0 like 0 dislike
9.5k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 9.5k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* ** * * ** ** * * **** F0,F1,Fn,n,a;
* * ** * * ** **** * ** **

* ** * * * * ** ** ** * * * &a);

**** * * * * ** ** ** * ***
* ** ***** * ** * * **
** *** * *** *** * * * * ******* * * ** ** *** *
** ** * * *** * ** ** * ** * ****** *** *
*** * ** ** * * ** **** ** ** ** * * * *
    }


* ** ******* * * ** ** *** ** * **** * Fn);

*** *** ** ** * * *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** *
int * ***
{
int ***** *
* ** ** *** * ** * ****
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* *** * * * * **** *** *** * ** ***** *
** * * * * * ** * * * * * ** ***** * * ** **** = c0+c1;
** ** ** *** * **** ** * ** *** *** ** ** * * = c1;
**** * ***** *** *** * * * * * * * * * ** * = cb;
* **** *** ** *** * *
** *** *** * * * * ** *** * ** *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * ** ****

int * ****
{

int ** * **
*** * **** * * * *

if(a==0) printf(0);
else if(a==1) * *
else {
** ***** * **** ** * * **** *** * *
* * * ***** * **** * * * * * * * ** * * * * = c0+c1;
** ** *** * *** * * * ****** * * * ** ** = c1;
* **** * ** **** *** * ** *** ** * * ** ** = cb;
****** ** ** ****
**** *** *** ** * * * *** *** ** *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include *** *

int main(void)
{

int * * ***
* *** ** *** *

if(i==0) ******** * **** *
else if(i==1) * * ** * **
else {
* ********* * **** * * ** * * *
* * * * ** * **** * * * * *** * = f0+f1;
* ** **** ** * *** ***** * * *** ** *** *** * * = f1;
* * * ** *** ** ** * **** ** ** * * * ** = fn;
* * ** *** ** ** **
** ** * * * ** * ** * *** * * * ** **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * **

int * ** *
{

int ** ** *
* * ** * * * ** ** * *

if(i==0) printf(0);
else if(i==1) *** **
else {
*** * * ** ** ***** * ** **** * **
* ** ** ** * ***** * * * ** * ** * = f0+f1;
* ***** ***** * * **** * *** ** *** ** ** = f1;
* **** * * ** *** * * * **** * * * ** = fn;
** ** * *** * ** *** **
* ** *** * ** * * *** ** **** * **** *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** **** * *** * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * ** **** * * ** * ** * * *** * * ** ***** d;
* ***** * * **** * * ***** ** * * * **** ** (d=2; d<n; d++)
* * ** ** *** ** ** * * ***** ** ** *******
* * ** ** * **** ** ** **** * * *** * *** **** * **** (n%d==0)
** ** * **** * *** * *** ** ** *** ** ** *** **** * ** * *** ***

   }
*** ******* ***** * ***** *** ** * * ** * *** * ** * *
* *** *** *** * * **** **** * * ***
*** *** *** * * * * * * * ** * ** *
* ** ** ****** * * ** ** ****** ** * ****
* * ** * * * **** * ** ** ** * * * * * * ** ** ** *** ** ** ** * ** ** (e==0)
* * * ***** * * * ** ** ***** ***** ** ** ** ****** * ** *** ** ** * ** ** * ** * *
* ** ** * * ** * * *** * * * *** ** ** ** ** ** ** ** *** * *** * **
* ** *** ********* ** ** * ** * *** ** **** * * * * ** * * ** ***** ** ** ** *** ** ******* ");
** * ** **** ** * * * ** * *** * *** ** * * *** *** *** * ** * * * ***
*** * * ** * * ****** * * * * * ** ** * * ** *** *** *** * **** ** * * * **** * * * * **
* ** * * * **** ** * * ** **** ** ** *** ** * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * ** *** *** * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * * * ** ** ** * ** ** ** * ****** ** d;
*** ** ** ** *** * ** **** *** ** * (d=2; d<n; d++)
*** *** *** ** *** * ** * *** ** ** ******* *
** ** * * * * *** ** ** **** **** *** * * (n%d==0)
* * * ***** ****** * * ** *** *** * ** * * * * * ** * * **

   }
***** * * ** * *** * *** ****** * ** * *
* * **** ** **** ** *** * * *** *** ** *
* *** * * * * **** **** ** *****
* ** * ** * * ** * * ** * *** * *** ***
**** * *** **** * ** ****** * * * * * * ** * **** * ** * * *** ** * (e==0)
** * * * * * * *** **** * * * * ** *** *** * ** ** * * **** * *** ** * *** *** *
****** * *** ***** * * * *** * * * * * ******* * * *** ** ** * ***
** *** * **** **** * ** * * ** *** * * * ** * * * * ** * ** *** ** *** *** * * * ** *** ** * * * ** ** ");
* * * **** *** *** ** * * * **** ** * *** ** * *** *** * ****
* * ** * ** ** * * * *** ***** * * * *** * * * * *** *** * **** * *
** * *** ** ** ** *** ** ***** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* **** * ** * * ** **** * **** * * ** * ** d;
***** * * ** ** * * ** * ** * * **** ** ***** (d=2; d<n; d++)
* * * **** ** ** * * ** *** ** ******
* * ** * * * *** * ** **** * ** ** * (n%d==0)
* * ** **** ***** * * * * * ** *** * *** * ** ** * * *
   }
* *** ** **** * ***** ** ** * ** * * * * *
***** * *** * * **** * *** * *** *** * *****
** ********** * *** ** * **** ******* ***
* * * ** ** ******** * * *** ***** *
*** * * * * ** * * * * * **** * * * *** * ** * * ** * (e==0)
* ** ** * ** * * ** * *** *** * * ** ** * ** * **** * * * * ** ******* *
* ** ** *** * * * * ** * * * ** **** * ***** ** * ** * ******* ** **
** **** * ** * * **** * *** *** * *** ** ** *** * *** * *** * ***** * * * ** * *** **** * ");
* *** ** ******** *** **** **** ******* * ** * * *** ***** ** **
* ** ** ** * ** * ** * *** ** * ** * * * * *** * ** * * **** * * * *
* * * *** * * *** * * * ***** * * *********
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* *** * *** * *** * Fn,t1=0,t2=1, n,input;
*** * ** ** * * **** * * * * * * ** ** * ***

** * *** * * * *** *** ** ** * * * n++)
* *** * * * * ** *
* ** *** * * **** * ** ** * * *** ** = t1 + t2;
* * ** * * * * * * * * * *** * * * * * ** *** *
* *** * **** * * * ** * *** **** * ** *** *
    }

* ** ****** ** * * * * ***** ** * ** ****** ***

* ** ** **** * *** ** * *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
***** ** * * *** *** * ** * Fn,t1=0,t2=1, n,input;
* * ** * * * * ** * * ***** ** * * ** *

* *** * * *** * * ***** ** * n++)
**** * ********** ******** *
* * ** * * ******* ** * ** *** * * **** * = t1 + t2;
**** *** * **** * *** * * ** ** ** * * ** ** ***
** * *** * **** ** ** ** * * * * *** *
***** * * * ** ** * *

***** ** ***** * * ****** * * * ",Fn);

** * * * * *** * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.58
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.9k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 4.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 8k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users