0 like 0 dislike
3.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.4k views

49 Answers

0 like 0 dislike
Hidden content!
* **** * * * *
*** ** **

int main(void)

{
*** *** * **** ** * x1,y1,x2,y2;
*** * ** * * *** a,b,c;
** * ****** * * ** * ** * * * ** * * * * *** * * ***
* * ******* *** *** *
** *** *** *** ** *** * * ** **** ** * ** = y2 - y1;
** * *** **** * * ** ** ** ***** * ** * *** = x1 - x2;
***** * * * **** * ** ** ** * * * * ** * = -x1 * (y2-y1) + y1 * (x2-x1);
* ** * **** **
* ** *** ** *** *** * *** * *** %.6f %.6f",a,b,c);






* **** * ** * * ** ** * ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** * **** * *

int main(void)

{
** ** * * x1,y1,x2,y2;
** ***** ** a,b,c;
* ** ** * * *** * * * ** * *** * ****** * ** ** * * ***** *
** * * * **
**** ** * * *** * * * ** * ** * *** * = y2 - y1;
**** ****** * * * ****** * ***** * ** * * = x1 - x2;
* ** * * ** ***** **** ** ** *** ***** *** * * * * = -x1 * (y2-y1) + y1 * (x2-x1);
**** * * * ** *
**** * ** * * * ** ** * * **** * ** ** **






* * * * * ** ***** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** * * * *


* * *



{
** * * y2, a, b, c;
** * * * * *** * ** ** * **
* ** * ** ********
*** **** ** *
* * * ** * * ** * *



a = (y1 - y2) / (x1 - ****

b = ** ** / ** * *

c = ******* *
** * **** * a);
*** ***** * * * * b);
* ** ** * * * * *
* ** 0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ** * *** * * * * *** x1,y1,x2,y2,m,b,c;
** * * * * * **** n;
*** ** * * ** *** ** ** ** * * * *** * * ****** ** ** **
* * ** * *** * *** ** *** **

    {
**** ** * ** * * * * ** *** * * *** = (y2-y1)/(x2-x1);
** * * * * ** *** ****** * ****** ** ** * = 1;
*** ** *** * * * ** ******* * *** * ** = m * x1 - y1;

    }
* ** *** * * * if (x2<x1)

    {
* * *** * * * * * * * * ***** **** * ** * = (y1-y2)/(x1-x2);
********* ** ** *** ** *** * *** **** *** * * * = 1;
* * * *** *** ** **** **** ** * ** * = m * x1 - y1;
* * ** * **** **** **
* * ** * ******* *** *** * if (y1 == y2)

    {
* ** *** **** *** **** ** * * ***** * ** = 0;
* * * ** * * ** *** * * * ** * **** *** * ** = 1;
* *** * * * ** **** * * ** ** * *** ** * = -y1;
* ** * * * ** **** * * *
* * ** ******** * if (x1 == x2)
* **** **** * * * *
**** * * *** * * * * *** * **** *** = 1;
* * ** ****** **** * * ************ * * * * * * = 0;
*** * ** ** ** * * * ** * *** * ** = -m;

    }
* * * * *** * **** * **** ** *** ****

    {
* ** *** ** * * *** * * * ** == b/n && m/n == c/n)
* * * * * ** * ** * ** * * * * *
** * ****** * * ** * *** ** *** ** * * * ** * ** * * * = m/n;
* ********** ***** ** *** * * ***** ** * * **** * ** = b/n;
** ** *** ** **** ** *** **** * * ** * ***** **** * * = c/n;
*** ****** ** ******* *** ** * * ***** * *
**** * ** * ******** ***** ** ** ************ *
*********** ** * * * * * *** * * ** *** *
** * * ** ** * **** *** * *** * * * *** * * * ** = m;
* ** * *** **** ***** ** * * * * * * * *** ** ** ** * ** ** = b;
* ** * * * *** ** * * * * * *** * * * * * * ** *** * * * = c;
** *** * * * *** * *** * ** * ** * **** * ** * *

    }
* * * * * ** ** * * * * * *** %.6f %.6f\n",m,b,c);
** * **** * * * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * * * ***** * * x1,y1,x2,y2,m,b,c;
* *** * * * * *** *** n;
**** ** ***** ** **** * ** * ** ***** **** ** ***** ** ** * * **
* * * * * **** * * * *** ***

    {
** * ** * *** * ***** *** ** ** *** * * = (y2-y1)/(x2-x1);
*** * * * * * * ***** * * * ***** * ** ** = 1;
**** * * ** * * *** **** * * * ** *** * = m * x1 - y1;
**** *** *** *** * ** **
** * * * ** ** ****** if (x2<x1)
* ** * * ** * * * * *
* **** * * ** * ** * * ** * **** * *** **** = (y1-y2)/(x1-x2);
** * *** * **** * * * * * * ** ** ** * ** * ** = 1;
** *** ***** * ** * **** * ** * ***** = m * x1 - y1;
*** * *** ***** **** **
*** **** ** **** ***** * if (y1 == y2)

