0 like 0 dislike
21.6k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 21.6k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* * * ****** * * * *** F0,F1,Fn,n,a;
** * * * * *** * * * *

* * ** ** ** ** ** * * ** ** &a);

*** * * * ** * * *** *** * *
** ** * * * * *
* * ** ** * * **** * * ** * *** ** * * ** ***
** * * * * * *** * ** * * ****
** ** * ** * ** * * *** ** * *** **** **
    }


** * * * * ** * * * * * **** Fn);

** * ** ** * * * * *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** **
int ***
{
int ** * *
** * *** * **** ****
if(a==0) printf(0);
else if(a==1) printf(1);
else {
** * ***** * ** * * *** *** * *
**** * * * ** * * ** * ** ** * *** ** = c0+c1;
* ** ** * * * * *** * * ** * ****** ** = c1;
** * *** * * ** ** * ** *** *** * * * * = cb;
* ** *** * * * *** *
* * * * * * * * ** * *** *** * *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * * *** *

int * *
{

int ** ** *
**** ** ** * ** **** *** *

if(a==0) printf(0);
else if(a==1) *
else {
* ** *** ** * * *** ** **** * * * ** *
** **** * * ** ** **** * **** ** * * ****** = c0+c1;
* ** ** *** * * * *** ** ** * * **** ** * * = c1;
** * ** ** * ** * * *** ** *** ** ****** = cb;
* *** * *** ******
* *** ***** ** **** ** * ** * *** *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * *** ** *

int main(void)
{

int ** *****
* **** ** **

if(i==0) * * *** ** ** **
else if(i==1) ** * **** **
else {
* * ** * **** ** * * * * * * * *
* *** * * * * ** ** *** ***** ** * * *** * = f0+f1;
* ** * * **** * *** *** ** ***** *** **** = f1;
* **** *** * ** * * ** ** * * * * * * *** * = fn;
* * ** ******* * * *
* *** * *** ** * * *** * * * * ** * *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * **

int *******
{

int **** ***** *
** * * * * ***

if(i==0) printf(0);
else if(i==1) ***
else {
*** * ** * **** ****** ** * ** * * **
**** *** * ** ******* * * * ** ** *** **** * = f0+f1;
** ** * * * * ** * ** * ** = f1;
* *** ** ** *** * * ** ****** *** ** = fn;
* ** * ****** ** ***
** *** * ** ** ** * ** * *** **
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* **** * * * *** ** * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * ** ** * * * * * * *** ** d;
* **** *** ** * * ** ** * ** * *** ** * * * *** (d=2; d<n; d++)
*** ** ** *** ** * ***** ** **** *** *******
** * **** ** ** *** ** ** *** * ** * * * ** * *** (n%d==0)
** ** **** * * ** * * ** ** ***** * * ** * * *** *** ** **

   }
* * ** ** * * ***** * ** * * *** * ***** * * * ****
** ** ** ** ** ** * * * ** *** * ** *** **
** ****** *** * ** * ** * * * * * ** * ** ***
** **** *** * ** ** *** ** *
* * * **** ***** ** * ** * ** ** * * * ****** ** * * * * * (e==0)
*** ** * *** ** ** ** * *** ** ****** * *** *** * * * * ** * ** * * * * * * *** * ** ***** * *
* ******** ** ** **** ** * ** * *** * * ** * *** *
** ** ***** * *** ** ** ** **** * ** *** ** * *** * ** *** ** * * ** ** ** ***** * ** ** * **** ");
* * ** * *** * *** * *** * *** ** *** *** ** * *** *** * * * **** ** * ** ***
* * * * *** ** *** ** * ** ** * * ** * * * ** *** * * * ** ***** * *** * ** ***
* *** ** * * ** * * ** *** * ** ** *** * **** *** * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** * *** ** * * ** **** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * * * **** ** * ** ** * * *** * d;
* *** **** * ***** *** * ** *** *** * ** (d=2; d<n; d++)
***** * ** *** ** **** * **** ** * * * * * *
** ** * *** * ** * **** **** * * ** * (n%d==0)
*** ***** * * ** * * ** * ***** ** *** ****** *** *** * ** ** ***

   }
* * *** ** ** **** *** ** * * **** ** ** ** ** * * ******
* ***** ** ** * ** **** * ** * * * ***** ** * *****
* *** * * ***** ** * * * * * * * *** **
** * ** *** ** * *** * * ***** *
* ****** ** *** * * * * ** * * **** ** ** * * ** ** ****** * * * (e==0)
** * * * *** * ** * *** ** ** ** *** *** ** * ******* * ** * * ** ***** * *** * * **
*** ***** * ** * * * *** ****** * **** ** * * * ** ** *** * * ***
* *** * * * ** * ** ** *** ** * *** * * * *** * ** * * * * * * * * * * **** *** * ");
**** ** * ** ***** ** * ** * *** ** * **** ** ******* ** **** ****
*** ** * * ** * *** ** *** **** * *** ** * * * * *** ** ** **** * ***
** * * * ** * * ** * ***** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* * *** * * * * * * ** ** *** *** *** * d;
** *** ** *** **** ** ** * * * * * ** ** (d=2; d<n; d++)
** * * ** * ** ** ** * * * * ** * * *** *
** ** * *** ** **** * ** * * ** * * (n%d==0)
** * * ** *** ******** * ***** * * * * * * *** * ** *** * * *** ** ***
   }
** * * * *** * * * ** ***** *** * ****** ** * ** *
** ** * * * ** * * * *** ** * ** *****
* ******* * ** * * * ** **** *** **
* * ** ** * * * * * * * ** ** ** * * ***
** * ** **** ** *** * * * *** * **** ** ** * *** * *** * ** *** * * * * (e==0)
** ** ** ** ** * * * * ****** * ** **** * ** ** *** ** * * *** ** * * **** ** * *
** ** ** ** * ** ** * ******** ****** * * * *** * * * ** ** *
**** *** * * ** * * *** *** * ** * * * ** *** * * ***** * *** ** * * ** * * * *** * * * *** **** * * * ");
* *** * ** * * ** * ** **** * * * * * ******* *** **** ** *** ******
* * * * ** *** * * **** * * ***** * * * ** ** *** * * ** *** * * * * * *
** ***** *** * * * * * ****** ** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** ** * * ***** **** * Fn,t1=0,t2=1, n,input;
*** *** *** * * * * ** ** * * * ** * * * *

** ** * * * ** *** ** ** * *** n++)
*** * * * ** *** * * *
* * ** *** * ** * * ****** ***** * **** * = t1 + t2;
* ****** * *** * ** ******* * ** ** ** *** ** **** *
** **** *** ** * * ***** *** * ** * * ** *** *
    }

* *** * * * * * ** ******** ** * *** ***

** * * * * **** * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * **** ** *** Fn,t1=0,t2=1, n,input;
* * *** * ** ** ** * * * **** * *** *** **

* * ** *** **** * * ** * * ** n++)
* **** * * *** ** * ** **
* ** * ** ** ** ** ** * * ** * * * * = t1 + t2;
*** * * ** * * * * * * * *** ** **** * * ***
**** * * * * **** * ** ** * * ***** * ** *
* * * * * ** * * *

* ** **** ** * * * *** ",Fn);

* * **** * ** * ** * *** ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 13.9k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 25.4k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 17.3k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 17.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users