0 like 0 dislike
21.8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 21.8k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
***** *** **** F0,F1,Fn,n,a;
* * * * ***** ** *** *

** *** ** *** ** * * * * **** *** * &a);

* ** * * * * *** * * **** * *
*** * * * **** ** *
* ****** * *** * ****** ** *** ** * **** * **** * *
** * * * * * * ****** * * *** ***** ** * * ****
** *** * * **** ***** ** * ** ** **
    }


***** * * * * *** * **** * * * Fn);

** ** *** ***** ** * * **** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * * *
int ** ***
{
int * ** * * *
***** * * *** * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
** ** * *** ** * * * ******** *
* ** ** ** * ******** ******* ** ***** ******** = c0+c1;
* *** ** * *** * ** * ****** ** *** ***** * *** *** = c1;
** ***** * * ** *** ****** * **** ** ** * = cb;
* * *** ***** ***
** * * * * *** * ** * *** ** * * * * ** *** *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ** * ** **

int * *
{

int * ** ** *
*** * * * ** ** ** *

if(a==0) printf(0);
else if(a==1) ***
else {
***** *** *** * * ** * * *** *** *
* * *** * ****** **** * * ***** * ** = c0+c1;
* ** **** ** ** * ** ** * ** ***** * ** * * = c1;
* ** * ** ** * ** * ** **** **** *** * * * = cb;
** ** ** ** * * *** *********
* ** * * * * * * ** *** * ** * * * **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * ** **** * *

int main(void)
{

int * * **
* * *** * * * ** * * *

if(i==0) ** *** ** **** ** *
else if(i==1) * ** *** * * **
else {
*** * * * * * * * ** *
** ** ** * ** ** * **** ** *** * = f0+f1;
*** * **** * ** * * * ***** ** * * **** *** = f1;
**** ******** **** ** * * *** ** ** * **** = fn;
*** * * * * * ** * ****
** * ** ** *** **** **** ** *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** *

int * *
{

int * * * ** * *
* * ** ** * *

if(i==0) printf(0);
else if(i==1) * **
else {
** * ** **** *** ** * * *** *** * *
** * ** ** ** *** * ** * * * * ** * * * * * * = f0+f1;
**** * ** ** ** * ** * * * * ** ** * ** = f1;
*** * ** * ** * ** * ** * *** * * ** * = fn;
****** **** **** *
** * *** * * ** *** ** *****
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * ***** ** * * **** * * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** * * * * * * * ** **** ** * ** ** * ** d;
* * * * * ** * **** ** * *** * * * ** (d=2; d<n; d++)
* ** *** * **** * *** * ** ** **** * *
*** ***** * ** ** *** * *** *** ** **** ** (n%d==0)
*** * ** ** * ** ** * * * ** * * * * *** * ** ** * *** * *

   }
** ** *** * * ** ******* * * *** * * **** * * ** *
* * * ** ** * ** * ********** * ** *** **** *
* * * **** * ** * * * ** * ***** ** **** * * *
*** * ** *** ***** *** ** * * *** ** *
** * ******* * * * * * * * * ** * * ** ** *** * * ** (e==0)
** * * ** * * * *** ** ** *** * * ** ** ** * * ** * * * * *** * *** * *** * **
**** * * *** * ** ** ** * * ** ** * * **** * *** * * ** * * * * * * *
******* * ** * * ** * * *** * * * * ***** * * ** *** ** ** **** * * ***** ** * * * * * ** ** ** ** ** ");
** * *** * *** ** * **** ** * ****** *** * ** * * ** * * ** *
** * ** ***** * **** * * ***** ** * ** *** ** *** * * ** * **** ****** *** ***
* ***** ** ** **** * ** * * ** * ***** * ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** ** * * ** *** * * ********** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** * ** * ** ** *** ** * **** * ** **** * * * * d;
* *** ******** *** ** * * ***** ** * * ** * * ** (d=2; d<n; d++)
** * ** * * ****** ** *** ** ** * * *** *
* * * ** ************** * ** * *** ****** * ** * **** (n%d==0)
* * *** ** * * * * *** * *** ** * * ****** * * **** *** ***** ***

   }
* *** **** ** *** ********** ***** * **** * *** ** *
**** * *** * ****** * ** ** *** ******* ** **
* * ** * * * * ** ** *** * ** *** * *
* * * **** ** * ** * * * * * * ** ****
* ** * * ** ** ** **** *** ** ** *** **** * ** ***** *** ** ****** ****** * * (e==0)
** *** * **** ** ** * * * ****** *** * * *** ** * *** ** * ** * *** ** *** ** * * ** *
******** * ***** * *** * **** ******* ** * * ** * * * * * ** **
** **** ** *** *** ** * *** ** ********** *** ** * *** ** * * * ** *** *** * * * ** ** * ");
** ** * * **** * ******** * ** * * ** ** * *** ** * * * * *
** ** ** * * *** ** ** ** * * * *** * * * ** * *** ******* ** * * * ****
* ** * *** * * *** ** **** * ** * * *******

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* *** * * * * * * * ** **** * d;
* * * ** * * ** ** **** * * ** * ** * * * * ** * (d=2; d<n; d++)
* * *** * ** ** ***** * *** *** * ** ** ****
*** * *** * * * **** * * ** ****** *** (n%d==0)
* ** * * **** ** **** * *** * ** ** * ** ***** * ** * * ** * * ***
   }
* ** ** ** ** * *** ** * ** * * ** * *** * ** * * ***
* ** *** * * ** **** * * * **** * ** **
*** ** * * * * * *** *** * ** * * * **
* **** ** * ** * * * ** **** *** *** * ** *
* * * **** * * ** ** ** **** * * * * * *** * * *** ** * ** ** *** (e==0)
** ** * ******* * * ** ** ** * * *** ** **** ** ** *** ** * *** *** ****** * * * * *
*** * ** *** * *** * * ** * ** *** * * * * * * ** ** *** * **
* ***** * * * * **** * ***** *** * * * * * ** **** ** * *** * ** ** * ** ******** ** *** ");
** ***** * **** ***** **** * *** *** *** * ***** ** * *
* ** *** ** **** ** *** *** ********** ** *** *** * * ** ** ** **** * *** *** * **
* * *** *** * ** * *** * ** * ** * ** *** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * * * ** ** * ** Fn,t1=0,t2=1, n,input;
** *** **** * * * *** ** * ** * * ** *

** * *** **** * ** * *** * * n++)
**** **** * *** ** * * ****
* * * * ** ** * ** * ** * * * * * *** * * = t1 + t2;
** *** *** *** * * *** * * * *** ** **** ** *
*** ** * * *** * ****** * ** * ** * **
    }

* ***** * *** * * * ** * ** * * **** *

* ** * * *** ** ** ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * ******* * ** * Fn,t1=0,t2=1, n,input;
* *** * ** *** *** ** * * * ** *** * ** *

* * ** *** * * * *** ** * * n++)
* *** *** ** ** ***
*** ***** *** * **** * ***** * * * * * ** * = t1 + t2;
*** *** * * ** ** * * * * ** ** ***** ** ** ******
*** * ** ** * *** ** * * * * * * * * ** * *
***** **

* * * ***** * ** * ** **** *** ",Fn);

* ** * *** ******** *** * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 14k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 25.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 17.6k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 17.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users