0 like 0 dislike
7.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.4k views

49 Answers

0 like 0 dislike
Hidden content!
** * * ** ** * * **


* * * * * *


* * * ***


******* * ***** * ***




* * * ( *
*
** **** ***
* * * * * * *** * * * * * ** * ** * * **
* = d - *
* = c -
= f * b - a * e ;
* = 0 - *
* *** *
*
* **** * * * *** ** = - * * * *
*


** ** *** * * *
** *** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** * ** **


* **
** * * ** **** * * ***** * * * * * * t = 0, a, b, c, a1 , ** *


*** * * * * * ******* * ** %f %f * * ** ** * * ** * * ****




* **** *** ** ******** * = ** - * / * * y2 - x2 * * *
* *** *** * ***** * = - * * / * * - * ***
** * * *** = - ** * - ** * *


* ** ** * * ** * * * *** *** * * *


*

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
***** ** * *** ** * *





int main(void)

{
** ** * **** * ** *
** *** *** ** * %f %f * ** ***** ****** *** * * * *** * * * *
* ** * - x2 == ** * **** != 0)
** * * *** *
** **** ***** ** *** = x1;
** * ** *** * ** * = 0;
** *** ***** ** **** * ** = -x1;
* * ***** * *** ********** ** * %f ** * **** *
***** ***** * *
* ** * if(x1 - x2 != * ****** != 0)
* *
* ** * * ****** = (y1 - y2)/(x1 - x2);
** *** * * ** * = y1 - (a * x1);
* * *** * ** = -((a * x1) + c) / y1;
******* * * ** ** * * ***** * ** * %f ** *** * **
**** *
**** ** if(x1 - x2 != *** * ** * == 0)
** * *
* * ***** ** * ** **** ** = x2;
** * * ** * *** * ** * ** = 0;
* * *** * * * ** = -x2;
* ** ** * * ** ** *** ** * %f ** ****
** **
* * ** if(x1 - x2 == ** * * * ** * == 0)
* * *
** * * ** * = 1;
*** * **** ** ** * * * = 0;
** ** * ** * * * * = 0;
** * ** ** ** * * * ** ** * * %f * ** * * *

 }
* * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * ** * ** **


**** * ***** ****


* ** ** * * *


**** ** * *




** * ( *** *
**
** * * * *
* ** * * ** * *** * * **** ** *** ** ***** **
* = d - *
= c - *
** = f * b - a * e ;
* = 0 -
* ** ****

* * ***** ** **** ** = - ***



* * ** * * * * ** ** * *
***** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* *** * ***** *** * *


* * ****
* ** * * ** *** ** * * * ** * * * * t = 0, a, b, c, a1 , *


* ***** ***** ** * *** * %f %f ** *** ** ** * * * * * ***** * * * * *




* * ** ** * * *** **** = - * / *** * y2 - x2 *
* ** * ** * * * * = * - ** / * * y2 - * * *
** ** * **** * * * * = - * - * *
* ** * * ** * * = a * -
*** * ** * *** ** ** = b * - *
** * * * ** * **** ** * * ***** ** * ** *


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** * *** **


* *
* * *** **** * ** ** ** * * ** * * t = 0, a, b, c, a1 , * *


* *** ** ** * ** * *** * %f %f ** *** * ** * * * * ** **** * ** **




* ******* **** ** ***** * = * - * / * y2 - x2 * *
* * * * *** ** ** * ** = * - / * * y2 - * * *
* * * * * ****** * **** = - ** * - * * *
* * * *** ** * * ***** = a / -
*** ** * * ***** = b / -
** * * *** ** *** * **** **** * * * **** * *


* *** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* *** ** *** **


*** *
* ** ** * * * * * ** ** * ** * * * * t = 0, a, b, c, a1 ,


* * * **** * * * * ****** **** * %f %f **** ** *** * * ** * ** * * * ** **




** * * * ****** = ** - * / * * y2 - x2 * **
***** * * * * *** * * *** = * - * / ** * y2 - * *
* * * * ***** ** * ***** = - * * - ** * *
* * **** **** ***** * = a / -
** ** ***** *** ** **** ** * = b / -
* * ** * *** **** *** **** * ** ** * ** * * * *


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
**** ***** * *





int * * *

{
* * * * **
* *** *** *** %f %f * *** ** * **** * * ** ** * * * *
*** * * - x2 == 0,y1 != 0)
** ** * * *
** * *** **** ** *** * = x1;
* * * ******* ***** = 0;
***** *** * ** * *** = -x1;
* ** ** **** * * ** * ** ****** * * * %f * * * *
* ** * * **
*** * **** if(x1 - x2 != 0,y1 != 0)
* ** *
* * *** * *** = (y1 - y2)/(x1 - x2);
* * ***** * ** * * = y1 - (a * x1);
*** ** *** * * = -((a * x1) + c) / y1;
**** * * *** * * ***** ** %f * ** * * ***
*****
if(y1 == 0)
*** * ***
***** * ** ** * ** = x2;
*** ** ** * * ** **** * = 0;
** * ** ** * ** * ** = -x2;
* ** *** * *** ** ** ** * ** %f ** ******
* ****
* *** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** ** * * * * * *


** * * * **** ** **


* *** * * * * **


* ** * * * * *




** ( **

* * ** * * *
* *** ** ** * ****** * * * ** * ******
** = d - *
= c - *
* = f * b - a * e ;
* = 0 - *
* ** ** *
*
** *** * * * *** * ***** = - * ** **
*


*** * * *** ** **
* * *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** ** * ** * * * * * x1,x2,y1,y2,m,a,b,c,c0;
** * ** ** *** *** * ** * *** * ** * *** *
* ** ** * ** ** * **** * * * * *** ** **
*** ** ****** ****** **** ** * *** * ** **
** *** * *** * * * ***** * ***** *

    m = (y1-y2)/(x1-x2);
* ** * * * * ** *** * * ** ** * **
* * **** * * * *** * * **
** ** * ** ** ** **
** * ** * * * ** *** * *
* ** ** *** * ** * ** ** * * **
* ** **** * *** ** ** *** * **** ** ** * * **** * * * %f %f",m,-1.000000,c0);
* * * * * **** * * ** **** if((y1-y2)%(x1-x2)!=0.000000)
*** * * ** ** **** * ** * * * * * *** * ** ** * *** ** *** * *
***** * **** * ** ** **** * ** * ***
*** * *** ** *** *** * ***** * * *** * * * ** * * * *** * * * *
* ** * *** ***** * ** *** * ** * ** * ** ***** * ** * *** * ** ** ** ** **** ** *
* * ** * ** * ***** * *** * *** *** ****** *** **** * ** *** * * *** ** *** ****** *** ***** *
** * ** **** **** * * **** ** * * * **** * *** *


* *** ** * * ** **** * ** * *** * ** ** ** *


* ** ** * * * **** ** * ** * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 13.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users