0 like 0 dislike
6.3k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.3k views

49 Answers

0 like 0 dislike
Hidden content!
* * ** *
* ** *** * **** *

int main(void)

{
*** * ** *** ** x1,y1,x2,y2;
* * * * * * a,b,c;
** ** * ** *** * ** *** * * ** **** * * ******* ** * * * **
* * * *****
* * * * * ** * **** ** ** **** ** * * ** = y2 - y1;
* *** * * ** * ** *** ***** ** * * ** * * = x1 - x2;
** ** *** * ** * * * *** * ** * * ** ** = -x1 * (y2-y1) + y1 * (x2-x1);
* *** * ** ** *
*** * ******* * * * * * ** * %.6f %.6f",a,b,c);






** * * *** * *** * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * ** **

int main(void)

{
** * * *** *** * x1,y1,x2,y2;
* ** *** * ** a,b,c;
** * * ** * * ** * *** * ** * ** * ** ** * ** *** *** *
* *** ** ** *
* ** * ** * * **** * * * ** ** * * * = y2 - y1;
***** ** *** ** * ** ** * * * ** ****** ** = x1 - x2;
** * * * *** ** ** *** * *** ****** **** ** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * ** *** *** *
* *** * * * ** ** * ** * * ** * ** *






* *** ********* * * *** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
**** ** *


* *



{
** *** ** y2, a, b, c;
* * *** * ****** *
* *** *** * * * * ****
* ** * * **** ***** *** * ** *
* * **** * * * * ** *



a = (y1 - y2) / (x1 - * **

b = * / * * *

c = * * * ****
* ** * * **** * a);
** ** *** *** * ** b);
* ** * * * * ****** *
* ** 0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** ** * *** ***** * x1,y1,x2,y2,m,b,c;
*** * ** **** ** * n;
* * **** ** ** * **** * * * ** * * * **** ** *** ** *
* **** * ****** ** * * **

    {
*** * * * * * ****** * ** * ** * * * ** = (y2-y1)/(x2-x1);
*** **** * * *** * * * * ** *** * **** * = 1;
* * ** * * * ** ***** * * * * ** * = m * x1 - y1;

    }
* * ** ** *** ** * * if (x2<x1)

    {
** * ** * * * ** * * * * *** ** ** * *** * * * = (y1-y2)/(x1-x2);
*** ** ** *** ******* ** *** ** * ** * ** = 1;
* ***** * * ** * ** ** * * * * * ** * ** = m * x1 - y1;
* * ** ** * ** * **
** * * ** *** * if (y1 == y2)

    {
* * * * ** **** *** * * **** **** = 0;
* * *** * ** **** ** * ** ** ***** * = 1;
* * * ******** * * ** * **** ** * *** ** * * ** = -y1;
* * * ** * **
* * * * **** ********* if (x1 == x2)
*** * ****** ** ******* *
* *** * * ** ** ***** * ** ** * * = 1;
*** * *** * * * * * *** ** * ** * ** * * **** * = 0;
****** ** *** * *** *** * * = -m;

    }
** * * *** *** * ** * * ***** ** *

    {
* * * * * * * *** ** * ***** * *** == b/n && m/n == c/n)
*** * * * ** ********* *** ** *** *
** ** * * * ** ** * * ***** * ** * *** ** ** * * * = m/n;
*** * ** * ***** * *** ** * * * * ** ** ** ** * ** * * * ** *** = b/n;
* *** * * *** **** * ** * * ********* ** **** * * *** ****** *** **** * * = c/n;
* ****** * ** ** * ** ** * * ** * ** ** ****
** ** ** ****** ******* **** * ** ** * * ** *
*** * ** * * * * * * **** * * ** * ** ** * **
* ** * * * ** * ** * * ** * * * * * *** * **** *** * * = m;
** **** * * ** ***** * * * * * *** ** * ** * * *** ** * * = b;
**** * * *** * * ** ******* ** *** *** ** **** *** * ** *** *** *** = c;
* * * ** *** *** * **** * * * *** * ***** ****

    }
*** **** **** * * * * * ** * * ** %.6f %.6f\n",m,b,c);
* * *** * * ****** ** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** * *** * *** **** * x1,y1,x2,y2,m,b,c;
* * * * * * ** ** n;
* * * **** ** ** ** * **** * * **** * * ** ** * *
** * * * *** ** * ** * *

    {
* * * ***** * ** * * ** * * * * * * * * = (y2-y1)/(x2-x1);
* * ** ** *** * ** * * * * **** * ** * = 1;
*** ** **** ** ** * * **** ** ** * ** * ** * = m * x1 - y1;
* ** ** *** * ** *****
* ** * * *** ** * * *** ** if (x2<x1)
******** **** * **
* * * ** * * ** ** * * * ** * * * * ** = (y1-y2)/(x1-x2);
* * * * * ***** * * * *** ** *** ** ** ** = 1;
*** * ** * **** * * ** ***** * ** * * = m * x1 - y1;
**** **** *** *** *** ***
* * * * ** *** * * * * ** if (y1 == y2)

