0 like 0 dislike
5.6k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.6k views

49 Answers

0 like 0 dislike
Hidden content!
// * * * ** by HoMingJui on 2016/11/3.

//



#include *** * *

#include ** * * **

#include * * *** *

#include * * **** * ** *





int main(){
******* *** ** *** *** x[2],y[2],a,b,c;
** * *** * **** * * *** ** ** %f %f * * * **** ** * ** * *** ***** **
* * * **** ** ******* ** *
* ** * ** *** * ** ** ** **** ** * ** **
* * ** *** * * * **** * ** * * * *
** * **** * ** ** ** ** * ** * %.6f ** **** ** *
* * * *** * * ** * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* * ****** ** *



int main()

{
** * **** * ** a1,a2,b1,b2,a,b,c;
** * * ** * * *** **** * %f %f **** ** **** * ***** * * * * ** * ***
** ** *** ** ** * ** * *
***** * * * **
* ** * * * ******** ***
* * *** * * * * * * * * %.6f %.6f",a,b,c);


*** *** * * *** * ***** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
** ** ** ** *** *



int main()

{
** *** ** * ** ** ** a1,a2,b1,b2,a,b,c;
******** * * * *** ** * ** %f %f *** ** * * *** * ** * * ***
* *** * * * *
* ** **********
* *** * ****** ** * *******
** * ** *** * ***
***** * * *** ****** * %.6f %.6f",a,b,c);


* * * * ** * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include *** ** * ** ***



int main(void){


* ** ** ***** *** ax , ay ,bx ,by ,a ,b * ***


* *** * * * * * * * *
* * *** * *** ** *** * * *** * *** * * ** * * * *** **
** ******* **** ** *** ** * * *** ** ** * * ** * * *
* * **** ** * ** * *** * * * ** ** * * **** * * * ** ** * * * * * * * * *


**** ** ** ** * *** * - bx) != 0){
* ** ** * ** * * = (ay - **** ** *
** **** ** * * * * *** = -m*ax + ay;
*** ** * ** ** = m;
** ** ** ** * ** * = 1;
* * **
*** ** ** ****** * * *
* ********** * * * * = 0;
*** * **** ***** = 1;
** * ** * *** *** = -ax;
*** **


** * * ** * *** ** = a;
* ** ** ** **** = b;
***** * ***** ** = c;


* * * < 0)
*** * *** ** * ******* * = -i;
** if (k < 0)
* ***** * * ***** ** = -k;


* * (i < 1){
* ** * * **** ** = 1/i;
** ** ** *** * = a*g;
* * * * ** * = b*g;
*** ** * * *** *** * = c*g;
****** *
* ***** if (k < 1){
**** * * ** ** = 1/k;
* * * **** ** * * = a*g;
* ** ** * = b*g;
* * * *** * * ** = c*g;

 }
** **** * * *
* **** * **** **
* ** ** * * ** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * **** * * *



int main(void){


** * ** **** ** ax , ay ,bx ,by ,a ,b ** ** *


* * ** ** **** ** ** * ******
* * ** ** ** ** ** * ** * * * ** *** ** *** *
* ** * *** ** * **** *** ** *** *** * * * * **** * *** ** *** **
* * * * * ** * *** *** * *** ** * ** *** * * *** * * * *


*** ** * * * *** - bx) != 0){
****** **** * * = (ay - ** *
* * ** * **** *** = -m*ax + ay;
* * ****** *** = m;
* * * *** ** * = 1.000000;
*
***** ** * * * * * *
* ***** ******** = 0.000000;
* * * * * ***** *** * = 1.000000;
* * * ** * * *** = -ax;
** *


******** * = a;
***** * * ** *** * = b;
*** ***** * * * *** = c;


* * * ** < 0)
* ** *** * ** **** * * = -i;
** * * if (k < 0)
* ** ** * ** ** *** * = -k;


(i < 1){
*** * * *** ** ** = 1/i;
* * * *** ** * ** = a*g;
* * *** * ** * = b*g;
********* *** ** = c*g;
*** * *
* *** if (k < 1){
* *** * * *** = 1/k;
*** * * ** * *** * * = a*g;
* * * * * * * * = b*g;
* * ** ** * = c*g;
***
*** * * ** ********
* ***** ** * *
** *** *** * *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* ** * *****
* *** ** ** * *
* * **
* i *** *
* a , b , c , * * ** ** *
** ** ; i ** * ; *
* ** * ** * , * * * * );




* * * * * *
** **** = **
*** ** * * * * * = - *
*


* ** ** * **** * *
*
* * *** * **** ** * *
* = * ** * ;
* = ;
*
* * * ** * ** *** ** a , b *








**** 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
* ** **** ***
*** * * * * * **

int main()

{
****** *** * * **** * * *** a,b,c,d,m,x,y;
* *** * * ** **** * * * * * * * %f %f ***** ** * * ** **** * * * ***
** * * ** * ***
** ***** * * * *****

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include * *** ****



int main(void){


*** *** * ** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* *** ** ** *** * *** ** * * * * ****
* ** * **** * * * * ** * * * * * * * ** ** ** ***
** * * *** * * * *** *** ** ** * * * * ** *** * * * *
**** * * ******** * * * **** *** * * * ********** ** ** * * * *


****** * * * * - bx) != 0){
* * * * ** *** * = (ay - * * *
** ** * * *** * = -m*ax + ay;
* **** * * * ** * = m;
* * ***** * ** ** = 1.000000;

 }
* ** ** * ** **********
* ***** *** * * * * = 0.000000;
* **** * * ** *** ** = 1.000000;
** ***** ** * * = -ax;

 }


* * * * * *
* ** * * ** ** * *
* * ** ** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** * * *



int main(void){


* * ** ** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


** **** ** ** ******* * * ** * * * * * *
****** ** *** ** * *** ** * *** ** *** * *
* * **** * * *** * * ** *** * * * * ** ***** * * *****
** ** ** **** **** * ** ** **** *** * * ** ** * * * ** * *** * **


**** * ** **** *** ** - bx) != 0){
* * * * * = (ay - ****** **
**** * * = m*ax + ay;
*** ******** * ** * = m;
* ** ** ** *** *** = 1.000000;

 }
* ** * * **** **
* * ** *** ** * = 0.000000;
* *** *** ** = 1.000000;
* * ** *** *** = -ax;

 }


* * ** * ** * * ** ***
** * *** *** * *
** * *** ** *** * **



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.27
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users