0 like 0 dislike
3.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.4k views

49 Answers

0 like 0 dislike
Hidden content!
// * * by HoMingJui on 2016/11/3.

//



#include * * ** *** *

#include ** ** ***

#include ** * * * **

#include ***** * ****





int main(){
***** **** ** * ******** x[2],y[2],a,b,c;
**** * **** * * ** ** ** ** ** %f %f * * * *** ** * ** * *** * * ** * * *
** * ** * * ** ** *** * * **** *
* ** *** * ** * * ** * *** ****
** ** *** ** ******* ** ** * * *
**** ** ** * * * * * * ** %.6f ******* *
******* ** * *** * ** **** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
*** * * ** ** ****



int main()

{
* ** * ** * *** a1,a2,b1,b2,a,b,c;
***** * **** *** * *** %f %f * ** ** * * * ** ***** * ** ** ** * * *
* ** * ** ** * ** ***
** *** * *** * * * ***
** **** ** * * * * *** *
* * * * ** * ** ** * ** * %.6f %.6f",a,b,c);


******** * **** ****** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * ** ** ** **



int main()

{
* * * ******* *** * * a1,a2,b1,b2,a,b,c;
*** *** * ** * * * *** %f %f *** ** * * * **** * * * * ** * *** *
* ** *** * ** * * ** **
***** * * ** *
* * ** ** **** ** ** *
***** * ** * ** ** **
*** ** * * ****** * * * *** %.6f %.6f",a,b,c);


* * * **** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include **** * ** *



int main(void){


* ** *** * ***** ** * ax , ay ,bx ,by ,a ,b * ** *


** ******* ** *** * ** *** * * *** ** *
** * * * * ** * **** * * ** * * * ** *
* *** ** ** ******* ** * * * **** ** * ** * * * * *
** * * ** ****** * ** **** ** * ** *** ** *** * * **** *** ** ** *


* * ** ** * * - bx) != 0){
** * ** * ** * = (ay - ** ** *
* ** *** ** * * ** * = -m*ax + ay;
**** ** ** * = m;
* * *** ** * * = 1;
** * **
* ****** * * ** * * * *
* ** * ** * * * = 0;
* ** * * * ****** * = 1;
* * ** * ** *** = -ax;
*** **


* * * ** * * = a;
** ** * * * * ***** = b;
** * ** * * **** * = c;


** *** * * < 0)
* ****** * * = -i;
** * * ** if (k < 0)
* * * * *** * *** * = -k;


****** * (i < 1){
* *** *** *** ** = 1/i;
* **** * * * * = a*g;
** ***** * ***** = b*g;
* *** * **** * * ** = c*g;
* * **
* * if (k < 1){
* * ** * ** * * * * = 1/k;
*** * = a*g;
** ** * **** * * = b*g;
* ***** ** * ***** * = c*g;

 }
**** * ** * *** *
** *** * * * * ** ***
*** * * * *****



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * **** ** *



int main(void){


** * * ** ** *** ax , ay ,bx ,by ,a ,b * * *


** ** * * ****** ** *** * ** *** * * ** * * *
* ** ** * * * * ** ** *** **** ******** ***** * ***
* *** * * * *** * * ** * *** ** * **** ** *** * ** *
*** ** * ** ** ** ** **** ******* **** * *** ** * * * *** * ** * *** ** ** *


*** * * ** ** * ** - bx) != 0){
***** ** * * ****** = (ay - * * *
* * * *** ** ** = -m*ax + ay;
* ** * ** * * ** = m;
** ** *** * * * = 1.000000;
*
* * * * ** ** *** *
* ** * = 0.000000;
** **** * * = 1.000000;
* **** ** ** ** * = -ax;
* * * *


** *** * *** ** = a;
* ***** * ** * = b;
* ** ** * ** * = c;


** * ** < 0)
** * ** * * * * * ** * = -i;
* **** if (k < 0)
** * * * ** * * * = -k;


* * (i < 1){
** ********* * ** = 1/i;
**** * ** ** = a*g;
* **** *** * = b*g;
* * * ** * *** *** = c*g;
*** ***
* if (k < 1){
** * * * ** = 1/k;
** *** *** * * ** = a*g;
** *** ** ** * **** = b*g;
* **** * = c*g;
* *****
* * *** * * ** *
** ** * * ***** * **
* * ** ** ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* *** *** * ** ****
** ****** * * *
* ** *
** * i ****
* a , b , c , ** ***** *** *
** ; i * ** ** ; **
* * ***** *** , *** * );




******* *
* * * **** ** =
* **** * ** *** * = - * *
*


* ** *** * * * * *
*
* * **
** = *** ** * ;
* = * ;

* **** * * * *** * * * a , b








** 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
** * ** * * *****
** *** *** * *** *

int main()

{
* ***** ** ** * * a,b,c,d,m,x,y;
* ** * * * * * ** * ** * * * * %f %f * * *** ** * ** * * * **
** * * ** * ** * * ** *
* ****** ***** * **

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include **** ** *



int main(void){


**** * * * * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* ** * * ** ** **** * **** * ** ** * ** * *
* *** *** * * * **** * *** * ******** * *
* * ** ** * * ** * * * * ** **** * * * * **** * * ***
* * * * ** * ***** * * * * ** * ***** * ** * * * * *** ** *


* *** * *** * * **** - bx) != 0){
** ** ** ** * = (ay - * *
* *** *** ***** = -m*ax + ay;
* * ** *** * ** = m;
* ** ** ** * *** = 1.000000;

 }
* ** * *** ** * * * *
* ** *** ***** = 0.000000;
*** * * *** = 1.000000;
**** * * * * * ** ** ** = -ax;

 }


* * *** * *** *
*** * ** ** *
**** *** ** *** ** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** **



int main(void){


** ** ** ********* ax , ay ,bx ,by ,a ,b ,k,m,c;


** * * * * ** ** ** * * *** * * *
** ** * * * * ** * * * ** ** * **** * *** * * **** **
* * * * * ** *** ******* ** ***** * * * ** * * * * *
* * ****** *** *********** * ** * * ** ** ******* * ** * *


* * **** *** * * - bx) != 0){
** ** *** *** ****** * = (ay - * ** *
* ** ** **** *** = m*ax + ay;
* * * *** * = m;
* * * **** * * **** * = 1.000000;

 }
** *** **** * ***** **
* ** ** * * * = 0.000000;
** * ***** * = 1.000000;
**** * *** ** * = -ax;

 }


* *** ** * * *
* ** ** * ** **
** * * * * ***



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.159
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users