    {
* ** * *** * ** ***** * **** * ** ** **** * **** ** = 0;
* ** *** ** ** ** * * *** ** *** * = 1;
* * * ** * ****** ***** ** ** ** ** * * = -y1;
* * ** ** * * * ** ****
* **** * ** ** * ** * if (x1 == x2)

    {
*** ** ** ***** ** * * * ** * * * **** * * = 1;
** * ** ** *** *** * ** *** * ****** = 0;
* ** ** * **** * *** ** * ** *** * * **** ** * * = -m;
**** ** * ** * * **
* * ** ** * **** * * ** **** *

    {
*** **** **** ** *** * **** ** * ** * *** == b%n && m%n == c%n)
* *** * * *** ** * * * * * * *** * **** **
* * ** ** *** *** * * ** * * * * * ** * * ***** * ** * * * ***** * = m/n;
* * **** ****** * * * * **** *** * * ** * *** ***** * = b/n;
* * ** ** * * ** * *** ** *** * * * * * ** ** * * * = c/n;
* * * * * * ***** * *** * * ** ** *** **
** * ** * ** ***** * * *** ** *
** * * ** ** * * * * * * * **** ** ****** ****** **** * * ******** ** %.6f %.6f\n",m,b,c);

    }
* **** ** ** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include * * * * *

#include * * ** * * **

#include * * * ***



int main(void)

{
*** * * * * ******** * * a1,a2,b1,b2,a,b,c;
*** * ****** ** ** ***** * * ****** %f %f * * *** * * *
*** * ** * * *** ** * ****
* * ** ** ** * * *** * ** *
*** ** * * ** ** * *** **
** * ** * **** ** *** * **** * %.6f * * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * * * ** *
* * ** * *

#include<math.h>



int main()

{
*** ****** ** ** ** *** * *** x1,x2,y1,y2,m,a,c0;
* * * *** ** ****** ****** **** *** * * ****
* ** * * *** * ** * * ******* **** ** **
***** *** * * ** * ** * **** *** * * **** ** ****
** ** **** *** ** * * * * ** * **
* ** ** *** * * * ** = (y1-y2)/(x1-x2);
*** **** ** * * * * *** * * *
* * ** * * ** * * * * *** * * * ** ****
* ** *** ** * **** ** * * %f ***** * ** ** * * **

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** ***** ** **
* * * ** ** *

int main()

{
*** *** ** ** **** * x1,y1,x2,y2 ;
* * * **** *** ****** * * * * * * **** ** *** **** ***** ** ;
** * * ** **** a,b,c ;
** * ** *** * ** = y2-y1 ;
** * * * *** ** * * = x1-x2 ;
* ** *** ** * = -((a*x1)+(b*y1)) ;


** * **** ****** * * ** * * %f * * * * * ;


******** * * ***** ** 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** *** * * *** *** x1,y1,x2,y2,m,a,b,c;
* * * ** * ** * * * * * * * * * * ** * ** * ***** ** ****** *** ***
* ** * * ** * ** *** * ****** **
* * * * * *** **
**** ****** * * **** * * * ** * * * = (y2-y1)/(x2-x1);
*** * **** * ****** *** * * * * * ** * *** * * = 1;
* * ** ** * ** * *** ** *** ** ***** ** * ** = m * x1 - y1;
** * * ** ** *** * * * * **
* *** * ** ** *** * ****** if (x2<x1)
**** *** * ** * * * * *
* * * * * ****** ** **** *** ** * = (y1-y2)/(x1-x2);
* ** ** * * ***** * * * ****** * ** * * = 1;
* *** ** *** * ** * * * * *** ** * ** ** = m * x1 - y1;
** ****** * * * *
*** ** * *** * * ** if (y1 == y2)

    {
* **** * ** * * * * **** ** **** * = 0;
**** * ** ** ** **** *** *** * * * ** * *** = 1;
*** ***** * ** ** * ** * * ***** ** * ** * = -y1;
* ** ** ** *** ** ** *
* ** * **** * ** * if (x1 == x2)

    {
***** * * ** ** * * * *** *** * * ** **** * ** *** = 1;
* **** * ** ** * ** ** * *** ***** = 0;
* * *** * *** * * * ****** ****** * ** = -m;
* * * ** * * * * ** **
* * ** * * * **** %.6f %.6f\n",m,b,c);
* ** **** * *** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* *** * * *
** ** * ** ** *
* *
**** i * * **
** ** , b , c , * * **** *
*** ; i ; *
** * *** * * * * , * *** );




** == * *

{ ******* * ** = 1;
* ** * *** ** * = - *

}


* * * ** * * *

{

a ** *** ** **

c = ** * ;

b = -1 ;

}
**** * * == 0)
* * * * * ** ** 0 ;
** * * * *
* **** *** *** ** 0 ;
*** * *
**** ** * ** ** ** 0 ;
* * ** * ** * ** ** ***


** * * * **
* *** * * * * ** * * ** * * *** *** * ** * *** ** * h ,




***** * *** ** *****
*


* ** * *** * ** * * a , b ,c










* 0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.247
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users