11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
9.5k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 9.5k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   *  *** * *   *** ** * *  F0,F1,Fn,n,a;
   ** **    *       ***     *** ** ***

   *  * *   *  *** * *    ** *  * ***      **  &a);

* ** **  ** ** *  *  **    *     * **   * *
 **  *  *    *   *  *   ** ***
 * ****** * **     * *  *    *  *   **  **   *******  *
*  *** *    ***    *      *** * *    *  *** * * **  
   * *   *     **   ** * * *   * *** *  * **** *     * *     *
    }


* * *** * *** ** ** *    * *  **    ***  **  Fn);

 * ***  *   ** ***    ** * * *   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** ** * 
int  ** ** 
{
int * ** ***    
 *** * **     *  * *  * *   
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* *   * **   *****   *  *  *** **      ***  *      
**** **   *  **  * * * *** *  * *  *  ****  *   **** ** * = c0+c1;
** *    *   ***  **** ****    **  ** **  ***     ** * = c1;
**** ** * * **  * **  *     **   *******    ** *   ** **   * = cb;
* **** ****   **   *** *  
*  ***  * ****          *  ** *    **    *****   
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *    * **** 

int   **
{

int  **** *** *  
*   *  *  *  * ** * * ******* 

if(a==0) printf(0);
else if(a==1)  *     
else {
 *   * **  *****  *  * * **    ** **** *  
 ***  ** * **** ** * *    *** ** ** *** ****   = c0+c1;
  *   *    ** ****  **        **  ***  * *  ** ***    ** * *    = c1;
 **** *   * *** **  **       * *  *   ** ** * *  ** * * * = cb;
 **     * * **  * * * *
       *****  *** ** **     * * **     ****    


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  *** * **

int main(void)
{

int  **   *  ****
  * **   *  *   ***  *

if(i==0)    * *  *  **  *  
else if(i==1)   *  * ****     **  
else {
* * *** ***  ****     * * **** * * ** 
*****   *** **** * ** * * ******  **          **  ***   **  = f0+f1;
** ***** *  *** * * ** ** ***      **   **   *  * ** * * = f1;
* * **  **   * *   * **  *    *  ***  * **  *       = fn;
*  * *** ** * **  **    **
     * *  * * **   *** **** **    * *  * *     ** **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * *** * *  

int * ** 
{

int  * *    * *
 *    *   * * *  **    *    **

if(i==0) printf(0);
else if(i==1) ***   
else {
* ** * *  * **  *** ** **   *  *  * ** ****
** * *   **     * * *  **  ******   **** *     ******* ** = f0+f1;
*** *****     **** *  ****     *  *  *** * * **   ** ** = f1;
 * **  *   *   ***    * *   *  *    **** * * *** = fn;
* * **    * *  *   **  *  *
   *  * **  *      *       * **  *** *  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** ** ** **** ** ******** *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
**** *** *** ** ** * * *** * ** * **** * * ** d;
*** * ** * ** * ** * ****** * * ** (d=2; d<n; d++)
* ** * ** ** * * *** **** *** *** * ***
** ******** * ** * * * * ** ** * * (n%d==0)
****** * ** ** * * **** ** ** * ****** * * ** * * ****

   }
* * * **** ***** *** * ***** * * ****** *
*** ** ** ** * * *** * * * **** * * ** *** *
**** ** * ** * * * * * * * ** ** ***
*** * *** * ***** * * * **** ** ** * *
* * * * * ** * * ** **** * ** * * *** * * * * (e==0)
* ** ** * * *** * * ** ** * * **** * * ** **** ** * *** * ** * ** * * ** ** ***
** ** * ***** *** ********** *** *** ****** ******* *** ** *** * *
* * * * * ******* ** **** * *** *** * ** ** ** **** ***** * ** ** ** * * * * ** * ** * * * *** **** ");
*** * * * * ** ** * **** * *** * *** * **** ****
* *** * ** * * * **** * ***** * **** ** *** * ** *** **** * * * ** *** *
*** ** * ** * * * * * * * *** * * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** * * * * ****** *** *** ** * * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** *** * * *** * * ** * ** * ** * d;
* * **** * **************** * * **** ** * (d=2; d<n; d++)
* * * * * *** ** * **** **** **
** ***** * *** ******** ** * ****** * * * * ** * (n%d==0)
* * **** * * *** * *** * *** ** * ** ** * ******* *** *** *** ** *

