0 like 0 dislike
5.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.1k views

49 Answers

0 like 0 dislike
Hidden content!
*** *** ** ** * *
* * **** * **

int main(void)

{
* *** * * * * **** x1,y1,x2,y2;
* * * * *** *** * ** a,b,c;
**** * * * *** * * *** *** ** *** * * * * *** *** ***
***** * * ***
** * ** * ****** **** * * ** *** * * * ** * = y2 - y1;
* * * ****** * *** * * ** ** *** * *** = x1 - x2;
* * * * * * * ** * ** * ** * *** * ** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * ***** * *
** * ** ** ** *** * * * * * %.6f %.6f",a,b,c);






** **** * ** * **** * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** *** *** * * *

int main(void)

{
*** * ** * ****** * x1,y1,x2,y2;
** * * ** **** * a,b,c;
* * * *** ** ***** * *** ** * *** ** **** * ****** *
** * * * * *** *
* * *** ***** * ** * * * ** * * * * = y2 - y1;
** * * ******* ******* ** ** * * ** *** = x1 - x2;
** ****** * * * * ** * * * **** ** ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** *************** *
* ****** ** * * *** ** * *** ** * * ** **






* * * * * * ** ** * ** ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* ** * *** * **** **


* * ** *



{
* * ** * y2, a, b, c;
* * ** *** ** * ** ***
**** **** * **** ***
* * ** * *** ** * **
* * * *** **** * ***



a = (y1 - y2) / (x1 - * ***

b = *** / * *

c = * * **
* * *** * ** a);
* **** ******* b);
* * * ** ** *
** 0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** * * * * * * ** x1,y1,x2,y2,m,b,c;
* *** ** * * n;
* * * * * * ** * **** * * * * * * ** **** * **** *
* * **** *** ** * * ** ** * * **

    {
* ** * ** * * ** ** * * * *** * * * = (y2-y1)/(x2-x1);
******** ** * * ** *** *** *** ** * *** *** ** * * = 1;
* * *** * * * * * ** * * ** * ** * ** * = m * x1 - y1;

    }
** ****** *** ****** if (x2<x1)

    {
** * * **** * * **** ** ****** * * * * * *** = (y1-y2)/(x1-x2);
* ** * ** * * **** **** * *** **** ** * ** * = 1;
** * * ** *** *** **** ***** ** *** * ****** ** * = m * x1 - y1;
* * * *** ** * * * *
* ****** ***** * ** * if (y1 == y2)

    {
** *** ** ** * * * * ***** ****** **** * ** = 0;
* ** * * * *** *** * *** ** ** * **** = 1;
* * * * * ** * * ** * * *** **** = -y1;
* ** ** ** * * * *
** * * ** * * *** if (x1 == x2)
* * * * * * * * **
*** *** ** ** * ** **** * * * **** ** * * **** * = 1;
* * * * ** ******** * ** * * ** * ** **** * = 0;
* * ** * ** ** **** * * * * * = -m;

    }
* * * * ** * **** *** ** * * ** *

    {
*** ** ** ** ****** ** * * ** * *** ** ** ** * == b/n && m/n == c/n)
* *** * *** *** ** *** *** ** * * *
* *** ** * * * * ******* ** ** *** **** ** * ** ** ** * * = m/n;
* *** **** * * ** * ** * ****** ** * *** ** * * *** * * * *** *** = b/n;
*** * * * **** ** * ** * * * * * ** * ** *** * ** *** * = c/n;
* ***** * * * *** ** * *** * ** ** * ****
* * ** * ** * ** * * * * * *** * ****** ***
** * * * * * * * * * * **** * * ** ** ** ***
** * * ** * * * * ** * * * * ***** ** * ** *** ** * ** **** *** = m;
* * * * ** * * *** * * * ** *** **** *** * *** * *** *** * * = b;
*** **** ** ** ** ** * * * * ** * ** * * * * * * **** * * *** * = c;
* * * * ** * * * *** ** ** **

    }
* **** * * *********** ** ** ** %.6f %.6f\n",m,b,c);
**** * * * *** **** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** *** * *** ** * x1,y1,x2,y2,m,b,c;
* *** ** * * * * n;
*** * ** ***** **** *** ** * * * * *** * * *** * *** *
*** ** ** ** ** ** * * * * * **

    {
** * * ***** ******* ** ****** * ** **** ****** * * = (y2-y1)/(x2-x1);
** * * * ** ***** ** * * * * ** * * * **** * = 1;
******* * * ** ** * **** *** *** * * * * = m * x1 - y1;
* ***** ** ** * * * *
**** * ** *** ** * ** * * if (x2<x1)
**** * * *** * * *
* ******* * * * * ** ** * * *** * * *** * = (y1-y2)/(x1-x2);
* * ** ** * * * ******* ** **** *** * ** * ** = 1;
** * **** ** * * * *** * * * * * ** ** * = m * x1 - y1;
* * ******* ***** ***
* * * * ****** * if (y1 == y2)

