1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 **  *  * *  *  ****** * ** ***  
*  *  ****    *  * *  **    * * *   * *    **** *** *** 
    {
*     *     **  *     * * **   * ****  * ** ********  *   (i=0; i<=strlen(string2)-1;i++)
*    * * * * *  *** *****   *****      * *** **  *** *  ** 
 * *   * *     *****  * *  **  ***  ** * ** *****  *   ** * *  * * ** *** (string2[i]==string1[i])
 ** ****** **  **** *    ***  * **** *  * ****      * ** *  * * *******  **    *  **  
 ** ******   ** *** *** *  ***   ****  ** *  *     **   ****  *  *  **        * *  * **  ** *  * ** *    * *
 * *** **    ** **** *  * * ****     *** * * *   *     * * *   * *    ** ***** ** *
*  *********      * *  **    **      ** ******* ******* * 
* ** *** **     *     *  ***  **** *        *** * ***** ***  *
 *    *  * * *    ** *** * **** *  * **   * *****  * * *  **
 ****     * *   *     *    ***  ****   ** **  ** **  ***** * *** * **** * * * *   *   ****    is a prefix of %s", string2, string1);
***        ** **  *  **  * *     **   *     ** *  *
***  * *  *   **  *****  ** * ** * **  *** **    *  
* * *     *    * **     ***   ****** *   *****   *  *** * 
  ***    ****  ** *    * **  * **  ***** *** *   *** * *  * *******  ******** *  *   **  is not a prefix of %s", string2, string1);
   *  ***  ** ** ***  * * ***** * *** *       * **  *   
    }
   *      *   *  **    *  * *  ********* ** ** **** * * * * *
    {
*  *** * *  *  *    ** * * *  *          * ***  (i=0; i<=strlen(string1)-1;i++)
  *******  * * *    ***  *******    ********** *    *** *
* * ***  **    ***  * ***  *  *** * * ***  * *****  **   *** *     *********   *    *  * (string2[i]==string1[i])
   * *  *      *** ***** ** *  * ***   *****  **   * ** ** * *    ** *   *** ***  *
*   ** ****  *** ****  *** * *  *  *     * ** ** **    * **   *        ****  *****  *  * **  **** * ****  *** *** **  
*   * *    *   **** **  *  * ***  ** *******  *  *   * *    *     **      ** **   *
*  ****    **  * *  * **  **  ** *** *  ***  ** *    * 
* *  * *   * *    **   * * **  *   * *     *   ** * *  * **
** **    * *  ****   ** *   **     *   *   *   * * * **   
  **** * **     ****    * *   *   * * *   * * ****     *  * ***  **     **  *    *  ** *  **  *   is a prefix of %s", string1, string2);
  *****  * * * *   **     *  *   ***** *** ** *  *  *  *
**     *  ******  * ** **   * ***  **    *  *    ** * * 
*   *    * ** **** ** *   **  ** ** *** ****  *  * *
* ** * **** * *  *** * ***   **   * **  **     *   ***  *   * *** ***** * * *** *** **  *        * is not a prefix of %s", string1, string2);
*    ***  ***  **  ***** *  * **   *** **  ** ** *  ** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 * ****    *****   *    *  **   * %s", chaine1,chaine2);
***      *  *   ** ***  * **   **  *** *  *
  ******* * **** ** * * * **   *    * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 ***** * * *      **  * **** lenght1,lenght2,c;
   ** * ** ***   * **    *  *  * * * b[100];
* ** *   ** ****   *** *   a[100];
*** *  ** ** **** ** *   * *  d[100];
*  **** ********       *  *  ** * *      *
******   * * *  *  ** ** ***   **  *  **  * *   * 
  **** ** ** **   * * ** * ** * **  ***  
       * **** * * *** *** ****      * *
***** *** *    **   ******     *    **** 
 ** ** ****  *** * ****   
**    ** * *  *  * ** * **  * *    ** **** ***** *****  ** is a prefix of %s",a,b);
*  ** ** * **  *** ** * * 
  ******** *  ** ** *********
 ***      ** ** *  ****** * 
   ***       ***  **  **  *  **** *  * * * ** * * *      *   ** is not a prefix of %s",a,b);
 *  * ** *  * *  * * **   **
 *  * ********* *** *   *  **    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **      *     **
#include ** ***  *  * **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
      * *** * i;
*** *** * *  ****      
  {
 ** * * * * * * * *** *****    *  *** ***     A[i]!='\0' && A[i]!=B[i]   )
**  **** **** *  * *  * * * *** *  **** ***** *** *   * * ****  0;
** *      *   ******  ******** **   * *    ** *     ** *
  ** * ** * * **  **** * * *  * *** ***         *  * ***      * *  *
  }
*   **    *** *** 1;
}


