0 like 0 dislike
5.8k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.8k views

49 Answers

0 like 0 dislike
Hidden content!
// * * * ** by HoMingJui on 2016/11/3.

//



#include ** ** * **

#include * ** *

#include *** *

#include * **





int main(){
* * * ** ** **** * * * * * x[2],y[2],a,b,c;
* * **** * * * *** ** ** ** ** * %f %f * ** ** ** * **** * * ****** *** * **
* ** * * **** ** *** *** * * * * * *
* ** ** *** **** ** *** *** **** * * * * *
****** * **** * ** *** ** * ** *
******* * *** ** *** * * **** ** %.6f * ** * * *
* * * ** ** * *** * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** * * ***** * *



int main()

{
*** * * ** * ** a1,a2,b1,b2,a,b,c;
* *** * * *** * * * * ** ***** %f %f * *** ** * * * * ***** **
** * * *** ** ****
* ** *** * ***** * *
* * * ** ** *** *** *
* * * *** * * ** * ** ** ** * %.6f %.6f",a,b,c);


* * * * * ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
** * * * ** * * **



int main()

{
* * * ** * ** ** a1,a2,b1,b2,a,b,c;
* * * * * * *** ***** %f %f ** *** * * ** * **** * * *** * *
** ** * * * **** ** * *
***** **** ****** *
*** * *** * * * * ** ***
*** *** * ** *
** ****** * ** * ** ** * * * ** %.6f %.6f",a,b,c);


** * ** * * ******* 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include **** **



int main(void){


*** * ** * * * ax , ay ,bx ,by ,a ,b ** *****


*** * ** *** * * * ** * * *
*** ** * * ** ** ** ** *** * ** * * * * ** *
* * **** * ***** ** * *** * * * *** * * * * **** * * ***
* * ** * * * *** ** * ** * ** * * * * ***** ** ** * **


* * * *** *** * * - bx) != 0){
******** ** **** * * ** = (ay - * * *
* * **** ** ** * = -m*ax + ay;
*** * * * = m;
*** * ** ** ** * * = 1;
**
****** * *** ** * ***** **
** * * **** * * * = 0;
* ***** ****** ** = 1;
* ***** * *** = -ax;
*** * **


* * **** * * * * = a;
* * ** * * = b;
* *** * * * *** = c;


** * < 0)
** ** ** ** ** * *** * = -i;
* ** ** if (k < 0)
****** * * * ****** ***** * = -k;


* (i < 1){
* **** *** * ** *** = 1/i;
***** * * * * * = a*g;
* * ** * *** * ** = b*g;
* ** * ** * * = c*g;
** * *
* ** * * if (k < 1){
* ** ** **** ******** = 1/k;
* * **** * = a*g;
* ** *** ** *** = b*g;
* * ** * * *** * = c*g;

 }
** * * * ** *******
** ** * * * ** * ***
** *** **** * * ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** * * *** *



int main(void){


*** ** ** ** ** * ax , ay ,bx ,by ,a ,b ***


** * *** * * * * **** ** * ****** *** ***** *
* * *** * * * * *** * * * * * *** * ***
** ** * * * * * **** ** * * *** *** * ****** * * ** * * ***
** ** * * * * * *** **** ** *** ** * ** ** * * * ** *** * *** ** * * ** *


*** * * ** ** ****** - bx) != 0){
****** * * * * ** = (ay - * *
****** ** = -m*ax + ay;
* * * *** * *** = m;
* ** * *** * *** = 1.000000;
* * *
* *** ** * * * * * *
* * * * ** * * = 0.000000;
** ** * ** * **** * = 1.000000;
* ** ** ****** = -ax;
* ****


* *** * ** ** = a;
*** * * * *** = b;
***** * ** ** ** * = c;


* * ** < 0)
**** * * = -i;
*** *** *** if (k < 0)
* * * * * *** ** ** = -k;


****** (i < 1){
* * *** **** * = 1/i;
* ********* * * = a*g;
* * * ** ** *** * = b*g;
****** ** ** * = c*g;
* * ** *
* if (k < 1){
*** **** * ** * * = 1/k;
* * ** * * * = a*g;
** * *** * ** = b*g;
**** *** *** * = c*g;
* *
* * ** ***** * * ****
* ** * * *
* ***** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * ** ** * **
*** ****** ** * ** * * *
** * ***
* i ** * ***
** a , b , c , ******* **
** * ; i ** * ; *
** ** *** ** ** , * * );




* *** ****
*** ** ** ** * =
* * ** * * *** ** * * = - * **
*


* * * **** *** * * **

* ** * * *
* = * ***** ;
* = ;

* * ** * * * * ** a , b *








*** 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
* * ** * **
* **** * * * **** *

int main()

{
**** * *** ** * * * a,b,c,d,m,x,y;
* * ** * ** ** * *** *** * * %f %f * ** * *** ****** ** * *** * **
** * * * ** * **** * ** *
*** * * * ** * ** * * *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include * * *



int main(void){


** ** ** *** ax , ay ,bx ,by ,a ,b ,k,m,c;


* ** * ** ** * *** *** * * * ****** ** *
* * * * ** * * ** * ** ** ** * *** **
* * *** * ** * ** * *** * * ** * * * *** * ** ** * ** ** ***
* * * * ***** ** * ** ***** **** * * ** ** ** ********* * ** * ** *


** * ***** * * - bx) != 0){
* * * * ** = (ay - *
* ** **** ** ** ** = -m*ax + ay;
***** * ** * = m;
** * * * * = 1.000000;

 }
* * * * *** * ** *
** ** *** ** = 0.000000;
** * **** ******** = 1.000000;
*** *** ** ** * * = -ax;

 }


** * * * ** **
* * ** ** * ** ** ** *
* * ** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * **



int main(void){


* ** *** ** * * * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* ****** * *** ** **** ** * * ** * * * ** **
** * ** * ****** * * ** ***** ** ***** * * ** * * * *
* * * * ** * ** ****** * * * ***** *** * ** * **** * * ** * **
******* *** *** * * * *** * * * * **** * * * ** * ** * ** * *** *


**** *** * ** * * ** - bx) != 0){
* * ** ** * * = (ay - ****
* ** *** = m*ax + ay;
* * ******* = m;
* * ** * * *** * * = 1.000000;

 }
* * * *** * *** *
**** *** * *** * * * = 0.000000;
** * *** ** ** = 1.000000;
* * * * ** * ** = -ax;

 }


* * * ** ** * * * *
* * * *** * *
**** ***** * * ** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.18
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users