0 like 0 dislike
7.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.4k views

49 Answers

0 like 0 dislike
Hidden content!
// * * * by HoMingJui on 2016/11/3.

//



#include * ** *

#include * * **** * *

#include ******

#include * * * * * *





int main(){
* *** * ** * * ** * * * x[2],y[2],a,b,c;
** * * **** ** ** ***** * * *** %f %f ***** *** * ** * * ** ** * * *** * *** ****
**** ** **** * *** ** **** * * *
* * ** ** *** * * *** ***** * * * *
* * ** * * * ** *** *
* ** ** * * * * **** ** ** ** * %.6f * ** * ** ** *
*** * ** * * ******* 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** ** ** * ** * *



int main()

{
** ** * ** *** * * * a1,a2,b1,b2,a,b,c;
***** * *** * *** *** %f %f * * * * ** ** * **** **** * ** *
* * ** * * * ** ** ** *
* * **** ** * **** * ***
**** *** ** * ** ******
* **** ** *** * * * *** *** *** %.6f %.6f",a,b,c);


**** **** ** * * * * **** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* ** * * **



int main()

{
* ** *** * *** ** a1,a2,b1,b2,a,b,c;
** ** *** **** * * ** ** ** %f %f * * ** * * * * * * * ** *****
*** ** ** *** ** ** ** *
* *** * ** * * * *** *
*** ** ** *** ** ** *
* * * * * *** * *
* * * * ****** * *** * ** %.6f %.6f",a,b,c);


* **** * ***** * * ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * * * * * *



int main(void){


* ** ** ** * ax , ay ,bx ,by ,a ,b *** * *


* * * * * ** *** * **** *** *** * ****
** ** * * * * * *** ** * **** * * **** *** * * *
*** **** * * * ** * * * ** * * ** ** ** * * * ** * *** *
* * * * ***** ** * * * ** ** * ** * *** ** * *** * * ** *** * ** **


** ** ** * ** * * * - bx) != 0){
* *** ** * * * = (ay - *** *
* * **** * * ** = -m*ax + ay;
*** * * * * * ** = m;
* *** **** *** * = 1;
*******
*** * * * * *** *
* ** *** * **** *** = 0;
* ** ** * * = 1;
***** ** *** * * = -ax;
* * *


* ** *** ** = a;
* *** ** **** ** * = b;
* * * ** * *** * = c;


** ** ** < 0)
***** **** ** * * = -i;
** ** if (k < 0)
* * * ** * * * ***** * = -k;


* ** *** (i < 1){
** ** * * *** *** = 1/i;
*** * ************* = a*g;
** ***** *** * = b*g;
* ** * ** * * = c*g;
** ** * *
** ** ** * if (k < 1){
** * ****** ** = 1/k;
** * ** ****** ** ** = a*g;
** ** ******* = b*g;
** ** ***** = c*g;

 }
* ** ****** *
* ** * * * * * * *
* ** ** ** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** ** *****



int main(void){


** *** ****** * * * ax , ay ,bx ,by ,a ,b * * ***


* ** * **** * * ***** * ** *** *** **** *
**** * ** * *** * *** * **** ***** ** * * * ** *
** ****** * ** * * * * * *** **** * ** * * ** * * *** * * *
* * * *** *** * * *** * ** **** ****** * * ** * * ****** *** **** * * ***


**** *** * * * * * - bx) != 0){
******* ****** * = (ay - * ***
* **** ** **** = -m*ax + ay;
** *** * * = m;
* * *** ** * = 1.000000;
**** * *
** ** ***** ****
*** * ** *** = 0.000000;
** ** * * * *** *** = 1.000000;
** ** ****** ** = -ax;
*** * **


* * * ** ** * * = a;
* ** * * *** * * = b;
******** * ** = c;


*********** < 0)
* * ** ** ** * * = -i;
*** * *** if (k < 0)
* ** *** *** *** ** * = -k;


* * **** (i < 1){
*** **** * **** ** * = 1/i;
* ***** ** **** * = a*g;
* * ** ** * **** * * = b*g;
***** *** **** = c*g;
*** **
* ** *** if (k < 1){
* * * *** = 1/k;
** ** * * ** *** = a*g;
* *** * ** * * ** = b*g;
* * * ** * * * = c*g;
** *
** *** ** * *
** *** ** * ** *
* * ** * ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* *** **** * *
** *** ** ***
*** * **
i ** *
* a , b , c , ** * * * ***** * *
* * * ; i *** * ; *
** * **** ** , * ***** );




*** * *
* ** * ******* = **
* *** ** ** * * ** ** * = - ***



* *** *** * * * * ** **
*
* * ****** *
= * * * * ;
= ;

* ***** * **** ***** *** a , b **








* * 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
**** * ** *** * **
** * * ** ****

int main()

{
**** ** **** *** ** * * * a,b,c,d,m,x,y;
* * ***** * * * * ** * *** * ****** %f %f ** * * ** ** * * * * **
*** ** * **** ** * *
* * * **** ** *** * * *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include * * * ** * *



int main(void){


* * * * * * **** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


** ** * ** * * * * * ** * * ** ** ** * *
** ** ** ** * * **** **** * * * *
* ** ******** * * * * ** ***** * *** * * ** * * ***** *
* * ** * * * * ** ** * **** ** * ** * ** ** ***** ** **** * ** * *


* ******* * ** *** *** * - bx) != 0){
** ** *** * ** = (ay - **** *
* * * * ****** = -m*ax + ay;
* *** * * * * = m;
* * * * *** * = 1.000000;

 }
**** * * *** *** * *
**** * * * * * = 0.000000;
*** * *** * ** * = 1.000000;
** * ** * * * * = -ax;

 }


* ** * * * *** **
* * * * * * *
* ** * **** * * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** **** **



int main(void){


****** ********* *** ax , ay ,bx ,by ,a ,b ,k,m,c;


*** * * * **** * *** * * *** ****
* * ** * **** * * * * *** ** *** * ** * *******
** * ** ** ** * ** *** ** ***** *** ** ** * * * * ** ** *
* ** * * * ********* * * * ** * * * ** *** * * * *** * ** * ** *** * * *


**** * ****** *** ** * - bx) != 0){
****** *** **** = (ay - * **
* ** * *** * * ******* = m*ax + ay;
* ** * * * ** *** = m;
** * *** * * * * = 1.000000;

 }
** * * * ******* **
*** * ***** ** * ** * = 0.000000;
* ** **** ** * = 1.000000;
** * ** *** * = -ax;

 }


* *** * * ** **
* **** ***** * * *
* * ***** * * ** ** ** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 13.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users