0 like 0 dislike
6.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.2k views

49 Answers

0 like 0 dislike
Hidden content!
* * * **** *


*** * ** **** *


* * * ***


** *** * ** *** ****




* * * ( *

* * *** **
*** * **** * * ** ** ** ****** ** * ******* * **
* = d -
* = c - *
* = f * b - a * e ;
* = 0 -
* * *
*
*** *** * ** ** = - * *
*


* * * * * **** * **** *
** **
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
** ** * * *


* *
***** ** * ***** ** * *** * * * * * ** t = 0, a, b, c, a1 , *


* ** ***** *** ** * * **** %f %f * ** **** *** ***** *** *** * ** ***




* * * * ** * * * * = * - * / * y2 - x2 * *
* ** * *** *** ** *** = * - * * / * - * * *
** ** ** ** ** ** ** ****** * = - * * - * *


* ** * * ** ** *** * * ********* ** * ** **** * ** * *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * ***** *** *





int main(void)

{
* ** * * * ** **
* * ** * * %f %f ***** * ** ** * * * ** ** ** ** * *
* * - x2 == *** *** * != 0)
* * * **
* ** * * * * ***** ** = x1;
* ** ** *** **** * ** *** = 0;
* ** ** **** * = -x1;
* ** ** * ** *** **** * * ** %f ** * * *** *
* * *****
* * ** if(x1 - x2 != * ** * ** != 0)
*** *
* ***** ** ** *** ** ** = (y1 - y2)/(x1 - x2);
* * ** * * * * = y1 - (a * x1);
* ** **** * * * ** = -((a * x1) + c) / y1;
* ** * * * * ** * ** * %f **** * *****
*** * *
*** ** ** if(x1 - x2 != ** * * * ** == 0)
* * *
** ****** ** * * = x2;
** * * ** **** ** ** = 0;
* * ****** *** ** ** = -x2;
*** * ***** * *** ** ** ***** * %f * * *
** *
**** * if(x1 - x2 == * * * * ** ** == 0)
*****
** ***** * ** *** **** = 1;
**** * * ** * ** * ** = 0;
* * ******* ***** **** * = 0;
* ** *** * ** *** * * * %f ** **** **

 }
** * * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * * ** * * *


**** * **** ** * *


* * **** * ***


*** ** ** *** ** **




** ( * * *

* * ** ****
* * * ** * * ** *** * * ** * * * ** ** *
= d - *
* = c - *
* = f * b - a * e ;
= 0 -
******

** * * ** ** * * ** * = - * * *
*


** ***** **** * * * * ****
* ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* *** *** ***


*** * *
* *** * * * ** * * * * *** * t = 0, a, b, c, a1 ,


* * * * * * * ** ** * * %f %f *** * ** * ** ** ** ** ******




* * ** *** ** * * * ** = ** - ** / ** * y2 - x2 * **
*** * ** *** * * * **** = * - * / ** * y2 - *
** * * * * ** ***** = - * - *** *
** ** **** * * * = a * - *
* * ***** * * *** * = b * - *
* * ** * * ******** ** *** * * ******** * ** **** ** ** * *


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** **** * * ***


**** **
* ** * * * * * **** * * ** * * ** * t = 0, a, b, c, a1 , *


* ** **** * * ** * * * *** * * %f %f * ** *** * * * ** * * * *** * * * ** *




***** * ** ***** * * * * = * - * / * * y2 - x2 * **
** * * ** * *** **** = - / * * y2 - * *
*** ** * **** *** ** = - ** * - * * *
***** *** * * * * * * * = a / - *
* *** ** * * * * * * ** = b / -
* * * ** * * ***** *** * * * * * *** * * *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * ** ***


* * *
** *** * ******* * * * * ** t = 0, a, b, c, a1 ,


* *** * ** * * * * ** *** * *** ** %f %f ** * ******* *** * ** **** ** *




** * * * *** * * = * - * / * * y2 - x2 * *
** **** * ** * * ** ** = * - ** / * y2 - * * *
* ** * * ** = - * - * *
** * * **** * * * * * = a / - *
* ** * * ** * ** = b / - *
* * ** *** * ** * * **** * * * * * * * * * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* **** * ** ** ** ****





int * ***

{
**** * * ** ** *
**** *** * %f %f ** ** ** * ** * * ****** *
* ** * - x2 == 0,y1 != 0)
**** ** * **
***** * ** *** * *** = x1;
*** * * * * * * ****** = 0;
** * * **** = -x1;
** ** ** *** * *** **** * * ** * * %f ** *** *****
***** ** *
** * if(x1 - x2 != 0,y1 != 0)
**
* ** ** = (y1 - y2)/(x1 - x2);
* ** ** ** **** * = y1 - (a * x1);
*** * *** ***** * * = -((a * x1) + c) / y1;
* ** * ** ** ** * *** * * %f ****** *
** ** *
* ** * if(y1 == 0)
*** *
** * * * **** ** ** * = x2;
**** **** * * * *** ** ** = 0;
* * ** * *** ** * = -x2;
* * ** ** ** * * * ***** %f * ******
* * **
* * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
*** * **** ** ** *****


* * **** **


* * ***** * ** *


* * * * * ****




*** * ( * * *
*
* ** *** * ***
* * * ** ** * **** * * ** * ** * ***
= d - *
= c - *
* = f * b - a * e ;
= 0 -
** *** **
*
* * ** *** = * - * * * * * * *
*


*** ** * *** * *** * * *
* * *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** * ** * ** ** *** ** * ** x1,x2,y1,y2,m,a,b,c,c0;
* ** **** *** * * **** * * * * * *** **
** ** ** * * ** * **** * **** *** * *** *** * *
****** * *** * * * * * ** * **** * * *** ***
* *** * *** * ** * * * *** ** * ******* * * * *

    m = (y1-y2)/(x1-x2);
** * * * * **** * ** *** * * *
* * * * ****** * * *
* ** * * ** * **** * ***
*** * ** *** * ** ** ** *
** * ** ** * * * * ** ** ** **
* ** ** * * *** *** * * * *** ** * * ** * ** ******* %f %f",m,-1.000000,c0);
** * *** *** * * * * if((y1-y2)%(x1-x2)!=0.000000)
* * *** * * *** * ******* * * * * ** ** ** * *
*** * *** ***** * * ** *** * * * ** * ** ** * **
* ** ** ** * * ** ****** *** ** * ** * * * ** * *** ** ** * * * ** *** *
** * **** ** ***** * ** * ** ** ** * * ** * *** * * **** ***** ** * * ** * ** ********
** * ******* * *** *** ** ** **** * * * **** ** * * * ** * **** ** *** ** ** * **
* ** ** * ** ** ** * ******* * ** ***** * *


** ******* ** ** ** * ** * *** * ** ** * *


* * ** ** * * *** *** * ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.163
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users