0 like 0 dislike
3.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.9k views

49 Answers

0 like 0 dislike
Hidden content!
// *** ** * ** by HoMingJui on 2016/11/3.

//



#include ** * ** *

#include ** * **

#include * *** *

#include * * *





int main(){
** * * * *** *** * x[2],y[2],a,b,c;
* *** * ** * * * ******* ** ** %f %f * *** *** ** ******* * * ********* * **
* ***** ** * * * * * * * * **** * ** **
*** ** ** ** *** * * * * * * * * **
**** * ** * **** **** * * ** * *** *
** * ** * ** ** ***** * ** * * * ***** %.6f * * ******
* ** **** **** * * ***** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
*** ** ** ** ** * *



int main()

{
* * * * ** * *** a1,a2,b1,b2,a,b,c;
** *** **** * *** %f %f ***** * * * **** * * ******* * ** * *
* * * **** **** * * *
* * **** * ** *
* * * ** * ** * * * *
** * ** ***** * *** ** * %.6f %.6f",a,b,c);


****** ** * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* ** * ** **



int main()

{
** * * * *** a1,a2,b1,b2,a,b,c;
* *** * ** * * **** * ** * %f %f ** ***** *** ** ** * * * ********
** *** ** * *** * *
** * *** *** **** ** ***
* * ** * ** *** * *
* * *** ** *** **
* * * * ***** ** * * ** *** * %.6f %.6f",a,b,c);


* ** * * * *** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** **



int main(void){


** ** ** * * * ax , ay ,bx ,by ,a ,b **


** * * * ** *** ** * * ** ** * * *
* * ** * * * * * *** * ** * ** * ****** * ** ***
* ******** *** ** * ** ** ** * ******* *** * ** ** * * ** **
*** ****** * * *** * * *** ***** * *** *** ** * * * * ** * *


* *** * ***** *** * - bx) != 0){
* *** * *** * * = (ay - * *
* * ** * * * * = -m*ax + ay;
** * * *** = m;
**** * * * * * * = 1;
* ** *
* *** * * * * ****
** **** * ** ** = 0;
* ****** *** * * = 1;
** ** * ****** = -ax;
**


** * * *** * * = a;
* ** * ** * *** = b;
** * **** * ** = c;


*** < 0)
* * ** ** * ** * *** * = -i;
* ****** *** if (k < 0)
* *** * * * ** * * = -k;


*** * (i < 1){
* * ** * * **** * * = 1/i;
* ** * *** = a*g;
**** ** * * * * = b*g;
** ** * * ** * = c*g;
*
* * * if (k < 1){
* * * ** *** = 1/k;
* ** *** * * * ** * = a*g;
* **** ** * * ** = b*g;
**** ** ****** = c*g;

 }
* *** * ** * * *
* *** * ***
*** *** ** ** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** * * *****



int main(void){


* *** ***** ** * * ax , ay ,bx ,by ,a ,b ** ** **


** * * * *** **** ** ** * * * * **** * **
* * * ** * * ** * * * * ** * ** ***** **** ** * * *
* *** * **** * * * *** *** ** * ** ** * **** * * * * **
*** *** * * *** ** * * ** * * * * * *** * * * * * ** **** *****


*** * ** * *** *** - bx) != 0){
* * * * * = (ay - ** *
* * * * * * * = -m*ax + ay;
* * ***** * * ** = m;
*** * ****** = 1.000000;
****
** * * * * ** **
* **** * * *** = 0.000000;
**** * * **** * = 1.000000;
** ** * * ** = -ax;
* ** *


*** * ** * * = a;
** **** **** = b;
* *** ***** ** ** * * = c;


***** * * < 0)
* * * ** ** *** ** = -i;
* **** * * if (k < 0)
*** * * ***** ** * ** = -k;


* * *** (i < 1){
***** ** * ** **** = 1/i;
*** * ** * *** ***** = a*g;
*** * *** ** * ***** = b*g;
* * ** ***** * * = c*g;
*** ** *
** **** * if (k < 1){
* ** * = 1/k;
* * ** ** ** = a*g;
**** ***** * *** = b*g;
*** *** * *** * = c*g;
** *
** * ** * * * **
** *** * * * *** *
******** * * * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * ********** ****
* ** ** * * *
** **
* i * *
*** a , b , c , * * * ****
* ** ; i *** ;
*** * *** *** * ** ** , * ** * );




* * ** *
* * * * * * * =
* ** ***** ** **** = -



** * * *** * * **** * ** * *
*
***** *** **
** = * ***** ;
= ;
*
* * * ** ** *** * * * a , b * *








* 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
* ***** *** *** * * *
*** * ** ** ** * * *

int main()

{
* * * * * ** *** ****** a,b,c,d,m,x,y;
* * ** ** * ****** * **** * %f %f * *** * * * * * * *** * ** ***
* * **** * * ** ** **
**** * * * * ******* **** ***

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ***** **



int main(void){


* ** *** **** * * * ax , ay ,bx ,by ,a ,b ,k,m,c;


*** * * ** * * ***** * ** * * * ** *
** * * *** * ** * ** *** ** *** ** * ** * * *
**** * * * **** **** *** * * *** ** * **** * ******** ** * *
** * ***** ** ** * * * *** * * ** ** * *** **** * ** * *** ** * ** * ****


* ** **** ** * - bx) != 0){
** * ** * * * = (ay - * ** *
***** * * * ** = -m*ax + ay;
** ***** * *** = m;
** * ** *** **** = 1.000000;

 }
* * * ***** *
** *** * * * = 0.000000;
* ** * ******* ****** * = 1.000000;
** * * **** *** * = -ax;

 }


****** * * ** * * ***
*** *** * ***
* ** ** * ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ** ****



int main(void){


*** * ** *** * ** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


** ** * * * **** * * ***** * ** ** ****
** * ** **** * * * ** **** ** ** * ** * * ** *
*** *** * *** * ** * * ** * * * *** ** **** * ***** **
* *** * *** ***** * *** * * * * * * ** * * * * *** * * * * * * * *


** * * * * * * * - bx) != 0){
* *** *** ** * *** = (ay - ** * *
** ** * * * ** = m*ax + ay;
* * ******** *** * * = m;
* * * * * ** * * = 1.000000;

 }
** ** * * * * *
* ***** * * = 0.000000;
*** * **** * ** = 1.000000;
**** ** *** * = -ax;

 }


* * **** *** * * *
****** **** * **
****** *** * *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.85
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users