11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
14.4k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 14.4k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*      *** ****  * *  ** ****   F0,F1,Fn,n,a;
  ***** **  * **    ** * *    **  **  *

  **      * * ***   ****   ** *** **********   * *** &a);

 *  *  **  *   *****   **  *    **    ****   
 *******  ** ***  ***** ** 
********    * * ** *** * ***  ******** ** ***   **  * * *  ** 
  *  *  *  ** ** * *  ******  * * *   *      **  * *
**  *  ****   *   ** *   **    *** ** *     * **   * ***  
    }


** *** *  * *** *  * * **      ** * *    ** ** *** Fn);

  ****** *** *   *  *   *** **   * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** *  *** * *
int    **  *
{
int   **    * * *
  ** * *** **  * * **  
if(a==0) printf(0);
else if(a==1) printf(1);
else {
   * ***    **  *   ****   * *  *   ***   
  *  **     *** * ** ** ***   * **  ***     *    *  *  ** **  = c0+c1;
**** *  * *   ** *** *  * **     *** *   ** ** *   **   = c1;
* *    **   * *** **  *   **  **  *  **     **** * * *  * = cb;
* * **** *    ***  *
 * **   **  **  ****** * *   *    *  * * ** *  
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *****    * **

int * *******
{

int * * **  *   
*       **   *   *** **  * *** 

if(a==0) printf(0);
else if(a==1) **** ** 
else {
* * * ***    **     *  *  ****  * **** ***  **
 *****   *  *** *  *** ** *   **     *    * *  *  = c0+c1;
*** ***  *  **** **  ***    *** **  **     ***    ***  *     ** = c1;
* *  * **  * *** *** * *  ** *   * **  *******  * ** * = cb;
 **   ***  *      * ** **  *
*** * ** *    *   **   *  * *      ** * **    


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** * **  ** ***

int main(void)
{

int ***  **** 
**      **  ****    **   *  *

if(i==0) *** **** * **** *   *
else if(i==1)    *******       * ****  
else {
**   **    * *  *  *** ** * ** *** ** *  **
 **  **  *  * *          * ***  *** * **    * *  ****  *  * = f0+f1;
* **    *** ** **  * ** ** *  ******  *  *  * ** * ** ** = f1;
*   * * * *** **** *    *   ** * *    *** *  *   *  = fn;
 * **** *    **  * *** *** 
**** *   ** ** *  *  ****        * * ** **   * *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * ***   ** *  

int  ** * * *
{

int ** *****   
  * ***  ***    *  * **   * *

if(i==0) printf(0);
else if(i==1) * * *  
else {
** * *  ** * ***  *   ******* *** * *   ** 
* *  **** * *        *    **      ***   *** ** * ** * *  * = f0+f1;
**  ****  **       * **** * *  **** *** *  ***** **   * = f1;
 * **   *  *    * ** * **  * * *** *** *  **  **    **** *    = fn;
   *   ** *  ***  **    **  *
*** *  ** *  * ** *****  ***       *** ***  ** **  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * *** **** * ** * ** *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * ** ** ** *** *** * *** * * * * d;
** * *** * * * * ** ***** ***** (d=2; d<n; d++)
* **** ** * *** * ****** * *** * ** *** *
***** *** * * * * *** * ** * *** * * (n%d==0)
* * *** * ** * * *** **** ** * * ** ** ** * ****** ** ** ***

   }
* * * * ** *** * ** * *** ** * * ** * *** * * * * ** *
*** * ****** * ****** *** ** * * * * ** *
* ** ** * * ** * * * ****
** * ** * * ** * *** * ** **** *** *** * **
** ** * ***** * ** ** * * * * **** ** * ***** * * * ** * * * * (e==0)
* * ** *** * ** * **** **** ** ** * * * ** * * **** **** * ** *
**** ** *** * * * * **** * *** * * ** ** * *** * ** * * *
*** ** **** * ** * **** ** * * * ** ** * ********************* * ** *** ** ** * * ** * ");
*** * * ** * * * *** * ** ** * ** *** *** * * **** ** ****** * *
*** * * **** * * * * ***** ** * * * ** * **** ***** * *** ** ** * *** ****** *** * ** * ***
* *** * *** ** *** *** ** *** ** * * ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** ** * ** * ***** * **** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * * * * *** ** * **** * * **** **** **** d;
* ** * * * **** *** ** ** ***** ***** ** (d=2; d<n; d++)
* * ** *** * * *** * *** ** * * *** * ****
* * ** **** *** * * **** * ** ** * * (n%d==0)
* * ** * *** **** * * * * *** * *** * *** * **** *** *** *** * ** **** ***

