0 like 0 dislike
3.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.4k views

49 Answers

0 like 0 dislike
Hidden content!
*** *** * * ***


* * ** * * * *** * *


* *** * ** * *


* ***** * * *** * *




* * ( *
**
** * ** *
* ** * * * ** * * * ** * * **** **
= d - *
= c - *
** = f * b - a * e ;
* = 0 -
**** ** *
**
*** ** *** **** ** = - * * *
**


* ** * * * ** * * ****
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * *** *** ***


* * ***
* * * ** **** * ** * ** *** * * * ** * t = 0, a, b, c, a1 , * **


* * ******* * *** ** ** **** * %f %f * ** * * * ***** * ** ** * *




* ** ***** ** * * ** * ** = * - * / * * y2 - x2 * *
** ** * * *** * ** = * - * / * ** - * * *
* ** *** * * * *** = - * * - ** * *


*** ** **** * **** ** ***** * ** * * ** *


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ***** * *





int main(void)

{
* * * * * **
* * * ******** ** * %f %f * ** ******* ** *** * ***
* ** - x2 == ** *** != 0)
** ** * *
* *** * * ** * *** = x1;
** ** * * * **** * * = 0;
** ** * * ** ** ** * = -x1;
** * *** **** * * *** **** * * * %f ** ** ****
** * * * **
** ** ** * if(x1 - x2 != * * **** != 0)
** * * ****
* **** * * ***** = (y1 - y2)/(x1 - x2);
* * *** ** ** = y1 - (a * x1);
* * ** *** ******* = -((a * x1) + c) / y1;
* * * *** *** ***** ** %f *** * * *
*******
* *** * if(x1 - x2 != * *** == 0)
** * **
* ** *** * * * = x2;
** ** ** ** * *** * ** = 0;
* * * * * * * *** = -x2;
*** ** *** **** * ***** ******* %f ** * * *
**** **
* * ** if(x1 - x2 == ** *** == 0)
******
** * * * *** * ** * = 1;
* * *** ** * * = 0;
**** ** * **** *** = 0;
** *** ** * * * ** * *** *** %f * ******* *

 }
*** ** **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
*** *** * ** *


* * ******* *** *


** * * ***


** * * * * * **




* * ** ( *
*
* * **
** * * * * ** * *** * ** ***** **** * * * ***** *
* = d -
* = c - *
* = f * b - a * e ;
* = 0 - *
* * **** *

* *** * * **** ** = - * * * * * * * *
*


*** ** * * * ** *** ** **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** **** * * ****


* *
* ** * * ** * * * * * * * ** ** t = 0, a, b, c, a1 , *


*** ** ** ******* * ***** * ** * %f %f ***** ** ** ** * * * * * * * *** ****




** ** * ** ** ** *** = * - * / * * y2 - x2 * * *
********** * * * * **** = * - * / * * y2 - * *
** * *** * * * = - * * * - ** *
* * *** * * ** * ****** = a * - *
* * * *** * * * * = b * - *
** * *** ******** * * *** * * * * * * ** * ** * *


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * *** * *



* * ** * *** ** * * t = 0, a, b, c, a1 , **


* ** * * * * ** **** * ** * *** %f %f * *** ***** *** * * * ** * ***




* * *** * *********** = * - * / ** * y2 - x2 * *
** ******* ** * *** *** = - * / * * y2 - * * *
*** * ** ** ** * **** = - * * ** - * * *
** ** * * * * *** * * ** = a / - *
* * * ** ** * ** * * ** = b / -
* * * * ** *** * **** * * *** **** * *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** *** * * * **


* **
*** * * * * ** * * * * * * * * * * t = 0, a, b, c, a1 ,


**** * ** * * * *** * * * *** %f %f * ** * ******* * * * * ** * * * *




** ** * * **** ** *** * = * * - * / * y2 - x2 *
* * * * **** * ** * = ** - * / ** * y2 - * * *
* ****** ****** *** * * = - *** * * - * *
* * * * * ** * * * * = a / -
* *** * ** ** ** *** ** = b / - *
* *** ** **** * ** **** * * **** ** * * ** * *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** *** ** *





int ***

{
* * * **** * ** *
**** * * ** * * %f %f * ** * ** ** ** ** ******* * ** * * *
* ***** * * - x2 == 0,y1 != 0)
** * ** ** **
** ****** * ** *** **** ** ** * = x1;
*** ** ** *** ** * * = 0;
** ** ** ** ** * * * = -x1;
* ** * ** * ** **** ** * * * * %f * * ****
* * **** ** **
** ** if(x1 - x2 != 0,y1 != 0)
*** ***
** *** * * ** ** * = (y1 - y2)/(x1 - x2);
* **** * * ** ****** = y1 - (a * x1);
* * * **** * = -((a * x1) + c) / y1;
** * * * * * ***** * *** *** %f * * ******
** *
** if(y1 == 0)
* ** *
* * ** * * ** ** * * = x2;
** ** ** ** * * = 0;
*** * * * ** ****** * *** = -x2;
* ** **** *** * ** * * * %f **** *** *
*** ***
*** ** *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** ** * *** **** ** * *


* ** * * * * * * **


** *** ********


* *** ** *




* * *** ( *
*
* * * * *** **
* * * *** * * * * * * *** * * ** *
* = d -
** = c -
** = f * b - a * e ;
= 0 -

**
* *** * * * *** * * = - * * * * *
*


*** * ** *** ** ***** **
* ***
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** ** * * * ** * * x1,x2,y1,y2,m,a,b,c,c0;
* ******* *** * ***** * ****** * *** ** * **
* *** * ** **** ***** * * * ***** * ***** *
*** *** **** *** * * **** ** **** * ** * **
* ** *** * * ** * ***** * * * * * * * **

    m = (y1-y2)/(x1-x2);
**** *** * *** * * *** * * **
** * * ** *** * *** **
* * ** **** * **** * *** ****
* ** *** ****** *** ** * *
*** *** * **** ** ** **** * **
** ** * * *** * * * *** * ** ** ** * * * * %f %f",m,-1.000000,c0);
* * * ** * ** * if((y1-y2)%(x1-x2)!=0.000000)
*** * *** * * ***** **** * ** * * *** * * ****** * * * ** *
** ** * * ***** * * * ** * *********
** * ****** * ** * ** **** *** * * *** **** * ** * * ** * * * **
** ** ** ** * * ****** *** ** ** ** * ** ***** *** * ** * *** **
** ***** * * * * * ** * *** ** * * ***** *** * ****** * * ** ** ** ***** * * ** **** ***
** *** * ** ** ** ** ** * * * * * ** **


** ** * * ** ** * *** *** * *


** * ** * * * ** * **** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.176
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users