1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
         ** *  * ***  *    
** *  * **    * *  * ** *** * *   *** *  * * ***** *** 
    {
       *  *****  *  *     ** ****  ***  * *    *****  *   (i=0; i<=strlen(string2)-1;i++)
  * ** * ** **    * *** ** * * ***  *  * **  **** *  **
*  ** ** * ******  ***       *  * * ** **  *  *    **   *   * *  ** **    *** ***     **** (string2[i]==string1[i])
    *      ****   *** *   *    **  **     * **** * ** *  *  *** * **** *** * *** *
**  *** *   *  * *   ** *  * **  **       * ******  *****    * **** ********   *** ***   * * * *   ******  **    *
*  * *   *    *** *   * *    **   **  *  * **  *** *** *     * *     * **** ***
   *** *   *   ** **** * **    *  *** **** ** *     **     * 
  *******  ***  ***    *     *   ***  *  **   *    *
 *     *     *  ***** * *****   * **          * *    * ****** 
*** * *  ** ***  *   *   *   **** * * ***  *  **   * *** * *   *   **   * ***** **  **  is a prefix of %s", string2, string1);
    * * ** *  ** * **     *  *** **    **   * **    
**     *  **** **   ** **  *  * * * * ** * ****    *  * **** ** 
 *      *** ****   * **** * *  ******* *** **  *  *     *
*   * * ** * *   *   *   ** *  **       **   *  *       *  *  * * *      ** ****   *  * * *   *   **    is not a prefix of %s", string2, string1);
 *  ***        *  *  **     *** *       * * * **** *    *
    }
   * * **** * *  *  **  *  **     * * * * * * * *** *   
    {
** **  ** **    * ** *  ***    ** *  *  ** ******    *  (i=0; i<=strlen(string1)-1;i++)
*         * *   *  * * ****  **   * * ** *  *  *  **
  **    *  *   **  **     ***  * ** *  *  ** * *   *** *   * **  **  *    *** (string2[i]==string1[i])
 ** *         *****     * *  ** * * * * ***  * * ***** * **   *   * *** *     *      
 ****   *    ** ** ** **  ****** ******* *****  *** * ** * *** **** *  *     *  ** ***    **   **   **  *   
* ** * ***** * **   ***  *  *** ***** **  *  *  * * ** * *  **    ****  *    *
   * **    *  * **   **   * **** * ***   *  * *  ***
* * *    * **    *****  * * *** **     *   *  * * ** *   *
 * *** *  *   **  *  * ** ** *   * *  ***     ***   * *  *
* *** * **    *  *  * ****  ** * ** **      ***  * * *  *  * *            *  *** * ** ****** is a prefix of %s", string1, string2);
*** ******   *   *  ***     * ** *   ***  **   *   * *
*     *  ** * ** **     *****  ***  ** * *   *     **** * ** *   
* * **    ****    *  * ** *   **   * ******* ***     **
** ** * ** * *** *** * *  * ** ***  *** ******  **   * **  * * *  * * *   ** *   * ******* ***   is not a prefix of %s", string1, string2);
*   ***  *   * *   *** ** * ** *        * ****** **   *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   * *** *  ****   ***** *   *** %s", chaine1,chaine2);
 * *****      *** *** *   * *    *  * *  *  ** *
*** * *** * *   **    ** ****       0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 * **  ** ***** ****  lenght1,lenght2,c;
 ** * ** * * *** ** *   * *   b[100];
*  ***  * **   **  ** ** **   a[100];
*  * **  *    ** **** **** ****   d[100];
* *  *  **  * * * * *     * *   *   **  ** 
**  *   ****  * * *** *  * **  * *** *  * ** * 
  * *  ** ***  ** * **  * * *   * *     
   *   * ***  *      ***  *    * * **** ** ** 
*** * **  ***  *** **  **** ** ** **** ***
     *  *** ******** **  ****   
*** *    * ***  **  *  *****  ******  * **** *   *  is a prefix of %s",a,b);
* **  **  * ** *** *   *
*  * * ** ***** **   *   *     ****
**   * * *  *  **  *  *** ***
   ****  * ****     * ****  *  ** *   *    * * ***** ** *   * **   is not a prefix of %s",a,b);
 * ** *   ** **  * *** * *
**  * *  **** **      **  *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * ** *    **  **   
#include  *****   ******  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
** **  ***      * * *   i;
* *  ****  ****** **     **
  {
**  *  **   ***  *  *    **   ***   **  *** *    A[i]!='\0' && A[i]!=B[i]   )
   * * *  ** ***    **** **  * *  **  *   *   ** ** *  *** 0;
 *  *  ** *   ** ***  * * ***  ***  * *    * * ***
 **  *    **     *  *      **  ** **  ***** * *** ***  * * *  *** *
  }
*** **  *   ** *  * 1;
}