   }
** **** ** *** *** ** * * * ** * * ** * ** *** * **** ***
* * * **** ** * ** ** *** ** ******* ***
* ** ** * * * *** ** * *** **** * * * * * * * *** * *
* * ** *** *** ** * * ** ** * ** *** *****
** * ******* * ** * * * ** * * ** ****** * ** *** ** *** (e==0)
* *** * * * * **** **** ***** ** *** *** ** * ** ** * *** * * * ** ** ** ** * * **
* *** * ** *** * ** *** * * ******** ****** ** * *
* * *** ** * * * ** * ** ** * * * *** * ** * ***** * * * * * * * * ** ");
* * ***** ** **** ***** * ** *********** * *** * * * * * * * ***
* * * * *** * ** **** * * *** * ** ** ** * ** * * * **** ** * *** *
**** *** * ** * * * * * ** * ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 * ****  ** **  *****       *  * ****  *** ***   * **   ** *** d;
    *   * ******* * *  **  ***   * *   **** *  * *    * * (d=2; d<n; d++)
 *  ** *   **** **** ** *   ***       *** * * *  ** ****
* ******* *     *** * **   * ** ***   ***  ******   *  *****  (n%d==0)
* * ** **  **   **     ***    * * ******   ** ** ** * * *  **   * *    **    ** 
   }
 * *      **  * *** *             *** ********  **  ** * **  ** * 
   *   ** *** **  **  ********* ** *** ** * * ** *
*   **   *  ***** **  *   * **  ** *  **** *  * *** ** ** **
* ********   *****  **  **  *  * ****   *   * **  * * 
*        *** *** *  * ** * ***  **   *** * ***  * ****  *  *** ****  *     (e==0)
* *****  *  ** *  * *  **   **** *   **  * *  *** *       ****  *   *  ****  *** ** *** *    * ** *  *** *
* * *    * * * *****  *   ***  *  **  * ** *  * **  *  ***  * * * *   *   * ***
 **** **   **** **  * * **  * *       * * * * *  * *     *   *   ** * * ****    ***** *** * **    *     *   ** * ****    ");
**** *  * ** *  *  * *  *****  ** * ***    **  * **   ** *    * * *    * *** ** ***   
***   *** * ** * *** * *   **  ** ***    * ** ** *  **       *   **  ***  ***   ** ** **  *  * * *  * ****  
   * * * **    * **  *** *   * *   *    ** *  *  * ** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
      *** *   *   *** *  *  *    Fn,t1=0,t2=1, n,input;
 *    ** ** ***  *    ******* *  ***   *   ** ** * 

     * ** * * *  ****** **** ** ** ***     n++)
*  ** * *  * * * ****     * **   
**     *     * *    **   * * *  ****   **  *  *   ****** = t1 + t2;
***** **** **    * ** * ** *****  * * ** * ***  * * ** ***  
   ** **** *   *   * **  **********  ** *  * **     ** 
    }

* *    * **** ***     ***** *    *** ** *   * **  *

***  ***   *  *   ***** *   * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
** **    *        * **     *** * Fn,t1=0,t2=1, n,input;
* ** * *  *** *   *     ** **   * **  * **   **  * *** * *  *    **

 ** *****   **    *  ***       * ***  * ***  * n++)
 * * * *****   *     *   * **  *
* *   ****  *  *** *   *   * * *  ***** ***       **  ** = t1 + t2;
  * ****    *      *     * **   **  ****  * *   * 
 *  * ** *   ** *     * *    ** *        *    ***  ** *
******* * *  *   **   * 

* *     *  *     * ** *  * * ***  *** **   ",Fn);

*** ******** * * * *    ** **  ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.115
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 8.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.4k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 12.1k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users