0 like 0 dislike
3.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.9k views

49 Answers

0 like 0 dislike
Hidden content!
** * * ** * *
* * * * * * ***

int main(void)

{
******** *** * * ** x1,y1,x2,y2;
* *** * *** **** ** a,b,c;
* ** *** * ** * *** ** ** * ***** * * ** * * *
*** ***** **** *****
*** *** *** * * ** * * * * ** **** * * ** ** *** * = y2 - y1;
***** * * ****** **** * * ** *** * ** ** ** * = x1 - x2;
* * ** *** ** ** **** * ***** ** * **** **** = -x1 * (y2-y1) + y1 * (x2-x1);
* ****
* * ** * * ******* * *** *** ** %.6f %.6f",a,b,c);






** **** ** * ***** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ***** * * * **

int main(void)

{
* *** * * * * ** * *** * x1,y1,x2,y2;
** * * ** * *** * a,b,c;
** **** ** * ** ** * *** * ***** * ** * ** * ** * *
*** ** * * *
***** *** ** * * *** * * **** *** ** *** = y2 - y1;
* *** * * **** * * * *** * ** ** ** ** = x1 - x2;
* ** * * * ** ** * ** ** **** **** *** = -x1 * (y2-y1) + y1 * (x2-x1);
** * * * * * **
* * ****** ** * * ***** ** ** *** **






* *** * * ** ****** ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** * * ** * *


****



{
** ** y2, a, b, c;
** ******* * * ** * * *
** * ** * ** ****
**** * ** *** ** **
** * * * * * **



a = (y1 - y2) / (x1 - ** *

b = ** * / * **

c = ** * **
* * * ** * *** * * ** a);
* ** *** ****** b);
***** * * **** ** * *
* * 0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ** * * *** * * ** x1,y1,x2,y2,m,b,c;
*** *** **** * * * * n;
** **** ** ********** *** * * ** * ** ****** * *** * * ***** **** ** * ****
* * * * ** * * *

    {
* **** * * * ** ** ** * *** * *** * ** ** = (y2-y1)/(x2-x1);
* **** **** * ** * * * ** **** * * = 1;
** ** * * * ****** *** ** * ** ** **** ** ** * ** * = m * x1 - y1;

    }
* * ** ** * * * * ** * * if (x2<x1)

    {
*** * ** ** * ** ** ***** * * * ** **** * = (y1-y2)/(x1-x2);
* * *** * * **** ** **** ** * *** ** ** = 1;
** *** * * * * * * *** *** *** = m * x1 - y1;
* *** * * ** ** **
** * *** * * *** * if (y1 == y2)

    {
* * ** *** *** * **** ** ** * ** * * ** *** = 0;
* **** * * ***** **** ** ** * **** * ** * = 1;
* *** * * * ** * * * ** * * ***** * ** *** *** = -y1;
* ***** * ** * *** * * *
** ** ***** **** ** if (x1 == x2)
** * ** ** ** *** **
* *** ** * *** ** ** * ** * *** ** ** = 1;
** **** ** * * * *** ** * *** ***** * * * * = 0;
** * *** ******* * * * * ** ******* * = -m;

    }
***** ** ** ** * *** ****** *** *

    {
* * *** * ** * *** ** * * * ** ** ** * * ** * ** * * ** == b/n && m/n == c/n)
* * * ** *** *** * ** * * ** ** ** * **
* * * *** * *** * *** ** * *** ** ** ** * **** * ** * * * ** *** = m/n;
* ** * * * ****** *** *** ***** ** **** ** * * ***** **** * * * ** ** = b/n;
* ** ** *** **** * * *** ***** *** ******** ** * * ** * ** ** = c/n;
** * * ***** ** * ** * ****** * * *** * **
*** ******* * ****** ** *** *** * * **
** *** * * * *** *** * * **** ** *** **** **** *
* ***** ****** *** * ** ** ** ** * ***** * * * ***** * * *** ***** = m;
* * *** *** * * * * * **** * ******* * * ** ** *** * ****** * * * * * *** = b;
* ** * ** * ** * * * ******* * ******* **** * ** ** ** * * * ** = c;
** ** *** * *** * ** ** ** ** * * *****

    }
* * ** ***** * * * * * * ***** %.6f %.6f\n",m,b,c);
* ** * * *** ** *** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * ** * ** *** * * x1,y1,x2,y2,m,b,c;
* * ** **** * * ****** n;
* ***** * ** **** * * *** ** ***** ** * * *** ** *** * * * *
* * ** * * **** * ** *

    {
** * * * * * ** *** *** *** ***** *** ***** ** = (y2-y1)/(x2-x1);
** * ** * ** ** *** *** ***** *** ** ** * * ** * = 1;
* *** * ** * ** ** *** * ** * * *** ** * * * * = m * x1 - y1;
* *** ** ** * * * * *
* ******** ** ** ** if (x2<x1)
** *** ***** * ***
*** * * * *** ***** * ** ** * * * * ****** * = (y1-y2)/(x1-x2);
** * * *** * * * * * * ** * ** * * *** *** ** = 1;
**** * **** *** * ****** * *** ******* ** ** = m * x1 - y1;
** * ** * * * **** * **
**** ******* ** * ** *** if (y1 == y2)

