0 like 0 dislike
5.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.1k views

49 Answers

0 like 0 dislike
Hidden content!
* * ** * * * *
** ***** * ** **

int main(void)

{
**** ** * *** * x1,y1,x2,y2;
***** ** *** **** * ** a,b,c;
*** ** *** * * * * ** *** ** * * * * * **** *** * ** ** * *
*** ** *
*** * ** * * ** *** * * * **** ** * * = y2 - y1;
*** *** * * * **** **** * * **** *** *** ** ** ** = x1 - x2;
****** * *** *** ** * ** ******** * ***** = -x1 * (y2-y1) + y1 * (x2-x1);
** **** ** *
* * * * * ** **** *** * ** * * %.6f %.6f",a,b,c);






* * ** ** *** *** ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** * * ** ***

int main(void)

{
** ** ** ***** * * x1,y1,x2,y2;
**** * ****** **** a,b,c;
* ********* * ** ** ** * ***** * * **** ** ***** ** ****
* * **** **
** ** * * * * * ** * * **** * * ***** = y2 - y1;
* * * *** * *** * * * ** * ** * *** * ** = x1 - x2;
** * * ** ** ** **** * ** *** ** * ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** ** **** *
* *** **** ****** * ** * *** **** * ***






* * * *** * * ** * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** * * ** ***


* * *



{
** * * y2, a, b, c;
* * ** ***** **** * *
** * * * * ** * * * ** *
** **** * *** ***** ** * ***
* *** ** **** * * * *



a = (y1 - y2) / (x1 - * *

b = / *

c = ** **
* * * **** * *** a);
*** * ***** b);
** * ** *** *
* ** 0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** * * * * * x1,y1,x2,y2,m,b,c;
* * ***** * * * * n;
** ** * * * ** ***** * * *** * * ** * ** * * ***** *
* **** *** * ** ** **

    {
* * * ** ** * * *** * ******** * *** ** * * ** = (y2-y1)/(x2-x1);
* *** * * * * *** **** * ** *** *** * ***** = 1;
**** * ******* *** * * * ** * * * *** ** = m * x1 - y1;

    }
* ** * * ** * ****** ** if (x2<x1)

    {
*** * * * ** ** **** * ********* * **** ** * * ** = (y1-y2)/(x1-x2);
**** * * ***** * ****** **** **** ** ** * * * = 1;
* ** * * * * ** *** * ** * ** * * * *** = m * x1 - y1;
* * * * * ** *
**** **** * **** * * ** if (y1 == y2)

    {
* ** ***** ** * * * ** *** ** **** * *** * *** = 0;
*** * * **** * *** * * * *** * * * ** * = 1;
** * ** *** ** * ** ** ****** * ****** *** = -y1;
****** * ** * *
**** * * **** **** ******** **** if (x1 == x2)
* * * * **** * **
* * ** * ***** * * * ** *** * **** * = 1;
*** ****** **** ******* * * ** * ** * * * = 0;
*** ** * * * ** * *** ** ***** * **** * *** = -m;

    }
*** * *** ** * * * * ** * * * * * ****

    {
* ** * ** *** * * *** * * * * ** * * ** * == b/n && m/n == c/n)
** * * * * *** * * * * **** * * * * * * ** ** *
* * * * ** * ** ** * ** * * * * ** * ***** * ** * * * * * = m/n;
* *** **** * **** * * * *** * * ** ** ** ** * **** * * ** * **** = b/n;
***** * ** * * * ** * *** ******* ** * * **** * ** * ** * * = c/n;
* * * ***** *** ** * * *** * * * ** * * * *
** * * ** * *** ** * ** * * ** ** *** * *
** ****** **** * **** **** *** *** ** *****
** ** * * * ** **** * *** * * * *** **** *** * * * * = m;
**** * * * * * ** * * *** ** ** *** * * * * ** *** * * ** ** = b;
** * ** * ** * ***** ******* ** * * * * *** * * ** *** = c;
***** *** **** ***** *** ** **

    }
* * * ** * * * *** ** ** ** %.6f %.6f\n",m,b,c);
* * ** *** * **** * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* *** * *** * **** x1,y1,x2,y2,m,b,c;
*** * * *** **** * *** * * n;
* ** ** * * * ** **** ** ** * * ** ** * **** **** * ****
* ** ** * * * * * * * ****

    {
*** *** **** ********* * ** * * ***** ** = (y2-y1)/(x2-x1);
* * ** ** * ** * *** ** * ****** ** * = 1;
* * * *** ****** * ** ** * * * * * = m * x1 - y1;
* **** * * ** * ** *
** ** ** * ** *** * if (x2<x1)
** *** ** **** * *
**** *** *** ** ** ** *** * * **** ** * = (y1-y2)/(x1-x2);
* * ** * * * * * *** ** *** ** *** = 1;
** * * ** *** * ** * * *** * * *** = m * x1 - y1;
* * *** * * * *
* * ** ** *** *** ** *** ** if (y1 == y2)

