1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
     * * **  ** *  * ** ***
*     *    **   *   *  **   ****** ****     *    * *
    {
***** ** * * ***  *    * *  *  **   *   * *** ***  ** ***  (i=0; i<=strlen(string2)-1;i++)
   ** *** *   * *  **     * * * * **    ** **  ****
  *    ***  *    * ***  **** *   * * **** * *    **  *    *** **  **  * *   *    **  **   (string2[i]==string1[i])
   *****  **** *  ***   **  **  ****   ** **   * * *   * **   **** * *****  **
 ***      * *    * * ***      *  **** ***   *  *   *   * ******* **   *  * *   *  *  *** *     *** *** **     * ** ** 
*  * **  *  **   *  *   **       *** *    ****** **      *   ***  * *   * * *    * *
 *  ****     * *** ***   *   *******   * *   *** ** *   * 
   * *  *   ***   ***** **** * **  ****  *   **   * ****  ***** *
 *  * * *  * * ** * **  ******* *    * **  ***   
 ***    **   ***   * **   ** **  *  **   ***   *   *   * *  ** *  ****     ** ** *      ** *   ***  is a prefix of %s", string2, string1);
* *** *   ***  ****     * * *  *  *  * *     *  * 
   *    *  ***  **  ***  * * **** **  ***  * *    *  *  *
   *** **  ****  * ***    ** * ** ** ***** * ** ****
*  **   *****      ** * * *   ***      *  * * * **   **** * ** **  **  **** *    ****    *****  *  is not a prefix of %s", string2, string1);
  ***** *  *   *** ***  *** *** **  ** **  *   **
    }
    **  **** * *  * **     **** *    **   *      *  ***** 
    {
 **    *   * **** ** *  *  *  *    ************** (i=0; i<=strlen(string1)-1;i++)
 *  *   **    * **      **     ****     * **      *
* * *  *  * ** *     *  * * **   ***         ******    *  * * * **   *   **  * *  **  (string2[i]==string1[i])
 ***** * *      *   * ****  * *  * *     * ** *    *** * **  *  **** *** *  *   
    *   * ***  * *  * * ** ******  **   *  ** ** ********   *** * * **   *** *  ***** *  **  *   ** * *      
**  * ****** *   *   *  ***  * **     ****  * **** ** **  *** * *   * *   ***  
*  * ** ***     ***  * ** *** *  *    **   * ******  *
  *  *  **  ***   * **  **     **  ***   * ** **** * * ***
 ****   *  *      ***     ** **  **  * ***   **  
*** ***   ** ** **    ** ******* ** ** ******   *  *  * *  ** ** ** *** ** * * ** **** * is a prefix of %s", string1, string2);
 * **** *   * *  ***   **  * **** * **  * ****  
****** ***  *  *   * ****   * *  ***** *** ****   *  *
* *       *** ** * * ***  ****** * ***   ***** *  ** 
 * ** ** *    *  ******  *  **     * * ** * ** * * * *  ****     *   ***  ** ***       * * * * *** is not a prefix of %s", string1, string2);
  **      ** ***  * **  * ** *** **  *    ** ** *    *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   * ****   *** *  ** **     *** ***     * %s", chaine1,chaine2);
  * **    *  *      ** *   *** ** *** * ** *  
  *  * **  *** ******  *** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
** ****  ** * ***   *    lenght1,lenght2,c;
  * **   *   **  * ****  *  * b[100];
**    ***  ** *  ***** * *****   a[100];
*  **** *   ** ****    * d[100];
 *  ***   **** ***** *    ** **  *   **  **    **  ****
* *     **  * *  ***** * ****   ***  **  ** *       **  *
 * *   *** **  ** *   * ** *  *  * *
 ** * *   * ** ** *       ** ***   *    **  
 **    **  ** ***  **     * * *   **   
***  *  **  ***  *****  * **
*  * *   * **    *   ** *** *      **     * ** *  * is a prefix of %s",a,b);
 ** **    *   *  *** * *****
*       ***** ******* **  **  
 *  *  ***  ***       *     * 
 * * ***    *** ** *** * ****  ** ***    ***  ** **   * **** *   is not a prefix of %s",a,b);
*  ****    *      *** * ** *
* ** *      *** *** * ** ***   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *  ***  *   **
#include  * *  ****    *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
   ****  * **** i;
  ** ****  *  ***   ***  **
  {
**    **** * **  **  * *  *   * ** ***   **  A[i]!='\0' && A[i]!=B[i]   )
  * *  **  * ***  *  ************   ****  ** * ***    ******   ***       * 0;
 ** **  **  * * ** ** **    **  *  **  *       **** 
  * ** *    *  *  ****  * *  * ** **  ** ** **** *** *** * **** **
  }
**  *****  *     1;
}


