0 like 0 dislike
4.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.1k views

49 Answers

0 like 0 dislike
Hidden content!
// ***** ** by HoMingJui on 2016/11/3.

//



#include ** * * * * * *

#include **** ***** **

#include * *** ** * *

#include * *** * * * *





int main(){
** * *** ** * *** * * ** x[2],y[2],a,b,c;
* * ****** ** * ****** * * ** %f %f ** *** ***** ** * * * * ***** *
**** *** ** ** ** * *** * * ** *** *
*** ** * ** * *** ** **** * * * * *
* **** * ** * * **** * **** *
***** * * **** * * * ******** *** %.6f ** * ** ***
** ***** * * * ** * * * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** *** * **



int main()

{
* * ***** * * a1,a2,b1,b2,a,b,c;
*** ** * * ***** **** * * * %f %f * ** * * * ** ** * * * **
** * * * * *******
* * * *** * ** * **
** **** * ** **** * **
** *** * **** ****** ** * * %.6f %.6f",a,b,c);


*** ** ** ** **** ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* *** * * **



int main()

{
** **** ** ** * * *** a1,a2,b1,b2,a,b,c;
* * ** *** * * %f %f * * * * * ********* ** * ** *
* ** ** * * * * ***
* * *** * * ***** * ***
*** * * * * * **** *
* ** *** *** *
* * * * ***** *** ***** * %.6f %.6f",a,b,c);


* * * * * * ***** ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include **** ** ** ***



int main(void){


* * ***** ** * ** ** ax , ay ,bx ,by ,a ,b * *


** *** ** **** ** *** * ** **** * * ** *
** * ** ***** * * * * * ***** * * * * *
* *** ** ** **** * ** * *** * ** *** * ***** * ** **** *
* ***** * ** **** * **** * * ** * ** * ** ** * *** ** ** *** * **


* * * * * ** *** - bx) != 0){
** * *** **** *** = (ay - *** ****
** * ** ** * = -m*ax + ay;
** *** *** = m;
***** * * * * * = 1;
* * **
** *** * *** * ***
*** * *** * = 0;
** **** * = 1;
*** * * * **** ** = -ax;
* *


* ** * * * * = a;
******* *** * = b;
* ** * ** * *** * = c;


* *** ** ** < 0)
* ** * * * ** *** * = -i;
* ** * if (k < 0)
* * ** * * *** = -k;


* ** * (i < 1){
* **** * *** *** = 1/i;
**** ** * * ** = a*g;
* **** * * * * * = b*g;
** ** *** * = c*g;
* * *
**** ** if (k < 1){
* *** ****** * * * = 1/k;
** ** * ** ** * = a*g;
** *** * * * * **** = b*g;
****** *** * * * = c*g;

 }
**** * * ** ***
*** * ***** *** *
**** * * * * ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** * * *



int main(void){


** ** ** * * *** * ax , ay ,bx ,by ,a ,b * ******


*** ** * * * *** * ** ** ** ** * **** *****
* * **** * * *** ** ** ** * ** ** ** ** * * *
* * *** * * ** * *** **** * * *** * *** *** *** * ** * * * * *
** ** * ** * ** *** ** ***** *** ** ** **** **** ** * **** * * ** ** ****** **


**** * * * * * - bx) != 0){
** *** * * * = (ay - ****
* *** ** **** ** = -m*ax + ay;
* ** ** * *** **** = m;
*** * * *** * ** = 1.000000;
* ****
* * ** ** * *
* **** * * * * = 0.000000;
** ***** **** = 1.000000;
** * * * ** ** = -ax;
******


** ** *** * ** = a;
*** ** * *** * = b;
* * * * * * * ** *** = c;


* * * < 0)
* * ** ** *** ** ** = -i;
**** * if (k < 0)
*** *** **** ** ***** = -k;


* * * ****** (i < 1){
* ** ** *** ****** = 1/i;
** ** * ****** * * * = a*g;
* ** *** * * * = b*g;
** *** ** * * ****** = c*g;
** ** *
* *** ** * if (k < 1){
* * * * * ** = 1/k;
** * * *** * ** ** = a*g;
** ** ** * * = b*g;
* * * * ** ** * = c*g;
*** * ** *
* * *** * *
** * *** * * * *
*** * * * * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
** **** ****
* **** *
* **
** i ** *
** a , b , c , * ***** * ** *
***** ; i ** ; *
* * **** ** * , ** );




*** *
* * * * = *
*** * * ***** **** = - ***



** *** ** *** **** ***

* ** ** *** *
* = **** * ;
* = ;
*
* * * * *** * * a , b * *








* * 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
** ** ** *
* * ** * ******

int main()

{
* ** ** * * * ** ** * *** a,b,c,d,m,x,y;
* * * * ** * ************ ** *** %f %f ** ** ** ** ** ** * * * * ** ** * *
*** ***** **** *** * *
*** *** * * ** ***** ** **

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ** * ** * **



int main(void){


* * *** * ** ax , ay ,bx ,by ,a ,b ,k,m,c;


** * * * ** ** ** *** ** ** **** **
* * ********** * ** * ** * *** ** * **** *
* ** * * * ** * * * * *** **** **** * ** * * ** * *** ****
* *** ** * * ** * **** * ** ** * * **** ** * * ** *** * * * * * * * * ****


* * *** *** ** - bx) != 0){
* * *** * ** * = (ay - * * *
* ** * *** * ** = -m*ax + ay;
*** *** ** * ** * = m;
* * * ** ** *** * = 1.000000;

 }
* **** * *** **
** * **** ** *** = 0.000000;
*** * * *** = 1.000000;
** *** * = -ax;

 }


** ** ***** * * *****
* ** * * * * ****** *
** ** ** **** * * * *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ***** * * *



int main(void){


** * ****** * **** ** ax , ay ,bx ,by ,a ,b ,k,m,c;


**** *** * *** * * ** * **** ***
** ** *** * ***** * * ** * ** **** * * **
** * ** **** ** *** * * * ** *** ** * **** * ** *** ***** * * **
*********** ** ** * **** *** ** * ******* * * * * * * * * ***


* *** ** * ** * *** - bx) != 0){
* ** * * * *** * ** = (ay - * **
***** *** * ** * * = m*ax + ay;
* * * ** ** = m;
** * *** * * **** = 1.000000;

 }
* *** ** * * * *
*** *** *** **** = 0.000000;
** * ** * ** ** **** = 1.000000;
**** * * ** * = -ax;

 }


* * *** * ****** *
* * * * ** * *
** *** ** * * *** **



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.3
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users