1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*      **  * * *     *  *   *
****  ************      * * * ****  *** **    *** **  * 
    {
  *** *** * * * ***  ** **** *  *  ** * * *** ****   * * *   (i=0; i<=strlen(string2)-1;i++)
 ** * *  * * * *  *   ***  ** * * *  ** *   *      
 *** **  **  ***   *  *          ******   *   ** * *  ****    * * *******   (string2[i]==string1[i])
 *  * *   ***   ** ***  * **** ***   ***** * ***** ** ** **  *  * ****  ** ** * * 
           ***** ***** ** ********** *   ****  ** *   **  *  **   **     *** *   **  * * *   *** *  * *  *
***   *      ***  **    ***** ****   ***  ******  *      * *  ***  *       *   *
**   **  * *  *** ***  *** *   * *  *****   **  *** 
* *  **  *    **** *   *** *   *  * *    ****** *     **   *  *    
    * * **  ********   ******  * **  * *  ** *** * ** * *
 * *  * ***** * **  * **  ***** * *   * * ****  ******  ** **  ** **  **  ** **   ** *  is a prefix of %s", string2, string1);
****     ****** *   **  **     ****  *  *  *      **  *
*** ******  ***  ** *****    **** *   *   ***  *       *  
 *  *   ******  **** * ****  * *** *   *   * *     ** *  
   ** **   ****  **** * ** ***  ***  ****    **      ***  ****  *** *   ***    * is not a prefix of %s", string2, string1);
 *      * * * *   ** **   ***      * * ** * *  * 
    }
 ** **     **   *       *  *  * **   *  *    *  *         
    {
 ** ** ****** ***  * ***     *** ***  *  *  ******** * *  * *  (i=0; i<=strlen(string1)-1;i++)
***** *  * **   **    * ** * ***  **  ** **    ** ** *
   **** *   *   **  **  * *   * **  **  ****   **** *  *  *   * ** ** * * * * * *      (string2[i]==string1[i])
 * ** ***  * * *  * * *           * * **** * *      *    **** **   ** **   **  ** * ***
 *  * * * *** *  *  *   ******* **  **** ** *  * * * *  **    * ****   * *  ** **    ****** *  ** * * **
****    **** *   *  * **** *  ****  * * *    * *** ** *  * *    ***   * ** *  * *
****       ***** ***  * * ** *  *  * * *       **** * *
   **  * ***  ***  *       * *   **   ***   **  **  *** * 
**** *    *  **  *   * **    *   * ** ** * *** * ***
*    **    *  ***    * ***  *   ****** * **  *  * ****    **  ***  ***  ** **** ******  *  ***  *  is a prefix of %s", string1, string2);
 *****  ***    **  **** ****  **  ** **   ***   * ***   ** 
*   ** ***** **    *** * *  ** ** * *   *      * *   *    **
 *****  ** ****   * *  ***     *    * ** ******* *
*  *    *  *  *   **   *  ** *  ***** *   ***   **   **  *   **   * *   *    *****      ** *** is not a prefix of %s", string1, string2);
*  *** * *   ***   * ** * * ******   ****  **  *   ** *  *   
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
** * * *** * * * **         * * *   *   * %s", chaine1,chaine2);
  **  * *     * ** *    **        ** *
  *   * **     *** *   ** **  * **   0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
** * ***  *****   *  ** *     ** lenght1,lenght2,c;
    * **** *  ********* *  *  b[100];
    **  ** **  ********  *   a[100];
 ******* * * * * ****   **** * d[100];
    *  * *    *  * ** ** * *      **  ****** *** ** *
  ** *      *******  ** * *** ***  *      * * 
   * * *  *      *     ** *   * *** 
  **  ******  * *   **        *  * **  * 
  * *  *         ** *  **  ********
 * ** **** *   **** *  * *
 * * *  * *   ** *    **  ** *  *  ** ** *  ***** * *   *    is a prefix of %s",a,b);
   *****  * *  * * ******* * 
 ** ** * **   ** *  * ****  **
*   **  ** *  ****    *   ******
***** ** * ** * * * **  **  *   *  ** ** ** * *    *  **** * **  * is not a prefix of %s",a,b);
 *  * * * * **  ** ** *  ****
  * *** ** * **  * * ** ** *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **** * * *** *  
#include  *  *   *   *** * 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
  * *     ******** i;
 ** *   *  * **  **   * **   ***
  {
 **    *  ***  * * *    * * ******  ****   A[i]!='\0' && A[i]!=B[i]   )
 *** * **    * *  ** *  ** *     *   ** ** **     ***   **  *** ***      0;
 * * * *  * ***** *      **      ****   * ***  * 
    **  ****   **  *  *  **  *  * ***** ** * **** *  ** *  *   **  
  }
**** **    ** *  1;
}


