1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 **  **** * ***  ***    * *
  * *** ***    *   **   *** **    ***  ** * * * ****  **** *
    {
 *** *  *** *   ** **** ****    ****  *  ** ** * *** (i=0; i<=strlen(string2)-1;i++)
* **** * ****   **    *   ***   *     * ***** * * ***   
**  *      *   *    * * ** * * ***   **   *   *      ******  *  ***    * ***  *  (string2[i]==string1[i])
****    *  ** *  ** **    * * ** *   ***  ***  *****  **  *  * *  * ***   **  * **
 * **  **  *  **** *    ****   ** * *   * * *  *   *   *** **    **  *  ***  ****  * *  * **  *** ** **    **
   * ** *  **  ******     *** *   * *** **  * * ****  *  **    * ** *  **   **** ** * *     
 ****   **** * * *  ** ** *****  ** *** ***    *    *****
 *** *      *****  ** *  **   ** ** *    * *   ****** * * * 
  ***    **    * *  *   ** **** * ** *** * ****  *   
 * ****   ***        ** *   *    * *   **  *  * **** * ** ** *  **** ** * * * **** is a prefix of %s", string2, string1);
********   ***  * * ***  * * *** ** * * *       * ** ** 
   *     ** *  **** **   * *    *  **    *   *** ** *
 * *  * *   *     ***** *** * **      **     * * ***  **  
****  *   *  **** ***  * *** ** ** **   *        *      **** * * ****  ***** ** *  is not a prefix of %s", string2, string1);
**    **     *    ***  ** ** ***  **  ** ***       ** **
    }
  ** *   *   * *  *    ****      ****  ** *** ** ** * * **   
    {
**  *  *   * * ** **  * ** ***** *  **      **  *  * ** (i=0; i<=strlen(string1)-1;i++)
 ** **  ****  * **  * *  **    ** * ** ** *    *  *  
****** ***       ** *   *  * *     **   ** ***** *       *** * * **  ***** *    **** * * (string2[i]==string1[i])
* *      ** *   ***       *  * * *  **  *   ** *** * *  *     **   ** *   * *** **    * *
 **  * *****   * * * * ** ** **** **  ****** * *     *  * *      ** ***** * * ** * ** * *   ** *  *  ** *   
 ** ** * *  **       *   *   ** *       *     * * * ** ****** ****  * * **   *******  * 
 *  ***  ** * **   * *  ****** * * * * **       *
 * *** *  * **   *  **  * *    * *  ******   **** 
***   * *  ** ** *** * ***** *  * *** *           *   **
 * ***  ***  **  **      *       *   ** *  *  *     * *  ***  * ** * *****  ***** **    *** *  ** is a prefix of %s", string1, string2);
 *** *  ** * ***    ***  ***  * * * * *    ****  *
** **   ****    ** * *      * *  * **  ***** *  *** *
 *   * *   ** **  **   ****   ** **   * **    ***** *  *
*  ** *  * * *  ******  * *** * *** * ** *  ** * *  *   ***** *  **  ** ******* *  ** * * is not a prefix of %s", string1, string2);
** *   *     ** ** ****  * *****  *** * * * *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
  ** ** ** *    *** ****** * * *  *    ** %s", chaine1,chaine2);
******    * *  **   *    **** *  ******
* * *** ** *  ****  * **** ****** *     0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  *      ***    * *    * * *  lenght1,lenght2,c;
     **** * *   ***   ** **   b[100];
   * **  ** ******   * *** *  a[100];
  **** *** * * **   **** ***   d[100];
* *** **    *  * **  * * ** * *   ****  ** *
*   *  ***  ** ****** * *** ***    *  ***  **   ** 
*    ** ** **      **    ****     ** * *** 
**     ** *    * **  ** * **  * ** **  
* *  *   * ** *** * *  *    *  *** ****  * 
 *  * ** ***** ** *** *  **
 **    **   *** *  **     ** * ***  * **    **   ****  *  is a prefix of %s",a,b);
*******    **** *    ** *  **  *
***     *** **    ***      
**  *   ** * ****  ****   **
** * ** *********  ***  *        *  *   *    **   * *** **   ****   *  is not a prefix of %s",a,b);
 **** **  *  * *   * * ***
 *** * *  *  * ****  ** * *    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * *    **  ****
#include  * *  *        ***
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 * **  ***  *  i;
** * *** ***  * *        *
  {
 **    ****   ****  *  *  *  *  * *** * * ***  A[i]!='\0' && A[i]!=B[i]   )
*  ** * *** *  *** ***  *  * * * * ** * **    *  ******** * *   0;
** * *       * ***  * *   * * **  *        * *** * * *
  ** *  *   * * *   *   *** ****  ** ***   **     * *****  *  ** ***** * **** 
  }
* ** *** * ***  *  1;
}