int main()
{
***      **       ***   *** **** a[n],b[n],c[n];
 ***   *        * * *  *     * *  i;
 * ** *  **    *   *   *  *   * *       * *    
**  **  ****   *****   ***** *****  *  ** *  * *
   *     *** **  * * **   * *  (aa(a,b)){
 ****  ** *  ****    *    *     *  ** ****  ********  ** *   *  ** *** ** 
 * *    *  *   *   *   **     **    * **       *    **  * **  ***   * **          ** ** * *   **
  ***** *  * * ** *  *  ****  *** *     ** *   * ** *** ***  *   * * * *** ****    **  * *     **  ** *
  ***  *  **   ***** * **** *    ** **  ** **  **  *  ****** **  **  * **  **

** **** ****   * **  *  *  ** * **** ***********  * *** 
***  ****  **   *    *** * *  **  ** ** *** ********** *   ** *  is a prefix of %s",c,b);
*  * * *  * ****   **  * * 
**   ***       * *** * ***      *  
 * ****      * * *   ******  *      *  * ******  ****** *   ***  **** is not a prefix of %s",a,b);
** *  **  *  **  * ***   * ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * *  **     *
  * *** ** *****  *   
int main (){
char  *     * 
char ******* * 
  *  *  * *   ** string1:  *****   *
 ***  *** **    ******   ** *  
***   **  ** *  string2: * * ** 
*** * * *   **         *  
*** * *****  *    *
 ** *   **   *   *** **      *    * **   is      ***    of  * **** * ****   * *
else
 * *** *      *   **** * ***  * *  is not prefix of    ** *** * *  * * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     **    *  **
#include  *** * *** * * * *
#include   ** **** *        
#include    *** * **    **  
int prefix(char p[],char s[])
{
    *** *  * * *      ****** *   ** * *
*****  *  ** *   **   *  ***   0;
**   * *    ** **    ** if *  *  **  ****  ***
   *    * ** *** * ***  *** **  *** *  1;
  *  ** *** **  * ** ***  *
 ***  * ******* **  **** 0;
}

int main()
{
* ***       *   **  * * *   p[999],s[999];
  ** *** **  * * * *  * ** ******  **
* * * ** **  * *    ** **** * * ** * *

 *** * *  **    * ***  **** *
**** *****   **    **   * * **** **  * **   is a prefix of %s",p,s);
*  *    * *   ** *  ***
 *****   ***  *     *  *  **** ** * * *   is not a prefix of *** ******  *

   **  ***  * ****** * *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   **  *** * * **  * 
int main()
{
  ** * *     **    ****  *   length1,length2,c;
*     ******   * ** *  *  ** *  **  a[100];
*      **** * *   *  * **   *    b[100];
   *** *  * *   *** *  **    * * d[100];
*  ** * ** * ** *    **  * **       ** * * *
 * *  **  *  *  ***** ***   ** *** *** * *  ** *** ** * * 
   **    ******* ***  ****  ** *** 
 *** *  *   **   **  **  * *  **** *** 
if (strcmp(a,d)==0)
 *   *** ** ** ***  * **  *  
 ** *  * **   *** *    **** *  ***** * ******  * *  ** * **  * * is a prefix of %s",a,b);
 ***   *   *  *** * *   *** * 
* *  *  ** **    ****      *  
  * ** * *     * ***   ***
 ***  * *      ** * * *  *   **   ** *   * * * * * *  *   *     *     ** is not a prefix of %s",a,b);
 ******  ** **  * *   * *
**  *   * * ** * ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     ** * ****
#include   * **** *  * * *  

