11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
18.3k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 18.3k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
**** ** *** **  *** **  F0,F1,Fn,n,a;
  *      *** ***  **  ** * ***  

  **   * * *** * *     ** * * * * *** ** **   *  &a);

    *  * **    *  * **  ** ** *** **
 * **    *  * *    *** *  ***
 **  ***  *     *  * * **   *  ***  *** **  **** *    ***   
   * **    * ***   *   *   *  * ***    * *** *   **    
**  *  ** * * *  **     *  **   ***** ** ** *  ***  * *  *
    }


*** ********  * *   *   *  ****** *** **  *   Fn);

**     ***     *  * **      ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **   *** * * 
int  ** * 
{
int    *  *******
 * ******* *** *  ****  *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* *   ****   *    ***  * * ** ***  ***    * *
 **   ******* *   ** *   *  *   *** * * * *  ***   *  **  = c0+c1;
    ** **** * *  *    * *  ****   **** ***  **   ** *  = c1;
  *****     ** * **     * *   ** **  * **   *    * = cb;
* *** ** ** *       *  * ***    * 
**  *  * *****   * * * *  ** *   **  * *   *  
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    ***  **  **   

int * **** 
{

int   *  * ** *
*  * *    **  * ***** * * *

if(a==0) printf(0);
else if(a==1) ****   
else {
* *   *  ****    **  * ** ** *  *  *    *   
   ****     **     ****  *** ** * * ** ** *   * ** *  * **  * = c0+c1;
**** ** * **  *** ** * **      *  ******* **** = c1;
* ** * ** **   * * *        * *  *   * * **   **** *  = cb;
   *** * ** * * ** ** ** ** *
 ** *  * *  ** *  *   *****  * **  *** *   **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *   ***  

int main(void)
{

int     *  * **
  *  *     * * ***  **** * **

if(i==0)    *  ****    *** *
else if(i==1) * * * ****  * ***   **
else {
*   ** ** **** * *    *** ** ***     ** 
***   *** *   *  *   **   *   *  ** ** * * *  ***    * ** = f0+f1;
 **   ** ******      **** ** **** *   ****  *  *   **  = f1;
*     *  ***    * * * *  * **  ** *     *      *   = fn;
***   *  **     ******  
 *****     ***  ****    ****    ******* * *   * *   
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *******     *

int   * * **
{

int * ***   ** *
* *        ** *  **  ** ** * **

if(i==0) printf(0);
else if(i==1)  * * * 
else {
 **    *****   ***  ***   ** **  **** * ** * 
  * *  * * ** **** ****** ******   ** * ** *    * **   **** = f0+f1;
 ** ******* **    *  *   *  *******   **  *  **** ** = f1;
 *  ** *  ****  * * *  *  *   * ** * *  *  *  **  * *****  * = fn;
*** * ***   ** *** *  *** *  
*  *  *   **   ***** * * *    ****   ***  ***    
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** * * * * ** * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ** * * ** * ** * ***** * ******** * * d;
* ** ** *** ** * *** ** *** * ** * * *** * ** * (d=2; d<n; d++)
** * * *** * *** * * * **** ** *
* **** * ** * * *** ** ** * * *** ** * ** (n%d==0)
* ** * * * **** * * *** ** * ** ****** ** * ** ** ** * *

   }
***** * * * * ** * ** * ** ********* ** * ** ** *
* ** *** * * ***** ** *** **
* * * * * * * * ***** * ** ** ** ** **** *** *
** * * ** **** * * *** ** * ** *
* *** * ** *** * ****** * *** ** ** * * * * * * * ** ** (e==0)
** ** ** ** * **** ** * * * * * *** ***** * *** *** * * * ** ** * ** ** **** * * *** *
* * ** ** ** * ** ** * * * * * * *** ** *** * ** * * * * * *
*** * * ** * * * * ** * * * *** ** * * ** ** ** * ** * *** * * **** ** * ");
** ** * ** ** * ** ***** *** ** ** ** ********* * * ** * *** * *
* ***** ** * **** * ***** * * * * ** ** * **** * * * * **** * * * *
* ***** **** * * **** * ** * * * ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** ** ******* ** * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * ***** * * * ** * ** ** * * * ** * ** * d;
** * ** * * * * * * * * * * * (d=2; d<n; d++)
** * * *** *** *** ** * ** ** * * **
* ***** ***** * ** ** *** * ** * * * * ** (n%d==0)
* * ** * *** **** ** * * * * ** * * ****** * **** * ** * ***

