11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
14.4k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 14.4k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*****    **** ****** **   * * ** F0,F1,Fn,n,a;
 * *** ***** *   ***  *  * *** *  

    *    **      * ** **  * * * *    ** * **  *  ** &a);

      *** *   * *  ** * * **** *  **   * 
****  ** *      *     **     
 *   *    ** * *   * *** ** * ***** ****   ** ***  **  *  
*** **   ***     ** **  ** **   * *  **     * *  *** * * * 
 * ***  * *  *   ***  * *** **   ** **       ** ** ***    
    }


*  * * **    * *  *   *  *** ***   * **   **   *  Fn);

 **  *  * **    **     * **  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     *   ** **
int    * * 
{
int   *** **  *
  ****    ***  ***** *   **  *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
**   *  **  ******  ***   *** ***  *******  
 *   **     ** **** * * * *   *** * ***  ***  **  **** = c0+c1;
 *  *    ** * **  ** ***** * **       *  ***   *    = c1;
***  * **    *** ***  * *** ** * * ***   *  **  **   * = cb;
 * * **   * **  ****    
    ** ** * * * ***** *** **     ***    *** **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   * *** ********

int  *   **  
{

int    ** *****  
*** *   *     *** *** *  **    *

if(a==0) printf(0);
else if(a==1)    * 
else {
   * *  *   *** ** *** * ** *** ****    * *   *
**    * * * * **** *    *  * *** * *  **** *** * * *  * *   = c0+c1;
*   ** * *  ** ** **   *   **        *** *** *   * * *  * = c1;
   *    *** **  **   ***  * ****  ** * * **     *  *    = cb;
   * * *   ***  *   ****  *
    **  * *    *    *  **  **    *****   *   


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** *  * ** * 

int main(void)
{

int * ***   * 
 *  **  *   *    ** ***   *  

if(i==0) ** * * * *        **   *  
else if(i==1)   ****   *   **  
else {
  ***   **  * ** * ***   ****   *  * *     
* * **** ** *  *** ***  *  * **     * **** *   * ***  * *   *   = f0+f1;
* *****  *   * * ** *** *** *** *** * * ***  * * * = f1;
  **     *  *    **  **   ****  *   ***    **** * * **  ** = fn;
  *   * *  ****** ** **** **  * 
   *  ****  **** ***    * **  *** *    ***  *  *** 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  * **   *

int ** * **
{

int  *   * * * * 
*      ******        **      **  * 

if(i==0) printf(0);
else if(i==1)     * 
else {
 ** *** *  ** ****  *      *** ***  *  *  *
*    *  ** * **  *** ****** *  **   *****  *  *   **   *** = f0+f1;
*   **     *  * **  *  *** *  ** ** **     ** ***** * ** **  * = f1;
 *   * *** * ** *  *  *        *    ******     * ***  *  * = fn;
**** ***  **** ** *  ***** 
*  **  ***  * * * ** * * * * ** *** ** **  **
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * * * ** **** *** * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** * ** * * *** ****** * * *** *** * *** d;
** ** ** ** * ** *** * *** **** * *** *** (d=2; d<n; d++)
***** **** **** * * * ** * ****** * * **
*** * **** * * * ** * * * * * * * * (n%d==0)
* * **** *** ** * * * *** * * * * * *** ** ** **** * ** *

   }
* * * ** **** * * * * ** * * * **
* **** * * * * * ** **** *** ** * * *** *****
*** *** **** ** ** ** *** ** ***** ***** ******* * ***
* * **** * * ***** * * ** * ***** ******* ***
* * * ** ** ** ** ** ****** ** * * **** * * ** * ****** ****** (e==0)
** * * * ** *** ** * * ** * *** * * * *** * **** * ** * *** * *** * * * ** * ** * *
** **** ** * * * * * *** ** ** * **** * * **** **** * ** * ** * **
**** ** * * ** *** * * ** * * *** ** * **** * *** * ** ** ******** **** * * * * ");
* *** * * * * ***** * ***** * * ** * **** **** * * * **
* * * *** ** * * * * ** * *** * *** ** * ** * **** ** ** ** ** ****** ** ****** *
* ** ** * * *** * *** ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
**** ****** * * * * * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * * * * * * ** ** * * *** * ** * * * ***** ** d;
*** ** ** * ** ****** * * * * * * (d=2; d<n; d++)
**** * * *** * * **** ** * **** **** **** **
***** * **** **** * * * ** * *** * * ** * * * * ** (n%d==0)
* ** **** * * ** *** * * * * ** *** * * ***** *