int main()
{
 *  ****  **   ** ***   *  *   a[n],b[n],c[n];
*******   ** ***    *** *  *   i;
** *** ** **    *   *  * * ** *     * ** *  ***
   * *** * *  * *****   *  *  * **  * *** * ***  * 
 * ** **  ***   *   **  * **  (aa(a,b)){
 ****   *  *     **   *  *******  **  * ***** *  *   *** *** * **** ****
 ** *  *  ***  * *   *** **   ** * ***   *** **  * * ** *** * *** *  **   * ** * * *      *
 ** *** ** ***  *  *  **    *** **  **   ** ****** ***      *  * * * ***** * ***     * *  ** **        ** *
 *  *      *   ** ****  * *   * * *** ** * *  ** ***    *** *** **** *   ** *** *   ** 

         * ** *** *  ***    ** *    ** *  ** **    * 
 **  ******  *   **** ****** *  * * * *  ***    *  ****   **   ** * * is a prefix of %s",c,b);
    **     * *  **   *
*** **    ***  *  ** **  *     *
 **** ** * * *    * *     *****    *     ** *   ****** **  * **  ** is not a prefix of %s",a,b);
 *  *  * * ***    ** ** *** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *         *   ** 
*    * * ****  * *  
int main (){
char **** **
char *    *  * 
 *** * *   *****  string1: *  *  
*  * * *         ** * *    **** **  
*  *    *    *** string2: *   * *
  ** *   *   * ** *****
** * ** **** *  
*  * *  * **  ** ****      *  *** *  is   * ***   of * ** *** *  **  
else
*       * ***   **** ***  * **   *  is not prefix of *** *  * * **   

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  * ****  * ** 
#include *  **   * *  
#include  * **** * ** 
#include  *    **  *     *
int prefix(char p[],char s[])
{
**********  ** *     *******  *  ** *  
 ****  * *** *   **     ** 0;
 **** ***  *  *  ** *  *  if * **  **  * **  
*  ** *  **   **  *   ***** **     1;
** * *   * * *  *** 
 * * ***   ** **    *   *   *  ** * * 0;
}

int main()
{
**  *** ******* *   **  p[999],s[999];
 *     * ***  *   * ****  * * *  ****  * 
 *****  ***** **  *    ** *   ***   ****

 ** * * * * ** **   *   *** **  **  *
 *** *   * ** *   ** *     *     * * * is a prefix of %s",p,s);
 *  ***** * * ** *    *    
  *  ***  ** ** * ***  * * * ***** is not a prefix of ** *  * * * 

** *   * *****  ** *  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    ***    * * * *
int main()
{
 ******  *     *  * * *****  *     *  length1,length2,c;
 * *   *  ** ** * *        a[100];
       ** **   ** ** ** ** * b[100];
  * *  ** ** *  **** * ** d[100];
     ****   * **  ** ****    **** ***   * *  * ** *** *
  * ***   ** * *  *  ** *    *** ** ***    *   ** *
** * *   **  ***  **    * ** **   *  
*  ******* **  * *** *     ** ***** 
if (strcmp(a,d)==0)
* **** ******  ********* ** **    
 * *** ***   ** ***** * ***  ****   ** * *  *** ** * ****          is a prefix of %s",a,b);
*  *  **    *  *  * * ** *  * 
**     **** ** **  ** * *  *
 **  **** *    ****        * **
* * *   **  ** * **  *  **     **   *  ***  *  *   *     * *     is not a prefix of %s",a,b);
* * ***  **  *  ***   * **
  * ** ****  ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** **** *   *
#include  * *     *  * * *