    {
*** ** ** ** **** * ****** ** * = 0;
** **** ** ** * ** * ** ** * * * ** * = 1;
* ** * * * * * ** * ***** ***** = -y1;
** * ** * ******* **
** * * * *** * ** ** ** if (x1 == x2)

    {
*** ** * * * *** * * * * ** **** * * * = 1;
* *** ** * ** * * **** ** * ****** **** = 0;
* * ** * ** *** *** * * ** ** * ** * ** * *** ** = -m;
** * * * *** ** * * *
* * * * * *** ** *** * ** * **** *

    {
* ** ***** * * **** * * *** * * ******** * * * * == b%n && m%n == c%n)
* ** **** * * ** *** * ** ** * *** * ******
***** **** * * ****** * * ******** *** * * * ** **** * *** * * *** ** = m/n;
* * ** * ** *** * ** * * * *** *** * ** * *** * *** * *** * * = b/n;
* * * * *** * *** * * ** * * * ** * **** ** * * ** * * * * ** ** = c/n;
** * ****** * ***** * * * * * * * * *
*** ** **** *** ** ** *** *** * * * * * *
* * *** **** ******* * * * **** ** ** * ** *** * * ** * * ** * ** ** * ** * %.6f %.6f\n",m,b,c);

    }
***** ** **** *** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include *** * **** * **

#include * * * * *** *

#include ****** ** * *



int main(void)

{
*** *** * *** * **** a1,a2,b1,b2,a,b,c;
* ** * ** ** *** * *** ****** * %f %f * * * *
****** ** ** *** *** *
* ** * ** ** ****** ******
* ** * ** * *** * * ** **** ******** *
** *** ** ** ** * *** * * ** * %.6f * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** ****** *
* *** * **

#include<math.h>



int main()

{
* ** ** * **** ** *** * * * x1,x2,y1,y2,m,a,c0;
** * **** ** ** ****** * *** * * * * * * *
**** ** **** * * *** * *** * ** * * ***
* ** ** * * * * ** ** * **** * ***** **
* ** ******** * ** **** *** *** * * * * ** **** *
* * ** ** * * = (y1-y2)/(x1-x2);
* * * **** ** * * * **
* * **** *** ** * ** * *** * * ** * **
** ** ** ** * ***** * ** * %f * * ******* *** *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** ** ** **
* *** * * ***

int main()

{
** * * * ** * ** x1,y1,x2,y2 ;
* * * ** * * * ****** ** * * ** * * * * ** * * * * * ;
* * * *** * ** a,b,c ;
* * * * *** ** = y2-y1 ;
* ** ** * * ** = x1-x2 ;
* *** * * *** **** = -((a*x1)+(b*y1)) ;


**** ** * * **** * ******** %f * ** * * * ;


* *** * ** * * * * 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* *** * * *** * * ** * * x1,y1,x2,y2,m,a,b,c;
* * ****** * * * ** ** *** * * *** * * * ** ** ** **** ***
*** *** ** ** ** ** * **
* * * **** * * *
* * **** * *** * * * * * *** * *** = (y2-y1)/(x2-x1);
* ** ** ***** *** ** *** ** ** **** * **** = 1;
******** ** * ** * ** ** * * ** * ** ** = m * x1 - y1;
* ** * * ** *** **
* **** * * * * * if (x2<x1)
***** ** ** * * ***
*** ** ***** ** * * *** * * ** ** **** * ** * ** = (y1-y2)/(x1-x2);
* * * * * *** *** **** * ** * ** * **** * = 1;
**** * ** ** ** ** *** * *** * *********** * * * = m * x1 - y1;
*** * *** *** ** ** * *
** *** ***** **** ** **** * if (y1 == y2)

    {
**** **** **** ***** * * ** * * * ** * = 0;
**** * * ** * ***** ** * ** ** ** * * ** * = 1;
*** * * * ** *** *** * ** ** * ** ** ** ** = -y1;
* **** * * ** ***** *
**** * ** * ** * if (x1 == x2)

    {
* * ** * *** * *** ** * * * * *** ****** = 1;
* ***** *** * * ****** ***** * ** *** **** = 0;
* **** ** *** * * **** ** **** *** * ****** * = -m;
*** *** * * *** * *
** * * *** ** ** * * * ** * * * %.6f %.6f\n",m,b,c);
** * * *** * * ****** * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* * **** * * *****
** ***** * * ** *
* * *
* i * * **
** * , b , c , ** * *****
* * * ; i ** * ; ***
* * * *** ** * * , **** * * );




* * ==

{ *** * ** **** = 1;
** ** ** ** * * * = - **

}


* **** * * * ** ****

{

a *** *** * ***

c = * * ** ;

b = -1 ;

}
*** == 0)
* ** * ** * * 0 ;
* * **
** * **** * 0 ;
** **
** ** ******* * * ** 0 ;
*** ** ***** * ** *


* * * * ****
* *** *** ****** * * * *** * * * *** * h , * *




* *** **** * ** ** ** * * **
*


** * **** ** **** ** a , b ,c










* 0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.2
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users