1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
  ***  *       * *  ** * * *
* ****  *    **  ******* *  * ** ** * *** *  * ****   *** 
    {
***   **  *  ** ** *   * * **** *   *  * ****  *   ** * * **** **** (i=0; i<=strlen(string2)-1;i++)
  * ******  **  ** ***** *   ****    *** *  *  ****
* **** ****** *     * ** *  *** ** * * *  **  **** **  * * ****     *  * *     **  * **    (string2[i]==string1[i])
    * **     ***  ** * ** *****    * **   * * ** ******  ***  **   ***  * 
*** * **  * **  * ****  * *  *** **    * * ***  *  * ** ***  *** **       *   *  *   **********   *** ********
*  ***   ** **   ****** ** * * * *  *  * ** **   * **** **  **      * *  * * 
***  ** ****   *   *  *  **** **  **  * **   *   **  
   *** * *  * * ****    *****  *** * *  *** * * * ***  * * *  
  ** *  ***  **  **** * * ******  ** *    * **  ** 
**** *** **    *  ***  *  *   * *** *** * *  * ** *** **  *********** **          * *  * *   *  *   is a prefix of %s", string2, string1);
 * * * *    ***  * **   *** * ** * *** *  **
   **** **  *   * * **   ** ** *****    *  *    
* * ***** * * *  *  *  ***  *   *   *  ** ***  ** * *
   **** **  ** *  **   *  * *  ******* **  *****   ***** * * * * *  ** ** ***   * *  ** * ** * ** is not a prefix of %s", string2, string1);
* * * * **       *  *   * * *   ***   * **  *** *  *   
    }
 * * *  *  *  *** ** ****  *  * *   ****   **    *     
    {
  * *   *** *  *  **   * **   * ** ***  *  *  ****    (i=0; i<=strlen(string1)-1;i++)
 *  * *  **  * * * * *  *  *     * ***  ****  *    
  * *** * **  * * **    * ***  ** * ***** **     **  *** *  **** *** * **  * *  ** (string2[i]==string1[i])
** ** ** *** *  * **   *  *** * *  *   ** ****  ***  ** **  *   **  **  * *
   **** *     *   **   * *** *   *   **    *** ****  *  ** ** ***  *** * ** ** ** **  **   **  *      *** *****  *** *
* **  * *    * ****        *** ****    **** ****  **  ***  *   **        **
** ***  ** **  ** ** **  * *  ** *     *  *    ** ***   *    ***
** *  * *  *   **  * ****   * ****** *   * *  
 ** ***  ** ****  * * *  * * ***  ** *   *     * *   **** *** 
* ** ** * * **** * *         * *  *   *    ***    *  *****    **** *    *    ***   ***  is a prefix of %s", string1, string2);
 **** * *****   ** **  ****     **  **     ** * ** * 
** ** *  ** **   *  *** *  *  **  * *  ** ****  ***
*  * * * ** ******   **  *   *  ** *     *  * ****
 ** * *  * **  ** ***** *  *    ** *  *** ** * **   * *   *  *  * *** *   **  *** * *  *  is not a prefix of %s", string1, string2);
 ** *  **  ******** * *    ***  ** * * * *** *  ****  * **
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 **  ****** * * **   *     ***  *** * %s", chaine1,chaine2);
 *** ****** ** * ** ***  * *  * * *** ** **** *
   *   *    * ** *     ***  ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
* *** ******     *   * lenght1,lenght2,c;
    **  *  *   *         *** * b[100];
*** *   * **** * * **    *  a[100];
 ***** * **  ***   **** **** d[100];
* *  *** * ****      ***        *  ***  **    *  ** 
*  **   *** * **  *  * *  * * ****  * *** *  
 *  *** ****** * *  ** *  **  *****
** *  *   ** * * *  *   * ** ***  *** *  *  *** **
 * *** **  ***   ***  * *** ** **** *    * 
 *** * **   * * * * ** ***
 ** *  *     * **  *****  *** ** * ** * * * *  *  * is a prefix of %s",a,b);
   *** **** ****  * * * *    *
  *** *   * *** ** *    *
***  * ** *     ** ** *    
* *** **   ****** * ***    * * ***    * ***     **  *** ***   is not a prefix of %s",a,b);
   *    *  ** * *** ** *  
* *   ** ** *   *** ** ** **** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *  *   **** *
#include ** * * *****    **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
   *   * *  *** * i;
*   * * **     **  **   *
  {
*****    **   **  *** **** *    ** *  *   A[i]!='\0' && A[i]!=B[i]   )
****  *  * ** *   * * ******* **   *****  **** ******   *  *  **   * ** **** 0;
 * *  * ** *********  **   *    **      *     *  ** *
**  **** * ****  ****    **  * ** ****** * * ** **** *   *** *  
  }
   *        * **   * *  1;
}