int main()
{
  *** * *  * * * *  *   * ***  ** a[n],b[n],c[n];
 ** *   *  *     ** ***  *  i;
*** *    *   *******  **  *   *   ** * ** * *****
******  * **  ** * * ***   **** **     * * *  **** *
*  *** ****  * *   * **   ** (aa(a,b)){
*** **  *    **      * * *  * ****   *  *** *** *****  ** ***    *  *****  
 * **   ****    *   *   ** * * ****   * * *****   ***   **   ******  ***  ***  *   **    **  *
 **  ** **  *** *     ** *  * * **  *  *****   ** **     * ** **  *    ***  *  ****  **    *  *         ** * * **  
 ** *** *   *  * * ** * *   * ***  *   ** ****  **     ****  * * **   * * *  **

*** **   * * **  **  **** ** * *  *  *******  
   *  ** * *      * *** ** **  **     ****** *       * *** **** * ** is a prefix of %s",c,b);
 * *** * *  **   * **** **  *
   ** *  ***  *  **   ** **  
 * **  *  **  *  **** * **  *** * *  **  **    * *** **  **** * *  **  is not a prefix of %s",a,b);
*** **  **     * *** * * *  ****   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *   *  *** * 
 * * **        *  ** *****
int main (){
char **  ***
char *****  * 
********   **  string1: ** * *** 
    ** * **** **  *  *** *  * * 
   *** *** **** string2:  *** ***  
*  *  *******  ** ** *****
** * * * * **** *****
** ***  *  ** * ***   *** * *   ** * is ********   ** of * ****  *  *   * * * 
else
 ***  *   ** * ** **   * * * *  *    *  is not prefix of **   *   ** **  *  ** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **  * * *** ***
#include  * *    ** *** 
#include   ** * *** **** ** 
#include       **   *    
int prefix(char p[],char s[])
{
*** **  **    ***  *   *     *    *    **  * 
**  *     * *  **** ** *  *  *   ** 0;
*      ****** * *   if * ***     * *** 
   ** *  ****  *  * **** * *** **  1;
 ** * ** **  *  * *
* **  ***  *  ****  *******   * * 0;
}

int main()
{
 * **  ** * ** ******** p[999],s[999];
*   *  **    *   * *  **     *    *** **    
 *      * *  * *** * **   **  *****  * * 

*   * **  ** *  ***   *  * *** 
*** *   **** *** *   *     * ***  * is a prefix of %s",p,s);
 *   *  * ** ** *** * * * 
**   * ** *  * *      *    ***  *  ** ** * is not a prefix of   **** * *

* **      *** *   *** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   **  ****    ** 
int main()
{
*     * *  * ****  * *****  ****  length1,length2,c;
   *  *  *  ** ** *          *     a[100];
  ***** ** ****     * ******* **  b[100];
   * ***  ****** ** * * *** *  d[100];
     *********    * * *****  **  *  **  * * * 
   **  * ** * *  *  **  *  **     * **   **  **   * 
*  **   ** * **   *  ***   ** **   *
**   ** ** *      *** *      * *** *** 
if (strcmp(a,d)==0)
   ******* * *   *** * *  * 
  **   * ****     *  *     ******  * * *  **     *    * **  *** * ** is a prefix of %s",a,b);
  *  **** *  ** * ***  *    *
 *** *** **   ***  *     *   **
   * * **   *  ** *   *   *
******* * * ****** * * *** **  *     * ***   ** ** *     *  * **** ** is not a prefix of %s",a,b);
*    *****    * ***  * * ***    
* * ***    **** * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***  **   **    
#include **  **** *** **   **

