11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
9.5k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 9.5k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*     *  ****** *** * ** *  * F0,F1,Fn,n,a;
*  ** * *      *  *  * ***  **    *

*        *** * **   ** ***   *** *  **   &a);

 ** ** * **    * **     *   **    * *  * ** *   
   *    *  * * *** ** *   
  ****  **   **    **  ***  ****  ******  **
 * ** *****   ** * * ****  ***  *  **      **    ***   **     
    *  ***  **   * ** *  ** * ***     ** **  *  ******     * 
    }


 *   *  ***  ** *   ** **** ***    * ***  ***   Fn);

* *  **  * *      **  **   * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **** ** ** 
int *  *  * 
{
int ****   * * 
 ** ****     * ***** ** *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
**** **** * ****  * *   * ********  **    *     * 
* *  * *   *  **** * * * *  **   **  ***  ** *  *  *  ****** = c0+c1;
    *** * * *  *    **   * ***** *   * **   * ** ** * ** = c1;
*    ** * *   ***** *      ******* * * *  *   *  * **  = cb;
   *   ****** *  ** * ** * ** 
*****  **  *****    * * *    **  *    *    *  ***
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **  **  *  ***

int  * ** 
{

int * * * ** **
 *  *  ***   ***    * 

if(a==0) printf(0);
else if(a==1) *  ** * 
else {
* * **      **  **** ** * ** *  *** *  * ** 
***    *  ***  ** ** * * *  ** *  *****  *    *  *** * * **  = c0+c1;
** ** ** * * *     ** * * **  *  *  **   *** * ** * = c1;
* **    ** ********  ***   ** ******   *  * ***** *  **   *  = cb;
  * **  *  ********* **   *** 
 *     *  **** ** **  *     **    *    *   ***  


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  **  *   *  * *

int main(void)
{

int   *     *  *
** *    *** * **  * *    **

if(i==0)  *  ** ** *      *   ** 
else if(i==1)    *** *  *    * ** * 
else {
*** * * ***  ******      *    *  * *   *  
   **  *  * *** * **  *  * ** * **    * ****  * *   *  = f0+f1;
** *** *   *   *** ***     ***** * *  **   ** * *  *  = f1;
***** ****   *  * *       **** *    *  * *  * ** **  = fn;
* * * ** *  **    **    ** *
 ** * * ***** *    *         *** *     * **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *   *  ******

int   * 
{

int ** * *     *  
          **     *    ****   

if(i==0) printf(0);
else if(i==1) *  * *  
else {
   *  * * *  ** ** **   ** * ****   *  ** ** 
  *    * ***   **  **  ** *    **  * ** **  ** *  **      = f0+f1;
       *    *     * ****   ****** *     *** **  **  *  *   = f1;
 * *     * *  *   * ****       * ********** *  * *   = fn;
****   **************  * ***  *
 *   ***   * *   ** * **    ****   *  **  * *  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * * *** * ** ** * ** ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
**** * *** * * ** *** ** * * *** ** ****** *** * * d;
***** ** *** * ** * * *** * * *** * * ** * ** (d=2; d<n; d++)
** * * ** ** * ** * **** * ******* * **** ***
* ******* *** * * ** *** * * ** ***** * (n%d==0)
* ** *** * *** ***** ** ***** * ***** * * * *** * * * ***** **

   }
* * **** ** *** * * * * ** * ** **** * *
*** *** ***** * * ****** * * ** *** **** * ** *
* *** ** * *** ** * * * * **** *** ***
* * * * ******* * * ***** ***** ***** * ** ***
* ** **** * * *** * *** * * * * ** ** *** * *** * ** * * (e==0)
*** * ** ** ** * * ***** * * * ** ** **** * *** * * *** * *** ****** * *** **
** * * **** ** *** ** * ** *** * * * * ** ** *** * * * * * ****
** * * ** ** ** * * ** **** * ** * ***** ** * ** ** ** * * ** * * ** * * ******* * * * *** ");
** ** * * *** **** **** **** * * ** * * ** ***** *
* * * * ** * ** *** * *** * * * * * * ** ** ** *** *** ***** ** * * ***** *
* *** ** * * ** ** * ** * * ** ** * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** * * * * * ***** * *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * * ** *** * * ****** *** ***** ** *** * **** ** *** * d;
*** ** ** * * ** * ** * * ** ***** (d=2; d<n; d++)
** *** ** * * ** ***** * * * *
** * *** * ** * * * *** * ***** * *** ** (n%d==0)
* **** *** * * * ** * * * * * ********** ** **** * * * ** ***