int main()
{
*****  *  * *** * ***  *  a[n],b[n],c[n];
***  *  ****  *   *   *  * * i;
* ***       *** ****        * *  *** * **     ** ** * *
 *** * * **  *  *** *  * * ***   *   * *  * *     
 *******  *** *   ** * ***  ** (aa(a,b)){
  *** **      * **  *  **  **          **   ***  ** ***** **   * * *** **  * 
** * * *   *    * *      * *  ***  *  *** * **   * ***   *   * * ** ** *****    *      *    **    *  
 *** * *****   **** ****        *******  ** *  **  *** ***  * * ****   ** *   **   *  **  * * ** ** ** ***  * **  * **   * * *
** *   ***    *    *  ***  ****  **  * * *  ***** **  **** *** * **** *** * ** 

 *** *** * * ****** *  *******  *    *** ** * * ** * **** 
*** * *  **   * *******  *** *  *  ***** ** *  ** **    *    * ****  * is a prefix of %s",c,b);
** * ****** **   ** * *
*  *** ***  *  ** *    * * *  *   * 
**   *   ***  * **  * *  ***  **** **   * * ** *** *   **** *  *  *   ** * is not a prefix of %s",a,b);
* * *  *      *  *  *   ** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      *  ***** ** *
 ** ** *  * *  * *    *****
int main (){
char **** ** 
char * **** **** 
* **      ***  string1:  * * 
**  ***** * ** *    * ** *  ** **  **
**  *** *      string2: * *  *  *   
*  **** *  *       **       
  **** *  ****   * *
* **  * * *  *** *  *   ****** **  ** *  * ** is *   *  *   of ** ***** * *  *    *
else
**  * ***  *      * ****** **** **    is not prefix of * **** *  ** **** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * **  *   * **
#include  *** *** **** **
#include  *   *  *  *** **
#include   * ** *****    
int prefix(char p[],char s[])
{
*  **        * * *  * ***  ****  ********  
* **   ** *  *** ** **** ****** 0;
 **      *   *****   ** if * *     ** * *  * ***
*  *     ***  **     ** **     1;
  * *** **      ** * *  * * 
 * ***     *** ***  * * **    0;
}

int main()
{
  * ** **   ****    ** p[999],s[999];
*  *****  ****  *    **  ****   *    *  * 
   *  *  ** ****  **** *   *  ** *** 

    *     ** **    ***  *   * *
  *  *  * * * **** ** ** *  * * ** *   * ** ** ** is a prefix of %s",p,s);
* *     ***  ** *    * 
      *  *****     * * * **  **  ** **   * *    is not a prefix of ***  ** ** * ***

* **** ***   * *****  ***** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *** **     ***
int main()
{
**  * ****    **  *    *** *   length1,length2,c;
 ** * * ***  * *  ** **** *  a[100];
* ***   **** * ***  **** b[100];
 ** *  *  * **  * ****       * * d[100];
*  **   ** ***  *   *** * ** *** * **  *  **  **
 *  *  * *  **   ***  * *** *** * ****  **  **  ** * *
**   ** ** ** **  * *   ****   *  * * **
*    ****   *  *  * * * **   * *  *   ***  **
if (strcmp(a,d)==0)
*** * **  * *****   *    * *
  **   ***  *   **     ** ****  *** ** ** **  * *** *  *   is a prefix of %s",a,b);
**** **** ** ***    ** * *  *  *
  * ** * **  *** **** *** ** 
  * *     * *  *** *   **
*     **  * ** * * ****  *** *  * ** **  **  *  *     **  **** is not a prefix of %s",a,b);
*  *  *   *** ** ******* *   **
 **  *******    * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     ** ***  *
#include ***     ***  ***

