0 like 0 dislike
7.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.4k views

49 Answers

0 like 0 dislike
Hidden content!
// ** * *** * * by HoMingJui on 2016/11/3.

//



#include ** *** *

#include ****** * *****

#include * * * * *

#include **** * * **





int main(){
* * * * * ***** * x[2],y[2],a,b,c;
*** * * *** **** *** ** * ** %f %f *** * * *** ** * **** * * ** * * * *
* *** *** ****** ** * *** ** ** * * ** ***
* *** * * * ** *** ** *** *** * *
* ** *** *** **** * ******** * *
* * * * ***** ** **** * ** %.6f * ** *
* * * **** *** * * * ***** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* *** * * ** ***



int main()

{
* * ** * * * ** * a1,a2,b1,b2,a,b,c;
** ** ** * ** ** * * * ** %f %f * * **** **** *** ** ****
* ****** * ** ** * **
* ** ** * ***
** *** * **** * *** *
**** * * ** *** * *** * * * %.6f %.6f",a,b,c);


* * ** * * *** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
** **** * **** *



int main()

{
* ** *** ** * * * * a1,a2,b1,b2,a,b,c;
*** * * * * * ** *** * %f %f ***** ** ***** **** ****** *
* ******** * * ** ** *
** ** * * ** * * * *
** ** ***** * ** * * * *** *
******* ** *** * *
* *** * * **** * * * * %.6f %.6f",a,b,c);


* * *** ** * ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** * *** * **



int main(void){


*** * *** * * * ax , ay ,bx ,by ,a ,b *** *


*** * * *** *** * * * ** ** * * ** **
** *** * * *** * *** * * **** * * ** *
** ** ** *** * ** * *** **** * ** ** * * * * * * * ******
** * * ** * * **** *** * * * * * ** *** * *** * *** ***** * * ** *****


* * **** * **** *** - bx) != 0){
***** * * * ******** = (ay - ******
*** *** *** = -m*ax + ay;
** * ** * *** ** = m;
* ** * ****** = 1;
* *
** ** *** *
* *** ** * = 0;
* * ** * *** * ** ** = 1;
* * ** ***** * * = -ax;
* **


* ** ** * = a;
**** * * ** ******* = b;
* * * * * * ** = c;


* < 0)
* ** *** * * * *** ** = -i;
* * **** if (k < 0)
* **** * ** ** ** ** = -k;


*** (i < 1){
* * * * * * = 1/i;
**** ** * * = a*g;
* ** ** *** ** = b*g;
*** * * * ** *** = c*g;
* *
****** * if (k < 1){
* * ** * *** * = 1/k;
* ** ***** *** *** ** = a*g;
* **** * ******* * * * = b*g;
** ** * ** * *** = c*g;

 }
** * **** **** **
* ** * * *
** ** * *** * ** * *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include **** * * ***



int main(void){


** * ** * ** * *** * ax , ay ,bx ,by ,a ,b **


****** ** *** * ** * ** * * * * * * **
** * * ** ** * *** *** ** * ** * ** * * ***
* * ** * ***** **** ** * *** * * * *** * ** ** ** ** *
*** **** * * ** * * ** ***** ** **** * * **** **** * ****** *** *


*** * * ***** *** - bx) != 0){
* ** ** * = (ay - * ** ** *
* * *** ** * *** = -m*ax + ay;
** * * ** * * * * = m;
***** * ** * * * = 1.000000;
* **
***** * **** * * **
***** ** * *** = 0.000000;
** * * *** * ** * * = 1.000000;
* ** * * ** = -ax;
** *


* * * * *** ** ** = a;
*** * ** * * * * = b;
** * * = c;


***** ** *** < 0)
* * * * ** * ** = -i;
*** * * if (k < 0)
* * * *** ** * * * * ** = -k;


* ** * (i < 1){
* *** *** * * * = 1/i;
*** * * **** ** * * = a*g;
*** * ** * * = b*g;
** * * ** = c*g;
* * * **
** * * if (k < 1){
* **** * * * * * = 1/k;
* **** * * * ** = a*g;
** *** * * = b*g;
** * * * ** * ** = c*g;
** **
** ** * ** **** *
*** ** * *** *** **** *
*** ** ****



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* *** *** * * *
** **** ***** *
*
* i *** *
** a , b , c , * * ** * * **
* ; i ** ; **
* * *** ** , ***** );




** *
** * * * ** =
***** * ** * *** *** * ** = - **
*


* ** * * * ** **
*
* * ** * ***
= * ***** ;
* = ** ;

* * * * ** ** ***** * ** a , b *








** ** 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
* ** * * * ***
**** * * ** **** *

int main()

{
** ** *** ***** ** ** ** a,b,c,d,m,x,y;
**** ** * ***** * *** ** ** %f %f ***** ** ** * * ** ** * * * * **
** **** * * *** * ** * * * * *
* *** *** * * * * * ** ***

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include *** ** ** *



int main(void){


* * * * * * * ***** ax , ay ,bx ,by ,a ,b ,k,m,c;


**** * * ** ******** ******* * * ** * *** * *
*** **** *** ** * * * * ***** * * ***** ** * ***
** * * *** * *** * * * * *** * ** ** * * * * * * **
*** * *** *** * ** * **** * **** ** * * ***** ****


** ** ** * ** ** * - bx) != 0){
*** ** *** *** = (ay - * **
** *** * * * ** = -m*ax + ay;
****** * * * * ** *** = m;
** * * *** * * * = 1.000000;

 }
* * ********* * * *
* *** * *** * ** = 0.000000;
** *** **** ***** = 1.000000;
** ** * ** * ** = -ax;

 }


** ** ** ** * * * *
* *** * * ***
** ** * * * * ** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * *** ***** **



int main(void){


* ** * ** * ax , ay ,bx ,by ,a ,b ,k,m,c;


**** ** ** ***** * * * * * ** *** * * ** * *
* *** ** * ***** * ** ** ***** *** * ** * *** *
* ** * ** * * * ** ** * * ** * ** * *** *** **** * ** *****
** ** ** * *** *** ***** * ** * * ** ***** ** ***** * * * * * * * **


* *** * ** * * * * - bx) != 0){
* **** * *** * * = (ay -
****** ** * ** ** * ** = m*ax + ay;
* *** * ** *** ** = m;
** ****** * = 1.000000;

 }
* *** * * * * **
*** * * * ** = 0.000000;
* ** * **** = 1.000000;
*** ****** * * * ** * = -ax;

 }


* ** ** * *
* * **** * * *** **
* ** * * ** *** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 13k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users