11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
10.8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 10.8k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*****  *** * ** *   **  * *** F0,F1,Fn,n,a;
*    **      * * *  ** *  ** * ***

  ** * *  **  *   **  *  **             **   &a);

* ** **   *  *    ** * *  ***** **      *
***  *   ***   *  **  *** * *
* ** ****     ***** *   *** ***   **   *** * *  *    * *  * **
**  * * *   ** *   *       * * *       * * * * **  
*       * *   *  *** **   **** * *****    *   * * * * *  * *     *
    }


 ****  **** * ** ** ** *** *  *  ******* ***  Fn);

* ** ***   **  *****  ** ** ** ***   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    **** *  **    
int **   *
{
int * *  * * *  
 ** ** *** ****      ** **** 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*      ** ***      *    **   ****      *  ****
* **** *  *       *   **** * * *      *  **  * * *  = c0+c1;
 ** *   ******  *  * * ***       **   ** ***  ***    *  = c1;
*      * **  * **     ***     *** * **** **   * *  * * ***   * = cb;
** **   ***  *   * * * *  **   
     **  **  *  * *  *  ** **     ***** *** * ** **   
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *   **  * * 

int * * * * 
{

int *  * * * *  
** **** * * ** *    ** ** 

if(a==0) printf(0);
else if(a==1)   * * 
else {
***   * **  * *      *     * *** *** *  **
*  *  ** * *** * **  *  ** **** *  ***  * *****    ** ***     = c0+c1;
   * **** ** * *    *** ***  ***     **  * *  ******  = c1;
  * *** * *  *** **  ** *   * * ***  *   * * *   *  = cb;
**** **    ******* * **** *  * *
**  * ***   * ***    **   * *****   * * *** *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** ***  **** 

int main(void)
{

int ** *  * * **  
     * ****     *   ****  

if(i==0) *** ** ** *  *  * *  **
else if(i==1)  **   * * * **  *  *
else {
*   * **  **  **** ** ** ********** * *
  ****  ****    * **** *  ** *   ** *    *   *    ** ****    = f0+f1;
******* **    **** *    **   * *   *  *** * * *   * ** * = f1;
**     * **    * *  **** * **** **   ** ** *   ** *    *  *  = fn;
  *****  *  *  * **
 ****** ****** *****      *  **    ****   *** **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * * ** ** *** 

int **   
{

int * **** * * **
** ****   * ** * * * ** 

if(i==0) printf(0);
else if(i==1)  **
else {
    * ** ****  **  *  *  ****   *      * *   *  
 *    ******  *   **  *     ***   ** * ** * *  *  *** ****  ***   = f0+f1;
*  ****  *** *  *  **   **  *    **   **   *   * = f1;
****    * ******** *** *** *  * * **  *  * *    * **   *** * = fn;
* ** ** *  ***    ** **
 * ** ***** ****  *  * * ***** * *   * **  ** **  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** * * * * * * *** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ** *** ** * * * * *** ** *** * * *** ** d;
*** *** * ** * *** ********* * *** *** ** ** ** (d=2; d<n; d++)
** * * ** ** * *** * * * * ** *** * **** *
****** * ** * * **** ** ** *** ***** ** *** *** (n%d==0)
** * * *** ** *** * * * ** **** ** * *** * ** *** * **** ***** * ** *** *

   }
** * ***** ** * *** * * *** * ** ******* * *
* *** *** *** ** * *** * * *** ***
***** * * *** **** * * ** * *** *** * * * *
* ******* ** ** * ** * * **** *** ** ** ** ** *
***** * *** * ** ** * * ** ********* ** * * ** * * * *** ** *** * ** (e==0)
* * **** *** ** ***** * * *** * ** * * ** * * * **
* ** ** *** ** **** * * ***** ** *** * ***** ** * ******* *
* * * * ** * *** * * * * ********* ** * ** * *** * ** ** * * * ** *** ** * ** * * * *** **** * ");
* * ** **** * *** ** * *** ** *** * ** * *** ** * *** **** * **
**** * * * * ** * ** ** * * **** ** ** ** ** * ** * * * * * * * * * *
* *** **** * ** * ** * * * * ** ** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * * * * ** **** * ** ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** ** ** ** * ** * ***** *** * ** ** * ****** * d;
* ***** ** ** * *** *** * * * * (d=2; d<n; d++)
*** * ** * ** * ** *** * **** * *
** **** * *** * * * * *** ** * * * * (n%d==0)
* * *** ****** ******* * ******* ***** * ** * ** * * * * **

