0 like 0 dislike
22.2k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 22.2k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** ** * ** * ** * * * * F0,F1,Fn,n,a;
* ** * ***** *** * * ** * *

* * ** ** * * *** * * ***** ** *** *** * * &a);

* * * **** ** ****** * * *
* * * * * * **** * * *
** * **** *** ** ** * ** * **** * * * * * * ***** ** *
** * * **** * * ** * ********* * ***** * ** ***
** * *** * * * * *** ** * *** * *
    }


* ***** * * *** ** *** * **** ** Fn);

* ** ** ** * ** * ** ** ** * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** **** ** *
int * * *
{
int * ** *
* ** *** * *** * * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
** * ** ** * ** **** ** * *** *
* * **** * ** * ** *** * ** * * = c0+c1;
* ** ** ** ****** * * * * * * * *** * = c1;
* ** *** ** ** * *** * * ** * ** ** ** * ** = cb;
* ** * * ***** * **
*** * * * **** *** ** ** * ** * * ****** *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ** * ** * **

int ** *
{

int ** * **
** * * * *** *

if(a==0) printf(0);
else if(a==1) **
else {
* *** * * * ****** ** * * * * * *****
** ******* ** * ****** ** ** * * **** *** = c0+c1;
******** * ** * * * *** * ******** *** *** * = c1;
** * ** * ******* ** * * ** ** *** ** = cb;
** * ** *
* *** * * * *** * *** ** * * * ***


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include *** *** * ** ** *

int main(void)
{

int * ** ***
***** * * * *

if(i==0) * * * ** ** **
else if(i==1) * * * ** * ** **** ** *
else {
* ** * * * ** *** ** ** ** ***
** ** * *** * * ** ****** **** ***** * ******* = f0+f1;
* * * *** **** *** ** * * * * *** * = f1;
** *** *** ********* * * ** * ** ****** = fn;
* * ** ** *** ** *****
* * * ** *** * **** ****
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ** *

int * ** *
{

int * *** **
* *** ** * * **** **

if(i==0) printf(0);
else if(i==1) **** *
else {
*** * ** * ** * * * * * ** ****
***** * ** * * * *** ** ** ***** * = f0+f1;
*** * * **** * ** ** ** *** ** *** * ** ** * = f1;
* * * ** * * * ** ** * * ***** * * * * * ** = fn;
* * * * ** * *
**** ** ** *** ********* *** ** ** * ** **** ** *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** **** ***** * * * ** ** **** ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** ** ** ** * **** *** * ******* **** d;
*** ** * * *** * * * ** * * ***** **** * * (d=2; d<n; d++)
* * *** ** * ** * ** * * *** * * * *
* * ** * ** ******* ** * ** ******** **** (n%d==0)
** ** ***** ** * * *** * * * * * ** *** * * ** * * * **

   }
* **** * ** * ** ** ** * * * * ** * ****
** * ** ** ** * * *** * *** * **
*** ** * ***** * * * ** ** * * * ** * *
* * ********** * * ***** *** * * ** * * **
** *** * ** * * * * ** * * *** ** ******** **** * * * * * * (e==0)
**** *** *** *** ** ***** * ** * * * * * ** * ** ** * *** ** ** ** ** ** ***
* * * ** *** * ** * ** *** ** ** *** ** *** * * *
******** ** *** * ** * * **** ** * ** ** **** ** ** ** * * * * * ** * *** ****** * ** * * ** ");
* **** * ** ****** * * ** *** *** * ** ********* * * **** **** *
* * * * * ** * **** *** * ** ** * * * * * *** ** *** *** * **
* * ** * *** **** * ** * ** *** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* *** ** *** **** ** ** * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** **** * ** * * * ** ** * d;
** * *** * * **** **** * * **** * ***** ** * (d=2; d<n; d++)
* * **** * ** ** **** * ** * ******* *
***** *** * ** * ***** * ** ******** * (n%d==0)
**** * * * * * ** ****** *** **** ** * * ** *** * **** * * * * * *

   }
* ** ** * *** * * ******** * * * **
***** *** * ** ** ** * ***** *** ** ** **** ****
*** ** * ** *** * * * *** * ** ** ** * *
** ** ***** ** * * * * * * *** ** ** **
* *** *** ** *** ** * * ** ** * *** ***** *** * * **** * *** *** ** * * * (e==0)
** *** ** ** ** ** ********* * * ** * **** *** ** ** ** ** ** ** * * *** *
* ** * * *** ** * * *** *** * **** ** ** * *** * * *** * *
** * * ** * * ** * * * * **** * ** ** ****** **** * ** * * ****** * * * ** * * ** ** ");
* * **** **** * *** * * * ** * ** ** ***** * *** * *** * ** ** * *
**** ** * * ** * **** * * * ** * ** * ****** ** ** ** * * * *** * * * ***
**** ** * * *** ** **** * * ** * **** *** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
*** ** *** * * * * * * ** * ****** * ** **** d;
*** * ** ** ******* * **** **** *** * * ** (d=2; d<n; d++)
* *** * * * *** * * ** ** *** ** * *** * *
* * *** * *** * * ** * **** * ** * * ***** (n%d==0)
* * **** *** * * * * *** ***** * * * ** * * ** * * * * * *
   }
** ******** ** * *** ** ***** * ** ** * ** * ** **
***** * *** * *** *** * * * * **
** * *** * * ***** ** * * ******* * * **
***** **** * **** * *** * * * *** *** *
********** * * ***** ***** ** ** * *** ** ******** ** * * * * ** *** (e==0)
*** ** *** ** *** ** **** * ** ** * ** *** * * * * * ** * * * ******** **** * * ** ***
* ** * * * ********* *** ** * ** * * * ***** *** *** **
** ** ****** * * * * * * ***** * * *** ** * * ** * ***** * * ** * *** ***** ** * * * ");
****** * * ** * * *** ***** * *** * ** ** ** ** * * * * ** * **
* * ** ** * * ****** ** ***** * ** * *** * * ** * ** * * * * * * *** * * * *
* ** * * * * ** * * ** ** ** * **** * * * ****
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ***** * * **** ** Fn,t1=0,t2=1, n,input;
* ***** * **** ***** ** * *** **** * * ******

** ** * * ** * * * * * ** n++)
** * **** * * ** * *
** * *** **** ** * * ** * *** * ** = t1 + t2;
* ** **** * ** * * * ***** ****** ** **** **** * ** *
* **** * * * * ** * * * * ** *** * ***** ** * *
    }

** *** *** * **** * ** * ** ** * **

** ******* * ***** *** * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * *** ** ** **** ** Fn,t1=0,t2=1, n,input;
* * * * *** * *** ** * * * ** ** ** * *

* ** * * * ** **** ** * * * * n++)
* * *** ** ** * ** **
* *** ** *** ** * ** *** ** * ** ** = t1 + t2;
*** ** *** * * ** * ** * * * **** * * * **
** * * * * * ** * *** ** ***** ***
* ** * ** * * * * **

* * * * * * ** ********* **** ***** * * ",Fn);

** ** * * ** ** * ** ** ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 14.2k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 26k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 11k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 17.8k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 18k views
12,783 questions
183,442 answers
172,219 comments
4,824 users