0 like 0 dislike
19.3k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 19.3k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** *** ** * * * ** *** * ** F0,F1,Fn,n,a;
** ** * * ** ***

* * * * ** * ** * ** ** * **** * *** * &a);

* * * * *** ** * ** ** ****** ***
* * * * * * ****** * ** *
* * *** * ** * * ** * ** ** *** * ** * * ** * *
** *** *** * **** * * * ** **** *
**** * ** ** **** * * *** *** ***** ** *** * *** **
    }


* * ** * * * * * * * ***** ** * * Fn);

* ** * * * ** * * * * * * ** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
int **** *
{
int * * ****
* *** ** * * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* * ** ** * * ** ** ** * *** *** * *
* * * * *** ** ** * **** * *** * ****** = c0+c1;
* * *** * * *** ****** * ** * * * ** * * ** = c1;
****** * *** ***** **** *** ** * ***** * = cb;
***** ** ** * * **** * * *
*** * ** * ** * **** * *** *** ****
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * *** ** *

int * *
{

int * *
** * *** ** ** ** *

if(a==0) printf(0);
else if(a==1) * **
else {
* **** * ***** **** ** * * * * *
***** ** ** ** **** * **** * * * *** ** * * = c0+c1;
********* ****** * **** ** * ** * * * ** = c1;
* * * *** **** ** * ** * **** ** ******* ** = cb;
*** ** *** ****** * *
* **** * * * ** * **** * ******* *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include **** ***

int main(void)
{

int * *** ** *
*** *** * ** * * ** ** **

if(i==0) * ***** ****
else if(i==1) *** ******* ******* *
else {
* * * ** * ** *** ** * * **** ***
* ** * * *** ** ******* **** * * * ******* = f0+f1;
**** * * ** * * *** * **** = f1;
*** * *** * * *** * * ** **** *** * ***** ** = fn;
** * * * * ***** ** * ****
*** * * * * ** ** * * ** ***** **** *****
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ****** ***** *

int ***
{

int *** * * *
* ** * *** * ***

if(i==0) printf(0);
else if(i==1) * *****
else {
** *** * *** * ***** * * * * * * *** *
* * *** ***** *** * ** **** ** * *** ** * *** *** * = f0+f1;
** * * * * * *** * * * ** *** * * * * *** = f1;
**** **** * * * ***** ** **** * ** * *** = fn;
* ** **** **** * * ** *
* ** * * ** * ***** * * ** *** *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * *** * ** *** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ****** *** ** * ** * * ** *** * ***** d;
** ** * *** * * ** ****** * * * * *** (d=2; d<n; d++)
* * ***** ****** * * ** * * ** ** **
* * * * * ** * *** * ** ***** ***** * * * * * (n%d==0)
** * * * * *** * * * * *** * ** ** * ** * * **** * * *** ** ** * *

   }
* ** * *** ***** * ** * *** * * ** *** * * *** *
*** ** * **** *** *** ** ***** ***** * * *
* ****** ** ** * *** * ** *** * ** ****** * *
*** ** * ** * ** * * ** **
** ** * * ** *** **** **** * * *** ***** * ** * * * ** ********* (e==0)
*** *** ** * * * *** * **** * * * * ** * *** * * * ** ** * * * * *** ****** *
* *** ** * * ****** * * *** *** * * ** ** * * * *** *
* * * *** ** * ** ***** ** ** ** ** * * **** * * * * * ** ** **** * * * ** * * * ");
* * ** * * *** * **** * * * * ** * * * ** ** * * * ** *
* * ** ** ** ** ** * * * * * ** ** * * ** * ** ** ** ** * ** ** * * ******* *** * *
* **** * ** * *** * ** * * * *** * * *** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * ***** ******* * * * ** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** * * *** *** ** **** ***** * ** ** * *** * d;
* ** ** * * ** * ** * ** **** * ** (d=2; d<n; d++)
** ** * * * *** * **** * ** **** * ** * * *
* ** **** *** * *** *** * * ** * ** * (n%d==0)
*** * * ** ** ** ***** ** ** * * **** * *** * * ** ** *

   }
* * * * ***** **** * * * * * * * * *** **** * *
* ** ***** *** ** * **** * *** * *** *
* *** * * *** **** *** *** * * ****
****** * * * * *** ** * * * ** * *
* ****** * ** * * ***** ** *** * ** ** ** * *** ** * **** (e==0)
* * * * * ***** *** **** ** ** * * * ** *** * * * ******* ** * *** *** * * ** ***
** *** * * * *** * * * ** * * * *** ** * * * * * ** * * * *
** * * **** * ** *** * ** * *** ** * * ** * **** *** ** * * * * * ***** * * **** * * * ** * * ");
* * ** * **** ** *** * * ** * * *** ** ** ** * ******* *** ***** *
* **** ** ** * ** * * ** ** * * * * ** * ** * ** ** ** *** ** ***
***** * *** ****** * *** * * **** *** ** * * ** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
** * ** * ** ** ** ** * * ***** * d;
** * * ** * * * * * * * ** * * * ** (d=2; d<n; d++)
** * *** ** *** * * ** ** * * * * * * * **
* * * *** * * * * * * ** * *** ******* ** ** (n%d==0)
** ****** * *** * * * * * * * * ** * ** ******* * * * * * *** *
   }
*** * ** *** * * * *** * * * * * * *** *** **
* * * * ********* ** ** ** * *** * * **
** * **** * * *** *** ****** * ** ******* * **
* * * **** * **** * * ** ******* ** * ** *
** * ***** ****** * * ***** * ** * ** ***** *** * (e==0)
*** * * ** ** * ******* * * ** * * ** ** * **** * ** *** **** ** *** *** ** * * **
* * ***** * ** * ***** *** * ** * * ****** ** * ** * ** * * **** ****
* ** *** * ** ****** *** *** * ** **** * ** * * ** * *** ** *** * ** * * ** * * ** ** ***** * * ");
* *** * ** * ** * ** *** * * ** * ** * *** * **** ***
* *** * ** ** ****** ******* ** *** ** * * *** ** ** * ** * * * *** *** * *** *
* *** * * * * *** ** * * * * * * *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
**** **** *** * * *** * Fn,t1=0,t2=1, n,input;
* * *** * * * *** * *** * *** * ** ** **** *** * *

* * * *** *** * ***** ** ** ** ** n++)
** *** ** * ** ** ** ** ** **
** ** *** * * * * * *** ** * ** * * ** ** * ** * = t1 + t2;
* **** *** * ** ** * * * **** * * ** ** **
* * * ** * ** *** * * * * * * * ** ***** ** * **
    }

*** ** ** * *** ** * ** **** * ** ** **

***** * * * * * * ** * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** ** * * ** * ** Fn,t1=0,t2=1, n,input;
* ** * ** * * ** * * * * * * * ***

* * ** **** ** * ** * ** * n++)
* ** * * ** *** * * *
* * * * ** ** * *** ** * ***** * * * ** * = t1 + t2;
****** * *** ** *** * ***** * * *** * * ****
** * *** * * ** * * **** * **** ** **
** ** *** ** ** * *

* * ****** ** * * ** *** ** * ",Fn);

* ** * ** *** * * * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 12.4k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 22.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 9.6k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.6k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users