** ** * * * * * ** ** * ** * * * * t = 0, a, b, c, a1 , **


* * * *** * ** *** * **** ** **** * %f %f ** ***** *** ** ****** ** *** *** * *




**** ** ** * ****** **** = - / ** * y2 - x2 *
* ** *** ****** *** * = - * / ** * y2 - ** * **
** **** * ****** * * *** = - * - *** * *
* * * ** **** * * ** * *** = a / - *
** *** * **** ** * = b / - **
*** * *** * * ****** * * **** * * ** ** ** ** ***


*** * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** *** ** * *****


*** *
* *** **** * ***** * * ** * * * t = 0, a, b, c, a1 ,


*** * * * * * * ** ***** %f %f ******** ** *** ****** **** * ** *




** * * * * = ** - * * / * * y2 - x2 * ***
******* * ** ** = * - * / ** * y2 - * *
** * * *** * ** ** = - * * * - * * *
* ** ** * ** * * * = a / -
* * * *** ** *** = b / - *
* **** ***** * ** * *** * ** * * * * ** * *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * * *





int * *

{
*** ***** * **** **
***** * *** * **** %f %f * **** * * ** * ** *** * *
* *** - x2 == 0,y1 != 0)
* *****
*** *** * ** * * * * = x1;
** *** * ****** * * = 0;
*** * * *** *** * * * ** ** = -x1;
** * * * * *** ****** * * *** * **** %f *** * *** *
*** ** **
* * ** if(x1 - x2 != 0,y1 != 0)
*
* * **** * = (y1 - y2)/(x1 - x2);
* ** * * * ** * = y1 - (a * x1);
* ** *** * *** = -((a * x1) + c) / y1;
* * ** ***** ** * * ** %f ***** * *
* ***
* * ** if(y1 == 0)
* *
* * * ** *** * * * * = x2;
* * **** **** ** * = 0;
* * ** **** *** * * ** = -x2;
*** * ****** * * * * ** ** * ** * * %f ** * *
*** **
* ****** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* **** * * * *


*** * * **


* * * * *********


**** ** * ** *




* * ( ** *
*
* * ** *
* * ** *** * * ** * ** *** ** * *** *
* = d -
* = c - *
= f * b - a * e ;
* = 0 - *
*** * *
**
** * * * ** * = * - * * * * *
**


* * * * * *
* * **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** * * ** * ** ** * *** x1,x2,y1,y2,m,a,b,c,c0;
* ** * ** *** * * ** * * ** **** * **
* * ** * * * * *** * * * **** ** *
* **** * ** * * * * * * *** * * * *
**** * ** * * * * *** ** ** * * *** * *

    m = (y1-y2)/(x1-x2);
******** * **** * ** ** * ****
* ***** * *** ** ** ** * ** *** * *
******* *** ** * * * ** ** ** *
***** ** * *** * ** * *
** * * ***** **** ** * ** * * * *
* * * ** ** **** *** **** *** ** * ** **** * ***** ***** * %f %f",m,-1.000000,c0);
* ** * * * *** * * ** if((y1-y2)%(x1-x2)!=0.000000)
* ** * **** * * ** * * * *** * * ** * **** * ** *
* ***** *** * * * * ** * * * ** * **** **
* ** ***** * ** ** ** *** * ****** * *** * *** *** * *** * * * ***
* **** ** * ** * ** * **** * * * * *** * ** ** ** *** ** *** * ** ** ****
***** ****** * **** ** * * ** * * ******* ***** ** * ** * * ** * ** * ******
** *** * * * *** ** ** * *** * *** **


* ** * * * * ** ** ** * * * *


* * *** **** * ** ** ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users