0 like 0 dislike
18.6k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 18.6k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** * ** ******* ** * ** * * * F0,F1,Fn,n,a;
** * * * **** ** * ** * * **

** **** ** * * * ** *** ** ** ****** ** &a);

**** * * ** ** **** **** * ** ** **
*** ** * ********* *
**** ********* ***** * ** ** ***** ****
* *** *** *** **** * ** * ** * *
* ** **** ** * * * *** * ** * * * ** * *
    }


** ** * * ** * * ** *** * ** ** * Fn);

* * **** *** ** ** * * ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** **
int * *
{
int * *** ***
**** *** * **** **** **
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* * ** ** * * ** ** ** ***
**** * * * * * ** *** ** ** *** **** ** * *** = c0+c1;
** * ** * *** * ** ** ** ** * * * * = c1;
**** * ** * * ***** ** * * ** * ** **** = cb;
* * * * * ** ** ***
**** * * * ** ** ** *** ** * * * ** * *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * **

int ****
{

int ** * *** *
*** * * ** ** * ** **

if(a==0) printf(0);
else if(a==1) *** *
else {
* * *** **** * * ** ** *** * **
* * *** * **** * * * ** ***** **** ***** = c0+c1;
** ** * ** **** *** * * * *** **** * * = c1;
** ** * *** * * ** ** * * ** * * ** = cb;
*** ** * *** * ** ****
** * **** * * * ***** * ** ****** ** *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ** ** * * *

int main(void)
{

int ** *
* * ***** ** * *

if(i==0) * * * * * *** *
else if(i==1) ** **** * ** ***
else {
* * *** ** ** ****** * * * * *
* ** * * * * * *** ** * *** ** * = f0+f1;
* *** * * ** * *** * ** * ****** ** * * * ** = f1;
* ** ** ** * ** * ** ** * ****** * *** = fn;
* * *** * ** * *
* * *** * * * * ** ** ** * *** * *******
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** **

int *
{

int **** *** *
* * ** *** * ** ** * ** ** *

if(i==0) printf(0);
else if(i==1) **** *
else {
* ** *** ** *** * * * * **** *
**** * * ***** **** * *** ** * * * * ** * ** = f0+f1;
** *** * * ***** ***** ** * * ** ***** * = f1;
** * **** * * ** * ** * ** * ** *** * * = fn;
* ** ** ** * ** ** *
* *** ****** *** * ** ** * ** * *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * **** * * *** ** ** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
************** * * * ** ** ***** ** * * * * * ** * d;
*** * * * ***** *** *** **** * * *** * * ** ** ** (d=2; d<n; d++)
* ** * ** *** * * **** *** ** **** *
* ***** * ** *** *** * * * * * ** **** * ** * *** (n%d==0)
** ** ** * *** * * * * **** * * ** *** * * ** * * ** * * ***

   }
* * *** ** * *** * **** *** ** * *** * ** * * * * *
* * *** * ** ** ****** * ** * ***** ** * * **
** * * *** * * * * * * ****** * *
*** ** **** * *** * * ** * * * ** *
* * ** **** ******* ** * * * * ** ******** ***** * *** (e==0)
*** * * *** ** ****** * ** **** * * ** * ** **** * *** ** * * * * * *** * * **
* * ** ** ** ** *** *** *** **** * *** ** **** * * *
**** ** ** * * * *** ** * * * ** ******* ** * * * ******** * * * * * *** ** * * * * ");
** *** ** ** ** *** ******* **** ** * **** *** * * *
* * *** *** * **** **** * * * * * **** *** * * ** *** ** ** * * ** *
*** * ** * ** * * *** ** *** * * **** ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** **** ** * ** * * * * ** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * * * *** * * * *** * * ** * ** d;
*** *** ** ** *** *** ******** * ** ***** ** (d=2; d<n; d++)
* ******* * * *** * * *** * * * *** *
* * * *** ** * * * *** *** **** (n%d==0)
*** * * * * * * * * ** **** * *** * * ** ** * * ** * ***** * ** **

   }
** ** * * * * * **** * * *** ** * *** * *** ** **** * ***
****** * * ** * ** *** ** ** *****
*** * ** * * * ** ** * * * * * * * * * *
********* *** * *** ***** ** * * * * * * *
** ** * * ****** *** ** ******** *** ** * ** * ** * *** * * **** ** (e==0)
***** * ***** * ** ** ** * ******** * * ** *** **** ** *** ** * * * * ** **** ** *** *
* ** * ** ** ** ** * * * * * * *** * * **** *** ** * * **
* ** ** ***** * * *** * ** * * * * ** ********* * * * ** * * * * *** *** * ** *** ");
***** ** ** * * **** ** * * * * * * ** ** * * ** **** ** * * ***
** * *** * * * * *** ********* * * * ** *** **** *** ** **** ** * **** * ** **
*** *** * ** * ** ** * ** **** **** * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* * * *** ** ** *** * * * * * ** ** ** *** d;
** * ** ** ** ** * ** ** * ** ** ** * *** * * (d=2; d<n; d++)
** ** ** * ** * * *** * * ** **** * *** **** * * *
* ***** ** ** * **** ** * * * * * ** * ** (n%d==0)
* **** ***** * * ******* ** **** * * ** * * * ** ****** * * *** * *
   }
*** * * ** ** * * ** * * ** * * * *** * ***
* * * **** * * ** ** ** * ** * *** *** * *
*** * * ** * * * * * * * ** * * ***** *
* * *** *** * * * **** * * **** * ****
* * * * * * * ** ****** ** * * * ** **** * ** * * ** * ** **** ** (e==0)
* ** * * * ****** *** * ** ** **** * ** * * * * *** * * * * * * ***** * *** * **
** ** * * * * * * * ** * * * * *** ***** **** **** *** *****
* * *** ** ** * *** ** * ** * *** * ** *** * * * ** * ** * ** ** * ** * * ***** ");
* ** *** **** *** * ** *** * **** ** * * ******* *** * ** ** ** * *** *** **
* * *** * ** * * ** ** *** * * * * * *** * *** *** * *** * ** ******* ** * ****
* * *** ** ** *** *** ** *** ** ** * *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** *** * ** *** * ** ** * Fn,t1=0,t2=1, n,input;
** ** * * * **** ** * * **** * * * * ***** * *** *

**** ******* * * * * ** ***** * * ** n++)
*** * * * * * ** ** *
**** ***** ***** * ** * ****** *** * *********** = t1 + t2;
* *** ** ** * * * * * * **
* * * ** ****** *** * * **** * *
    }

****** * **** ** * *** *** * * ** * * **** *

* * * * ** * * * *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** ** *** * ** * * ** * Fn,t1=0,t2=1, n,input;
* *** ** ** ** ** ** ** ** * * * ** * ** * ***

* **** * * ** * * **** ** ** *** n++)
*** * ** **** **** * * *
** ** ** ** ** * * ****** * *** **** ****** *** = t1 + t2;
*** * ******** * ** ** ** * * *** ***** ** ***
**** * *** * ****** * * *** * ** *** ***
*** ** * **** * ***

** ** * ** *** ** * **** ** * *** *** ",Fn);

**** * ******** * * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.96
©2016-2026

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 12k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 22k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 9.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.2k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users