int main()
{
 ***** * ***  *** ** * *  *     a[n],b[n],c[n];
 * **** * ***    *  **  **  i;
*   ** * **   * * *  ***** *** *    * * ** *   *   *
  * * * * ***** **** *  * **   *   ** * * ***** *** *  
** *   *   ** * *  ** *  * * * (aa(a,b)){
     *** ******** **   * ** * ****** ** *      **  ** *  ** 
*  ****  ** **** ****** **   ** * ** **  ** * ***  ***  * *   ** **  *  *    ** *** 
** *   **  *   ****   ****** *     **   **  * **   **     **  * ***      ** *******   **  *     ** **  *** 
 **  ******   *  *  ** ** *   ****    ***    **  ******     ** ** **  ** * *  

   ****      ** * *  * * * * **    ***  *    *  ***   
 *  **   ******* *   **** *    ***    *   * * ** *  *  * * *   is a prefix of %s",c,b);
  * * * **   *    * **   * * 
  *  **   ***  *** *   * *   ***  ** 
 * **  *     * ***  **  **   **  * *  *  *******  *  * **  ** *  is not a prefix of %s",a,b);
**   * * *  ***      **  **   **  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *  ***  * * *
*  ** * * *  ***  ** * * 
int main (){
char *  * * 
char   * *  **
****** *  * * * string1:     *  * *
      **  * ** *  ** ***** * *  ***
*    ** **    * string2: **  ***
* *  ***   * * **  **
* **       *   **
 ** *       *** *** * *** *    * ***  *  *   is *   *   *  of     **  ** ***
else
  ** ** **    *      **** *** *****   *   is not prefix of  **    *  * *  *** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *******   * 
#include * *** * ***    * *
#include  **  **** *****
#include  **   *  *** * *
int prefix(char p[],char s[])
{
* *     ***  **  **        ** **   **  *
 ** ** * * *** **** * * ** * * 0;
** **** ***     *   ****  * if    *    *  *  ** **
 ***  *** *    *  * *       * 1;
    *  **** ***  **  ***
   * **** *** * *  **     * * 0;
}

int main()
{
   **  *    * ***   ** p[999],s[999];
* ** *  **  *  ** ***  ** **  *   *  **** *   
*  * *** ***   * * *      *     * **  * *

 *    *** * * ***   *  ****   * 
* *** * ** * ** *  * *      *  *     * *     is a prefix of %s",p,s);
 ** *   *  **   
   * *  *   *  * * ** *  * * ****       *  is not a prefix of ** ****  *** 

 ** ** * ** **   * * ** *****  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ** *   *  * *  
int main()
{
     *    *       ****** *  length1,length2,c;
  *  **  **    * * ** *    **  a[100];
**     * ** **  * **  ** **  * b[100];
 ***   ***** *  * * *** *  ** *   * d[100];
   **  * **   * * *  ***  ** ** *  ** *  ***
 *   * *  *  ** ** * *** ** * ****** * * ** 
** ** *** *   * ** *      *** ****  ****   
   ** * * *   ****  ******   * * * *** 
if (strcmp(a,d)==0)
* *** * ***** *****  **  * 
  ** * ***  **  ** ** **   **  *  *****  *     ***** * ** **  **  *    is a prefix of %s",a,b);
** *  ***     ***      ****  
 *       ** **   ** ***** *
****** * * *  *  **  ** * 
*   * **     *    *** * **  **  ***** ****** * *   *  ** ****      * *  * is not a prefix of %s",a,b);
   * ***      ****          * 
*  * *    *  *  * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****   *** **
#include  *   *     *  

