1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
**     ***  **  * ***  *******   
  ****  * * *   *** * *  **  * *  * * *  *  **    *   ***
    {
   *     * *  **  **  * *********   *  ***   *  * **     (i=0; i<=strlen(string2)-1;i++)
*** *** *      ** ** ** ** ** **  *    * * *****    * 
 **  ** * **    **  **  * ****  *       * ** *  **     **   *  *****  * *** * **** (string2[i]==string1[i])
* * *  * *** * ** *     *** * * *** **  *  **** * * *  ** *** ** ** * * *  * * **
   * *  *    *  *** *   *   * ***    *  *  * **    *   * **    ***** *  ** *    *** ***  **  * ****  ** *   * 
    * ** ** *     *   ** ** *  ***   ** ** **  *****   **** *  *  *  **
*  ** *  * *                * *** **  *   *   * ***  ** 
 ** ** *     * * * ******  ****** *  * *    * * ******   *** 
*   * *  ** *   ***          **** * ** ** *** *
 *  *       * * * * *       *  **  **  ***    ** ** **  *** * *    ***** ***   ****   **  is a prefix of %s", string2, string1);
  ******   *  **** * *      * * **   *  ** ***  *    ***  
 ** ***  *****  *      *  ****** *** *******  *  
  **    **  **** *  *  ** ** ** * **  **  * ** ***  **   
 ****  **   *  *     *** * * *   *     *   *    * ** * ***** **   * ***** ***** **  *    ***  ***    *** is not a prefix of %s", string2, string1);
*   ****** ** **  * *** *   * * * *** * ***    * **** 
    }
 ***** **  ** ** * ***  **  * *** * **   * ** **  ****
    {
   ***     **  *     * *  * **  *       *****  *  ***  (i=0; i<=strlen(string1)-1;i++)
 *   *  ****   * *** * * **   *** **  ******* ** ** ** * *
   **  **   *** *    * * **  *   *  * * ***   ***  * * ** *** **  **  *** *  * ***   (string2[i]==string1[i])
* *****    **** ** *  *  ** *   *  * ** **** ***** * * * * *  ** ***     ***** ** ** 
*  *     * **        *  * *** **  **** * ****   ** * *** ***  * ** *  * ***  **** **** * **  ** * ****  *** *    *   ** 
    **   **** * * **  **** * ** *  * ** * *** ****  ** ***   *  *  * * *  
* * *  ***     **** *** *  * * *   ***  *** *  
  * * *** * ****     *** *       *  **** * *  *****     * 
* * * *  **   *** * *** *  ** *  ** * **  *     
 * **  ** *** *     *  ***** **      * *   *      * *         ***  **** ** *  *****   ** ***** is a prefix of %s", string1, string2);
**    ** *        ***  * ** **** ***  *  *  **    
    ***   * *    *     *** ** * * * ********** * ** **  **
 ******* *  ** *   *** **   **    **  *  ****** *   ****  
* * **  ** * *  ****    * **  **  * *  **  **  * ** * ****   * ** *  **  *** *  ***  * *  *  * is not a prefix of %s", string1, string2);
  ** **  **  * * * ** **  **   *       **  **      ****  
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
*** **  ****     *  *** * **  *** * * *  * %s", chaine1,chaine2);
 *   **    **  *   ******** **     **    ** *   
*  * *   *    *      * ** * * ** *  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
* *** * ********   **  **  * * lenght1,lenght2,c;
   ** *  * * *  *   * ****       b[100];
* ** **** *  *   **      *****  a[100];
**      * *  ** *  ** *** *  d[100];
* **  ** * ** **   * ** *  *   * *** ****** **  
**   *   *   * ** *  **  ** **    **    ** *  **   
* *  *  * *******   * ** ** **   *  
****   ** ****     ***     * *   ** **
 ** ***** * * **    *****   ** *** *  ** **
*****   * *******  * ***  *
   ** * ***  *  * **    *   * ***    *   *  * * * * is a prefix of %s",a,b);
  **  * * **  ** * * **
 * *  *  *   * ** ***    ***** 
 * *    ******** *    **   ***
*** *   * * **** ** *******  * **  ***   *  *   *    is not a prefix of %s",a,b);
****  ** *      *****    **
    * *   * *  ** * *   *    *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *        * **     **
#include **  **  **** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
   ** *      * *  i;
 *   * * ** *     * **** ***    
  {
*  **    **    ***    ***  *    * ** *   ***    *  A[i]!='\0' && A[i]!=B[i]   )
** ***   **   * ** *** ***** * * * ** *  *  * * * *** ***   *  ****  0;
 ***** * ***     *** ******  * ***        **  * * **  *
     ***  **         * *   * ****     *** * ** * *  *    * 
  }
 * * ** * * ***** 1;
}