int main()
{
     ****** *   *  *  * *  a[n],b[n],c[n];
**     *  *  ** **  **  **  i;
    **  *   ***** * *** **  *  *   * *  ** * * 
* *** *    * * *   ** * *** ** * *  *** *    *
*  **    **     *    *** * * **  (aa(a,b)){
 * *** **** ***  *    ****   * **   **     ** * *  *** ****  ***
*  *** * *  ***** *  **   * *   ** *****  ***   ** *  * * ** * **   ** * *****   *  *** 
*    ****   ****  ***    **** *  *   *  * * *  *   ******** ** * **  * **   **  *****  * *** ****** **  **
** *   *   * *** * * ** *****    **       *  **         **    **  * *  

******* * ***  * **  *  *  *     *  * *  **** *  **   *
* * *  *** *    ** *    * *   ****  * * ** * ** * *  * * **   *   * * **   is a prefix of %s",c,b);
 *    **  *   *****  **  *
 ** *    **   **    **      * ** *   
*    * * ** ** **   **  * **   ** ** * **  *    *   ***** * **  is not a prefix of %s",a,b);
 **   *  **  ** *  * ****  *   ***  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **    *   * *
***   * ****  ** *****
int main (){
char  *   * * 
char  *  * *
**   ****    string1:  **** **
**  *   *  ** *   ******* * **** 
  * ***      string2:  *   ***
 *** *    * **   ** *   * * 
  *    ***  *******   * 
  * *    **   *    ** ** *   **   is  *****     of  *  **  **** ** ** *
else
 ***  * *    *** *  **  *    ***    * **  is not prefix of    **  ** * * *   * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***   *   ** *
#include **** * ******* *   
#include *** *** * ***  *
#include * *** *         
int prefix(char p[],char s[])
{
*    ***  ** *  ***   *  * *    **  **
  *   *  ** *  *    ** *  * ** 0;
* *   * **   * *****    if *   ** *** *       * ***
  **  *      *  ** **  *    *   **  1;
** *  *****    **  **  
 ***  *** **   ** * *   *** **  * 0;
}

int main()
{
 ** *        **  ** * p[999],s[999];
***  *  * *  * * **  ***  *  *  **  ** * *
       ***  ** ** *** *** * *     * **   

* *   * * ** **  **  * *    * 
** ** **  *  *   **** ** * **  is a prefix of %s",p,s);
   ***  *  ** *    
 ** ** ** **  * **  ***  * ***** ** is not a prefix of  *  *   *   

***    **   * ******* * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *  **   ** 
int main()
{
   *** **** *** *   * *****    length1,length2,c;
       **  * *  * * * ** *  ** ** *  a[100];
  *  *   *     *** * ** *    *    b[100];
* * *   **** ***** *  *  ** * d[100];
  *  *   ** ** *  *   ** * ** **  * *  * *****  * 
   **  *   *  ****  *  ** ****  * *** *** **  *
**     ** *  *** * * *  *  ** ******** **
       *  ** ****   *  *  ***     ******
if (strcmp(a,d)==0)
 *  ****   ** * * *  ** * 
   *  ** * ** ** *        * ***  * ******* *   * * * *  * *  *** *  is a prefix of %s",a,b);
*  *         ** ***** ** 
 * ** ** *****   ** ** * **  **
  ** * *  * ****      ** *  *
   * * *          ** **   ** **    *  ** *** * * *  *  *  ****  ***** *   * is not a prefix of %s",a,b);
* * *        * **  ****
*  * ****  **  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  **  ***** *  
#include ** **  * * **** *  