int prefix (char * **   * * str2[])
{
 * * **  *  *  ** **  ****  *   * * length=0,   ** * 
** * *    * ** ** *
**    ***     * *   *** * **  ** = ** ** * *  ** 
*  * *** **   ******  ** *  
* ** ** **  *******   *    ***  * *   ***** * * *** ***
** **      ***      *  *** ***** * **  * *  *  
****    ***       * *   **  ** if   * *** *  *
 * *  ***  * **    * ***           **  ***      * ***  
* *   * **   ***    * ** * **    }
 * **           ** *  *  **** **
*  *   *   * ** ** ***   (count == length)
*  * * *******   * **  * *****   **** **** 1;
        *  ***  *    ***** * * else    * **    0; ***** ****      *  *
     *      *****   *  ** 
}
int main(void)
{
 *  **    * * **    **    *   * **  * * *
*** **  **  ******* *  *** 
  *  *** ** **  ****  **        *   *********  * *       str1, str2);

*   **** *  **  ** ***    *   *  ***  ***   **
  * * **   *    {
*********   * *   * *  *     *  **  ***    ** ******** **   *      is a prefix of ***   *    str1, str2);
**  **  * **  *** *   *   **  
***  *   ** * ** * **  ** 
****   ********* *  **  *  *** * ** ** * *    ***      ** *  ** *  is not a prefix of * *  **   str1, str2);

*    * *******  * **** *** *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ****** * 
#include  *  ** ******* 
#include    *****   * * **  

int main()
{
** * * * * * *   * * **   * prefix[100];
* ***  *  **   *  * * * * * **  * word[100];
 * **   *  * * *  *   ** *   *  * ** *** ** * %s", prefix, word);
   * **  *  ** * ** ***** i;
** *** * ***  * *  **** *** = 0; i< strlen(prefix); ++i)
* *    ** ****  **** *    
 **  ******** *** *  ****   *    **   ** ***   *  *** * *  *** **  *
*     * * *     *   ****  ***    *  * * ***  *** *   
** * *** * **** * *** *** *     ** * *   **  ** **   **********   *     ** * **  * * ** *   is not a prefix of %s", prefix, word);
 * * **     * * *  *  *   ** ** * *  ***  *****  * * * **   *  *****   ****    ** * 0;
*   *** * * *      * **          ** ** *  * * ** *   
*   *    ***     **  *  
****     * *** ***** * ** **** *   *   * is a prefix of %s", prefix, word);
   * *   **** * * * ***  ** **   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *** **  * * *
#include     *** ** ** ***
#include    * *   **** ***

int main()
{
 *   *  * *  *    * * * ** *  prefix[100];
 *** *  *  *  * ** * **  ** *  word[100];
* *** *    ** *** *  **    ** ** * **  ** %s", prefix, word);
*     *** ** ********   * *  *****   i;
   ***** *  *  *** * **** ** = 0; i< strlen(prefix); ++i)
  **  ** *    *   ***  **  **   *
* ******   **  ***  ****** * ** * *  *  ** *  ***  * *    *  
**  * ****     * *   ** * *   * *    *  ** *  ** ** * **
  * * * ***  **   ***  * **** *     **  *  * * **** *     *    * * *   *     ***  **  ****   * is not a prefix of %s", prefix, word);
 * ***  * **** ** *  * ****** * * ** *   * ******  *** * *   *  * * *** ** * *   0;
  ** **** *   **  ***** **   *  * * **** **   * *** *   *
* *  **   *** ***  ** ***
*   * **  ***   * *   ****   **  **  *  is a prefix of %s", prefix, word);
**   ****** * *** *    * *    0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * *   **  *** *****
 ** * * * ** *     
*   *   ** * *      **** *   

int main()
{
**      ***** *  char ***  ***
* ** ***     * *** char  *  * **
 ***  *** * ** * **  **** ** *         **     *   word);
***   * *  *  *  int i;
*** *  **    for(i = 0;   **       * *  *   ++i)
     ** **   {
**   * *  **  *    * * *   *   **   *  ** 
*        ****   *  ** * * ** {
  *    **  *  * **     * *      * *  ** *   * *  *     *    * is not a *  * of            word);
 ******   *   *  * **  ** *   *** *  * *   * **  0;
  *** *  **     *****    ** * }
 **  *    **   * }
   ***  *  *****  * *  ** * * is a prefix of   *  * * *  * *  word);
** *      *      0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.31
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 18.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 16.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users