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直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

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// *** * * * by HoMingJui on 2016/11/3.

//



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}
answered by (-126 points)
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Hidden content!
* * ** ** **



int main()

{
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}
answered by (-124 points)
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Hidden content!
* * **** * *



int main()

{
* ** * * * a1,a2,b1,b2,a,b,c;
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}
answered by (-124 points)
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Hidden content!
#include ***** * * *



int main(void){


* ** *** ** ***** * * * * ax , ay ,bx ,by ,a ,b * **


** *** * **** ** * * ** * ****
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* ** * *** * = b*g;
** ** * ** * = c*g;

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return 0;

}
answered by (-122 points)
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Hidden content!
#include * ***** ** *



int main(void){


** **** * *** **** ** ax , ay ,bx ,by ,a ,b *** *


** * *** * * *** *** * * * *** * ** * *
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return 0;

}
answered by (-122 points)
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Hidden content!
** ** **** *
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* *
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answered by (-87 points)
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Hidden content!
* ** * ** **
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int main()

{
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}
answered by (-103 points)
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Hidden content!
#include ** * ** *



int main(void){


* * ** ** * * ** * ax , ay ,bx ,by ,a ,b ,k,m,c;


** ** * * ** *** ** **** * ** ** * *
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 }


*** **** * * ** * * **
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return 0;

}
answered by (-122 points)
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Hidden content!
#include * *** * **** ** *



int main(void){


**** ** ** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* * ***** ******** * *** * * * * *
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 }
*** * * * ** * *
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*** * * *** ** = -ax;

 }


*** * *** * * *
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*** * ** * ** * *



return 0;

}
answered by (-122 points)
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