11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
16.4k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 16.4k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ** *  ** ***  ******  F0,F1,Fn,n,a;
* ***     *** *   * * * ******  *

**   ***  *** **  *   **  **   *** ***  * *  *  *  &a);

 ****  ** * *** * * ***  * * * *  *** *
***   * * * * *   ** ** * *
  **  *** **   *****     * *  * *  ****   **   * *   **   *
 **    ** **        *** *** * *** *    *   *****   *
* * *****  * * **  *** * ***  **  **  *  ****    
    }


**** ****  * *  *    * * *** *  ** *  **  ** Fn);

 *  *** * * ** *  *   *    *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **        * **    
int  * ***
{
int  ****  *   *
 ***** ****  **** *  *  **
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*   **  *** * *  *   ** ******    *      
  *   **  **  *       ******  *** * **    ***** * **** *    * = c0+c1;
 *  *   *   *****  ***   ***  * **  * **** ****  ****  **  = c1;
***  *         ***     * ****    *    * ** ** **** *   * * * = cb;
*****     * **   * *   
  ********** **    * **     **  *  ** ** ***  **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** **  *    

int    *  *
{

int   **  ***** *
*** * * **** **      *  *  **  

if(a==0) printf(0);
else if(a==1) **   *  
else {
****** * * * *  * ****   ***   **  *  **    * 
*   ***   ***  * ** ** **  ****      **  * * ** **     = c0+c1;
*     * * * * ** ** **   **   **** *   *    ***   *    * = c1;
* ** ** * * * *  *    ** * *** *    **     *  ** **  *  ** * = cb;
** ** ******    * * * *
        * * *** *  *    ** * * **** **  * *   * **  


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include       *****  ***  *

int main(void)
{

int  *   * * **
*  ** ****   * **** * * 

if(i==0) **    * **  ***   **
else if(i==1)   * **   *     **    *  
else {
 *** **** ** *  *  **    ************* **
***** ***** *** *  *  *       * * * ** * *   *  ** *** *   ** = f0+f1;
   *  **   *   *  *****    *   ****** * *  *  **   **  * = f1;
    ***  * **   * *   **     *** * * **  **  * *  = fn;
**       * *   ***   **  * 
  **    *  ** * ***   *** ***** ****** **      *  *** **    
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * **   

int **   *
{

int   ****  * 
    ***  ** * **  * ** * *  

if(i==0) printf(0);
else if(i==1) ****
else {
* *  * *   *  *   * * ***  *   ***** *** *   *
   **  * ** ***** **  ***  ****   ***  ** * ***    *** * = f0+f1;
*      *    * *  * **  *    ** ****  **  *  **   **  *  = f1;
 *  *****  ***   *****      **  **     *** * **   * * = fn;
 *****  *  *** * *  ** *   *
 ** *** **  *   * * ** *** ****   *   ******* * *  *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** ** * *** ** ** * * * ** ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
**** *** * * * * * ** ** *** ** ** * * * *** * *** d;
********** ** * * * ** * *** * * * ** * ** (d=2; d<n; d++)
* ** ** * *** * *** ** **** ** * **** * ** ** *
* *** * ********** *** *** ** * ** ** ***** *** (n%d==0)
* *** * ***** * *** * ***** ******** * * *** * * * ** * ** * ** *

   }
** * * ** ** * * ** * * * * *** * * ***** *
** ** * *** ** **** * **** *** * ** * * * *
* * ** **** ** ** * ** ** ****** ** * **
** ** * * * * *** * *** * * ** ** ***
** * ** * ***** ** * * **** * * **** * *** * * * ** * ***** (e==0)
* *** ** *** * * ***** ** **** ** *** * * * *** * * * *** ****** *** * * ** ** * * * *
*** ** ** ***** * * ** ** * * * * ** * * *** * ****** *** *
* * * **** *** * * * * *** ** ******** ** * * *** * * * * * ** * **** * ** * ** * * * * ** ** ");
* ** * * ** * * * **** ** ** * ** *** *** **** **** *** ** ***
* * ** * * *** ** ** ** * * ** ** ** ** * *** ** *** **** * * ************ *
* *** *** * * ** **** * ** ******* **** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** *** * ** * * * * * **** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
****** *** * ** *** * * * * * * *** **** * ** d;
** ** * **** * *** * * * * ** ** * * (d=2; d<n; d++)
* *** * **** * ** * ***** *** * **
**** **** *** * *** * ** ******* * * * ** * **** (n%d==0)
*** ***** ** * * ** * ** ** ******* *** ******** * * ******* * ** *