    {
*** * * ****** * ** * * **** ** ** ** ** * * = 0;
***** * * ** ** **** * ** * ** * ** ***** * = 1;
*** *** ** ** * * * ** *** * = -y1;
* ** ** * ***
** * ** ****** ****** ****** if (x1 == x2)

    {
** **** * * * * * * * ** * * **** * * ** * * = 1;
* * * *** * * * * ***** * * ** ** * * ** = 0;
****** * * * * * *** *** ** ** * * **** * * = -m;
* * * ** * ** *** * *
* *** **** **** ** * *** * ** ***** *

    {
** * * * * * * ****** ******* * * * * *** *** * * * == b%n && m%n == c%n)
** * * ** * * * ** * ** * **** ** ** ** ** * * * **
** ** * *** *** * * * ** ** * * * ** * *** * * * * ** ** = m/n;
** ** * ******* ** *** * * *** * ******* * **** * * * = b/n;
* ** ** * ** * * * * * ** *** * * *** *** ** ** = c/n;
* ** * *** *** ** ***** ** * * * * *** ****
****** **** * * * * *** ** *** * ****
***** * * * ** * ** **** * ****** ** *** ** * ** * ****** ***** * * %.6f %.6f\n",m,b,c);

    }
** ** **** *** *** * ** * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include ****** ** * **

#include * *********

#include **** *** *



int main(void)

{
** ** * * *** * ** ** * a1,a2,b1,b2,a,b,c;
* ** ** * **** **** ** ** ***** %f %f * ** * *** ** ***
* * * ** * ** ** *
* **** ****** *** *** * *
* *** * *** * * ** *** *** * ****** ******
** ** * * ****** ** ******** %.6f * * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** **********
* * * * * **

#include<math.h>



int main()

{
**** * * ********* x1,x2,y1,y2,m,a,c0;
* ** * * * * * * * ** * * * *** * * ** *
** ***** **** * * ** *** ** * * ** * **** ***** * **
** ******* * ** **** * *** ** ** ** **** **
* * ** * * * *** *** ***** ** ** *** *** * *
* **** * * ** * * = (y1-y2)/(x1-x2);
** * * ** * * * ** * * * * * *** * * *
** ** ** * ******* * *** * * *** *** *
** ** * ***** * ******* * * * * %f * * *** ** * **** * **** *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * **** * ** **** * *
** * **** ****

int main()

{
* **** **** *** x1,y1,x2,y2 ;
* *** * * * * *** *** ** ** * * ** *** ** **** *** * * * ** *** * ;
** * * ** * ** a,b,c ;
* ** *** * * * * ** = y2-y1 ;
*** ** *** * = x1-x2 ;
*** * ** ** **** * = -((a*x1)+(b*y1)) ;


* * * * ** * **** ** ** **** %f * * *** ****** ;


**** *** * ** 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
**** * ** * ** ** ** * * x1,y1,x2,y2,m,a,b,c;
* * * * * * ********* * *** * * * * * *** * * * ** ** **
** * * ** * * * ** *** * **
* * * * * ** * * *
* * ** ** ** ******* ***** * *** ** *** * = (y2-y1)/(x2-x1);
*** ** * ** ** * * * * *** ** **** * = 1;
*** * * * * ***** ** * * *** ** ** * * * * = m * x1 - y1;
* * ** ** **** * * *
* **** **** ** * **** if (x2<x1)
***** * *****
* ** * ** **** ** ** * * * * ****** ** = (y1-y2)/(x1-x2);
* ** *** * ** * ****** * * * *** * * ***** = 1;
* * **** * ** ** **** *** * ** * ** ** ** ** * = m * x1 - y1;
* * ** * ** ** ** **** *
** * * * ** *** * *** *** if (y1 == y2)

    {
*** ***** ** * * * *** ** *** **** * * * = 0;
** * * * *** ** ** ** ** ** ** ** * * * = 1;
* ** ****** **** *** *** ** * ** * * = -y1;
** * * * *** * ****
* * * * * *** * ***** if (x1 == x2)

    {
* * * * *** ** * *** ** * * * ** * * * * *** = 1;
* ** * ****** * *** * ** ***** ****** ***** = 0;
**** **** *** * ***** * * ** ** *** * = -m;
* ***** *** *** ***** **
**** * ** * * * **** ** * * ** %.6f %.6f\n",m,b,c);
* ******** **** * * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* * ** * * *
* * * *** *
** * *
** i ** * ***
** * * * , b , c , **** * *** *** *
; i ** ; *
* * ** ** * * , * * * * );




**** == * *

{ **** *** * = 1;
** * ***** * * ** * ** = - ** *

}


* * *** ** ***** * *

{

a * * *** * * * *

c = * *** ;

b = -1 ;

}
** * == 0)
* * ** * *** * * * 0 ;
* * * *
* *** * * ** * * 0 ;
** * * *
**** * *** * * * 0 ;
** *** * * ** ** * * *


** ** ** * *
* * * **** * * * * ** ** *** ** ***** h ,




*** ** * * ** * ** * * *
***


* ** * * *** ** *** a , b ,c **










*** * 0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.52
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.8k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users