int prefix (char ***     ** str2[])
{
   ** ** ***   * *     * * length=0, *   *
  *   * * ** *  *   **
********      ** *   *** ******* * =           *  
   **     **      ** *   
 **  *  *****  *  *  *** * *      ****   *** 
*  *    ** *    ** * *     * *  ****
 * ** * *  * **   *     ** **** *** if  *** * *  **
****     **  **     * *        * **  *  ***  * *****  **  
    ** *  ***    ** * **  *  ****     }
  * ** *         ** * ***  * * *    * *
* *   * *  * ***   * ** (count == length)
      *     *     ***  * *** **   * *     *  1;
 ** *  *** * *          ***  * else   **  *** * 0;     ** *  ****** * *   
 *****   ** * ** ** * * *    
}
int main(void)
{
**** ***** * **   *  ** *    **   ** *  * ** *
     * ****   *  **** *  **
*         **** ***     **  *   **  *   ***  str1, str2);

   ***   * *   ***  *** ***   * ***   *  ***
*  **   *   ***  {
 *  ******  * ***  ****  ****    **  *** ***      *   * * **      ** is a prefix of * * * *  str1, str2);
 ****  *     ** * * *   * *  
   * *  * *  * **** ** * *****
***  *****  **  ** *    * **   * * ***  ***** ***** * *** *   ****    * * is not a prefix of *** *  str1, str2);

* *  ****   *    **    **** **** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **   * *** 
#include * * ** * ** *  ** 
#include *  * ** **      *

int main()
{
     ***** *    *  **   *  *  prefix[100];
  **  *** *** * **  ***** * *  * * word[100];
*   **** * * *   ** * *  * ** *** **   ** * %s", prefix, word);
     ***      * *   *   * *  * * i;
****  **    ***   * ***  *    **  = 0; i< strlen(prefix); ++i)
***   ** *  ***  * *   *  *
 ****    *** *** * *  **  *  *  *   **       *  * * *     **   * **  ** 
***  ** * * * **   *** *** * ***** *  * *   ** *
* **  * *** **** * *      *** * **  * * **  ** * * *  ** ** * *   ****   **     *** ******* is not a prefix of %s", prefix, word);
** ** *  ** * *  * *    *   *  ** * **  *  *** ***** ****  * ***  * * ** ** ** 0;
 **     ***  *  *  * *  *   * * *  ***   ** *******
*   *     *  * **** * **   **
****  * ** ** ** ****   ** ***     ** * is a prefix of %s", prefix, word);
  *  *   *** *  **  ***  *  * *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   *  *  *  ** 
#include ** *** * ******* *
#include * * * **  * **   *

int main()
{
 **  *  * * ****** **   *** *  prefix[100];
*  * **   * ** * *      ** * * *   word[100];
*  ** *** *  ***   ***   *  *   * %s", prefix, word);
* * *  ***  **   * *   *      *   i;
* *   ** * *  *  * *   * ** = 0; i< strlen(prefix); ++i)
*** * *******  * *   *  * *** *
 **   ** **  ** *  * **** ****  **  *    ** ***  **   ******* *** **  
    **  *** *   ** * *   **         * *      **    
***** *  *** *****  **** *  **  ** ** * *  ** **  *  ****  ** * **** **  *   *    **  is not a prefix of %s", prefix, word);
**  *   ** *  *  * *  * *    * ****     ******  **    * * * *** * *      * *    * *  0;
**     ***** * *     *  ******** ***    *   **** ** *   **
** * ***** ** * ** *****   
* ** ** *****  ****    ** * *      * ** is a prefix of %s", prefix, word);
*   * ***  ****   * ** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*****   * *  ***   ****  
 * ** * ** ****
* ***** *  * * *  *** ** 

int main()
{
 *      *  **    char   *    *
*  * ***    *  char  ****
* * **  * ****   **  ** **     *  *  *  word);
  * *  *   ***** *  int i;
 ***** * *     for(i = 0;   **   *** * * ++i)
****  * **   * {
 *** * **  * *   *     ***  **   * ***  * **  **
* * ** *  ******    *    **** *  {
**   * *** ** * ** * *  *      *    *  *  *     * *  *  *   is not a    of   *    **  * * word);
  *  *   * **  *       *  **     *   *  **  * *   * 0;
*    * ** *      ** ** **   }
**  *  ** * ** * }
 ****     * *     **   ***   is a prefix of      * *   * *  word);
 ** **   **   ***  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.69
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users