int prefix (char   ** **   str2[])
{
   *  **  *** *   * ***** length=0, * ***
  **   **  ** *   ** **  *
 * *  **       *  ****   *  * * =   **  *  **** ***
* ***   * *    *  **
 * *  *  * *    * ***     * *    **        * * 
** * *  *  *  *    *  * *    **  * 
   **   *  ****  * **   ***   if  ********
**  *   *   * **   ***  **           ** ****  * *   ****   
******* ***   ** * *  * * *  ** * ***   }
  * ***         ***** ** **** * *  
     *  *        * * * * (count == length)
**  *  *      **** ****      **  * **  1;
*   * *  * * **   ** * **   else  * **  * 0; ** *  **    * *      
******     * ***  * *  * * ** 
}
int main(void)
{
*  ***  *   ** *** *** ** *   * *  ***** * *
   * * *  ** * *** *    ***
 **  *  * *     ******  *  *  *   **  *  * ***    str1, str2);

 **** ** *  *******  *  * **   * *  ** ** * *
 ** * **  * {
     * *** * * * * *   *******  * * ** *  ** *      ** *     * *** is a prefix of *** *    str1, str2);
******    ** ** ****      *   *
**   ***  * ***  *****    **    ** 
 *****  *     ******** **    ***** **  ***** * *  *      is not a prefix of  *  **   str1, str2);

  * **  * * *  **  * * *      * ** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  ** * * *
#include * *  ***** ** * 
#include *       ***   **

int main()
{
*****      **  *** *  *****  ** prefix[100];
 *   ** *    **** * word[100];
 **  *  ** *** * **  * ****  **    ** *  %s", prefix, word);
  * **  ** * ****** *  * ******* i;
 *  ** * *** ** ** *** *  ***  *  = 0; i< strlen(prefix); ++i)
  ** * *  **   *** *    **
**  *  *** ****  * *  *  ** *** * ****  ***   **   ** *  *  *      * ****
 *  * * **  *     *  **   *  **     *    * *  ****** *  
* * * *    * * *   ** ***    *  **  **   *    * **  *   **        * ** ***    ****    ** *  is not a prefix of %s", prefix, word);
    *  *******  *  * *    ***     ***  * * *  **   **** ***  **   *     *   ****   0;
   *   *  * ** *   ** ***   ** ***  * *      *  * ****
    *  *  ***  *  * *** ** 
  ****      *  ***  *  ** ***  * **   ** * * is a prefix of %s", prefix, word);
   * ** * *     *    * **      0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *   *  *** **
#include ******  *** **
#include * ***      *  * *

int main()
{
* ** ***   ****  * ****  * * * prefix[100];
 **      *  *     ** **  * *  word[100];
***  *    **  ***  * **  *** **  * %s", prefix, word);
 * *   ** * *  *** ****     *** i;
 * *  ***    * *  ***  **     *** = 0; i< strlen(prefix); ++i)
 *  **   ********* *  ***   *
    *  * * *  **** ** *  * ** *  ** *  *    * *  ** *   ****** *  *     
    *     **  ****** ***    * **  ** **  ** * ** *** *
****   *    ** *  *****  * **** * **  *  **** ***       *    * * * **  * ****  *** **** ***   *   * is not a prefix of %s", prefix, word);
  *   * ** **  * *   * ***     ** *   * * *     * ** * * ** ****** * *  * **   * * * *  *** 0;
**  ***     ***  *   *** ** * **** **** *  *  ** *  ****  
 ****  *  *  ** * *   ** 
* * **** ******    *     ***    *    is a prefix of %s", prefix, word);
**   * **** * ****  **  * **** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * * * ***     **  * ***
*  *     * **  ***  *   *
*** * *  * ****   * *   ** 

int main()
{
* ** * **  * * * char  *****
   ** ***  *** char *******
 ***  ** **  * *    ** *** *  * ** ***  *    word);
* *  **     int i;
*  * * *** * * for(i = 0; * ***   *        ++i)
  * *  *      {
           *  **   **   ** * *      *   **** *
* ****         ***  ** ** {
****     ** ****    *    ** *****   ****   **  ***** *  * is not a * ** of * ** * *** **  ** word);
*     *  **  * **  *** *  **  * **  **        *   0;
  *    *  **  * ** *  * **** }
**  *  *   * * }
 ** ** ** ** * *    ** * is a prefix of    *  ** *  **  word);
 ***  *   *** * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.95
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 11k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 10k views
12,783 questions
183,442 answers
172,219 comments
4,824 users