0 like 0 dislike
12k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 12k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* * * **** * * * * * F0,F1,Fn,n,a;
* * ********* ** **** * **

** ** * * * * * * * * * *** &a);

*** ** * ** * * ** *** * * ** **
* ** * * * * * *
* * * * *** * * ** * * ** ** * ** * **** *** **** **
****** * ** **** *** * ** * **** * * * * ** * *
*** * * * ** * * * * *** ***** **** * ** * *
    }


******* * ** ****** ** ***** * * * * Fn);

** * *** * * ** * ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** **** **
int ** *
{
int * * * * **
* * ** * *** **** * ***
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* *** * ******** *** * * ** * * ****
* ** ** ** **** * *** * * * * * *** ** *** = c0+c1;
*** **** ** *** * *** * * ** * * *** * * * *** * ** = c1;
** * **** * * * * * * * ** *** * * = cb;
* ** * ** * ***
** * ** * * ** * *** *** * *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include *** * *

int *
{

int *** * *
* * * **** * * * ** * **

if(a==0) printf(0);
else if(a==1) * * **
else {
*** * *** * * *** * ** ***
**** ** ** * * *** * * * * * * ** ** ** = c0+c1;
** ****** * * ** *** * *** * * * * ** * ** = c1;
* *** * ** ***** * *** * *** * *** * ** * * * ** = cb;
*** * ** ** * ** *** ***
*** * * ** * ** * * * ** * * ******* **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * * ** * **

int main(void)
{

int ** * ** ***
* * * * * * **** **

if(i==0) * * * * * * ***
else if(i==1) ** * ****** **** **
else {
* *** * ** ** * * ** *** * *
* *** ****** * **** * * ** ** ** = f0+f1;
* * ** * ***** * ** * ** * *** * ** = f1;
** * * ** ** * **** *** ** * ** ***** = fn;
* **** * * ** **
*** ** *** * ******* * * ** * *** * * *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * **

int * **
{

int ***** * *
******** *** * ** * ** *

if(i==0) printf(0);
else if(i==1) **
else {
** ** * ** * * *** *** ** * * * * *
* *** *** *** ** ** ** * * **** ** *** *** * * **** = f0+f1;
** ** *** *** * ** * *** * **** * * * * = f1;
** ** ** ** ** * * ** ** * * * * * ** ** = fn;
* * *** * * * * *
******** * * *** * *** ** * * * ***
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** ** **** ** * ** ** * *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * * * ** ** * ** * **** **** ** * ** *** * * d;
** *** ** * * * *** * *** * ** * * ** * (d=2; d<n; d++)
**** * * * * * * * * * *** * * *** ***** * *** *
* * ***** ** ** * ** * * * ** *** * *** (n%d==0)
*** * * * * * * ** * ** * * * ** * * * * * * ** **** ** * *

   }
**** *** ** ** * * * * ** ** * ***** ** **** * ****
* * * ** *** **** ** * **** * *** * * **
* ***** ** *** * * ** ** * * * * * * *** * * **
** * * * * *** ******* *** ** ** ***
* * **** *** **** **** ** * *** *** *** ** * ** * ** ** (e==0)
** ** * * *** * * * ** * *** * **** ***** ****** *** ***** ** *** * ** * * *** * * *
* * ***** ****** * ** * * ** *** * **** * ** * * * * * *
*** * ***** * * ** *** *** * * ** ** * * * ** * **** *** **** ** *** ** ** * **** ** ** ***** * ** * * ");
** **** * ****** * *** ***** * * ***** ** * *** ** * *
* *** ****** * * ** **** ** *** * ******** ****** ** ****** ** ** * * * * *
* ** * ** **** ** * ** *** ** * *** * ******

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * *** * ** ***** ** * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * *** * * * ** * * ****** **** * d;
**** ** ** * **** * ** *** * *** ***** (d=2; d<n; d++)
* * ** ** **** ** ** * * * * * **
* *** * * **** **** * * *** * * ** (n%d==0)
*** ** ****** *** * * ** ** * ** * **** ** ** * *** ***** ** * *** * **

   }
* ** * ** * *** **** * * *** ****** ** * *** ***
* *** * ** **** * ******** ** ** * ***
*** * ****** ** * *** * * *** ** *
* * *** * ** * ****** * * ** * * * * * ***
* ** * * * ** * * * * ** * * * * * * *** **** ** * * * **** * *** (e==0)
* ** * * * * ** ****** * * * ** * ** ** * ** * *** * **** * **** * ** * ** * ***** ** * *** **
* *** ** * ** * * ** * * ** * ** ** * * ** *** ** ***** * *
** * ** ***** *** ***** ** **** * * * ** * ******* * * *** * * * * * ** **** **** ** * * **** ");
* * * * ** * ** **** ** * * ** ******* *** *** * ** *** * *
****** ** * * * **** ** ***** ** *** *** ** * * * * * * * * ** * *** * *** **
* * **** * * * * *** ***** *** * **** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
***** * **** * ** * * **** *** * d;
* ** *** ** ** * * * ***** * * * * * * (d=2; d<n; d++)
** *** ** ** * * *** *** * *** *
** * * *** * *** * ***** * *** * **** (n%d==0)
** * ** *** ** * ****** * *** * ** ** * * * ** * * *** * *** * ** *
   }
* * * ** *** * * ** **** * ** ** **** * * * * * ***
* ** *** * **** * * ** * * **
** ** ** * *** ** * ** * ** ** * *** * *** ** ** * * *
* * ** ** **** *** * * ** * * * *** *
**** ** *** *** * *** **** ** * **** ** * ** *** *** * ** ***** *** * (e==0)
** * * * ***** * * *** *** ****** ***** *** * ***** * * * * ** * ** * * * **** * * * **** **
**** ** * *** *** * * * *** *** ** ** ** *** * ** * *** ** **
**** * * ** ** * *** * * * * *** **** ** * ** * * * * **** ***** ******* * * * **** * ** ");
* * * ** ** *** * ****** ** * ** * * * ** * *** * ** **** *
* ** * *** * ** ** ** * * ***** *** * * ** * **** * **** ** ************
* ******* ** ** **** * * * ***** ** ** * **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** ** ** * **** * * * Fn,t1=0,t2=1, n,input;
* * ** * * * **** * **** * *** * **

** * * * ** ** * * ** ** ** ** ** * n++)
* **** * ** * **** ****
* * * * * **** * * ** * * * ** = t1 + t2;
* ** * ** * ** ** * * * **** * *** * ** * *
** ******* ** * **** * * *** * * ** ** * **
    }

** * ** ** ***** ****** ** ** * *** * **

* ** * * * **** * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * ** *** ** * * *** Fn,t1=0,t2=1, n,input;
* * *** * **** ***** ** * *** *** **** *

*** * * ** * *** * *** * **** * * * n++)
* * *** **** * * ** * **
* ** ** *** ** * ** * *** ** * * ** * * *** = t1 + t2;
* ** *** * ** * * * * * *** ** * * **** * ***
** * * ***** * * * * * * *** *** *
* ***** * *** * ***

** * * * *** * *** * * * ** ** ",Fn);

****** * * * * * * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.44
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.4k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.4k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 6k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.9k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 10.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users