1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 * * ***  ** *   * **     ***
  **  ***  * **** ***   * *    ** *   ** *   * ** **  ***   
    {
 ** ** * * * *****     **    *******  **  **  ** * (i=0; i<=strlen(string2)-1;i++)
*     * *****    * **  * ***  ***  ***   *    *   *     * *
      * *** **  ** ** ****   **    *** *** ** * *   * *** ****   *   ***** *  * (string2[i]==string1[i])
*   * * *  *  **  ** * *  *******   ***      **  * * *   *****   ***  ** ***** * *  
**  **   *** ****  * *   *  **** *      *  * *  * * * *  **   **    **  ***** * *      **  ****  * ** * * **
 *    * * *   ** *    *    ***      *   * **   * ** * ***        **   *   *   *  ** 
  **    ***  **     **  *         *     *** *  * **   * * 
** * *   ****    ** *  ** * * *   *   *  *  *** *  *  * **
* ** * * ****  * ***   ******   *   *  *   *   ** * 
** *  * *****  * ** **  * *****   **   ***** ** * * ** ***    **  ** **   *  ****    * ***  is a prefix of %s", string2, string1);
    * ***  *  **   * * * *     ****   ** **  ***** *   
 **      *  *   ***     * * **   * * *  ** ***  * *
 * **    ** **   **  *   ** **   ** * * *  * * *   *** * *
** ***   *  * ***  ***  **   ** *  **  * * *   *   **  * **** * *   *******      **   ***** * is not a prefix of %s", string2, string1);
  * * * * *********** ***  ** *   **   * ****** ***  * **** 
    }
**   * * *   ** **  *    **   *  *********  **  ** *  ** 
    {
 *  ***  * *********  *** ***** ****** * * *  *** *** **  (i=0; i<=strlen(string1)-1;i++)
*  * * ***     ***  * **  ***  *   ** *   * *    *** *     
*  * ***** *   ***       * * ***  * *   * **  ** ** ** ******** *  *** * ** *****  *** (string2[i]==string1[i])
 * * *   **  *   * **    * **    * *    *  ***   *      **    * *** *   *  ** **   
 ****   * ***  ****  * ** ** *** * * *** *  *        *  *  *   * ** * *  *  * *****   *       *** *  * * ** * * *
**** ******     * * * *  ** * *  *    *  * ** * * **   *   *** **  ****
*  *    **  * *  * * *** * **** *** ***   ** **   ****
  ******  * *  * **   **       * ** ****  **  ***   **** 
*  *   ** * * **  *  ** ** ** *   *      * ****  
* ** ** ** * ****  *  ** **   * **  * *  *  ** *  *  **   ****  **  *   ** ***  **** **    is a prefix of %s", string1, string2);
  *     *  **  *** ***  * * ****  *  * ** ******     * **  
   *   *       **  *    ** **  *   **    ***  *  **  **
*** **  *  * *   *     * ** * ** *  **     **** * * **
 * *    * *   *       **  *****     ** *  ****   ** *** **    ****  * *** * *  * ***  ** *****  is not a prefix of %s", string1, string2);
 **   **  ** ***  *** * **   ** *  *** *  ** ***  * **  * *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* * * * * ***  *    **** * ***** *     %s", chaine1,chaine2);
    * * *   * *     *   *** ** ***** *  *  * ** 
 *******   ****    * *   * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
    *  * ***   * *   *  lenght1,lenght2,c;
 *****  *** * ***   ***   *** b[100];
** * * **    ***  *** ** * **  a[100];
  *     * ****** **     * * **  d[100];
 *      *     * ***** *****       *  *** * **   * **** 
 ** *    * ** ***  *  * *  ** *  *   **    * ** *  
  ** * *  *  * * ****    * *      *
   ***  *******  ***  *  **  *** ****** *** 
* **** *** ****  * * *   * *  * **
*   *****  * *    *****  **
**   ****** ***  * ******  **** **     *** *   is a prefix of %s",a,b);
*** ***  * **    * *** *
***  * **  * *  ***** ** *  **
 * * ***  *  * * * **     *  * 
    *********   *** ** *  **    * *   ** ** *   **  ** **  ** ******* is not a prefix of %s",a,b);
**  ****  ** *** * **  * 
** * *  **** **  *   ******** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * *   **  ***
#include * ***  * ** *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
** * ** **     ** i;
    ** * ***    ** **  *   * 
  {
   **   ** * **  ** *** **   * ***   ****   A[i]!='\0' && A[i]!=B[i]   )
* ***  *    *  **    **  *   *** *   *** * **      ****   *** * **  *******   *** 0;
   **   ***  ****  * *  ****  *******   * ** * * ** ***  
  * **** **  *    ** ** * **  ***   ** *  ***** * *     *  *  ****  *
  }
      **  * **   *** 1;
}


