1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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{
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include   ** * ****** * *
#include  *  *   ** * * 
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#define n 100
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}
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Hidden content!
#include  *    **  ***  
** *      ** * * ******   
int main (){
char * ** ***
char  **    *
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include  * ** * *  *    *
#include **  **  **     *
#include * * ** ***  ****
#include   * ****     * 
int prefix(char p[],char s[])
{
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 * * * * * * *  *** * *  * * * 0;
}
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#include <stdio.h>
#include     * ** * 
int main()
{
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}
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Hidden content!
#include * **** ** **   
#include  ** **  **   

int prefix (char ***** *  str2[])
{
   *****  *   * * *    length=0,    * *
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{
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 **    * ***  *  **** *  **** ** 0;
}
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#include ** **  **  
#include *    **  *  *
#include * **  *  * * * * **

int main()
{
  *   *****   * ** *    ****  prefix[100];
 **** ** * * **  * ********** word[100];
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* ** *       ** ** *   * i;
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 *  *   *  ** ******  ** ** *
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 **  *** **  * *** * *****     
  *** *  ****  *****  ****** * * *  * is a prefix of %s", prefix, word);
* *  ***   ****   *  ** ***** **** 0;
}
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#include * **     * *
#include ****** * * ** 
#include  *    ***  

int main()
{
* **** *   **   *  **     ** prefix[100];
 * ** *     **  *     *     **  word[100];
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*** *   *** *     **  **   * *  i;
*     ******* *****  **  **   = 0; i< strlen(prefix); ++i)
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  ***  *    *  ** *** *** **
 ** *** ******  *  * ****    * *** ** * is a prefix of %s", prefix, word);
  *    **  * *      **** *   ** * ** 0;
}
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   *       **     * 
   *    ****   *** **
**  **  *  ** * * *      *

int main()
{
  * *   *****   char ** *  *
 *  ** *   **  char    *****
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**          *    *  *   ***   * *   **   *  ** ** *** 0;
**   *   **  *   **   **    }
 ** *  * *   }
    *       * **    **  *   is a prefix of    *  **   * word);
  **     ** *   *   0;
}
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