   }
**** * * **** *** * **** * * ** * ** ****
* *** ** * * * *** * ** ** ** * *** *
** *** * * **** *** * ******* * * * **** *
*** ** * * * ***** * * * *** ** * *
* * * * * ** * * * * *** *** *** * * ** *** **** * *** ** * * (e==0)
* * * * ** * * **** *** * * ** ***** ** * * ***** **** *** * ** *** * * * * * **** * * ** *
** *** * ** **** * *** * * * * * ** ** **** * *** * * * *** ***********
* * * * * ** *** *** *** **** * ***** * * * **** * * ** * *** ** * ** * **** ** * *** * ");
*** * * ** ** ** ** * ** **** * *** **** * * * ** * * ***** * * * **
* ** ** * ** *** * * **** * ****** ** * ***** ** ** ** ** * * * ** * ** * * *
** ** * * **** ** * ** ** * ** ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
** ** *  *   ** **  ** ***         * * * *******  * *  * *  * d;
 ** ***  *   *        **   *** **   *** ** *     ****** **  * (d=2; d<n; d++)
*** ** * *  *     * ***  *** *   ** ***    
*   * ******   *** *  *  * *****  *   ***      *    **  * (n%d==0)
* *  *** *  * *            *  ***  *    **        ***  ** ** ** **  *       *** * 
   }
 * * * * *  ** **  * ***** * * **  *****  ***  *  * * **     
   *   *    * * *  * **** * *  ** ** *  *** **  * *
* * *       ** **    * **     *     **  * *  *  ** ** **** 
*   **   ** * *   *    ***     **  **  **  * * *  *  *     
* ***  * ***       *   *    *  **    ***  **  *  * * **   *      ** ***    ***  ** **  (e==0)
*     *  *** ****  **   * * * * * **** * ** *  *  ** * ******     *   * * ** ***** ***** **** ** *   *  *      *
*   ** ***          **** * * * * *  ****   ****    *  *** * ** *   ** *  * ****    
**  *    ** ***     ** * * **   ** ** **  *  *** * * ** *  **    **  * *   ***  **     ****   * ***  * ***  *  **  **  * ** ");
  *   *** * *   **    **  * ********  ****   ** *   * ***  ** **   **  * ** **   ***  **
****   *** ** ** * *  *  **** ** **   ** * ***   ***  *** *   *  **  * ****  *   *** *  ** **  *    * 
* **** **    **   * * **    ***   *  * ** *   *         *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 *    ***  *     ** ** * * Fn,t1=0,t2=1, n,input;
* *  *** ** * *  * **  * ***********  * ****  **** *

***    *  * ** ***   * * *  ** ****   n++)
 *    * **    *** * ** *** * 
 *  *** *  * *  **   **** * *****  *  * **  * ** *  * ***   = t1 + t2;
*  *    **********  ** ****** ***  *****       *   ***** 
*    **    * *  * ***   *   *  *   *** ** *   ****  *  *
    }

 *** * *  **     * * ***     * * * * **    *   **

* *      * ****    **  * * *****  0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*  * **  *   ** * ******   *  Fn,t1=0,t2=1, n,input;
* *** * * *   * * * * *** * ***** * ***  * * * * *   * *

  ** * *  ****       * ** ***   *  **        *  * n++)
 **  ***** **  * ** *  **
    ****  * * * * *      ***  *  * *** ***    *  *  ** ** = t1 + t2;
 **    *   **     **  * * *  ******* *  *   *** ** * * 
*** *  *   *** *   *   *  ** *     *       *** **   **
  ****   *    * * ***  ****  

***    *** ** * ***  **    * ********  ****      ",Fn);

* *  ***     ** *  *  ** ** *  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.86
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.8k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 4.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 8k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users