1-11 Exercise 3: Prefix of a string

0 like 0 dislike
14.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 14.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
  *** *  *** **    **       ****
*   ** *     ** * *  ***   * * ** ***  ***  ****   *
    {
 *** *  *    *** * **    *  ***    * *    **  * **** ** **  *** (i=0; i<=strlen(string2)-1;i++)
** *  ***  *  *   * *    *   ***   *****  *   **** **
** *  *  *****    *    *     **** ****  **  **  * *  ***    ********** ** ** ****** (string2[i]==string1[i])
*     *******  ** *  ** **** * **** ** **   ** ***  *  **  * * ****  *   **  **   ***  
  *** **  *** *   ***  ** *   ** * ****** *** **   * * **** ***** ** **   *      * **** ***  *****   ***      *
     *** *     *   ** *           ** *    * *** * **   *   ** ** * **  ** **** * * ** *  
 *    ****   * *  * *  * ** *     ******* *     *** * * * *
 *****  ***   *     *   *     ** ** *  **** ****    * ***   
* ***  *  **  * **  * * *   ** *** ** ****   ** *  
**** * **** ** ***  * *** * **** **** * * *   **  * * ****  *   * * ***  *  ** **** * ** * ** is a prefix of %s", string2, string1);
** *  *  *   *    *  *   ** ****** * ***   **   * ****
 *      *****      * * * * ******  **     *  * *   ** * *  **
*** * *  ****  * *         *  * * **  *     **   * **
 *****   **** **  ***   ****** ***  *    *     ** ***  **** *** * *  **      *****  **  *** **     is not a prefix of %s", string2, string1);
 *  *** ** **     ****  ***  *     * *    **** *   * * *
    }
* ***** *  ** **      ** * * ** ******     ** *   *** *
    {
  * * **** * *** **      ** ** **      ******* *   **  (i=0; i<=strlen(string1)-1;i++)
    *  **   ****  * **  ****** * * ***     **   * * *  **  
***  * ****       ** *     *    ***  *******   * *  ***** *** *    ** ** **  ** **    * (string2[i]==string1[i])
 **       *  *  * **  **  ** *    ** ** *** *  **** ******* * ** *   ** * **
  *  *** ** *    *   *    * **** **  ****** *   ***  ** *** *** *    *  *  ** * ***** *   ** *  *** **  *   *****  **
**   *    * ****** **** ** *   *** *  *  ***  *   *** ****  *  ****     * * *****
   *  * *  ********  *****  ** ***  ** * *  *  * ***  *  * *
* **   ** **  * ** *** ****  * ** * ** **   **  * * *  * *******
  ****  *          *    *  ***** ****   ** * ***      ** 
**       ***** * *  *   *** *   *** * *  *  *** *** * * ** ***  ** *** *   **** * *   * is a prefix of %s", string1, string2);
 **  * * *  * **  ** **  **  ** *  *  *  * ** ** 
** * **    ********* * ** ** *    *     * ****  ***    
*    *  *****   ** **  ******  * ***  *** *  ** *** **
*    **   **   **  * ****** ** ***  * * ** *  * *   ******  * ***** **  * *    ** **   is not a prefix of %s", string1, string2);
*****   *  * * *****     ****   *   *  * *    ** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 * *  **  *   ***    ** ** *  * **   *  *  %s", chaine1,chaine2);
 ************ ***   ******* * * *    *      ** ** *
  *   **    ******   *  **** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*  *      *  *** *    *    lenght1,lenght2,c;
 ***    **** **  ** *  * * * * b[100];
*  ** *   * ** * ***      * *  a[100];
*** **  *  * ** * ***  **  *   d[100];
* *** * ** * *     ***** *  *  *  * * ** ** * * ***
** *   *  *  ****  *   * ***  *    **  ** 
****    ** * *  ***  *  * ** * ***** 
****** * *     *  *  **   ** *  ***   * *****
   *  ** ***  **   ******** ****
*   *   ** **  ** *   * *  *
 ** *****          *  *****   * **     **** *    *    is a prefix of %s",a,b);
 ***  *  ** *  * **  ** *
 **  *   * ** * **     ** **  
 **     *  ***   *  ** * ***  *
* ***     **  * * *     * **  * * * *  ** **  ** **   ** ** *  *   ** is not a prefix of %s",a,b);
    *** *  *** *** ** *   *  
*   **      *******  *  **  *  * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **   **** * **  *
#include * **** * *     
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
   ****  *  *   **  i;
 **** ** ***    *** ** ** **
  {
** *       **  * * *   **** * *  ** *** *   A[i]!='\0' && A[i]!=B[i]   )
* ***   *  * *  * *****   * ***  * ** ***** *   ** **  **  ***   * * *  0;
  * *   ** *  ** *  *  * ** *       **  * *****  
**   **  *** **  ***  *     ** *    * ***  ***    *      **   ***
  }
   *   * * * 1;
}