    {
***** * *** * *** *** **** * *** * ** ** * = 0;
* * *** ***** * ** *** * ** * * ** * = 1;
** * ** * * ***** * * **** *** ***** * = -y1;
* * * ** * **** *
** * * ** * * * * * if (x1 == x2)

    {
** *** * * *** ** **** * *** * = 1;
* **** **** * * *** * **** * ** ** = 0;
* * * *** * ** * ******* * * ** ** * * * = -m;
** *** ** * * * * * * *
** ** * *** **** * ***** ** ** **** **

    {
**** *** * * * **** **** ** ** ***** * ** == b%n && m%n == c%n)
* ** * **** ** * ** **** * * * * * **
* * * * * **** *** * * *** * ** ** * * * * * ** * * * * * * = m/n;
* ** * ***** * ** ** * * * ** ** * * * ** ** *** *** = b/n;
* ***** ** ** ** ** * ** *** * * ** * *** ** ** * * * ****** * * = c/n;
*** * **** *** ** * * * * **** * ** *
* **** *** ** * * ***** ** *** ** * *
* ** *** *** ** ***** * ** * ****** ** * * ** * * * ** * ** * ******* %.6f %.6f\n",m,b,c);

    }
*** * * * * ** ** * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include ** ** * * * *

#include * ** * ****

#include * ** ** * *



int main(void)

{
*** * ** ** *** * ** * a1,a2,b1,b2,a,b,c;
** * * **** ** * * * ** ** %f %f * *** *
**** * * ** ** ** * * ** **
** * * * ** * * ** *** **
*** * **** * *** ****** **** ***
* * ** * * * *** * ** ** ** %.6f **** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** *** * *** **
*** * * * * *

#include<math.h>



int main()

{
* * *** * *** * * * * * x1,x2,y1,y2,m,a,c0;
*** * ** * * ** *** * *** * * **** *** * *
* * * * ** **** * * *** * * ** *** ***
** ** * *** ** * ** *** * * ***** ** ***
* ** *** * **** ** * *** * ******** ***
* * * * **** * * * *** ** = (y1-y2)/(x1-x2);
*** *********** * *** ** *********
** ** * ** *** * * ***** * ** * ** ***
* * ** ** * * * * ** * * %f *** * ** * **** ** **** * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** *** * ****
* * ** * ****

int main()

{
** * ***** *** * x1,y1,x2,y2 ;
* *** ****** ** ** * ** * * * ** *** * ** **** ** * *** *** ;
** * **** * ** * ** a,b,c ;
** ** ** ***** * * = y2-y1 ;
****** * ** * * * = x1-x2 ;
* * ** ***** * *** * = -((a*x1)+(b*y1)) ;


* ***** * *** *** * *** %f ** * * ;


* ** ** * *** * * 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** *** ** ** * x1,y1,x2,y2,m,a,b,c;
** *** * * * ***** * ** * * * ** ** ** ** ** * ** * *
* * * ** * * * * ** *
* * *** ** **** *** *
* * * * * ** *** ** * *** ** = (y2-y1)/(x2-x1);
** * * * ** * * **** *** * * * **** * ** = 1;
* *** * *** ** **** * * * ** * * * = m * x1 - y1;
* * **** ** ****
* **** **** * ***** *** ***** if (x2<x1)
* ** ** ** * ** *** *
* **** ** * ** * ** * **** * **** = (y1-y2)/(x1-x2);
* ***** * * * * ** ** * * * * **** * = 1;
*** * ** *** * * * ** * * **** * * * ** * * = m * x1 - y1;
** * * *** * * ** * *
* * ***** *** * *** ** *** if (y1 == y2)

    {
*** * * * * * ** ** *** * *** ** ** *** *** *** * = 0;
* * **** * * * ** * * ** * * *** *** = 1;
* ** * * *** **** * **** * ** ***** * * *** ***** ** = -y1;
* * * ******* * *
** ** *** **** ** * * *** if (x1 == x2)

    {
*** * * * **** * * * ** * * * * * **** ** = 1;
** * ** ** * ** **** ** * **** ** * *** * * = 0;
*** * **** ** ***** ** *** ** * ** * ** * **** * = -m;
* **** ** ** * * ** *
* **** * * ** * *** * * * %.6f %.6f\n",m,b,c);
* *** ** * ******* ** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
*** * * **** * ***
* *** * * ** *** **
** **
*** i * **
**** * , b , c , * * * * **
* ** * ; i *** * ;
**** ** ** * *** * , ** * );




** == **

{ * *** * * = 1;
*** **** *** **** **** = - *

}


*** ** ** * *** ****** ***

{

a * **** ** **

c = * * * * ;

b = -1 ;

}
* ** == 0)
* * * * ** * 0 ;
* ***** * *
* * *** ** ** ***** 0 ;
* ** * **
*** **** * *** ** * 0 ;
* * * ********** * ****


** * * **
** * * ** * * * ** ******* ***** * ** ** * h ** , **




*** * * * * *
**


**** * * * * * *** a , b ,c *










** 0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.250
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users