11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
13.2k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 13.2k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
  * *    **   *  * *  * *** * ** * F0,F1,Fn,n,a;
 ** *    ** **   * * **** *  *** *****

  ** **  *  ***    * * **** **  ***  *** *****   &a);

 * **  *****  ***   *  ** * **    ** *
 *** *  *     *  *****
* *  ***    **  **** * ***   ****  *   * *  ***   ** *      
***  ***** ** *** * **  ****** * ****  * * ** *   * **   *
* **        **  ** *  *** *** * * **** *    ** **   ****
    }


* ****** ****     * * ******  ***    **   * *   Fn);

*  *    * *     * **  *   **  * ***   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *     * **** **
int * **    
{
int      ****  
 **********  ** * ****   * * 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*****   **   * ** *  * * **** *   **  ** 
   ****   *** *   * *******       * **    *  ** * ** ** = c0+c1;
 **   **  **     *** **   **** *** * *   ****  ***   = c1;
* *  ** ****  **** *    * *    ** * ** *** *** ****** ****  = cb;
 **** *  ** *  *** *** *  *****
*  * ** *  * *  *  * ** ** ** *    **  *** **  
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * **  *   *  

int *** *  *
{

int  *  *  *** 
****   ** ** ***** ****  *  

if(a==0) printf(0);
else if(a==1) **   **   
else {
 ** ** * * ****** **    *  ****   ***  ***
** ******** * **** ** *** *    ***      **  * * *** * = c0+c1;
  *********   * ****  *  **   *** ** *  ** * ** * * **** ***  * = c1;
* **  ** *  ****  ***   ***** * *  *** * *** **** *    = cb;
        *  **  **** ** **
**    ********    * **  * * *  ****   ***** * ** 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **  *   * ** 

int main(void)
{

int  * **  **
*   ***      * *   * *** ****

if(i==0) **     *       ******  *
else if(i==1) *  *  * *         *  
else {
  *  *  ***    *  **  * * *** * * * * *** *  *****
 *** * * *   *  * *   *****  ** *****    *****  *  ** = f0+f1;
 *    * * *      *  ** **********  *      * ******   **   * = f1;
*  ** *  ** * *** **   ***  **   ** *  *******   = fn;
 **  ** *  *        ** ** *  *
 ***   *  **  * *** * * **   *** *   ** *       * **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  **  * * * * 

int  *  
{

int **   ** **  
*  **** * **  *         *    *  **

if(i==0) printf(0);
else if(i==1)      *
else {
   * ** ** ** * * *  *** * * *  *   *  **   
 *   *** * ***  *  **** * *  ***** **  *** *** **   * ** = f0+f1;
*   ** *** *****  ***   *  *  * **    ** ** *  *    * **   = f1;
 ***  ** *** ***   *  ** **** **  ***  ****     **** **   * = fn;
 **** * ***    *  ****   **   **
   * ****  ***     * *   *  ** **  *  *******   *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** ***** * * ** ***** * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * **** **** ** *** ** ** *** ** ** * ** * * d;
* * * ** * * * * *** ** ** * * *** ** * * * (d=2; d<n; d++)
** * * ** * ** *** * *** * ** ** *
*** ** **** * *** ** * **** * * * * (n%d==0)
** * ** * * * ** ** * * * **** * * *** * **** ** ***** ***

   }
**** ** ** *** * * ** * *** ** ** * *
*** ** **** ** * ** * ***** ** ** ** **** **
**** **** ** * ******* * * ***** * ** * ***
* ** ** *** * ******* *** * **
*** *** * * *** *** ** *** * * *** * * * * ** * (e==0)
* * * *** ** * ** ** ****** * ** * * ** ** ** **** * *** *** * * * * ** ** ***
* * * * ******* **** ** * * * * *** **** * *** * * ** **** * * ***** * **
* ** * * ****** *** ** ** * * *** * * * * ** * ****** *** * * * ***** **** ** * ** ** * *** **** **** ");
** ****** *** ** ***** ** *** ** * * * *** * * * *** ** **
** * ** * ** * * *** *** * *** ** * ** * * **** ** *** * * ** ** * * ** *
* ** * * ***** ******** * * ** ** **** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * *** **** ** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** **** ***** * ** **** ** ***** * ** ***** ** d;
** ******** ** * ***** * **** * * (d=2; d<n; d++)
********* ***** * ** * * *** * * * **** **
* ***** ** * * ** * ** * *** * * ** * (n%d==0)
* * * **** **** * *** **** ***** * ** * ** * * * *** * ** ****

