0 like 0 dislike
5.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.4k views

49 Answers

0 like 0 dislike
Hidden content!
* * * *** * *


** * ** * * ***


* * * ****


* * * * * * * **** *




*** ** ( **
*
** *
* *** * * * ***** * ** * * * ** **** * * *
= d - *
= c - *
= f * b - a * e ;
* = 0 -
* * ** *
*
* *** * * ** * * ** * **** = - * * ***
*


* * * * * * * ** ** *
* ** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ***** * **


* * **
* * ** ** * * * * **** * * * * * t = 0, a, b, c, a1 , **


*** *** ** * * *** * * *** * %f %f * * ** * ** ***** *** * *




** *** *** *** * * * ***** = ** - ** / * * y2 - x2 * **
** ** ** * * ** ** = - / ** * * - ** * * *
**** * ** * *** * ** = - * ** - * * *


* ***** ******** *** ** * ** **** ** * ** ** * * *


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ** * ** **





int main(void)

{
* *** * ** ** **
* * ** ** %f %f ** ***** *** **** * * * * **** ***
*** * * - x2 == * *** ** * != 0)
**** *** **
*** * ** * ** * ** ** = x1;
** ** * * * ***** ** = 0;
****** ** * ***** * * = -x1;
** * ***** ** * * * %f ** ****
** *** * ***
* ** if(x1 - x2 != ** * ***** * != 0)
* * *
* * ** * ** ** = (y1 - y2)/(x1 - x2);
** *** ** * * *** = y1 - (a * x1);
* **** ** * = -((a * x1) + c) / y1;
* * ** ** * * ** ** * * * %f * *** * * *
* **
*** * ** if(x1 - x2 != * ** == 0)
*** *
* ** * * * ** * * = x2;
* * ** ** * **** * * = 0;
* ***** ** ** * = -x2;
** ** *** * * * * * * *** ***** ** %f * * ** ***
* * **
*** *** if(x1 - x2 == * * ** *** ** == 0)
** * *
* ***** * * * * * ** * * = 1;
*** * *** ** * **** ** = 0;
* ** ** ** ** **** = 0;
* ** * * * * ** * * **** * * %f ** ** * * *

 }
**** ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * ** * * ****


* ******


** **** * ** ***


* *** * * * * ** ******




* * ( ** *
*
** * * **
* * **** * * * * * ******* *** * **** * *
= d - **
= c - *
= f * b - a * e ;
= 0 -
* *** *
**
* ** * * * *** * * ** * * = - * * * *
*


* * * * ** ** ** ***
* *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
****** * ***


***
**** ** ** * * *** * **** * * * ** * * ** t = 0, a, b, c, a1 , **


*** * * * * ** ** ** * * %f %f ** **** * * **** * * * *** **** *




* * ** ** **** = * - / * * y2 - x2 * *
* * ** * ** * ***** * ***** = * - ** / * * y2 - * *
***** ** **** * **** * * * = - * * * - *** *
* ** ** * ******* ** * * = a * - *
**** ** * ** ** ** **** * * = b * -
* * **** *** ** * **** * * ** * * * * * ***** * **


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * ****


* ***
* *** * ** ***** * * * * * ** t = 0, a, b, c, a1 , *


* ** ** *** * * *** * ** * %f %f ** *** * * *** ** ** * * * ***** * *




**** *** * * * * ** * = * - / * * y2 - x2 *
* ** * **** ***** = ** - * / * * y2 - * *
***** **** ** ** ** = - * * - * *
** * *** ** ** * * * * = a / -
**** ** * * * * * * = b / - *
** * ** ** ** * * * * *** * * * ** * * * ** *** *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * *** **** *


* *
*** *** * * **** ** ** ** * * * * * * * * t = 0, a, b, c, a1 , *


********* **** *** * * * * *** ** %f %f * *** **** * * * * * ** ** *****




** ** * * ***** * = * - * / * y2 - x2 * **
* * * * * ***** = * - ** / * * * y2 - * * *
* * * * *** *** * *** * = - * * - ** * *
* * *** **** * ** *** * = a / - *
* * * * * **** * *** *** = b / - *
*** ** * ** ** ** *** **** ****** * ** *


*** * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * **** **** *





int * * *

{
* * * *** * ***
* * ** * ** * %f %f * *** **** ****** *** ** ** ***
* **** ** - x2 == 0,y1 != 0)
*** * * *
***** * ** * ***** * = x1;
*** **** * * *** * * = 0;
** ***** * ******** * = -x1;
** ** * * ** * ***** ** * * ** ** %f **
* * * **
*** * *** if(x1 - x2 != 0,y1 != 0)
* *
* **** * * ** * * ** = (y1 - y2)/(x1 - x2);
* *** **** * ** = y1 - (a * x1);
**** ** * * * = -((a * x1) + c) / y1;
* * * * * * ****** ***** ** **** %f * * * * * * * *
**** **
** * if(y1 == 0)
*******
* * * * *** * ** = x2;
* * * * * ** ** *** = 0;
** * ** * *** * * = -x2;
* ******* * ** ** ** ****** * * %f ** *
** * *
** * ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** **** ** * ***


** * * * * ** *


** * ** * * ** **


** *** * ** * *




* * ( ***
*
* *** * ***
* ** * * **** *** *** * *** ** ***** * ** * ***
* = d - *
= c - *
= f * b - a * e ;
= 0 - *
* * * ***

* *** * *** ***** * = * - * * * * *



* * ** ** ** *****
* *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
*** * * ** ** ** * * ** * x1,x2,y1,y2,m,a,b,c,c0;
** ** * **** * * ***** **** ***** ** * ** * ***
*** * ** *** * * ******** * * **
** * ** ** **** * * *** ***** **** ** *
* * * ** ** * ** **** * * * ** *** ****** *

    m = (y1-y2)/(x1-x2);
** * * *** * * * * ** * * * *
***** *** * * *** * *
* ** * ******* * *** *** ***
** * * ***** * ** * *
** ** * ****** ** * * * * * * ** *
* * * ** * * ** ** ** **** ***** ****** **** *** *** ***** %f %f",m,-1.000000,c0);
* ** *** ** * if((y1-y2)%(x1-x2)!=0.000000)
** ** ** *** *** ** * * * * ** * **** ** * * ***** ** ** * *
* *** * * * * *** ******* ** * * * * * * **
*** ** ** *** ** * * *** *** ** * ** * *** * ** * * *** * * * * ******
* * *** * ****** * * ** ** * ** * ** ** **** ** ***** * * *** ** ** ** * **
** * **** *** * * ** * **** ***** *** **** ** *** * * * * * **** *** ** * ** **
* *** ** * * * *** ** * * * * * * **** **


* *** * ** * * * ** * **** * * * * ***


* * * * * *** *** * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.253.97
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users