int prefix (char    ** str2[])
{
 ** * ** * **  **** ***  * ** * length=0,  **      
  ***  * **   *  **
* ** * *  *  **** **    * *   * * = ***** * **** ** *
***** *** **     * **** *** 
  **  *  * ** **   **  *  * *   * **   * ** 
   ***** * * ** *  *      *** **  **  ** * ***
*  ****  *  **    *  **  *  *  ** if ** ** ***** **  
  * *** * **  **   **       **  **  * * ** * ****  ***  
*   **** **  * * *   * **    **    }
   * *          *  *   *   * **       *
*       ****  * ******** (count == length)
*   ** *   ** ****  * **  * *  *  ****    ** 1;
   *   ********* *  *** * else      **** 0;   *** * *****    **  **
*        * *  * *** **   *   * 
}
int main(void)
{
***   *** * *** ** *** ****  *** **    * ** *  
* * *    *****   *** * *
 **** * *** ***  **  *     *** * *** **   **   ****  *  str1, str2);

*   * *  *** ** *  *     * **   * ** ** **  
 ***    ***  {
   * *  *  *** ******  **      **  ***   **   *   *     * *******    * is a prefix of    * *  *  str1, str2);
**  * *  **** ***** ** **** *
** *** * ** **** *** *******
*  * * * *  ** *  *****   ** * *  *   ** *****  *** ***  **  **    ** is not a prefix of  *   **   str1, str2);

** * ** *   *** * * ********** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **   * * **
#include **  ***  * * *  * *
#include *   **  ***   *

int main()
{
**   **** **   *  **** *   *** prefix[100];
**   **  *   ** *   **  ***  **  word[100];
  * **    ** *  ******  * * ** **    %s", prefix, word);
*    **  ***      *     *  *** i;
   ****  * **  * *  * *  * * * * = 0; i< strlen(prefix); ++i)
**  ** *  * *** **  * **    
  * ** *****   *  **  ****** * *    **  * **     ****    * **** ****
   *****  * * **   *  * *** ***    ***********  
   ** *** *     **   *  * ****   ***    *** ******* ** * ***  *  * * * * *  **    *  **  ***  ***  is not a prefix of %s", prefix, word);
 * *  ***     **      *  ****  **  *   **   * ** *** **  * *  *     ** ** *****    **   0;
     ****     **  *** ** **  * * *    ********  **
* * ** ** **   ***   **** 
*****  *** *** *        *****  * * * is a prefix of %s", prefix, word);
** **  * *   * ***** **** *   *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****      ** * 
#include ** **** ** * *   
#include  **   **   *    *

int main()
{
   *  ** * **   ****** *** *     prefix[100];
 * ***    *  * * ** * **** **** * word[100];
*  **    ** **     *** * * * ***  *  ** * %s", prefix, word);
*  * **  * **** *  *   **    * i;
* * ******* * *     *   *    *  *  = 0; i< strlen(prefix); ++i)
 **** *  * *** ***** * * ***
*  * **** ******** *   *  *  * ** * * **    *** *    ** *    ***   ****   *
 ** * **  * * *   ** *  *** **  **  ******* *** * *
 ***** * *  *  ****     ******* * *  ** * **** * *** * * ** *******   *  *** *  * **  * **   * is not a prefix of %s", prefix, word);
**  *  * **  *  ***     ** * ***     ***  **  *  **     * * **     ** ****   *** * 0;
* *     *   * *  *  **  *      *         *   *****     *  *
   ** *  *  *    *   ** *  
 * ** *  ***  ******  ***       ****  ** is a prefix of %s", prefix, word);
 ***  *** ** **      *  *  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *  *  **   *  **
* ** * *****     *        
*    **      *    ******  

int main()
{
** ***  *  **    char    ** ***   
 *** **** ** *  * char   ** **
* **   *   *** **    ***  * * *******   *    word);
 * ***  *** *  int i;
*** **   ** for(i = 0; * *     ** ** * ++i)
 ***   ** * *** {
 * ** **  * *   * *  * ** *   *    ** * *** *  *
 *  **  *    *     * * *    *  {
    ** * **    ** *  *  * * *    **   *** *  ** *   **** * * is not a    of   ****     *   word);
    * * ** *  *   **** ** ***  **    * *       ** 0;
 ** *     **      * * *     ** * }
** **** * *   }
 ****   *  * *   ****** *** * is a prefix of * ***** *      word);
  *       * **  ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.202
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users