   }
*** *** * ** * * ****** ***** ** * * *** **
* * * *** ** * * * ** * * ** ** * * **
* **** * ** *** ****** **** * * ** *********
* ** ** ** ** * ** * * * * ** * * **
** ** ** * * * * **** * * * ********* * * ** ** ****** ** * (e==0)
* * *** * **** ** * ** * * ** * *** ** * ** *** * * ** * ***** * ** **** * ***** * ** * *** *
* ** ** ** ***** ** ** * ** * *** * * * * * * * * * * **
**** ** * ***** ** * * * **** * *** **** ** ** * **** * * * ** * *** * ** * **** * **** ");
* *** * *** ** * * * * * * ** ********* ***** * * ** ** * * * * ** * * *
* ** * ** ** ** **** * ****** ** *** * *** * * ** ** *** * ****** ** **** ****
* ***** ** **** ** ** * ** ******* * ******* * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 * ****  ***     *   **    * ** *   *  ** ****  *** **** *   d;
**  ***   *     ****** **    ***  ***  * *  ** *  *   (d=2; d<n; d++)
* * * ***  * ***     * ** **  ****  **   ** * * *  *  * 
   * *       ** * * ***   *** *  **    ***  * ** (n%d==0)
*** **  ******    **      ****   ***** * *  *  **** *    **  ****   **   ****    * 
   }
 ****   *** ** *  ******* * ** *** ****    *  *** *
    * ***   *     * *  *      *** *  *** *  ** 
   *** ** * * *   ** ** * *   *  *   ***       *  ******
 **** **    ***   *   ******** *** ** * * * ****   **  *
*  *  * *  **   ** ** **    * ***  ** *  * ** ** *  **   * *******    * ** *   *  (e==0)
*    ** * **  *   ********  **  ********    ** * * * *   **   **  *   ***** *  **  * * * *   ** * * **** **
* ******* * * **  * **  **** *** *  *      **  ** ** ** * *     *   **      *  *** * **
**  *  ***  ** *   ***  *********  *  **   **  **  *  ***  **** **  **  *  ***  *** *  ***  ***  **   ** * ");
* * ** **  **   * **  ****  * *  ** * * * **  ****  * ** ******* ** **     * * **** *** *   
* ** ***   *  *  *  **  *  * ****  *       ** *  * ** ****  *******   *   *  *  **    **    *   **
    **** ****  ****  * ** **   ***  *** *** * * ** * * 
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* * ***   * * * **** *      Fn,t1=0,t2=1, n,input;
  *** **** ** ** *** ****    * **  * *    *******  *****

   *  ****   ******** ***** ***  *   n++)
 * ** ** * ** *  *   **   *
* *** ** * * * **** ** ** **  *  **  ***    * **  *   *  * = t1 + t2;
  **   * **** * *    *   ** **** ***  **   *  * *  *    *  *  
 **  * * * *     *  *** **  * *    **  * ***** **      **
    }

 ***   **** ****   * * **  ** ***   * ** *** *  * 

**  *** ** **     ***  * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 **** *    ***  * **  * ** **   Fn,t1=0,t2=1, n,input;
     ***    **** *  *  *   **  *** ** ***    ***** **   

 *  ***  ** ***  * ** * **  ** *  *    n++)
*      **   * * ***   ****** 
* *  * *******  ****** ** * *  ** **  * * *** * ***      = t1 + t2;
* ** * * *  ** ***** * **    *****  ** *** * * ****     ****
  * * *   *****   *   **   * ***     *  ** **    ****  
*   **** ***** * **  ** * ***

 *  ** *  *   ******  **  * *  *** ***  ",Fn);

*   ** *  *  ** *   *    * * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.104
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 10.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 19.7k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 8.3k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.7k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 13.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users