0 like 0 dislike
9.5k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 9.5k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* ***** * ** ******* *** ** F0,F1,Fn,n,a;
* **** ***** * * * ** *** *

* * * *** * * ** * * **** * * * ** * * &a);

** * *** *** ***** * * ***
** * * * * * ** * ** *
*** * * * ** ** * ** **** * * * * *** * ** *** *
** * * * * ******* * *** * * * ** ****** * * *** ***
**** * * * * ** ** *** * * ** ** * ** ** * *
    }


** * ** ******** * *** ** * ** * * Fn);

**** ** * ** * * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **** * * *
int ***** **
{
int **** * **
*** * ** ** *** ** **
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*** * **** * * * ******* * * * **
* ** * ** ** ** ** ** * * * * * ***** * * = c0+c1;
* * * * ** * ** **** ** * ****** * ** *** * ** * = c1;
* ***** * * ****** * * ** ** ** * ** ** * * * = cb;
** ***** *** * ***
** * ***** ** * * ** ** * * ** ****
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * **

int **
{

int *** *
** *** * * *** **** * *

if(a==0) printf(0);
else if(a==1) * *
else {
* * * *** * * * ******** *** *
******* ** ** ** ******* * **** **** * * *** = c0+c1;
* * ** *** * * *** * **** * * * = c1;
* **** ** * *** *** * **** * *** *** = cb;
* * *** * * * *****
*** * * *** ** *** ** * * ** ** ** *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ** * ** *

int main(void)
{

int * ***
** *** * * ** *** **

if(i==0) * * ** **** *
else if(i==1) ****** ** **
else {
*** *** ****** *** * * * * ** * *
* ** ** * *** *** ** * * *** * ** * ** ** = f0+f1;
***** * * **** * ** * **** *** * ** * *** ** * = f1;
* * **** ** * * * ** ***** * *** * ** = fn;
** * ** * * *** **
******* *** *** * **** * *** ** * * * **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** *

int **
{

int * ** * * ** *
* **** ** * * ** * **

if(i==0) printf(0);
else if(i==1) ** *** *
else {
** * ** * * ** * ** **
**** **** * * * * *** *** ** * * ** *** ** *** = f0+f1;
* ** * * ** ******* **** **** * * ** ***** *** = f1;
** *** **** * * * * * * *** * * ****** * = fn;
** ** **** *** *** * ****
** * ***** **** * * * ** **** **** **
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * *** ** *** ** *** *** *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * * * * * ** * ** * * ** **** *** * * d;
** **** * * ** * * * ***** *** ******* ******** * (d=2; d<n; d++)
* * * ** * * ** * * *** ** * *** * *** *****
* * * *** ***** **** * ** * ** * ***** *** ** (n%d==0)
** ***** * ** ** *** * ***** ** ** **** * * ** * * ** ** ****** ******

   }
** *** *** * *** * * * * * ** *** * * ** ** *
* **** **** ***** * * * **** * ***
** ** ** *** * *** ** * ** * * * * * * *
* * * * * * * ** * *** *** * * **
* * *** **** ** ** * * *** * * ** * * * * *** *** * * * * * * * * (e==0)
* * * * ** ** * ** ** ****** ****** ** *** *** ** * ** * * * *
*** ** *** ***** * *** * * * **** ** * ** * ** ** * * * * *** ** * *
** ** * ** * * * ** * ** ** * ** * ** * *** * ** **** *** *** *** *** * ** ** *** ");
** * * ********* ** *** ** * ** ** * * * ** * * ** *** **
* ** * ***** ** ********* ** ** ** * ***** ** * * ***** ** * * ** * *** *** * ** ** ** *
*** * ***** ** * *** ** ** * *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** *** * * *** * ***** ** **** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** * * * * * ***** * * * * *** ** * **** * d;
***** ** ** *** **** * **** * **** * * *** ** ** (d=2; d<n; d++)
*** * ** * * * **** * * ** * ** **** **
* **** * * * * ** **** * ** **** * * (n%d==0)
* * * ***** ** ** *** * ** * ** ** **** * * * * ****** **

   }
*** * * ** ** ** * * * * * * * *** ****** * ***** * * ** * *
* * * *** ********* ** ** * ********* ** ** ** ** **
***** ** * * ** * * ** * * * * ** ** *
* * * * ** ** ***** **** ** * * ** ** **
* **** * * * * * ** * ** * * * * ***** *** ** ** **** * * (e==0)
* * *** * * * * * ** **** * ****** ** *** * ** * * * * ** *** * * ** *** ***** ** **
* * * * ***** *** * *** ***** * * ** * **** ** * * ****
** ** * ** *** * ** * ** ** * ** ** * * * **** * * * * **** ** * * * ** * * ** * * ** * ** ** ");
*** * * * * * ** * * ** * * * ** * ***** ** ** **** ** * * * ***
*** * *** * ** * ** * *** * ** * * ** ******* ** ** * *** * ****** *** ** *
**** * * ** * *** ****** * ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
***** ** ***** ** ***** * ** * * * ** * ** * * * d;
** * *** * * ** * **** * * * * * ****** *** *** ** (d=2; d<n; d++)
* * *** * *** ** * * * ** * ****** **
* * ** * ** * * ** * * * *** ***** *** * (n%d==0)
* * * * * * **** * ** *** ** ** * * * ** * * ** * * ** ** *
   }
* * * * * * ** * ** * ** ** *** ** * ***
***** * * * ** ****** ** ** ***** ** * *
* ** *** *** ** * * * * ** * **** * **
** ** ** ** * **** ** *** * ** * ** *
**** * ** ** ** * *** ** ** * *** *** ** * * *** (e==0)
*** * *** * ** ****** ** ** * * * **** * * *** * ** * *** *** * * * ***** ** ** ***
* * * ** *** * **** * * * ** * * ** **** * ** ** * ********* **
* ******* * ** * ** * * * * **** * * * *** * **** ** *** ** *** * * * * ***** **** *** * * * **** *** ** ");
* ** * *** *** ** * * **** ** * ********** * **** ****** **** *
*** ** *** * **** * * * * ** * * ** ** * * ** ** ** ** * * * ** *
* * * ********** * ***** * ** *** **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** ** *** * **** ** * * Fn,t1=0,t2=1, n,input;
* ** *** ** * * * * * * * ** * * * * *

*** **** * **** * ** *** ** * n++)
** ** * ** * ***** *** *
* ** ** * ***** ******** **** * ** * ** * * = t1 + t2;
*** *** *** ** * **** **** *** * * * * *** * * *
** * ** * * * * ****** *** ****** * * *
    }

** ***** * * * ** * ** * * * *** **

*** ** ** ** **** *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** ** * ** *** * * * * Fn,t1=0,t2=1, n,input;
* * ** *** * * *** ******* * ******** * **** * * **

* *** * * * * *** ** ** * * n++)
* **** **** ** * ******** *
* ****** * ** *** *** * * * ** * ****** **** = t1 + t2;
* * *** ** * * ** * *** * * ** ***
*** *** * * **** * *** * ***** * * ** * **
** * ** * *** * * **** *

** ** **** ** ** * ** * * ** ",Fn);

*** **** ** * ** ***** * **** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.140
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 4.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 8k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users