    {
* * ** ** * ** ** * *** ** * *** * * = 0;
* * * *** * ** **** * **** *** ** * ** * = 1;
*** ** *** *** ** * * ** ** *** *** ** ** = -y1;
** ******* * * *
** ** ** * * * * * ** if (x1 == x2)

    {
* ** * ***** * ** * *** * * * **** * * * * = 1;
* * * * ***** * *** * ***** ** *** = 0;
*** ** ** * ** *** **** ** * ** * ** * ** ** * = -m;
**** ** * * *
**** ** ******** ** * ** * ** ** * * **

    {
*** **** ** * *** ** * ** ** ** * * * * ** * * == b%n && m%n == c%n)
* *** * ** * * * **** ** ******** **** **** *** * * *
* ** ** * * * * **** * * * ***** * * ** * **** * ****** * * * ** = m/n;
* *** *** * *** * * ** * *** * * *** *** ********** * * * **** = b/n;
** * * * ** ** ** * **** ** *** ** ** **** * ** * * * * ** *** * = c/n;
*** * *** ** * * ** *** * ** * *** * ***** * **
** * * ** * ** * ** * * ** * * * *** ** **
** **** * ** * * * * ** ** * ****** ** * **** * ** * * ****** * ** ***** * %.6f %.6f\n",m,b,c);

    }
* ** * * * * * **** * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include ** * ** **

#include ** * ** ** *

#include * * * ** ** * **



int main(void)

{
* * **** * * ** **** a1,a2,b1,b2,a,b,c;
* *** ***** ** * * * * * ** * %f %f ** **** * * * *
** * ** ** **** **
* * **** ********* * * * *
* ** * ** ******* *** *
** * * *** *** * ** ** ***** * *** * %.6f * * * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** * * * * ** * ***
* * * ** *

#include<math.h>



int main()

{
* **** * ** ** ** *** x1,x2,y1,y2,m,a,c0;
**** ** *** * * ** ** *** *** *** * *********
********** * * ** * * **** ** *** * *** ** ** *
** **** ** *** ** ** * **** * *** * ** ** *** * *
* * *** *** ** * ** ** ***** ** * * ** * **
* **** * * ** *** * = (y1-y2)/(x1-x2);
** * * ** ** * * * * * * **
* *** **** * * ** * * * * * * ** **
** ***** ** * ** * * ** * ****** * %f * * *** * * ** * ***

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
*** ** *** * * ***
* ** * * *

int main()

{
*** ** ** ** * * * * * x1,y1,x2,y2 ;
* * * * **** ** ** ** * * ***** * * ** * * * ;
***** * * ******* ** * a,b,c ;
***** ** ** * **** **** = y2-y1 ;
* ** * ** * * * = x1-x2 ;
* ** * ******* * = -((a*x1)+(b*y1)) ;


* ** * ** ** ***** * * * * %f ***** * ;


** * ** **** ** * * * 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** ** * * *** * * x1,y1,x2,y2,m,a,b,c;
** * * * * *** * ** ** * *** * * * ********* * * * * ** **
* * ** * * * * ** ****
**** ** **** * ** * **
* ** *** * * * ** * *** * ** * *** ** ** = (y2-y1)/(x2-x1);
* *** ** * **** * *** * * ** ***** * * ** = 1;
* ** ********** *** * ** * *** * ** ** **** * = m * x1 - y1;
*** ** ** * ** *** *
**** **** * ** **** * * if (x2<x1)
* *** * **
* * ***** * **** * * ** ***** *** * *** = (y1-y2)/(x1-x2);
** * * ** * * **** *** ****** * * * * = 1;
**** ***** * * *** * * ** ** * ** *** * *** = m * x1 - y1;
** * * ** * * * ******
*** *** **** * * * *** if (y1 == y2)

    {
******** * * ** ** ** ******** ** * * ** * = 0;
* * * **** ** * * * *** **** * = 1;
* ** ** * * *** * * **** * *** ***** ** * = -y1;
** ** * * * * ** *****
* **** ** ** *** if (x1 == x2)

    {
** * ** ** * * * * * **** * *** * * * * = 1;
* ** *** * * **** **** **** ** **** * ****** *** * = 0;
** **** * * ** ** * * ** * ** ** * ** * * ** * = -m;
*** * * ** * **** *
**** ** ** ** * **** ** ** * * * %.6f %.6f\n",m,b,c);
***** *** * ****** ** * * * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
** *** **
*** * ** * *** *
* * **
* i * ***
** *** * , b , c , ******
* **** ; i * ; *
** * * *** * , **** * );




** == * *

{ ** * * * ****** = 1;
** ***** * *** = - *

}


*** * ** * * * * ** *

{

a * * *

c = ** ;

b = -1 ;

}
* * == 0)
* * *** 0 ;
* *
** * * ** ** 0 ;
* * * ** *
* ** * ** *** 0 ;
*** ** ** ** * *


* ** ** * *
*** ****** * * * * * * **** *** * * * * * h ** , *




**** * * * * * *



** * * * * * **** ** * * a , b ,c *










* 0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.194.171
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users