int main()
{
**   * * *******  ***    *** a[n],b[n],c[n];
* * *  **   *** *  *   ** ******* i;
  **   ******  * ****** *    * ****  * **    *
***  * ***  **   **** *  **     **   * **  * 
 ***  *  **   *   * *    *  ** (aa(a,b)){
 ** ** * ** *    ** *  ** *  ****    *** *  * **  * * ** *****  *
* *   *        * * *** * **    **      * *     ***** **** ***   *****     ***** *  * *** 
 **** *  ** * ***    *  ***  * **    * *  **  **    *     ** *  **    *   *   ***  * **  *  ** **
*  * ** *** *  *  ** *** * * *  **** * * * * ***  * **  ** *  **  *  ** * * **** *  *

 *** **** *** * * ***        *   * ****  *    **   *  * 
* *   **    * *  * *  *  *      ** *   **     * **** ***   *    * *    is a prefix of %s",c,b);
* *  *     **  ** * * *  ** **
      ***** * ****  * *  **
**  *** *  *      *  *   * *   **  ** * ***   **  * *  * **** ***  is not a prefix of %s",a,b);
***   ******  ** *       * ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *  * ** 
   *  * ** **  *       * ***
int main (){
char    ***  
char  * *  * *
  * ** * *  **     string1:      
  ***  ***  *  *  * * *   ****  * 
* *  **** *    string2:  ** ** *
***   ** ****** *     *
** * *  * **   * **
   **  *    *** * **    ** *    * *  ** is ** *** ** ** of    * ***      ** 
else
     **   ** * *   *  *      * *  ** * is not prefix of  ** *      **  **    

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** ** *      *
#include     * *  *** * * 
#include *    * ** *****
#include * * ** ******* 
int prefix(char p[],char s[])
{
   * **  *  * *  ** * * * * * ** ** * * ***
***** ***  * **  ****** ***   ** 0;
 ******* ** *  ***     *  if * * ** *  * * ****   
*   *  ***  *** ***  ** ** ****** 1;
  *** ** *    * * *  *** * 
*** * *   * * * *  * ** ****  0;
}

int main()
{
*    * *  * * * ** *   *  p[999],s[999];
**** ****** *** ** ***  * * *   *   *  * ***
** *  *****   *   *     ** ***  * ** *    

   *  *  ***  *  ****   *  * * * *
*** ** ** * **    * * ***** ***    * * is a prefix of %s",p,s);
 * ****  ****  *****   *
  * *** ****  * *   *    *   * *** is not a prefix of ***** * *

    * ***    *   *     * **  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **    * **  * *  ***
int main()
{
** ***  **   * * **   **    length1,length2,c;
*** * *** **  ** *****   * * * * * a[100];
     ** * ** ****  *  **    *** b[100];
* **  * **   ***  ** *  *****  d[100];
 **      **   * **** * **********  ****  ** * * * *****
* *  *   * **  * **** **  ** * ** *  ****  
*   **  **   ** **   *** ** * * **   **
 **   **  *    *  **  ** ** ***   *   * ** ** 
if (strcmp(a,d)==0)
*** ** *   *  *** ***   * *
* ******  ****   **   **   **  * **  * ** ** *     * * * ***   is a prefix of %s",a,b);
*   ** *   **     ** **   *** **
*  ** ***   * **  ***   
* * **          *  *      ***  *
****   ****     ****** ***  **** * * **   * * *** **** *  *   *** * *  is not a prefix of %s",a,b);
***  * ** * *   *******
*  * ***  * ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** ******* * 
#include  * *  * *******