   }
** ** * * ** * ** ******* ***** * ** * * * * ** * **
* ** ** ** * * ** * *** * * * ** * * * ****
* ** * *** * ** * ***** ** * * ***** * * ** * ** * * ** **
* ** * * *** ** *** **** * * * * **
** * **** * ** * * *** ** *** ***** *** * * *** ** * ** ** * * (e==0)
*** ** ***** * ***** * * **** ** *** ** * * * *** ** *** *** ** * *****
** * *** ** ****** * **** * **** * **** * **** * * *** * * ** **
*** * ** * * * * * ** * * * *** ** * ** * * ** *** * ** **** ** * * * * * *** ** ******** * ** ");
* *** * **** * *** ** * * * ** *** *** * * *** * * ** * ** * * ***
** * * * ** * * ** ** * ** * ** * * * * ***** ** * ** *** * ** ** ** *
** * ****** * * * ***** * ***** * ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
**  * **    * ** ** * *** ** ** ** ** *     ***   *  d;
   **        **  ***   * *   *      ** *   **  ** *  **   ** **  (d=2; d<n; d++)
   *  *   *  *  ***       * ****** * ** *  ** *******
 * *  ***  * ***    * ****** ***  **   *   * **   **    (n%d==0)
   ** *  ***  ** **** * ** * **   *  **      ** *** *****  ****   *   **   ****** * *** 
   }
 **  **   **** *     ******   ***** ** ***  *  *** * *** * ****   * 
  *   **    * *** **   *   **** *   *** ** * ** ***   
 **  ***    *** ****** **** **** * *  * *****  ** ***  
*  **  *  **** ******* **  *  **   ** * *   *** **  *    
* ****** *  * *   *  * * **   * *  *  * **  *   *  ****** * * * ***  *****  (e==0)
*   *  * *       ** *   * ** **   ***   *** *   *    **   ***** ****  *  **   **** **   ****  **  *** * **    
   *  ***    ***   *** *    **   *** * *** **  *****   ** **    **     * ** ****   * 
*   * * *** *   * * *  ****  * * * *  *  ***    ***** *** *** ******* **** **   ** **  ** ** *  *    *   *   *     *  * * ");
**  *****     * * * *** **   **    *  * ** *** * *   **      * *     ****** * * **  * **
*******    **  **   *** *  * ***   * * * **    ** ***** *    * * ** **     **** *    **    **   **  *  *  ***  
 *** *  *  *** **   **   ***** * ** * ***  **  
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 *  *   *********   *** ***   Fn,t1=0,t2=1, n,input;
   ** *  * *** *     *   *** *    ***  ****   ** * **

  * ***   *  **  **  *     *  *   ** * * *   * n++)
 ** * * *** ******* *   *** ** 
**    * **** * * * ****   ******   **     * * *  ** *   = t1 + t2;
 ** ****   ** * ****     * * ***   * * * * * **  *
    * * ****** * ***** ** * ** *** * * *  * ****  **   ** 
    }

****  *  * * *  ** * **** ** *    ***** ***** 

  * **** ** * ***    *  ** **  0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* * * **  **  * * ***  * *   Fn,t1=0,t2=1, n,input;
 *****  * * *  * * * **   **   *  ** ****** *  ** **  ** * 

* ** **  **  *** **   * ** ** * *  ****   *   * *  n++)
*  * **   *  ** *  * *    *  
   *** *** * * * *** ** *    * * **  * *  *** * ******* *  = t1 + t2;
 **   * **   * * ** **  *     ** * *  * ** ***  *** **  
*  *****  ** ***  * *** ** *  **  ** **   **  **    * **
   *        * *   *  *******   *

*  *** *  *    *  *  * ***    **  *  *   ",Fn);

 ** *  * * *  *    ****    * ****  * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.129
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.8k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 4.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 8k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users