0 like 0 dislike
3.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.4k views

49 Answers

0 like 0 dislike
Hidden content!
* *** **** * *


* *** * * * * *****


* * * *** * * ** **


* * * * ** ** **




* * * ( **

* * ** *
**** ** * ** *** * * ***** ** ** *
= d - *
* = c - *
* = f * b - a * e ;
= 0 - *
*** ** *
*
* **** * ** ** * = - * ** * * *
*


* *** *** * * * * *
* *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** ******** ** *


* *
*** * ** ** * ****** * * ** * ** * t = 0, a, b, c, a1 , ** *


*** **** **** * * ** ******* %f %f * ******* * * ** * * *** ** * *




* * ** * * ** * = - ** / * * y2 - x2 * *
** ** * ** ***** * * = - ** / * * - * *
* * * * * **** * **** = - *** * - ** * **


* * * * ** *** *** * *** ** * * * * * * **


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* **** ** ** * * * *





int main(void)

{
* * * * * **** * *
* * ** * * %f %f ** *** ** ** * * ** ** * ***
** * * * - x2 == * * * != 0)
* * * *
***** *** ** * ******* * *** = x1;
*** ** * * * * *** = 0;
* * * *** *** *** ***** = -x1;
* * * ** ** ** ** *** * %f * ** *
* ** * **
***** * * if(x1 - x2 != * ***** * != 0)
** ***
* * *** * ** = (y1 - y2)/(x1 - x2);
* ** * *** = y1 - (a * x1);
**** *** * ** = -((a * x1) + c) / y1;
**** ** * * ** ** * ****** %f ** ** **
* * *
**** if(x1 - x2 != ** ** **** == 0)
* **
* * * ** * ** ** ** = x2;
******* * ** * * ***** = 0;
** * *** * ** **** = -x2;
*** * ** *** * ** *** * * ** %f * *** *
* *
* ** *** if(x1 - x2 == *** * * ** == 0)
**
* * ** * *** *** *** *** = 1;
* ** * ***** * * * **** = 0;
* * * * ** ** * = 0;
* * * * *** ** * ** %f * ** * *

 }
*** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** ****** ***


* ** * ** * *** * * *


* * *** ** * **


**** ** ** ** **




* ( * *
*
** *
*** * ** * * * * ** ** ** ** * * * * ** *
= d -
= c -
** = f * b - a * e ;
* = 0 -
*** *
*
** ** *** * * * * = - ** * ** * *



* * *** * * ** *******
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** *** * * * *


*** ***
*** ** ** ** **** * **** * * ** * t = 0, a, b, c, a1 ,


*** **** * * ** *** *** %f %f ** **** *** ********* ** ** ***




* * *** * *** ** * * ** = * - * / * * y2 - x2 * *
* * * * ***** ** = * - / * y2 - *
* * ** ** * *** = - * * * - * * *
* * * * ** ** * ** **** * * = a * -
****** ** ** ** = b * - *
* * *** **** ******** * *** ** ** ** * * * ** * ** ***


** * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** * **** ***


* * *
* * *** * * * ** *** * *** * * * * t = 0, a, b, c, a1 , *


* * * ** *** **** * * ** %f %f * * *** ** **** * * * * **




* ** ** *** * **** * * ** * = * - / * * y2 - x2 * *
*** * ** * ** * * *** = - * / ** * y2 - * *
*** ** * ** ** *** * = - * - ** * *
* ***** ** ** ** * * = a / -
** * * * ** ** * *** = b / - *
**** ** * *** *** * * * * ** * ****** * * * * *


** * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** *** *** **** *


* *
* * ** * * ** * * ** * * t = 0, a, b, c, a1 , **


***** ******** * ***** *** * * %f %f *** *** * ** * ** *** ** * *




** * * ** **** ** ** = * - / * y2 - x2 * *
*** **** * *** ** = - / * * y2 - * *
* **** * ***** * * * = - * - ** * *
** *** * *** * = a / -
* ** * * **** * ** = b / - *
* * ** ** ******* ** * ** * * ** * ** * * ** ** * ** *


* * * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * * * *** ** *





int *

{
* * * *** *** ** * **
* ******* * %f %f * ** * *** * * * * * ** ** ****
* ** *** **** - x2 == 0,y1 != 0)
* * * *
*** * * *** ** ** * = x1;
* *** * * **** * ** * = 0;
* ** ***** * * = -x1;
* * * * ** * ** ** **** * *** * %f ** **** **
* **** * ** *
* * if(x1 - x2 != 0,y1 != 0)
*
*** ** *** *** * * = (y1 - y2)/(x1 - x2);
*** *** ***** **** = y1 - (a * x1);
** **** *** * * = -((a * x1) + c) / y1;
* ** ** ** * **** * ** * * %f ** * **
***** * *
* **** * if(y1 == 0)
**
* * * * * ** ** = x2;
** ***** * ** *** *** ** * * = 0;
***** ** *** ********* = -x2;
* *** ** ** ** ** * * * * * * ** %f **** **
*** ***
** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** * *** *


** * * * * *


** * * * * *****


** * ** *** **




* ( **

* * **** *
* *** * *** * * *** ** *** ******** *** * * * ********
= d - *
* = c -
* = f * b - a * e ;
* = 0 -
* * * **
*
* ** *** * **** * **** = - * * * * * * * *



*** *** * * **** *** *
* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
* * *** * * **** x1,x2,y1,y2,m,a,b,c,c0;
* **** * *** * ** ** ** * * * **** ***
**** **** * * ** * **** * * * * * * ** *
* * **** * * * * * ****** ** ***** **
* * *** *** *** * * ** * * ** ** * *** ******

    m = (y1-y2)/(x1-x2);
** * ** *** ***** ** ** ***** ****
* ***** * ** * **** * * ** **
* * *** *** * * ** * * **
* * *** * * * ** * * * **
*** ** *** * * * * ** ** ** *** *** *
***** * * ** **** * * * * **** ********** ** ** * ** ** ** %f %f",m,-1.000000,c0);
*** ** * * ** ** * ** * if((y1-y2)%(x1-x2)!=0.000000)
* * * ** * * *** * * * ** ** *** ** ** *** * * * *** * * **** **
** * * ***** * ** * ** ** ** ** * ** * ** *
*** * * **** * ** ******** * *** * * * * * * ****** ** * ** *
* ** * ** ** ** ** * ** ***** *** *** * *** * *** * * *** * *** * * **** ***
** ** **** * **** ** ** ** * * ** ******* * ** * ************** * **** ** ** ** *
** * * * **** * * ** *** *** * ** **


** * *** * **** * ** **** * * ** ** ****


*** ** * **** * * **** * ** ***** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.44
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users