0 like 0 dislike
17.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 17.9k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* ** ** ** ** ** * F0,F1,Fn,n,a;
** ** ** * * *** **

* ** ** * * *** ** **** * ** ** *** * * &a);

** ***** ** * * * ** ** * ** **** **
** * * ** * ***** *
* * * *** * * **** ** * * ** ** ****
* * ** ** ** ** * * * ** *** * * * **** **
** ** ** * ** ** * ** * ** **** **** *** *
    }


** * ***** * * * * * * ** * * Fn);

* * ** ** * *** * *** ** * ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *
int * *
{
int ** *** **
** *** * * *** ** * ***
if(a==0) printf(0);
else if(a==1) printf(1);
else {
** * ***** * * ** * ** ** *** *** * **
** * ** *** * **** *** ** * ** * * * ***** * = c0+c1;
***** * * ** ** * ** * * ** *** *** * * * * * = c1;
* * * **** *** *** *** * * * *** * *** * *** = cb;
* * *** *** * ** ** *
** * * ** ** * ** * ***** * **** *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * *** ***

int * **** *
{

int **** ** **
** * * *** **** * * ** **

if(a==0) printf(0);
else if(a==1) ****
else {
*** *** ** ** * * ** * * * * *** **
*** ** * ** * ** ** **** * * *** ** * *** ** = c0+c1;
**** *** * * ** ** ** * * * * *** * *** ** ***** ** = c1;
* * ** *** *** *** * ** * = cb;
**** * * * *** **** *
** * * ****** * ** ** * ** **********


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * ****

int main(void)
{

int *** ****
** * * *** * ***

if(i==0) **** ** * * *
else if(i==1) ** ***** * ** *
else {
*** *** * * * * * * ****** * *
* ** *** * ** *** * * * ** ** ** ** ** = f0+f1;
* * *** *** * ** ** * ** * * * ** * * ** *** = f1;
* ** * * ** **** * * ** * ** ** * *** ** = fn;
* ** ** * ** * *
*** ** **** *** * *** * ** * ***
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** * **

int ** **
{

int ** *
****** ** ** ** * * **

if(i==0) printf(0);
else if(i==1) * *
else {
* ******* * * * ***** ****** ** *** *
** ** ***** ******** *** * * *** * * = f0+f1;
** ** ** ** * * * * ** * **** * * * = f1;
** * * * ** ** * * ** * * * * = fn;
** * * ** * ** * * ** **
**** * ** * * **** * **** ** * * **** **** *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
***** * ******** ** *** * * * **** *** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ***** * ** * ** * * * * * * * ** * d;
* * ** * * *** * * ** ** * *** *** ** ** *** (d=2; d<n; d++)
* * * * ** ** * ** * * * *** *** ** ** *****
*** ** * * ** * * ** * * ** * * ****** * * * (n%d==0)
* * * ** ** * ** * *** *** * * ***** ** ** * ***** ** * ** * *** ****

   }
* * * * * * * ****** ** * * ** * ** ** *
* *** ** ** ** ** * * * ** * * ** * * **** ****
** ** ** *** **** * * * *** ** * * * *
* ** * **** * *** ** * * * * * * * *** ** * *
********* * ** * ** * ** ** ** ** ** * ** ****** * **** *** * * (e==0)
** *** * * ** * * * * *** ** * * * ** * * * ** * ** * * * *** **** * * ******* * * *****
* * * **** ******* ** * * ** * * ** *** ** * * * ** * * * **
** * ** *** ******* * **** * *** * ** * *** * * *** * * *** * ** * ** *** ** * * * ****** * * ");
*** ***** * * * **** ** * ** * ** * * * *** * *** **** **** * *** ** *
** ***** * ** ** * ** ** ** * * ** *** * *** ** * * * ***** * * **** *** *
* **** ** ** * * ** ** ****** ***** * ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
**** * * * * ** **** * ** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** * * * **** * * ** ** * * ** ** ** d;
** * * * ****** * * * *** ** ** *** **** *** (d=2; d<n; d++)
* * * * * ** **** * * *** * * *** *
*** * * *** * * * * * * * * * * * (n%d==0)
***** ****** ** ** * ***** ** * ** * * * ** *** ** * *** * * * * ** * ** * * * ****** *

   }
* **** * *** * * * * **** *** * *** * * * * *
* ** *** *** * * * **** * * ** * **** ****
* ** * ** ** **** ** ****** * * *** *
* ** * * * ** ** * ** *** * **
* ******** * *** * * *** **** * ***** * * *** * * *** * * **** * (e==0)
* * * * ****** * * * ** **** ** ** * ** * ** ** **** * * ** * ***** * ** * **** *
********* * * ****** ***** **** * ** * ** ** ** * ** *** * *
* ***** * * ** *** ** ** * *** * ** * ** * * ***** * * *** ** * ** ** ** * * * **** ***** ");
* ***** * * **** * *** * * * ***** **** *** * *** * ** * ** * *
* *** **** * * ** * * * * ** * ** ** * * **** ** ** * * * * * *****
*** *** * * * **** ** **** * * * ** ****

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* * ***** * **** * ** * ** * * * ** * d;
* ** *** ** ** *** * * * * * **** * * (d=2; d<n; d++)
***** *** *** * *** *** ** ** *** ** ***** **
** * ***** * *** * * ** * * ** * * * * ** ** * (n%d==0)
* *** * * * ***** ** * **** **** * * * *** ** * * * * * *** * * *
   }
*** *** *** * ** * ** * * ** * * **** * * * * * *
* * *** * * * *** ** * * * * ** * ** * ** *
** * *** * * ** * * * * ** *** * * ** ** ***
** *** **** ***** ** * * * * ****** * ****** ** *
** * * * * * ** * * * ** *** * * ** * **** ** * * ** ** * (e==0)
* * * ****** ** ** * ** * ***** ** * **** * * ** *** ** **** **** * ****** * ** ** * ****** * ****
**** * ** * ** * ** ** * *** * * * * ** ** *** * **** ** *** * **
* * * * * ** **** * *** ** * * ** ** ** * * * ** * **** * * * *** ** * * ****** * * * *** ");
*** * * ** **** * **** * *** * *** * **** * ** *** * * * * ** * ****
*** * * * * * ** * * * ** ** *** *** * * * * ** * * * ******** **** * * * * * *** ***
*** ** ***** *** * **** * **** *** * **** * *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** *** * * * **** ** Fn,t1=0,t2=1, n,input;
* **** * * ** * * *** ** ** **

** * * ** ** ** * * *** * ** * n++)
*** ** * * * *
*** *** ** *** ******** ** * * *** *** * * = t1 + t2;
* * *** * * ** ** ** * *** ** ** * * ** ** *
** *** *** ****** **** * ***** *** * * ** * * **
    }

* ** ** *** *** ** *** **** *** * *****

* * * *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** *** * ** * * * Fn,t1=0,t2=1, n,input;
* * * * * * * * *** ** * ** ** *** **** *

** ***** * * * *** ** * * * * * * n++)
* * ***** * *** ** * ***
* ***** * *** * * **** * * ** *** *** ** * = t1 + t2;
*** ** ***** * *** * * **** * ** ** ** * *
* ** * * * * **** ** ** ***** * * * **
*** *** *** ** * *

** *** * * ** ** ** ** * ** *** ",Fn);

* * * * * * * ** * ** * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.197
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 11.7k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 21.5k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.8k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users