   }
* ** * ** * **** ***** * ** ** ** * *** *** ** ** * **
* *** ******** ****** *** * ****** *******
* * * * * ** *** **** * * * ** * * **
***** * * **** ** ** ** ** * * * ***** *** **
**** *** * *** ** * * ******* * * *** * ** * *** * * *** * * **** (e==0)
* * ****** ** * *** * ****** * *** **** * *** ** * ** * * ** ** * ***** * ** ***
** * * ** * * *** * * **** * * ** ***** ** ***** * ** **
* * ** * ** * ** * * ** * ** * ** * * *** *** ** ** **** **** * *** ** * * * * *** * * ");
*** *** **** * *** ** * *** ** * * * ** *** * * ** ****** * * ** * ** ** **
*** * *** ** * ** ***** * * * * ** *** ******** * * ** * * *** **** * **** **
**** ** **** * ** ***** ** ** *** ********** *** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* ** * **   * **** *** *        *    *** *****  ** d;
*     **    * *   ****  ****** *  *    ***    * * *      * * (d=2; d<n; d++)
    ** * * *   **  ** * ** * * ** *****  *** ***    * 
   **** * * * * * *   *    *   **    * ****      (n%d==0)
  *  * *** **** ***   ***   **   *   ***** **** *  *   ** ****   *** **  * **      ** *
   }
 ******     *   **** *** ***     * *   *  ** * * * *   **     *****
* ***   ** *  *  * **  * *  * ***   *      *    * ** 
 *   * ** *  * * *    * *   *  * ** **     * ** **** * 
 **  * *  **     **  * *  **** ** * * *    *  ***** ** *****
 ** *** * **  **    *       **     *** ***   *   ***  *** ***  * *  *  **       ***  (e==0)
*  *   * ***   ****  *  *****  * *  ** *   * * ***   ** **  ***  *     ** * *    ***  *   ***  **  *****    
 ******* ****  *       *       ***** **   **** ***** ***   ** ****** *** *        **
 * *     **** **       *** ** * * ** ** * ** ******     ****** ***  ** ** * ** *     *** ** **   ** * * *** ");
*** * *** *   ****** * * ** ** ******* ** ***  *   ***  *  * *****     *** *  *** 
* * * *   ***   **    * ** *   ** **     *   ***   ****     ***   *  *  * * * ** * ******* ** *** **   **** *  *
  *** **   **   *  ** ****    *  ******** * * *******
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*   * **   **   **  * **  ***  Fn,t1=0,t2=1, n,input;
** *      *****     **** **  * * ***** * ** **  ******

**    *       ***   *  *  * ** **  *  *** * * n++)
****  ***      * *        *  **
***  ***   **   *        ** ***   *  ***  * ***  *  **   = t1 + t2;
* *******  ******  *  **  *****  **   ** *     **** *  
** **    ***** ** *  ****  *   *** ** * ***   *  ** **  *  *   
    }

  ***** *      * **  *  **** ** **      *   ** *  * 

***   * * ** * **** * **  ** *   0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* *        *      **** *   * Fn,t1=0,t2=1, n,input;
    *  *****  * * *** **    ***** *  *  ***   **** ***  *

*   **** ** *  *   *   * *  *****  **         n++)
 **   * ** *  **  *   
 *      **** ** *  **  ** **** * * *   **  **  ******** = t1 + t2;
***    **** * **   *   *    **   **  * **  **  ** *  **  
 ******    ** ***  *  ** *** ** **   *   ***** ** ***** 
  ** **   *** * * *  ***  **  *

*** *    * * * * * *  * * ****** ** ** ",Fn);

*     * *   *  * *   **          0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.28
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 8.3k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 6.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.1k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 11.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users