0 like 0 dislike
4.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.2k views

49 Answers

0 like 0 dislike
Hidden content!
// * * * * by HoMingJui on 2016/11/3.

//



#include *** **

#include **** * * * *

#include * ** * ***

#include **** *** * ** *





int main(){
** * * *** *** **** ** * x[2],y[2],a,b,c;
** *** *** ***** * ** * * * * ** * * %f %f ** * *** *** ** *** **** *****
* * *** * * * * ******** * ** * * ** *
* * * *** * * * ** ****** ****** * ***
**** * * *** * * * * * * ***
*** ** * * *** * * * * ** ** * %.6f **** ** * *
** ** * * * * ** * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
*** * ***



int main()

{
* * *** * ** *** a1,a2,b1,b2,a,b,c;
*** * * ** ** * ***** %f %f ** * *** * *** *** ***** * * * ** *
* * ** * ** **** * ****
* * * * * ** * ** * *
* ** ** * *** *
* *** ** * ** ***** %.6f %.6f",a,b,c);


** *** *** ** * ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
** ****** **



int main()

{
* * * * ** * ** * a1,a2,b1,b2,a,b,c;
** *** *** ** ** ** ** ** ** ** *** %f %f * ** ** * * * * *** * ** *** **
*** ** ** * * * ** **
* *** * * ** * * *
* * ** ****** *
* ** *** ** *
** * * ******** *** * ** %.6f %.6f",a,b,c);


* ** ** *** ** *** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include *** * * *** *



int main(void){


** *** *** *** * ax , ay ,bx ,by ,a ,b **** *


* *** * * * ** * *** * * *** **** * *
* *** *** *** ** **** * * * * ***** * *** ***
** * * *** * ** ** * ******* * * * * ****
*** ** *** * * ********* * * * ** ** * *** *** ** * * *** **** ** * *


* * ***** ** * - bx) != 0){
* * *** * ** * = (ay - **
** *** * * * = -m*ax + ay;
* * ** ** * ** * = m;
*** *** * * * * * = 1;
* * *
*** ** *** * **
** * * * ** *** = 0;
* * ** * * *** = 1;
**** ** * ***** = -ax;
***


** ** * * ** * * = a;
** * * * * *** *** = b;
***** * ** = c;


**** * *** < 0)
* * * ** * *** = -i;
* ****** if (k < 0)
* ** ** ** * ** * = -k;


** * (i < 1){
* * * *** * ** = 1/i;
*** * ***** * * = a*g;
* *** *** * = b*g;
*** * * * * * ******* = c*g;
* ** *
***** if (k < 1){
**** ** ** * *** = 1/k;
* ** ** ** *** = a*g;
* ** ** **** * * = b*g;
** ***** * * ********* = c*g;

 }
** *** ****** ** * * *
** * * * ** * * *** * **
** * *** * ** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** ** *** **** * **



int main(void){


** *** * * * * * **** ax , ay ,bx ,by ,a ,b ****


* *** * * * * ** *** * * * * *** ** * *
*** **** * * ****** * * * * ** *** * ***** **
* * *** **** * * ** ** * *** * * **** * * * * ** ***
* *** * ** * ** * * * * * ** ** ** *** * ** * ***** **** * * *


* ** * ***** * - bx) != 0){
* * ** * * ** ** = (ay - ****
* ** **** * * = -m*ax + ay;
** * ** * *** * ** = m;
** *** *** * **** = 1.000000;
**
* **** * *** *****
**** * ** ** ** = 0.000000;
* * * ** *** = 1.000000;
* * ***** * * = -ax;
* ** * *


** * **** *** = a;
* * * * * * * = b;
* * ** ** * * * = c;


** ** ** < 0)
***** ** * ** *** ** = -i;
* ***** if (k < 0)
** * * ** * ** * *** * = -k;


* ** (i < 1){
* * * * ** *** = 1/i;
**** ** * **** * * ** = a*g;
** ** * * * ** = b*g;
** * ** * ** * * * = c*g;
** *
* * * * if (k < 1){
* * * ***** * ** = 1/k;
* * *** * * = a*g;
*** * ** = b*g;
** * * * **** * * = c*g;
**
* **** ** * * ** * *
* * * * * *** * *
******* * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * ** * *** * *
*** * * ** ***** *
* ****
* i * *
** a , b , c , * ***** * *
** * * ; i *** ; *
** ******* ***** , ** * );




** **
* *** * ** * * = *
* * * * ** * ***** = - *
*


****** * *** ** *** * *
*
*** ** * ***
= * ;
* = * ;

* * * ** ** ***** ** a , b *








** * 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
** ** * * ****
**** * ** * * ****

int main()

{
** * ** * ** **** * a,b,c,d,m,x,y;
* ** * ** * *** *** *** * %f %f * * **** * * * * * * *** *
* * ***** ***** * * * **
*** * ** ******* * * * *** **

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include * *** * * **



int main(void){


* ***** ** * ***** ax , ay ,bx ,by ,a ,b ,k,m,c;


***** * * * * * **** *** * *** * ***
* **** ***** * ** ** * * * * * * *** * **** * * * * *
** * * ** * *** ** * * * * ** ******** ** * * * *******
*** *** ** * * * *** * * * * **** ** ** ** * * * **** ** * * *


* ** **** ** * * * - bx) != 0){
* * **** **** * = (ay - ** * *
** * ******* *** = -m*ax + ay;
* ***** ** * * * * = m;
*** * ******* * * = 1.000000;

 }
* *** * * **** *
* * ** ** * * = 0.000000;
** ** ** ** * * * = 1.000000;
* * ** ******* * * * = -ax;

 }


* * ** *** * ** *
* *** **** *
** ** ** * ** ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** * **



int main(void){


* * * * * ** ** ax , ay ,bx ,by ,a ,b ,k,m,c;


** ** * ** ** ** *** ** ***** * **** ***
** * **** * *** * **** * * ***** *** * *** ** * ******* ** *
* ** * ** **** ** *** * **** ** * * ** *** * * *** * *** ** **
**** * ** ** * *** ** *** ** * *** **** * * * **** * * * * *


* * * * * * * * * - bx) != 0){
** * ** **** ** = (ay - * * ***
* *** ** * * * ** = m*ax + ay;
* * ** * * * * = m;
* ** **** * = 1.000000;

 }
** ** ** ** ** ** **** *
** ** *** * * **** = 0.000000;
*** * * ******** = 1.000000;
** *** * * *** * = -ax;

 }


* * * * * * *
* ******* ** ** * *
** *** * * * *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.197
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users