0 like 0 dislike
5.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.2k views

49 Answers

0 like 0 dislike
Hidden content!
*** ***** * *


* * * * * *****


* *** * ***


*** ********* *




* * * ( * * *
*
* * * *
* * ** *** * * * *** * * * * ** *
= d - *
= c -
* = f * b - a * e ;
= 0 - *
** ***
**
** * * * ** * * * ** ** = - * * ** *
**


* * ** * ** ** *
** ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * * * * * *** * *** * ** **
*** *** ** *** *** **** * *
** * **** *** * * * ** ** * * *
* **** ** * * ** ** *** * ***
* **** * * * ** * ** * *** * *** ** **** **


** * *** * ** * ** ***** * * (a-c!=0)
*** ** ** * ** * * *** ** *
* *** * **** *** * **** *** * ** ** *
*** * * * * ***** * * ****
** ***** **** ** ***
* **** * ** * * * ***** * **
* * * ** ** * * * * * * (a-c==0)
***** ***** *** **** ***
** * *** * *** **** *** **** * * ** *** *** *** *
* ** *** ** *** ***** * *** * ** ** ** ** ****
*** * **** ** ** *** ** * * * * * ***** * * ** ** * * ***
* ** ** ** * ** ** ** * * **
*** ** ******* ** ** ("%.6f ",e);
** * * * ** * ** ("%.6f ",g);
* *** ** * ** * **** ("%.6f",f);






** ** * * ** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include **** * * *



int main(void){


** ** * ****** * * * ax , ay ,bx ,by ,a ,b * * **


** * * ** * * * *** **** * **** ** * * **** *
* * ** ** *** * * * ***** * ** * * ****
** *** ** * ** * ** * * * * ** * * *** * * ** *******
*** * * * * *** * ** * ******** * * * ** * * **** *** * *** ***


* * *** * ** ** - bx) != 0){
* * * * * = (ay - ** ** **
** * ** * * * = -m*ax + ay;
* *** ** * ** *** = m;
*** *** * *** **** = -1;

 }
* * *** ** * * * * * *
**** *** * * **** ** * = 0;
* *** *** = 1;
** **** ** * * ** = -ax;
*


* * * ** **** * = a;
** ** * **** ** * = b;
* * ** **** * * * * * = c;


*** * ** < 0)
* * * **** *** * * = -i;
* * * ** * if (k < 0)
* **** *** ** * * * * ** = -k;


*** * * (i < 1){
* * ********* ******* = 1/i;
*** ** *** * * = a*g;
****** * * * * ** = b*g;
** ** **** * ***** = c*g;
** *
* ***** ** if (k < 1){
* * * * * * * ***** * = 1/k;
* * * *** * = a*g;
* * * ** *** = b*g;
** * ** * * * ** *** = c*g;
** *
** * * *
** **** * * * ** *
* **** ** * *** ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
** * * * * ** *


* * ** *** * * *


* * * * * *


* * ** ** ** * * *




* ( *** )
*
*** * ****
** *** * * * *** ** * *** ** * ** * * * ***
= * *
* = c -
* = f * b - a * e ;
* = 0 - *
** * **
*
*** * ** ** * ** ** = 0 - * = 0 - * = * *


* **** * ***** * ****
* * *
**




******* ** * ** ** ** *
** ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include * * *****





int main()

{
** *** * * * * *** * *** * *
**** ******** *** *** *
* * * ** *** * *** * ** ** ****
* *** ** ** * * * * *** * **








** * ** * * * * * ** * * * *** %.6f %.6f",a,b,c);

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* * ** *** *


* **
* *** * ***** * ** * * *** * ** * * * * t = 0, a, b, c, a1 ,


***** * *** ** *** ** * * * *** %f %f * ** * * **** *** * * ***** * *****




** * **** ** ** **** **** = y2 - y1 / * * * y2 - x2 * ***
** * * ** * ** * *** = * - ** / * * - ** *
* ****** * ** * *** **** ** = - * - * *
**** ***** * ** * **** * ** * = a /
* * ** *** ** * ** = b / c;
* * ** * * **** * * ** * * * **** ** * * *


** 0;
answered by (-105 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * *** * * *** ***

int main (void)

{
*** * ** ****** ** *** x1,y1,x2,y2;


* * ** * **** * ** ** *** a,b,c;


*** **** * * * ** **** ** * * * * ** %f ** *** * * * ** * * * ** * **** **
* * * * *** * ** **** ***
* ** ** * *** * *** * * * * *** ** *
*** *** * *** * * * *** * *




* * * * *** * * * ** ** * **** %6f %6f",a,b,1);
*** **** *** *** * ** * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
*** * * * ***** ** * *** * * * * *
* ** * ** * * * * * * ** **
*** *** **** ** * *** ********* * *
** ** * ** * *** * **** ** *** ** ***** * **** * ** **
* ***** *** *** * * **** ** **** *** * * *


* * *** ** ** * ** * ** * ** (a-c!=0)
* * ** * **** *** * *** ** * *
** *** * ********* * ** ** * *** *
* *** *** **** *** **** ******* **** * *
* * ******* * ** * ******* ** ****
** * ** * ** ** * * *
** * *** * * * * ** *** (a-c==0)
*** * * ****** * * ** ** ****
** *** * * * * * ** *** * ** ** *** ***
**** ** * * ** ** * * *** ** ** ** *** * * *
** ** ****** * * * ** *** *** * ** ****** * ****** * *
** * * * * * ** * ** * ** * **
* ***** **** **** *** * ("%.6f ",e);
** * * * *** ** ("%.6f ",g);
** * *** ** * ("%.6f",f);






*** * ********* * * *** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * *** * * * * *





int ****

{
* *** ** *** ***
******** **** * * * %f %f ** ** * * *** ** ** ** * * *
*** * ** - x2 == 0)
* *** * **
* * * * **** ** * *** = x1;
*** ** **** *** ***** = 0;
*** ***** * * * * ** = -x1;
*** ** ** * ** * ** * ***** *** %f ** ** * *
* ** **
* if(x1 - x2 != 0,y1 != 0)
** **
*** * * * **** * * = (y1 - ** - x2);
* * * ** **** *** * * = y1 - (a * x1);
*** ** *** * * = -((a * x1) + c) / y1;
* ** **** * * * * *** *** * %f *** *** * **
** *
** * * *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * ** *


****** * * *


** * * * * *


* ** * * * **




* * ( ** )
**
** * ****** *
* **** * **** * * ** ** * ******** * ** *
* = d -
= c -
* = f * b - a * e ;


*** *** *
*
** * * ** * * *** ** * = 0 - * = * * -



** * * ** ** ** * *
** **
answered by (-276 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.233
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users