11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
11.8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 11.8k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*   *  *******  * * * * * * F0,F1,Fn,n,a;
*  ** * * * * * * ** **** *  *** *** * 

 *  *  * * ** *   * *** *** ** ** * *   **    &a);

* *   * ****  *** **   ** * *** **   *  *   
   ** ** ***** *   **     *    *
 **   * *  **** **    * * * **   *** ***** ***  *** *    
   * *  **** *** * * *** ***   **** * *** *   **   *  
 ** * * *  **  *** * * ** *** ***  **** *     * *** *  *    
    }


   **   * ****   ** *  *** * *** * * ** * Fn);

*   ** *** ** * **** *    ** *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** * * ** **** 
int   ***
{
int **  *  *** * 
   **  **  ***   * *   
if(a==0) printf(0);
else if(a==1) printf(1);
else {
** **     ** ***** **  *  * *   ** * *
  *** * *** * * ***   *   ***  * * * ***  **  *  * *  *  = c0+c1;
*  * *  * ****    **  **  * **  *** ** ****   *  *   = c1;
   * *  *  ****  **   *  ****  *    *  **     *** ** *  * = cb;
****  ***  * * * *   * *  
* *  ***  *   ** * ***  ******** *  ***   *  
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ****      **   

int  ***  * 
{

int ***  **       *
****   ** ***    *** ** ** ***

if(a==0) printf(0);
else if(a==1)  *  **
else {
*     ****** **   * * ***    ****** **
 *  **  * ***    * *** *  ***  *********        *     = c0+c1;
** **** ** * *  * *  ** *  ** **** ** **   **  *   ***   = c1;
* * *  **      *  *   **  **     ***   ** *      **   = cb;
* *** * *** **  * ***** *
 *  *  *  ** *     * **    ****** *  ***  *  * 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **  *  *   ** **

int main(void)
{

int **     *** ** 
 *** * *** **      * ***** ***   

if(i==0)   **  *   *     ***   
else if(i==1) **  ** *  ***** * 
else {
*   * ***** **   *  * ****  * *** * ** **
*** * * * ** ** *   ** * *** **** * * **      *   * *    *   = f0+f1;
  *  ** *    **** *   *  *   * *   ***      *   *    = f1;
   ********** *** * *   ***    * *    * *  * ** * *       *** = fn;
** ***    *   ** *  * *  *   *
* ** *   **** * *** ****  ** *    * *** *   
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** ** ***

int ***   * 
{

int *      * * 
 **    ***  * * *  *    

if(i==0) printf(0);
else if(i==1)    ** 
else {
   * ***  * **      ***     *******   * ***** *
* ***** *  * *** ** * *   ** **  *  *    ** * **** * ** = f0+f1;
 * ***  * **     * **  **  **  * ** *  ** **    **  * *   = f1;
* **  ****  *  ** **  **    *  * **  *****     = fn;
*    * *  **********
 * ****   *    * **  * * *   * *  *      * * *  *  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
****** ** *** * * *** * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ** * * * ** * ** * ****** **** ** d;
* ** ** ** * ** **** * **** * *** * * (d=2; d<n; d++)
**** ** * * **** * **** * * ** **** * ** * *
* *** ** **** * * * * *** ** * * * * ** (n%d==0)
* ***** ** *** * *** * * *** ** * ** ** **** * * * *** * ****

   }
* ***** * * *** * * ** ** ** **** * * *****
** * * * *** ****** * * **** **** * *** * * *
** * ** * * * **** ** * ** ** * ** ** * **** *
** ** **** **** * * * * * * * ***
***** *** * * ** * ** * * * *** ****** ** **** * * ** **** * ****** (e==0)
***** * ** * * ** * * ** ** * * **** ** *** * ** * * ** ***** * ** *** * * * ** ** * ** * ****
*** ******* * * * * ** ** ** ** ** * * * * * * ** * **
* * * ** * ** ** ***** * ** * ** ***** ** *** *** * * ***** ** * *** * ***** *** *** * * *** * * **** ");
* ** * * ** * *** * *** * * * * *** * *** ** *** ** * ** * *** * * *
**** * * * * * * * ** * * ** ****** * ** *** ***** ** * * *** *
*** ** ** *** * *** * * ** *** ** ** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** ***** * ** *** * ** ** ** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * ** * ** *** * **** ***** *** * * * ***** d;
** * * * * * * *** * * * * ** ** * ** (d=2; d<n; d++)
****** * ******* ** *** * ** ** ** ** ** ** ** ******
** ** ***** **** * ******** ** * ** **** **** * (n%d==0)
**** ** * **** ** ** * * * * ** * ** * * * ** ** * *** ******* * *