int main()
{
** ***  * **  ***** ** ****  *    a[n],b[n],c[n];
  *   *  *   *** *    ** ***  i;
** ****** ** ** *    *   *  * * ** * ****  * 
   ** * *   ****  *    *  *** ****    **  **   **   *  
 *  * * **    * *** *******  (aa(a,b)){
 *  *  **   ***  ** *   *** ** ****** ** ******  * ****  *  ** * **    * 
* ***   *  *  ****    ** * *  ***** *   * ****** **  **** * **** **       *     *  * ***    
  *   ****  ***** *** **** * ***  * **** *       ** * ****  **  * ** ****  ***  ***  * * **   **        ** 
* * *  **   **** ** * * *  **  **     ******   * * ** *** *    *    **   *** *   *  *

  ****  *    *   **  * **** *    *** ** *  **  ****** *
            *   **  **   **  ** *** *   ** * * **** * ** *     *  ***    is a prefix of %s",c,b);
* *  * *       **  ** * ****  *
  *      * *    ***   * ** **
 *  * * **    *** * ***   * **  * ***** *  *** ***** *** **  is not a prefix of %s",a,b);
***  * ******* **  ***   ** * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include            ** **  *
  * ** * * **  ****   *
int main (){
char  * *  *
char *  * * *  
****  *   *    string1: * * *  *
*  ***** * ** ** * **   *   
**   ********  ** string2: ****** *
 *  *    ** * * ****** * **   
*  *     * **** ***  **
       *   * *  *   * ***  * *  *** *   is ** *       *   of ***   *** ** *  * 
else
*      **   **  *      *  **** ** *  *  is not prefix of  * **** * **  ** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * ** *   ****
#include    * **  ***** **  
#include  *   ****  ***   
#include  ** * *  *  * * **
int prefix(char p[],char s[])
{
* **      ** * ** **    **       * ******  
**    **  *    **  * ** *  ***   0;
** *    ****  ** * ** if    *  * *** **   * 
* * *  **** *   * **  ** *** *  1;
***** ** **** * *** *   
  ***** *  **   *   ** *     **** 0;
}

int main()
{
** * ****   * * *****  *  p[999],s[999];
**** **       * *  **  *  ***** **** **
*******    * * ** *  *     **      ****  * 

 **  **      ** **  * ***  *  ***
 * *  ****** **  *    **** *    ****  is a prefix of %s",p,s);
* *****   ** *****
*   * *** **  * * * *** ******* ******* * is not a prefix of * *    *  *

   **   ** *  *** *   *  *** * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * **     *** 
int main()
{
  *  *****  ** ***  *  *  *** * length1,length2,c;
 ***** *** **    **      * ** a[100];
** *** * ***  * ** ** *  *   b[100];
 * **  * ** **  * * *   **** ** d[100];
  *  *  ** *     * **  ** * ** ** ***  *** *** **** * 
***** * *** *  *** *   ** *  * ***** * *
*     * ** **  *** **** *   *  * ***    *
*******  *** *** *  **    ****** ** *   
if (strcmp(a,d)==0)
** ********    *   ***  
** ** ****  **** * **   * ** *****  *   **   ***  * ** *** *  *  * **  is a prefix of %s",a,b);
*  **     ** * *  * *   *  
    * *     ** * * * ***  *    **
   *** ***  * * *  *   * *    
*  *   ****    **     *    **  **** **  **       *  *** **   * ***   is not a prefix of %s",a,b);
** **       **       * * *  *
** * *    ** * ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     *   *
#include  *  ** *     **