int main()
{
*   **   *** **  *  ** *   a[n],b[n],c[n];
* ** *****  *  ****  ****   i;
 * *** * *  ********  *    * ***  **   * * *  * 
  *******  ***  ** *  *   ** * *** *     *** **  
* *  *   * * * *   **  * ***  (aa(a,b)){
**  **   *  *** * ****  *    * *  *        **  **  * *  * **   * *   
* *      *   *  **  **** *   ** *** * * *** ** *** ****     * ***  *  **** *        ** **
 ***   *** ** *   * ** ****** *  **** ****  * ******  **    *******    ** * **  * ****  * * * * *      *   *    ***  
***   *  *   *  **    **  * **  **** * **** * *  *    ***** ****  *  *** **  *   ***

**** ** *  *** ** *  ****** ** ***** *** *  * **  *   
*  * **** *  * *  ***    * ** * ** * ** *   * *  *         * ***    is a prefix of %s",c,b);
 **    ******* * *     **** *
 * *   *** *******  *****  
 **   *  * **** *  * ** * *****  * ** ** *     *  **   *     **     *  is not a prefix of %s",a,b);
 *  ***         *  *  ***  * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * *   *   ****
* **   *  * * * * * 
int main (){
char     ** **
char ***** * 
***  *  **** string1:        **
 ** ****  *****   *  * ***** 
 *   *****  string2:   *  * *** 
 * *    ** * ****  **  * 
 *  ** *  * **    *  *
 *****  *   *   ***  ** ** ** * * * * ** * is  * ** ***  of  ** *  *   **   * * 
else
*   *       *   ***   **     **** **   ****** is not prefix of *   *    * *   ****  * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***** ***   ***
#include  *  * *  *** 
#include * *  * *    **  
#include * ** *  ***   *
int prefix(char p[],char s[])
{
** ** ** * **    **     * *  * * *  * * *    
**** * * *  ****** * ** *  *   0;
 *****  * *    ** *  *  if **  * * ** * * ** ** 
* ***** **    **  * * ****  * 1;
* * * ** *  * ** * 
* ****** ****   **   * ***       0;
}

int main()
{
    ***  *** *** * *   ** p[999],s[999];
*  *** **    *  **   * ****** ***** *    **
 * ***  *  *   ****    * ** * * ****  **

* * ***  *    ******   *** *  **  
  *   ***** * ***  *** ******* **  *      is a prefix of %s",p,s);
     * ********       **
*   ** ***** *        **    *    **    is not a prefix of *  ********

  ****   * * **   *  *  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ** ***  **  **
int main()
{
 *** ** * *  **  ***  *  ****  length1,length2,c;
*  ****  *    **** *  ** **    a[100];
*    ***  ***   *   *** **  b[100];
   ***    *** * * ** *** d[100];
***  **   ** *  *   * ***** **  *     **     *
    ****  *** *  * * ** * **    * **   ** *   **  * *
*  *  * ****    ***     * ***    *  
* *****      ***   * ******** ***  *  *  ****
if (strcmp(a,d)==0)
 *  * **   * **  *   ****** *  * 
***  **** ** ***** *** *   *   *   **** **** ** ******** *   ****   * is a prefix of %s",a,b);
**   **** ***  ** *  ***   *   
 * * ** * **     ********   ****  ** 
    ** ****  * * * ***** 
* **   * ** **       ***  **** ** *** ** * *     * ***  * ***   is not a prefix of %s",a,b);
 * *  *   *  *****     ***** 
 ** *   * ***  ***  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *   * *  *****
#include * * *   ***   