   }
* * *** * * ** * * * * * ***** * ** * ** ** ** *
* **** * * ** **** * ** * ** * *** ** * *
** ** ** * *** ** *** * * * * * ** * * * **
** ** * * * * * * **** ** ** * *
* *** *** ** * * ******** * ** *** *** * ****** ** * **** * * *** (e==0)
** *** * * * * *** ** ** ** * ** *** * **** ** **** ** * *** * * * * * * ** *
** * * ** * ** * * ** * ***** * ** * * ** ***** ** ** * * * ** **
* **** * ** * ** * * * * ** **** ** ** * * * * * * * * ***** ** * ** *** * * *** * ** ** ");
**** **** * * * *** * *** * ** * * * * **** ** *** * * * ***
* ** *** * * ** * ** * **** ***** * ** * * * ** * * * ** *
* ** * * *** *** * ** * * * ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
***** **   *** ** *  *   *     * ***  *  **   ***     * **  * d;
* *   * * * * * ******** ***  ** * * ** *  *  *      **** (d=2; d<n; d++)
*****  ** **  *  *  ** * *  *   ********  * *****  **  
** **  * ** ** **** ** ** *    ***    ***    *  *   * *** (n%d==0)
  **** * * **** * *  ** *** * * ** * * **** **  ** * * *  *******        **    * **  **   
   }
* *    ** ** * **  ** **    *      *   ****    *         * 
        * *  *   **  **  ** * ***** **** *    ** *   * *** *** 
  *   **  * *** *  * * *    *  *      ****** *  ** *      * *
  ****  *   ** ** *    * ***  *     * ***     *   ***  *  
*  ** **   * ** *  *  * *** *    * ***** ** ****  *  ***  * *** *  * ***       * * (e==0)
******  ***  *  * * **** **  * ***   ** *  **  ***** *  *** **  ***** * **  * * **  ** **  ******** ***  ** ****
 * ***** *  **    ****  * *  ** *** ***** ** * *    ** *****  * * **  *   * **  *     
** *** *   * ** *****     **  ***** ** * * *  * * *    *    * *  * **** *  * * * **** **** **  ****  ** ***  *   *           *  ");
 ****   ****     * *    **         * ***   **   * **** *** *  **  *** *  *   **  *  **
  *  **** * * * *   * * *** * **  * ***    *  ** *** *****      *  *     *   *  *   ** ***** **** * *  *
**** **  * *** * *** ******** *   * * * *   *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 * *    *  **   ** *** *  ***     Fn,t1=0,t2=1, n,input;
    **  * ******   ***  * * *  **   **  **  * * *  * *  *

* * *  ** * **   *   *    **    ** n++)
 **    **  * ** *    * * *
** *    **      *  *****    * **  * *** ********  ** *** *    = t1 + t2;
   * * * ** ** * *    * ****    *  ***    * **** **   *  
*   * *  * *   ** * *** *******  **** ** ***  
    }

 **  *** *******      *   *** * ** *  * * 

*  **   ***  *** ** *  * *  ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 *** *  * ***  *  *   * **  *        Fn,t1=0,t2=1, n,input;
   ** *   **       ** ***  **  **    *** * * * * ** **       

** ****** *  *****  * * * ***   * * * * * *   n++)
 *     ***  * * * *     *  
   *  * *   ***** **   *  ** **  ** * * *        * = t1 + t2;
**   * ****** *** * * **  **     *     *    *   **** **  
**  ** * ****  *  ** **  *** ****** ** **  *    *   *
***  * *   * * * ** **  **  

*  ***  * * ** *** ** ** **** *   *  ",Fn);

 *  **  * * * **  * **    ****  * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.205
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 8.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.4k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 12.1k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users