   }
* * **** * **** * ** * * **** * * * * ***** * **
* ** * * * * * * ** ******** ** * ** *
** *** * ** * * ** ** ********* **** *** ***
* * *** ** * ** * ** * ** * * **** * **
* **** ***** ******** *** * ** * *** ******* * * * ** * * (e==0)
*** ** ** * *** ***** ** * *** ** ** * ** * *** ** ****** * ** **** ******* * *** *
*** ** ** * ** * * * * * *** * * *** * * * * * ***** * *
* ** **** * ** * * * * * ** ** * ***** *** **** ****** ** *** ** ** ******** * *** * * ******* ");
** *** * * * ** ******* **** ** * * **** ** * * * ** * * * * ***** ***
* ** * * ** * * ** * * ** **** * * *** * * **** *** * ***** * ** * * ** * * * * **
* *** ** * ** ** * ** ** * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
**    **  * **  * *    ** **   **   **** *  * ***     * * ** d;
**  ** ** **  ****  ** **       ** *   * * * *    **  * (d=2; d<n; d++)
*  *  **  *  *     * * * ** *   * *  **  *** * ***   * **
  *      *     *   *****  * * *** *  **  *** *** *  (n%d==0)
        ***  *  *    *  *  * **  ** *****        **    *****   * **** *  * * ** * *  
   }
    *  * *   *******  *** ****** ***** * * * *  * *  *   ** * 
  * * *  * **   *  *  * * *  * *** ***   * *   ***  **   *
  ***  **  *  *     * *  ** * * **  * ** * ****   *
*  *  ** *  ** * * **   * ******** * **  **  **  *      **
 * * ******* *   ** **   ****  * *** * *   ** **   *  **   ** ** **  * ** *  **** (e==0)
 ** *** **  ** *   * ** *    *** *   ** * **    ** ** * **** *   *  * *  *  * **  **  ***  * *  ******    **
*** ** ****  *       *       ** * ***      *  ***  ***  ***   *   **  ***  *  * *  * 
 *  * *  * *  ** *    *   **  *** *** **  ****  **        * *** **    *******   * **      *   *    * *   ***    ");
** *  *** *  * ****  *  **  ********  ****   ** *** *    *** **   ***  * * * *  
*  * **    * *   *  * *** **** * *  * ** ****** **  ** ** *  **     * ***  * ***  *  *  **  ***  *** 
    *   ** ** *  ***   * **     *  *    * ** *** ** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 ** * * * *  *   **   ** ** * Fn,t1=0,t2=1, n,input;
* ** * *  ****   *  *  * *  *       *  *** * * * *** * * *  *  * *   

**   ** *  ** *   *** **      **  *   n++)
 **** ** *   *** * * * *  **  
 ***** *** ** *  ** *** *        *     *  ** ** ****  ** = t1 + t2;
 **  * *** * **    **      *   ** **  ** ***   * ****      **
*  * **    * * *    ** * *   **  *   *  ******** **   ** 
    }

 **** **** **   *   ** ** ****     * ** * *     

*** **      **     *** *         ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*  * ****       **** * ** *  *  * Fn,t1=0,t2=1, n,input;
**** *  *   *****     *  ***  *   ** ** *** *  ** * *

 ** ** ***  *** * * * * *  ***  **      **** n++)
**** **  **  ******* *  * *
   **  ** * *  ** ** **  *  * * *  ** *  *     * *      = t1 + t2;
**    * *   * *  * * ** ** ** *    **  * *     * * *   *** * *     
  * * *     ******    * *** *** *  **    **   * **  * 
****     *** ***     ** * **

*  * * * ** ** ***     *      ***** ",Fn);

** * *   **  **  *      ** *    0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.97
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 12k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 21.7k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 15k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 14.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users