0 like 0 dislike
6.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.2k views

49 Answers

0 like 0 dislike
Hidden content!
// *** * * ***** by HoMingJui on 2016/11/3.

//



#include * ** * * * *

#include * *****

#include ** ** * * *

#include * ** * * *





int main(){
*** **** *** * ****** * x[2],y[2],a,b,c;
* * *** * *** * * * ** ** %f %f * ** ** ** ** ** *** ** * ** **
** * ** * * * ** ** * *****
***** * ** ** * * *** *** *** * *** * *
** * ** * **** * ** * * ** ** ** * ****
* ******* * * ***** * * * ** %.6f ***** * * *
** **** *** ** *** * * ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
*** ***** * *



int main()

{
* * *** * ** **** ** a1,a2,b1,b2,a,b,c;
* *** * ** ******** ***** ** %f %f * ** ***** * * *** * ** * *
** ** * ****** * ** **
** * *** * * * * ** **
*** ** * ** * * * *
** ** * ** * * ** ** %.6f %.6f",a,b,c);


* * ** * * ** ***** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * * ** *******



int main()

{
* * ** ** ** * ** * * * a1,a2,b1,b2,a,b,c;
* ** * * ** ** ** * %f %f * ** * ***** ** * * *** *** * *
** ** ** ** ** ***
* *** **** * *** ** * **
** ** * ** * ** * ** *
* * * *** * * * **
*** ** *** ** ** * ******* * *** %.6f %.6f",a,b,c);


* ** ** * * ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * *******



int main(void){


* **** * ** *** ax , ay ,bx ,by ,a ,b ** ** ***


* * * * * * *** * ** ** * ** ** *
** ***** ****** * ***** * **** ******** **** ***** *** * ** **
******* * *** ***** ** * * ** *** *** ** **** ** * ** * *** ** * *** *
* * ***** * ** ** ** * * ** ** * * * ** * * * ** *** *** * * *


* **** *** * * ** ** - bx) != 0){
** *** *** = (ay - *****
** ** * * * * = -m*ax + ay;
* * ** ** * ** * = m;
*** * = 1;
*
* * ***** ** ** * *
** * *** * *** = 0;
*** * * ** ** = 1;
**** * * * * * = -ax;
***


*** * ** * * * = a;
* * **** * ****** *** = b;
** ** ** ** = c;


******** < 0)
* * * * * * ** * **** = -i;
**** * if (k < 0)
* ** * ******** **** = -k;


* (i < 1){
** * **** = 1/i;
** * *** * ** * * * = a*g;
* * * ** *** * * = b*g;
** * * ** * ****** = c*g;
* ***
* ***** if (k < 1){
** *** ** * = 1/k;
*** * * ***** **** = a*g;
* * ** ** * * ** * = b*g;
* **** ********* = c*g;

 }
******* *** ***
** ** *** * * *
*** * * **** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ***** ** ** *



int main(void){


** * *** ** ax , ay ,bx ,by ,a ,b * * *


*** * **** **** * ** ****** * *** **** ***
** * ******* ** * * * * ****** ** * * *
** ** ** * * ** ** **** * ** *** * **** ***** ** * ** * ** * *
** * **** * * ***** * ** * ** *** * *** * ***** * * *** **** * ** ** *


*** ** * * * ** * - bx) != 0){
* ** ** * * = (ay - ** ** *
* * * ******* * = -m*ax + ay;
* * * * * *** = m;
* * * ** * ** * = 1.000000;
* * ***
* * * ** * * ** * ***
* * ** *** * *** = 0.000000;
** ***** **** * = 1.000000;
*** **** * * = -ax;
*** *


* * * ** *** * * = a;
** * *** *** * = b;
*** * **** ** * * = c;


*** * ** * < 0)
* *** * * * ** = -i;
*** if (k < 0)
**** * ******* * = -k;


* * (i < 1){
* ***** ** ** *** * = 1/i;
**** *** ******** * * = a*g;
* ** * * * * * * *** = b*g;
*** *** **** **** = c*g;
**
**** *** if (k < 1){
* * * * * * = 1/k;
****** **** *** ** * = a*g;
***** ** * * * ** = b*g;
****** * * * * **** = c*g;
* ** *
*** *** * ***
* * * * * * * **
** * ***** ** ********



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* ** * * * **
** ***** * * * *** *
****
*** i * ** *
** a , b , c , * * **
* ; i ** * ; ***
****** * * * *** , ** **** );




**** **
* ** *** ** * *** = *
** * ** * *** *** ** = - **
*


* * ** ** ** * ** **

** * * * * *****
* = ** ;
* = * ;
*
* **** * * * ** *** a , b **








* * 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
* * ***** * * ***
* *** ****

int main()

{
* * ** **** * * a,b,c,d,m,x,y;
***** ***** ****** * *** * *** %f %f *** * ** * * * **** ** *** * *
** *** * * ** * ****** ***
* * ** *** ** ** ** ** *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include **** ** * * *



int main(void){


* * * * * * * **** *** ax , ay ,bx ,by ,a ,b ,k,m,c;


* * * *** * * * ** **** * ****
******* * * * * ** * ** * * *** *** *** ** * * * *
* ***** * *** * * * ** ** ** ** *** * * ** * ***
* * * ** * * ** * * *** * * * * ** * * **** * * * *** ** **** * * ***


* ** * *** * * * ** * * - bx) != 0){
** ** * ** * ** = (ay - ** ***
** * * ** * * = -m*ax + ay;
**** * ** ** * * = m;
* * ** * *** * *** ** = 1.000000;

 }
** **** ** *
* * * ** = 0.000000;
*** * * * * *** = 1.000000;
***** * *** **** = -ax;

 }


** *** ** * * ** ** **
** ** ** ** * *
** * * * * * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * *** *** *



int main(void){


* ** ** * *** * ax , ay ,bx ,by ,a ,b ,k,m,c;


** ** * * *** ** * * *** * ** *** *
* **** *** * * * ** * *** * ** ** * ** **
* ** * *** *** * **** ***** * *** * *** *** * **
* ** **** ***** * ** * ** * *** * * * ** * * ** * ** ** ** **** ** *


*************** * - bx) != 0){
** *** * *** = (ay - * ***** *
***** * * = m*ax + ay;
** *** ** *** = m;
** *** ** * ***** = 1.000000;

 }
** * ** * ** ** *** *
**** * ** = 0.000000;
* ****** ** * = 1.000000;
** * * ** **** * ** = -ax;

 }


** **** *** *
** **** *****
*** * ** * * * *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.59
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users