int prefix (char ***   str2[])
{
*  * ***   *** * ********  *** * length=0,  ** 
 *     ** **  * ******
**  * *   ****** * **   *** =  *        *   *  
*    ** ** ** ****** **
 * ** *****  * * * **  ***  *     *  ** *   **   ****
  ** **  *       *  *****   * * *   **  * 
** ** **  *   * ** * ** *** if ** ** *   
   **       * *  ** ***       * *      ***  * *   *  * *   
* *  ** * * ** **  * * ****   *  *   }
****** *         * *** *  * **  ****
** * **   *   *     **  (count == length)
**  *  ****   * *   *   *  * **      * 1;
       * *  ***  ** * *  ** else    *     *** 0;  * * * * *   **  
*     ****    *  * *   ** *** 
}
int main(void)
{
 * * **     *   * * *       ***    **   **** 
* ** *  *  *** * * * * *
* *** *** *  *      * * *  ******  * *      str1, str2);

**   *   **  **  *******  * **    * ** **   **   
 ** * ** ***    {
***        * ** * **  * *    **   **   *   **  **   **  ***   *   * * ** ** ***  is a prefix of   ** ** str1, str2);
  ** *    *** *   * * *** *** *  
 ** * *   ** **  * ***** *
 ** *    ** *   *  * *  *     ** *  *     *****    * *  ****  * * is not a prefix of **** *  * str1, str2);

*  *   * * *   ****  ** **   *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **** * *   
#include  * **    
#include  ** *  ** **      

int main()
{
     * *** * *  ****    *  prefix[100];
  *     * ** *** ** * ********* word[100];
 * ** *  ***    *** **  *  ***   *  %s", prefix, word);
  **   *  ** *  ** ** * *      i;
*     ***    *   **  *** * *  = 0; i< strlen(prefix); ++i)
   **** * ***   *  ** * ** * 
* ***  ** ** **  ****   *** *** ** *  *  * ** ** ***  **  * * *  *  *
   * * *   *   *  **  * * ** *  **    *  *  ***   *  **
    **** **   ** ****     * *  * * **    *  *   ***********   ****** * **   **  ** **   *  is not a prefix of %s", prefix, word);
** * *** **  * *  **   ***  * * **  * *    * *** *    *  * ** * * * ** ****       0;
* * * * *****  ** *   ** *   ** * **  ****       ** **
** *    *   **        *   *** *    * 
  *     **   ** *   ****  *****  ****   is a prefix of %s", prefix, word);
 ***  ****   * ***** *** ** ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  *       *****
#include * *  **  *  * **
#include    * * * * * **  **

int main()
{
***  *****     ** *   ****    ** prefix[100];
* ** ** * **** *     **  ****  word[100];
*    ** *    ** *** *  ***  *   ** **  ** %s", prefix, word);
****   * ** ***     **   ** * i;
 * *   ** ******  **   *    ** = 0; i< strlen(prefix); ++i)
* * *  ** ****  *** * *
* ***  **  ** *  *   * * * *  *  *      ** *   **    * * *  * * ** 
**   ** ***** *  *    * **   *** * ** ****   * * * * *
 * *  *  *  *   **** *********** *****  **  **** *  *** ***   **    * *    * * ***  * **  **  is not a prefix of %s", prefix, word);
***   ****  *  *   ** * * ***    *  ***   **  * * *  **  * **  ** * * ** *   **  0;
 * * ** **** *   ** **** * *  * **   ****** * *** * *
* * * ***  *   * * ***        
**  **  ******  **   **  *   *  *** *    is a prefix of %s", prefix, word);
  * **  ** * *   ** * *  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    ** *****  *  ****
*  *  * *******   * *  
    **    *     * * ** * 

int main()
{
   *** ** *** * * char *** *
 **   *   * * char   **  *
**     * *  *    * *   *** *    ***     * word);
** *  * ****  * * int i;
*  *   *  * *   *** for(i = 0; **       *** *  ***  ++i)
  *      * * **** {
  *     *******    * *  * * ** *** *** ** **
* ** * *   *** ** *  *   **    {
*   * *    *   * ***  *    * *     * ***   *  *    *   is not a * *  of **  * ** *     *  word);
 *  **      ***** **  ** **  * * * *   **  **    *    0;
* *      ** * *      * *  ** *  }
 ** * ***    **   }
 * **  *       **      * ***  * is a prefix of  * * *   *    word);
 * *****     ***     *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.32
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12k views
12,783 questions
183,442 answers
172,219 comments
4,824 users