0 like 0 dislike
10.8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 10.8k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* * ** * * * * **** * F0,F1,Fn,n,a;
*** * ** * * ******

* ** *** ** ** *** ** **** * ***** * &a);

**** ** *** * ** ** ** ** ** * **
* ** ***** ** *
* * **** ** *** ** *** ***** * * ** ********* * * ***
** ** * * * * ** * ***** * **** ** * **** **** *
* *** * * ** ** ***** *** *** ***** ***** **
    }


************** * * *** * * * * ** *** * Fn);

* * ******* * * * ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** **
int **
{
int *** * *
* * * *** *** * * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
** * * * ** * ** *** * *** ****
** * * * * ** ** **** **** ** ** ** * * * * * * * = c0+c1;
* * * * * **** ***** ****** ** * ** ** *** = c1;
**** ** * ** ** ** ** ** ** * * * **** = cb;
***** ** * *** * * **
** *** *** * * * **** * ***** * ** **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ** * * *** **

int * *** *
{

int * ** * *
* * ***** ** ****** * *

if(a==0) printf(0);
else if(a==1) * *
else {
* ** ** ** * * ***** ** * * * *
**** ** * * ** *** * * * *** * * **** = c0+c1;
* * ** ** * ** *** * ** * ** ** *** * * = c1;
** ** ***** ** * * ** ****** ** * * ** * = cb;
* * ** **** **** **** * *** *
**** ** ** * ** **** * ** * * *** * * **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * ****

int main(void)
{

int ** * ***
** * ** * ****** * *

if(i==0) * * **
else if(i==1) * * * * * * ** *
else {
** **** *** * **** ** *** * ** * **
* *** ** ** * * ***** * * **** * * *** = f0+f1;
* ** * ** *** * * * * ***** ***** * = f1;
** * ** * *** * * * * *** * **** ** ** ***** *** = fn;
* ** * ** *** ** * * *
** *** *** ** ** **** **** ***
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *

int * *
{

int * * ****
* **** ** * *** ** ** ** ***

if(i==0) printf(0);
else if(i==1) **
else {
** ** * * * ** **** ** * * ** *
*** ** ** * * * * *** ** * * * * = f0+f1;
** *** *** *** *** * ** * * * **** * ** * ****** = f1;
* ** ** * ** * * * *** *** *** * * = fn;
** * ** ** * * *** *
*** ** * ** *** ** *** ** * ** *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * *** *** ** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * **** *** * *** * ***** ** *** ** *** d;
** ***** *** *** ******* ** * * (d=2; d<n; d++)
*** ** * ** * *** * * * * * * * * **
* * *** * * ******* * * * * * * * * * (n%d==0)
* ** * * ** * *** * ** ****** * * * * * **** **** * * ** * * * *

   }
* *** * * * ** ** ** ** **** * *** * * * * *** *** *** *
*** *** ***** *** *** ** *** * *****
** ********** * ** ** ** * * * ********
****** * * ** * *** ** * * * ** *** * ** *
*** * * * * * ** *** * * ** * * * * *** ** ** * * ** (e==0)
** *** **** *** * *** * * * * * * *** ** * **** ** ** ** ** ** * *** ** ** *** *** *** * *
* * * * * * *** *** * **** * ** * *** ******* * *** ** ** **** * * ***
* ****** * ** * ********* ** * ** *** * * **** ** * ***** * ****** * ***** *** * ** ** ** ");
** ** ** * * * ********* * * ** *** ** ***** * ** * *
*** * ** * ** **** * * * * ** * * ****** * * * * * * ** ** *** *** * *
* **** * * ** *** ***** * ** ** * *** ** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * ** * ** * **** **** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** ** * ** * * *** * ** ** * ** **** ** d;
* * * ** * ***** ** * ** **** *** **** (d=2; d<n; d++)
**** *** * ** * * *** * ** ** * * * ** * *
* **** * * * ** * * ** *** ** * * * (n%d==0)
*** *** ** ** ****** * * * *** ** ** *** * * ******** ** * *** **

   }
** ****** ** * ** * ** ** * ** *** ** * * *
*** * **** **** * ** *** * ** * ** * *
**** * * * *** * * *** *** *** ** ** * ******
** * * * ***** *** *** * * * ****** *** * **
*** ** **** * ******* ** * * **** ** ******* *** * **** * ** (e==0)
* ** ** ** * **** * * *** ** ****** **** ****** ******* * *** * *** ** * * * * ** * * **** * *
** * * * * * ***** * ** * *** ** ** * * ** * * ** ** ***** *** * **
** ** * ** ** ****** ** ** * * ***** * ****** * *** * ****** * * *** * * *** *** * ** ");
** *** * * * *** ** ** ***** ** *** * * * * ** * * *** * * * ** ** ** *
* * * ** * * * * * * * ** * * * ** * *** ** * * ** ** * * **
******* * ** * ** * ** * *** ** * **** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* * * *** **** *** * ******** * * **** d;
** * ** *** * **** **** ****** * * * **** (d=2; d<n; d++)
**** ** *** * * * ** * ** ** * *****
*** * **** *** ** * * ***** ** * *** * ** * * ** (n%d==0)
** * **** * * **** ** *** * ** * *** ***** * ** **** * * * ** *
   }
**** ** * * * * *** ** ** ** * **** ***
*** * *** ** ** * ** * * * ** *
** ** ** *** * *** ** * ******* * ** **
* ** * ****** * ** ** ** * * * **** * * * ** *
* * *** **** ** *** * * ** * *** ** **** ****** * * * ** (e==0)
** * ** * *** ** * * ****** **** * * **** ** *** * * * *** ** * * **** ****
* *** **** * * * ** ** ** * *** * * * * * * ** * *** **** ****
** * * ** * * * ***** * **** **** *** * *** ** * * * * * *** **** ** * ** * ** ********* ***** * * ");
* ** * ** ** ** *** * **** * *** * * * * *** * * * *** *
*** ***** * ** * **** * ** * *** *** ******** **** ** ****** * **** * * **** ***
* ** ** ** ** ***** ** * * * * * *** * * **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** ** * * * * * ** ** ** Fn,t1=0,t2=1, n,input;
* ** ****** *** * * ** ** ***** ** ** *

* **** * ** * ** ********* **** * * * n++)
** * * **** ***** ** ***
*** * * ** *** * * * *** *** *** *** * * * ** = t1 + t2;
** ** * *** ** ** * * * * * ** ** **
*** * * ** **** * **** ************* ** *** * ** **
    }

* ** * ** * ***** **** * ** ** ****** *

* ** * * *** * ** * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
***** * ** * * ***** ** Fn,t1=0,t2=1, n,input;
* * *** * * * **** *** ****** ** ** **** **

* * ** *** * ** * * *** *** ** ** n++)
* ** * * * ** *
* *** ** ********* * *** * ** * *** *** *** = t1 + t2;
* ** * ***** * * ** ** ** ** ** ***** **** *** ** * *
** **** * * * * * * * * ** * ** ** ** * * ** **
* *** * * ** ** *** *

**** * ** ** * * *** * * *** ",Fn);

* *** ** * ** ** ** ** * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.4
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 6.9k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.6k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.1k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users