int prefix (char * *** str2[])
{
*  ** ** ** *   **** * * **** * * length=0, * *  * 
* * * * ****    ***  *
**  *  * *** *******     *** *** = *   *   **        *
 *   ********  * *  *    *  * 
 * *           *** ***** **** *   ****  *** * ** *    
  **  * ****** **   *     * ***  ***   *
* *  * * **    **   * **    * if * *   * ***
 ** * **   *    **  *       ***   **   **** *****     
****  *   ***** * ** *   *  *  **   }
*   *           *     * * * *** *  *   
 **** ***     *    * (count == length)
*  * *     *  *   ***   * ** *   ****  * * ** * 1;
* *  * ***       ****   *  ***  else    ** * 0; ******  *    *  *   *   
      * *    ****  ****** 
}
int main(void)
{
 * *    * **  ** *  **** * *   * ****  **  
 ***  * * * *** ****  
     *** * * **  ** ***** * **** ** *  ********  str1, str2);

***  * **** ****  **  **    *   **  * * 
  *   * *   *   ** {
********* *** * ***    *   **    * * **   *   ***  **  **  * *  ** is a prefix of  *** ** * str1, str2);
   *   ****** ** *      **  * 
* * *** *  *  *   *  * **
 *  ** * ****   * **   **  * * **** ***   *  * **  **  *    **   is not a prefix of  ** * *  ** str1, str2);

 ** *  ***   * **   **  ** ** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** *   ** *
#include  *  * * * *  * * 
#include *  **   **    *

int main()
{
****      *        ** ** ** * prefix[100];
 ***  *     *   **     ***  **** * word[100];
**  *      ** **   *** *     * * * *      %s", prefix, word);
 **  *    *  **   * * *  i;
* ****   *** ***  *  *   *  *  *** = 0; i< strlen(prefix); ++i)
 *** *   **   ***** **  *   *  
* *** **        * *      *** *  *   ***  * * ** * ***   *    ****   *  *
 ***     ****  *   * ****   *  *    **   * *      **  *
* *   ** *      **  **     ***  * *  *  ********   *  * * * * ***   ** * *  *  *  * *   is not a prefix of %s", prefix, word);
  **  ******* * **    * * *  **    * *****   *   ** ***  *  **** * ** * *  ** ** 0;
*  *** **  ** * * **   * * ***  * * **     **** **  *
 **  **   * **** * **** ** ** 
  * *******    ********** *  ***  *   **   **    is a prefix of %s", prefix, word);
 *    * * * * *    * * *    *   **** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *****  * ***   
#include    * *** **    ** 
#include  * ***** * **  **  

int main()
{
  * ** *****      * **** *  **  prefix[100];
* **** * **  *** * * ****   *   word[100];
** **   * *   **    * *** *** ****   *** %s", prefix, word);
  *** *       *** ***   i;
 *** ** ** *  ** * *   ** * ** ****** = 0; i< strlen(prefix); ++i)
 **  * *** *** *    *** *   ***
* ***         *    ***   *  * ** *** **   *   *   ***   ***     
 ****   *   * * ** *******       ** ** *** **** **  ***  ****
    ***  * *  *       ** *    *   ** **   **  * **** *   *  * ** **   **** ** *  ***** * *  is not a prefix of %s", prefix, word);
 *  ** *   * ** *  **   * ***  *  **  ** * ** *** **  ** *** *** ** * *  ***** **  * ***  0;
    * *****  *   *     * ** *  *      *  ***   *    ******  **
* **  **    *  * ** * * * *** 
     ** *** *   **  **  ** * *    *  ** is a prefix of %s", prefix, word);
   * **  ***   ** * * *   *  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * **   **     ****
  * *   **    **   ***   **
*   * *  *****     *  **

int main()
{
*** **       char *****
  *** ** *****  ** char *  **  
*  *****    * *  *   * * * *  *******  *   word);
       * *   * * int i;
 *  *    * * *   for(i = 0; ** ** *        ++i)
  *    ***   * {
****  * ******* ***** * **  **   *   * * 
   ***   *** * *  **     ***  * {
    *** ** * * *            * * *** **  * *    *****  *** **  is not a * of  * **    ** word);
* * * *  *  *   ***   **** *  ******    *  * **    0;
* *  **  *** *    *   *  * ** }
  *  *   **  }
********  ***   * *  **   ** ****     is a prefix of ** *** * **    *   word);
  *** *  *   **       ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.205
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12k views
12,783 questions
183,442 answers
172,219 comments
4,824 users