int prefix (char  **  * * str2[])
{
 **   *** ** * * * ***      length=0, ***  
 ** **** *  ** **** 
    * * ** * ***   **   **    *** * = ***   **   * **  *
*   *  *   **** *    * * * 
* ***** *   ** * * ****      **** * * ****  * * * 
*  ****    * * * * ** * **  * *  *** ****
* *****       *****    ***  *  if *   ****  
**     *      *           **   * ***   **   *   
 *   * *********** * ****  * * **   }
**  ****           **** *  * *  **  **  
  ***** **   ******   (count == length)
* *  * *  *  *  ** **  ** **** ** *   *  *  1;
*** **     *******  *  *  *   else   * ** *   0;  **  * ****   * ** *  
 ******   * * *     ***    ***   
}
int main(void)
{
** ** * *  *  * *    * * ***    ***
     ***** * ****  **  *
 **       **   *  *** * *   *  ** *      ** *  * * str1, str2);

****        ** *  **      * *  * *  ** *    ****
** * **     ** {
*  * ***   * **  *  ** *  **    * * *** ******* * ** *****  *****  is a prefix of *** *     str1, str2);
*      * * ********  ** *****
* ****   ** *  **  *      ** *
***  ** *** ***   **  ***** *       **     *  **    *    **  *  ** **  ** is not a prefix of ** **     str1, str2);

 ** *   ** **  ** *** * *     *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **    * * ******
#include *****  *   *  **
#include ******  *** *

int main()
{
 ***    * * * ******* *  ** ** ** prefix[100];
   **** *   **     * **** *    word[100];
    ** ******* ***      ** * * * ** %s", prefix, word);
* ** **  * **   *** **  **** i;
* ****   *  *** * *   **   *** = 0; i< strlen(prefix); ++i)
****     * ***  ** * *    *  
**  * *     * *    *** ******    * **** * *** ** ** * **    *
** **  ***   ** **   * *   **   *      * **  * *** ** 
* *** ** ****      * **  *  ******** ***   ****** *  ** ***  * *  *    **    *  **  * ***** ** * is not a prefix of %s", prefix, word);
 *     **  **  * **  **  *    ** **  ********  * ** *** *  * *  ***  *  *    * *****   0;
****   * **** ** ******   ** *** **  *  *  ***   *     
** ***** *  ***  **   *  * 
  *** **    ** *****  *** *   ***   *** is a prefix of %s", prefix, word);
 **  ** *  ** ** * *  ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** * * ** **
#include      * *  ** ****** **
#include * * ** ***** **

int main()
{
 * ****  **  ** * *  **    *** prefix[100];
* *** ** *   **** ** * *  *  *  word[100];
 ***  **   *** * ** **** ** * *** **   %s", prefix, word);
**  ** ***   * *** *****  ***  i;
*    * **   * ** **** * ***  ** = 0; i< strlen(prefix); ++i)
  **  * * ***  **  * ** * *  
* *   **  *      *  * ***     **  **  *  * *     ** *  ** ***
    ********  ** * *  * ** *  ***   **    **  ** ***
 *  * **  ***   *  * **  *    * * * *    *   * **     *    * *    * **      *   * * **     is not a prefix of %s", prefix, word);
  *****      * *   * *  **** *   ** *   *  ****   *  * ***** *   *   *** ** **   * 0;
 *  *   *****  *  *  * *   *** * *  **   *     *** *  *
  **  **** *    **  * **  **
 *** *** * *   *** *    **    * ** *  *   is a prefix of %s", prefix, word);
 **  **    *     *     *   *  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *  * **  *   *       
** * *     *  ********   *
*   **  *      **      

int main()
{
  ** **** * * *  char *    *****
 **  **   ***  * char   **  *
 *  * *    * * * * *  ***** * *   **     *  word);
****          * * int i;
 *** *      ** **  for(i = 0;  *  ** * *  * * *  *  ++i)
 * * * *  *** {
 ***  **   * *   *      * **    ** **** *   ***** 
   *  * *** *     *     **** ** {
 *          *    * **     *  * *  * ***     ** * **** *    is not a     ** of * * *   * ** word);
 *   *   * *** * ***  *  *    ***     * *  *  * 0;
    *  *    *   * ***  *  * }
  *  **      *   }
* * *   ****    * *  *  *  is a prefix of ******* * *  * word);
*    * * * ** * *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.50
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users