   }
** **** ** * * ** * *** * ** * *** * *** * ** * *
* * * * * * * * * ** **** *
* * ***** *** ** * * ** ** ** ** ** **
*** * *** * * * * ** * ** * *** * * *
** *** * * ** * ** ** ** ** * * * ** * * *** * ** ** *** (e==0)
* ** ** * * * *** *** ***** ** *** * * *** ** * ** ** ** ** ** **** * * ** ** * **
*** * ******* ** * ** ****** **** ****** ****** ** * * **** ** *** *
* **** * **** ** * **** * **** * ***** * * * ** ** * * * * * * ***** *** * * * * * ******* * * ");
* * * * * ** * * * ** * * * * ***** *** * **** ** * ******* *** ***
* * * ** *** * * * **** * * ***** ** * * *** **** * ** * * ** * * * *** ** *** ** ** *
******* * * * * * *** ** ***** * *** ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 *  ** *   **   * *  * ** * ***   ***      ***** *     *   * d;
  *  * **  * ** ***      *   *** *** ***  *  *  *** ** *     ***** (d=2; d<n; d++)
 ** *  *  ****     **   **     ** *  * **** **   *
  *  * *  *** *    *    * * *  *  ** *  * ***          ***** (n%d==0)
 * *** *     ***** *   *  * * ****** ****** **    ** ***** ** *  **** ****    *
   }
** ** **     *****  *   *** **     *   *   *** *****   *  *** *
*** *** * ***  **   ******* **** ** * * *** ** * *
 * *   *  *  **** ***   * *   * *       ** * *  *** *  * *
* **** *  *          * *    *  *   *  * * ** * * **   * *
    * ** ***  *   *** *** * ** *  **** **  * *   * * **   *  * * * * ** **   *  ***    (e==0)
   *** ** ** **** ***    *   **   ****  **  *** **  **   * ** * ***** *  * **   **    **   **  **    ** * ****  
*** *     *** *   ***  * * ** ** *  *** ** * ** **  *   ** * *  **     ****  ***
 **   *  * * ** *     * *****  * ** *     *    **  *  ** *** **  *****  * ** *   **        **  *  **  ** ***  *     ****    ");
   *     *** *  * *     *  *  ***  *****     ***    * ** *   *     **** **  **** 
* ** **         ****  **** * ** ***        **  * * *  ** *   **  **** *    * ** *****  *  ***** *** *** ***
  *  *   *   *  *  **   ** *  ***    *  **   *  * * *     * **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*  *** * * *  *   *  ** * * * * Fn,t1=0,t2=1, n,input;
   * ** * **    *** ***** ***  ***  **** **  *****    *** 

        *  *****  * *     *  *** * * ** * n++)
  ** *          *  * ***
   ****   *  * * **  **    *    * ***   **   = t1 + t2;
 * ****   *   ***** * * * **** *   ** *  **     * **
* * ** **   ***  ** **  *     ***    *  * *  *** **  *  *  *  * **
    }

** *       ***    ***  *  *****  ** **  * *   **   

 *    *** ***  **** *  *** **  ***    0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* *  *   **  *    ***   * ** *  * Fn,t1=0,t2=1, n,input;
       ** **** * ** * * ***   *  **      * *  *  * ********  

* ***  *   **     * *  * **      *  * * *  ** * n++)
  ** *     ****   *  *   **  
  *****  **  * ***   * *  * ** * * *** *  * * *** ** ** = t1 + t2;
   *   * **   *   * **** ** ***   * **   ***  ** 
*  * *  *  **** *  * * *  * ** **  *  * **** ***     *** * *
***   *  *    *** * ****

***  ***     *    ** ***** ***   ***   *  * ",Fn);

***     * * *******      *      0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.4
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 6.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.3k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.1k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users