1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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{
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}
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#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include     *   **  **
#include    ** * *  *  ** 
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#define n 100
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}
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Hidden content!
#include  *** ***  *  *
*** *  **  **  ***** ** 
int main (){
char * **  * ***
char  ****    
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include   *       *   
#include  * **   ******
#include  **** ** *** *
#include  * **  *     *
int prefix(char p[],char s[])
{
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 * **    *    * ***   ** *  0;
}
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Hidden content!
#include <stdio.h>
#include  *** *  ** *
int main()
{
 *  ** **     *** **  * **  length1,length2,c;
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**** * *  * * **   **  **    
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}
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Hidden content!
#include   * ** * ***  **
#include     **** ****  

int prefix (char ******** str2[])
{
 *** *   ****  **  ******** length=0,  *    
*  *  ***    *** * **
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{
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** * * * ****  ****    *   ** *  0;
}
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#include ** ***   *
#include ******   *  **** 
#include    **    *  * *** 

int main()
{
***  *   *    *  ***** * *   *  prefix[100];
   **  *  * * * **   **  * **  word[100];
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*        * ****   **  *     *
*        * *******  **  * **     * *   *     is a prefix of %s", prefix, word);
***** * *** **   **   * **  * *  0;
}
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#include *  *  **       
#include    * ***   
#include  ***  ***    *  

int main()
{
  *  * ***   *   *  **** prefix[100];
  *****  * ** **    ** **   word[100];
****  **  **   **   ***    **** * *** *** * %s", prefix, word);
*         *  * **   * * **   i;
 ** *   *  *   ****  *       = 0; i< strlen(prefix); ++i)
*   *   ***    ****   **  *
 *   * * *** ** **  *      **   *** ****   *** *   **  *  * ***     *
 *  **   *   ***    * *   **  *  * ***** *    * ****** ***
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 *  * ****  *     *   ** *    ***  *      **  is a prefix of %s", prefix, word);
  *  * **   **   *  * *  *** 0;
}
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**   ** ***  **   **  *
  * * *  ******** ** * 
** ***  * * ** * *  **  * 

int main()
{
  ** * **  * ** ** char **   ** * 
*  *     *   ** char  ** **  *
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** **  * **** *  *   * * *  * }
*  *  *     *  }
  *   *       * * *    **   ** * is a prefix of ****  * *   word);
 *  *   *  *   ** 0;
}
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