int prefix (char *   str2[])
{
*** ****  *** **** * ***    **  length=0,   *    
*   * *** ****  
****  *    * **      *  ** *  *     = ** *  ********
******* ****  *   ** *   
 ****    *  * ***** *** *****  * * * * * * *
 *****  *  *  ** * *  *** **** *  ****
 * ** ** *  **   * ***  **     if    *      * ***
  ****   ****  ***  *       ***   **    ***  *  ***  
*  * ***** *   * ** *  *         }
***   ** **            *  * ***** ** ****
  ****  *     **** *    (count == length)
* **   *  ***    ****   **       *  * **   1;
*****  * * * ***** *** ****** else * ***    * 0;  * *** ** * *    **   
 * * * ***   *      ** 
}
int main(void)
{
**  *** * **** * ** ****  ** *     ** *  *  *   
* *      **** **** *  *   
 * **            ** ** *  * *   * **    ***   * * * * str1, str2);

*  * **  **   * ***    *   *   * * * *** 
   **  * ** *  {
   *  ** **** **  * **    * *****    *     * **** ** ***      ****  ***** is a prefix of *        str1, str2);
***  *   ** ***** * **  ** ***
****  *   * *      ***** *  * *
    ** *** ** **   *    * *  *     ** * *   ***  **      * * **   * is not a prefix of  **** * * str1, str2);

**  ***   *  ***   * *   *   *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *  * * **  **
#include   **  ***  *  
#include    ** *        ** *

int main()
{
*** * *   *    ** * **  *   **  prefix[100];
* *  * **  ***   ***    **** word[100];
* *      **    *   *  * **  **  ** *   %s", prefix, word);
*   ***  *   *    *** * *   * i;
** ***    ** * * *    * *      *** = 0; i< strlen(prefix); ++i)
* * * ****  * ***** *  *****
**  * * **  *  *  ** *         **   * **** * ** **  ***     *
   ** **** ** * **    * ** ***  *** * *  * ** **********
 * *  **   ****  ** * * *    *  * ****** *** *    **** *   * *** ***** *** *    * ** **  **  *** * is not a prefix of %s", prefix, word);
   * *  ***  ***     ****       **  *      * * ** *   *    ** ***   **    * **  ****   * * 0;
**      **** * ** **  * * *  ***** ** * *  ** *  
       ** ***  ** * **   * *  *
** *****  **  **  **** *****   ***      * is a prefix of %s", prefix, word);
  * ***   * * **      *    ** *   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ***  *   ******
#include    * **  **  * * ** 
#include   *** *  ** ******* * 

int main()
{
 * ***** *    * **    *  ****  *  *   prefix[100];
 * * *  *  * *   ** *   *   * * word[100];
** ** **** *   * * *    ***   ****   * %s", prefix, word);
  ** **    * * ***  **  **** i;
 * *** **   ***** ***  * *  = 0; i< strlen(prefix); ++i)
****** * * ** *** * *    
*** ****     * * ****     *****  ****         ** *  **    *   *  *    
 * ***** *  *   * * * ** * ***  *  **   *   *     ***
   **** * ****  ** ***  *  * ****    *   *   *    ** *  *  *  *      ** *    ** * **   *    is not a prefix of %s", prefix, word);
 *** ***** * * * **   **** ** *  *  **  **  * **    *    * *  **  **  * * * ** *****  * 0;
*  *** *  **** * * ***  ******    * * ******    * ***  ** * 
 ***** ** *** **    ***  *   
 *** * *  ***  * * * * *  **  *  *** is a prefix of %s", prefix, word);
  ***  *      * * * * * * * *** *   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****    ***  **  * 
  *  ***      *   *   *  
 *****  *  ** ****    ***

int main()
{
*** ** * * ** char ***   *
* * * *  ***    char  ** *
  ***     *   * * * * *** *  * * ** **   *  word);
    * * ***      int i;
 *  **    * *  for(i = 0;   *  *  **** * ++i)
*  ** *  *   **  {
* * **  *** *   *  *    *** *          *  * 
*      ** *         **   **  ***  {
 *    * *** *  *  *   *  **  *  ** **  *  *  *  * * **  is not a      of  *   * *  * word);
  *     ******** * *  ***       ** *  *  *  ** * 0;
** *** **    *   ***  * ** }
 *  *     *   }
*** *     ** *** **  *  is a prefix of *****     *    *  word);
* **  *   ******       0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 20.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 13.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 18.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users