   }
* * * ** *** * * **** ** **** * *** ** * *
****** ******* *** ** * * * * * ** * * ** *
* ******** *** * ** **** ****** ** ** * * *
** **** * * ** * * * * * * * *******
* *** ** * * ** ** ** * * * * * ** ** ** *** * * * *** * (e==0)
** *** *** * * **** * *** * ** ***** * * * * ****** * ** ** ** * * *** * *
***** ** ** * *** ** *** ***** * *** ** ** * * *** * ** ** **
** * * **** * * *** **** *** * * * ** * ** *** * *** ** * ***** ** ** ** ** ** * *** * ** ** * ");
* * * **** ** **** * ** * ** * * * **** * ** *** ** *** ** * *****
** * ***** ** * ** *** ** ** * * * * * ** * ** * ****** * * ** ** *****
** *** * **** * * *** * ** * * *****

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
*  *   **  * *      *   * *    *** **  * *  *** **** d;
 ** ** ***   **** *    **      * * ***** * *** * (d=2; d<n; d++)
  *** **    *  *  ***  ** ***** ***** ** ** **  * ** * 
*  *   ** *  *    *******  **  * **  * *  *** *** **** (n%d==0)
   ** *  *   ***** ** ***   *  ********   * **  ** * *   * ***  * **     ** * ** * **
   }
 *  **** ** *   **    ***        * ***   * *   *  ****   ***  
*  *  * ** ****    * ** ** *** ** *** *      * **   *****  **
  **   * *   ** **   * ** * *****   *** * * ****    
 *    *  *     * *  *  *** **  *   *     *** *  * 
****  ********** ** ****  ***   * * ****  ** ***  **  **  *   ***** ** * *   *    (e==0)
 *** *  * *** **   ***  *  * *  ***** *   ** * ******* * * *  *  ** *  ** *  * *   * *  * * ***    * *** ******
*** *** *  ** ****    * ** *   * *   * * *   *       * *    *     *** *** *** *** *** 
   ** * * *     *   ** **  *  * *  * *  * **  * ****       * *  *    ** * **** * *  *    *** ***  **   **  ***   **  ** *  ");
 ****  **  ** *** *   **   * **  ** **     *   * ****  *   * *** **      *****    * 
*** * *  ***        **** * *    * *      ** ****  *  *  * * * **  **    ***         *    *  
 *** ***    ****  *  * **** ** ** *     ***  *  **** 
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
**        *     *      **  Fn,t1=0,t2=1, n,input;
**  ***** **    *  * ** *   *    ** *** *   **  * **  

*     ***    ***   ***  * *** *   ***  * *  ** n++)
*    * ** *** *** *  **  
  **     ** ****   * * *  ** *** ***   * * *******   = t1 + t2;
   *****  ** ** *  **  ***   *** * *** * *  *  **  ****** *** *  *
**  **   *  *   *** *** ** ** * * ** **    ***** *****
    }

***** **   *  *  *      *** *  **   * *  *  * *   

    *  *** *    **  *** *  ******** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*    ** *  * *  * ***  ** Fn,t1=0,t2=1, n,input;
  ** **        *** * * *** ** * *  *  ******  **    *    ***

** ** **  *    * * ** *  ** * * ****  ****** n++)
****   * * ** **    **** 
* * *  ******  * *   * *   **  * **   *   ** * * **   = t1 + t2;
 *   *  *  * * ***** * *    ***** ** *** * **  *    *****  
* *  ***** * ** **     ***    ***      *      *  * *  * ***    
* * *   *       *  * * * **   

 * ***   ******* *   **  **  * ***** ",Fn);

* ******     *   *   *   *** *  * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.50
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.3k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.3k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.8k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 10.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users