0 like 0 dislike
5.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.1k views

49 Answers

0 like 0 dislike
Hidden content!
* *** ** * *


* * * ** *** * **


**** * *** **


** ** *** * * **




* * * ( * * *

*** * * * ** **
* * * ** * * ** * * * ** ** *** * ***
* = d - *
* = c -
= f * b - a * e ;
= 0 -
* * * **
*
* * * * * * * ***** = - * * * * **



*** *** * * * * * **** *
* * *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
** * **** ** ** * ** * *** ** ** * *
*** * * * ** * ***** * ***** **** **
* ** * * * ** ** ** ** * * * ** * *
* * * ** * ****** * * * *** ** *** **
** * *** ** **** ** ** ** * * * * * ** ** *** ***


****** * * ** * * ** *** * (a-c!=0)
* * * * * * * **** *** * * ***
*** *** ** *** * ** ** * ** * ** * * ***
* ** * * ***** ***** *** *****
* ** * ******** * ** * * *
* ** * ** ** * * * *
**** ** * ** * * ** ****** ** (a-c==0)
** * *** ** * ** * ** *
** ** ** * ** ** *** * * ** * *** * * * * *** * ***** *
******** * ** * * * * *** *** ***** * * ** * * *
** * * ** * * ** *** * **** ** * * **** * *** *** ** * *
* ** ** ** * ** ****** * * *
******* * * ** * ("%.6f ",e);
* * * ** ** ("%.6f ",g);
** ** *** * *** ** ("%.6f",f);






*** * * ** ** ** *** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include ** * * * *



int main(void){


** * *** * * * ** * ** ax , ay ,bx ,by ,a ,b * * * **


**** ** **** * ** ** ******* ** ** ** **
* ** * ****** ******* *** * ** * ** * ** * ** ***
*** * ** *** * * **** * *** ** * ** *** **** ** * ***
* * *** * **** * ***** * ***** *** *** ***** * ** * * **** **** *


* ** ** * **** *** ** ** - bx) != 0){
* ** ** * * **** * = (ay - * * *
***** * ** *** = -m*ax + ay;
* ** * * * **** * * = m;
* * *** * *** * * = -1;

 }
* * * ** *** *
********** ** ** = 0;
* **** *** ** * = 1;
**** ** ** ** * * * * = -ax;
** ** ****


** ** * * ** = a;
* ** * ** **** = b;
** * ** * **** *** = c;


** * * ** < 0)
* * ** ** **** * = -i;
** * * if (k < 0)
** * ** ** * *** ** *** = -k;


** * * (i < 1){
**** * * ** * * = 1/i;
*** ** * ** * * * = a*g;
** * *** *** ** ** = b*g;
* * * ** * * *** ** = c*g;
* *
** ** *** if (k < 1){
*** * * ** ** * * = 1/k;
* * ** *** * ** *** = a*g;
* *** * *** = b*g;
** * * * * *** = c*g;
* * **
** * ** * *
* * ***** * * * *** * *
* ** * * ** * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
** * ******** * * *


*** * ** * * *


* *** ** *** * * *


* * ** ** * *** ***




* * ( ** )

* * ** * * *
* * * ** * * **** ** ** * * * * * * ** * ******
= * *
* = c -
* = f * b - a * e ;
* = 0 -
** ** *

*** * * **** * * * ** = 0 - * = 0 - * = * *
*
*
****** * * * ******* **

**




** * ***** * ** * * *
*** * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include * * *** **





int main()

{
* ** ** *** *** * * * ** * ***** * ***
*** * * * * * ** ** ***
** ****** *** ** ** * *
****** **** ** * * **








** **** * ****** * * *** %.6f %.6f",a,b,c);

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* **** **


* *
* ** * **** * ** * ** * ** * * *** * t = 0, a, b, c, a1 , *


* * * *** ** ** * ** * * ** ** **** %f %f *** * ** * * ****** * *** **** *




** *** * * * *** * * * ** * = y2 - y1 / * * y2 - x2 *
** *** ****** *** *** ** ** = * - / * * - * * *
*** ** ** ***** ***** = - * ** - * * *
* ** * **** * * ** = a / *
****** ** ** ** * = b / c;
**** * * * **** ** ** * *** ** *


* 0;
**
answered by (-105 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** ** *

int main (void)

{
* *** *** *** * * x1,y1,x2,y2;


* ** ** * * * ** ***** ** * a,b,c;


** *** * * * * * *** * ** *** *** %f * * ** **** * * ** **** * ** ******
* ***** * **** * ******
* * * * *********** ** * *******
** * * ** **** ***** * * * *** * *




* * * *** * **** ** ** * * ** *** %6f %6f",a,b,1);
* * *** *** ** * * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * ******** * * * ** * ** ** * *
* ** ** * * * ** * *** ** *
* ** ** ** ** * * * * * *** *
* * ** ** **** * * *** * **** * *** * *** **** *
** ****** * * **** *** **** ** *** * * ** ** *


* ** * * * *** ** * * * * (a-c!=0)
* ** ***** * **** ** *
* * *** * *** ** ** ** **
*** * * ** ***** *** * **** * * ** *
* ** ** * ** ** * * *** * * **
** *** ** * **** ***** *
** * * * ** ** ** (a-c==0)
* * ****** * * * * *
******* * ** * *** ** ** * * * *** ****** ** ** ** *
** ** * **** * * * * ** * ** ** *** * *** **
*** *** * * * ** * * *** * *** * * * * * ** **
* * ** * ** * ***** ** *
** ** * * * * *** ("%.6f ",e);
** ** * *** * ("%.6f ",g);
** **** *** ****** ("%.6f",f);






** *** ** * * **** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * *





int * ***

{
** * * * ****
*** * * %f %f ** * * * * * * *** ** *
* ** * - x2 == 0)
* *** ** ** *
*** * ** * ** * ** = x1;
* *** * * * * * ** * * = 0;
** * * * * ** * ** ** = -x1;
*** * * * * ** *** * ******* * %f * * ** * **
** **
*** ** * * if(x1 - x2 != 0,y1 != 0)
*** ***
** ** * * * = (y1 - - x2);
* * * * *** = y1 - (a * x1);
* * ****** * * = -((a * x1) + c) / y1;
*** *** * ** **** * * ** %f * * *****
*** *
*** ** * ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** ** ** **


** * * * **** *** * ****


* * ** * **** *** **


*** ***** ** * **




** * * ( )
*
* ***** ***
*** * ** *** * * ** * * * *** ** ***** *
= d - **
= c -
= f * b - a * e ;


* * * **

*** * * ** * * * * = 0 - * = ** - **



** * ** * * * *** ** ** *
* *
answered by (-276 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.53
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users