0 like 0 dislike
3.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.9k views

49 Answers

0 like 0 dislike
Hidden content!
*** * ** * *


* * ** **


*** ** * * *


* * * * * * * *




* ** (

** * ** * *
** * * * *** ** *** * *** ** * ******* * **
= d - *
* = c - *
= f * b - a * e ;
* = 0 - *
* * *

* * * *** *** * * = * - ** * ** *



*** * * ** ********
*
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * * * *


* * * *
** *** * * * * * * * * ** * t = 0, a, b, c, a1 ,


*** * * ** *** * *** **** ** %f %f * * ** ** * * * ** * * *** * **** **** *




** * *** * * * * * * = *** - / * y2 - x2 *
* * ** * *** ** * * * = * * - * / * * - * * *
*** **** ** ** ** * = - * * - * *


** * * ** ******* ** * *** * *** ** * * * ** * * *


** **

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * ***** **





int main(void)

{
* * ** * * * * * * **
****** *** * * %f %f * * ** * ** * * ** * ** ** *
**** * * * - x2 == ** ***** != 0)
* * * ** *
* * * * ** * ** **** = x1;
** ** ** * **** **** = 0;
**** * * * * ** *** * * = -x1;
* ** ****** * * ** * ** ** * %f * * ** * ** *
**** * *
******** if(x1 - x2 != **** * **** != 0)
** ***
* ** * ** **** = (y1 - y2)/(x1 - x2);
** ** * *** * = y1 - (a * x1);
* * * * = -((a * x1) + c) / y1;
* **** * *** *** ** **** ** %f * **** **
* *
** *** if(x1 - x2 != ******* ** *** == 0)
* **
*** * **** *** ** * = x2;
**** *** * = 0;
*** * *** ** * ** **** = -x2;
**** * * * * ****** *** ** * ** * %f * * * ****
*
** * * if(x1 - x2 == **** * * == 0)
* ** **
* * * * * * *** * = 1;
*** ** * * ** * * * * = 0;
*** *** ***** = 0;
* * * ***** *** * * ** * * * %f * ** * * *

 }
* * *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** * **** ** *****


* *** * ** *****


* ** * ** * *


* * ****** ** * **




** ( * *

****
* ** ***** * * ** * ** **** * * * * * ***
* = d -
* = c -
= f * b - a * e ;
* = 0 -
*

** * ** * **** *** = - * * * *
*


* * * ** * ** * * * * *
* **
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * ** ***** ** ** *


* * ***
** * * * ** ** * * * * * * t = 0, a, b, c, a1 ,


* * * ** * ****** *** * * ** %f %f ** ** * * * * *** ** ** * ******




* * **** ** ** ** * = * * - / * y2 - x2 * ****
* ** ****** * *** * = - * / * * y2 - * * *
*** * * ** ** *** * = - * * - * **
* *** ** * * * * ****** **** = a * - *
*** * **** * * * ** = b * - *
***** * * * ** * * ** **** ** **** *


* * * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ** * ***** ** * ***


**
** * * * * *** *** * ** * * * * * t = 0, a, b, c, a1 , *


* * ***** * * * ** * **** * ** * %f %f * ** *** * ** ** * * *** **** * *




** *** * * *** *** *** = * - * / * y2 - x2 * *
***** ** *** **** ******* = *** - * / * * y2 - * *
* ** *** * ** = - ** * - *** *
* * * * * *** = a / -
* ***** * *** **** * * = b / -
* * * ** * * ** * *** * * ** * ** *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ** * * *


* ** *
** * ** * * **** * * * ** *** * t = 0, a, b, c, a1 ,


* ** * * * * *** * * * %f %f *** * * * * ** * * * ** ** *




* ** * * * ** ****** * *** = * - * / * * y2 - x2 * *
** *** * *** ** * = - ** / * * y2 - * * *
** * * ** * * ****** * * = - * - * * * *
**** * *** * ** ** = a / - *
* * * ** ** ***** ** = b / -
**** * ** * ** **** * * * *** * ******* * * **


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * ***** **





int *

{
* * *** * * * ****
* * * ** *** ** %f %f ****** * * * **** ******* *
* * * - x2 == 0,y1 != 0)
* ** **
** * * * * * = x1;
** * * * * ** * ** * *** = 0;
* *** * * *** * * * * * = -x1;
*** * ** * *** * ** %f ******
* ** * * **
** ******* *** if(x1 - x2 != 0,y1 != 0)
****
* *** * = (y1 - y2)/(x1 - x2);
** * * ** ** * = y1 - (a * x1);
* * * * ****** = -((a * x1) + c) / y1;
** * ** * * ** **** * *** * * %f **** ******* *
*** *
***** * if(y1 == 0)
** *** * **
** **** * *** * = x2;
** ** * ** ** *** *** *** * = 0;
* **** ** *** ** * * * = -x2;
* ** *** *** ** *** * * * ** * %f ********
* * *
* * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * ***** * *


* *** **** * *** * * *


* * * *** **


** * ** **** *




* ( * *

* * * ***
****** * * * * * * ***** * * * *** *** * **
= d -
** = c - *
* = f * b - a * e ;
* = 0 -
* *** **** *

*** **** ** ***** **** = * - * * *
**


*** ***** * * * * ***
* * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
* *** * ** ***** * **** ** * * x1,x2,y1,y2,m,a,b,c,c0;
***** * * * * * ** * *** ** ******* * *** ** * *
**** * **** ** *** *** ** * * *** ** ** *
** * * * * ** ** * *** * * *** * **
***** ** * * ** * ******* * *** ** *

    m = (y1-y2)/(x1-x2);
* ******* **** * ***** ****** *** ****
** *** * *** *** ** ** ***
*** * *** * **** ********
* ** * ** ** * ** * * ******
**** * * ** * * * * * * * * ****
* ** * ******* * * * * * * * **** ** **** * ** * %f %f",m,-1.000000,c0);
** * * **** * *** * * if((y1-y2)%(x1-x2)!=0.000000)
* * ** * * *** ** * ** *** ** * *** ** * * * **** *
*** * ** * *** * * *** * * * * ***** ** * *
* ** * ** * ** * *** * * ** ** ** * ** **** ** ** * * ** * * ** ** * * *
* * ********** ** *** * * * * * ** ** **** ** ** * * * **** *** *
****** ** ** * * ** ** **** * ** *** * * * ***** *** * * * ** * ** *** ** * * * ** *
* *** ****** * ** ** ** ** ** ** *


* * * * *** ** ***** ** * ******* * * * **


* ** *** ** * ** *** ****** **** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.38
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users