int prefix (char ***  ****  str2[])
{
* **** **** ****** ****** *   length=0,  *    **
**    **   *    **** 
* * *  * * ** ** **  * **   *  * **   =  ****   *** *
***     ** *** *  *    *  * **  *
   * ***  ** *     *  * *** **   *  * * **  * * 
  *  **    *  *  *** * *****  *** **      *
** *       *  **   *   *  * *   if  *      ***
 **   *****   *   ***       *  *** *  * * * *** **      
* **   * * **    *  ***    ** *     }
 * *               *** ****    * *
 ****  ***  **** * **  (count == length)
 *** **    ***  * * ** *   ****  * *   ****  1;
*** ***     * *** * ****  *   ** * else *********** 0;  ** ****** **  
*    *    ** **      *   ** *    
}
int main(void)
{
*      ** **  * *  ** *   **      *** ** *  *
 ***     * * * *****  **
***** *   ** *   ***   ***  ****  *  * **    *  str1, str2);

*  ** ***  * **    **   * *   * * *** *  
 * **  *** * {
*  **    ***** * ***  * * *  **         *** *  * *   **** is a prefix of  ** *** * str1, str2);
 *    ** *  ****  **  **   *
**** **  ****** *** *** ***  
   *  *** ***   ** **     ** *    * ***     *  **  ***  * * *  is not a prefix of ***  ** str1, str2);

  **   ** *********   **   *****  * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *****      ** * 
#include    * *  * * *
#include   * **** *** ***

int main()
{
 *** *    *  ****  *   *     *   prefix[100];
 ****  *  *** *   * *   ****** * *  word[100];
*** *    *   ** **  **  ** ***  ** *   *  * %s", prefix, word);
** ** ***   * * * * * *   * * * i;
*** * *  *   **  * *     *****  * = 0; i< strlen(prefix); ++i)
         **      ** *  ***
 *  ** *  * ***  **  ** ** * *  ** ****  ****** * * * * *   **
**    ******* * ** ** *    *  * ******* ***   * ***
* *   *******  * ** *** * **       *    * * ****   * *** ** *  * ***  ***   ** ** * ** * **   * is not a prefix of %s", prefix, word);
  *  * * ** *** *   * ** **  ******  * ***  *** ****  **   ***   ***  * *  *   **  **** 0;
   **  *   ****  * ***   ** * * *  *******  **  * 
        *  ***  *  * * *  
  *  ******* * ** **   * ***      ** ** *   is a prefix of %s", prefix, word);
*  ** *  ** *  * *  * * ** ***  * **  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  * * *** ***  *
#include       ***   * 
#include    * *  **  

int main()
{
*   * *** *    ** **  * *  prefix[100];
* **       **** *** *  ***  * word[100];
*  * **** * **** *****   *  * *** *  %s", prefix, word);
     ***      * **  ***  ** *** i;
*  *   *   * * ***         *    = 0; i< strlen(prefix); ++i)
   ***  ** ** * ***  **** 
  **   **  * *** * *** ****    * * *  *** ** **  *** *    *       *  
     **    * ****  **  **  * ****** * *** ** *     
 * ** *     * *     ** *       *   * ** ** * *  ***   * * *** ***   *   *   ** *  **  *  * is not a prefix of %s", prefix, word);
** *     *  *  *   * * *  ***** ***  *** ** * *  ***  ******  *** *  **  * * **  *      0;
   *** * *  ** *** *     * * *   **  * **** ****  *** ***  *
* * * *** ***    ***  ** 
  **    *  ***  *  * * *  *     *  ***    is a prefix of %s", prefix, word);
    *   **  * **  *    **** *  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*       * * ****** *  
****   ******* ** * **
*   **   * * ** ****   **

int main()
{
    *   ***   char   * *** 
 **      *** **   char  * ** *
**  **  *****  *** *     * **** ***  **** * word);
**    ** ** **** int i;
**     * ****** for(i = 0;   **  **   * *** ++i)
   * **  ** ** * {
  * **  *       *  **       ***    ***   ***** *
 ***  ***     ** *  *****   **     {
***     * ** *         **** *   * ** * ** ******  * ** * **   is not a    of *  *  **    *  ** word);
** * *   * *         ** ***   *** * * *  ** *  *  0;
    **   *       * *    ***   }
 ** * ** **  *** }
     * **   ** *         * is a prefix of  * **   * **    word);
  **   **  *     * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 18.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 16.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users