1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 * *   *   *****  *  ***  ******
*  **  ** **  *****  *  *** **  *  *  ** **     *  **  * *
    {
  * ****** * ***    * *  *  **   **  ** *********  (i=0; i<=strlen(string2)-1;i++)
      * *** * *     ** *  *   ***    * ***   **   * * *
* ***** ***   *  *     *** *** ** * ****** ****  * * * ** *** ***  ***    **  ****    (string2[i]==string1[i])
 *** * * *   ***   **  ****   * *   ***** **  *** *  *  * *    * *  * * *   * **    *  
* ** **      ** **         *** ** *  ** ****   *** **     *  * *   ** ***   *** ** ** **** ** *      * * * ** *** *       *
 * *  ** **  ****     *  *** * * *    *****  **  ** ******* * *  *  *   * ** *
**** **     ** *    *  ***      *  *   ** * *** **** * 
*  *  ** **  *** *  ** **  ****  * **  *  *   *     * * * **   * 
  * * **  * ***** * *  ** **      ****** * * ** 
   ****** ** **** *** *    * *  ***  ***** *   ** *   ***    * * *   *** * *    *   *  ** *  is a prefix of %s", string2, string1);
      * * **** *  ** * *  *****  *  ***  *  ***  * * *  
 * **  ****   * * *  **  **  * ** *  * * * *  *** ** **
 ***  **  * *  **  ******  * * * *  *   * *    
  *      *        ****     *   * * ****   ***  * * * ***  * *** **    *   *** **  *  * *  is not a prefix of %s", string2, string1);
* * ***      *      **   *  **   **   ****   *   *  **** 
    }
* ** **** * * ***  * ***   * * *   *  *  ****    *** **
    {
   *   *  *    * **  * ** ***   * *  *   * ** *     **** (i=0; i<=strlen(string1)-1;i++)
** *     *  * *    * **  ****  *      *  *  **   * **  
*   **** * *   ** ****   *   *  **   * * ***   * ****  *  * *****  *      *** (string2[i]==string1[i])
  *   ***  *    * * ** *** *       *  * * * * *  *   * ******   **   ** **    *   *  
  * *** * *  * * ***  ** **  * * *   **    **  ****   * ** ******   *           * * * *     ******  
 *   * ***   * **   ******* ***  *  *    **   * *     *  **  **   * **   ****     
  *  *  * **   *****  ** ****  * *    **** * * *   * **   * 
**   * ***  *** * *   ***** ** * *  * * * * *  **** * 
* ** *   * *  *   ***** *** **** * ** *****   *  ** ***   * *
 ** **** *  ********* *******  * *** ** **  *    *  **** *** * *** *** ** ** * *   ***    is a prefix of %s", string1, string2);
 ** ***   *   * *  *  *   * ** * ** *  ** ***  *** **  
  ******* **  **** ** * ***** ***  *      *    **** **
* *  * * * ** ** **   * *  *     ** ** **   *** **   ** 
 *  **  *   * * *     **  ** ** ***  **  ** ****  **  * **** ******* ** *  *   * ***  * * is not a prefix of %s", string1, string2);
 **  *   ***  * *****  **  ****** ** * **  * **     * *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
***   *    *   * **   ** ***    ** ****   %s", chaine1,chaine2);
* ** * ****  **  ** ** * * * *****  * *****   
 * ** *   * *** * *   *  **  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*     ***  *   *  * **** **   lenght1,lenght2,c;
   ****   *** ***  ***  * * * b[100];
*   **   *     ** *** ** **  a[100];
*    ** ***  **    ***   ** *  ** d[100];
 * * **  *  ** **  *     * * ***** * * **  **  
  ****  *  **    *      ** **  **** ***   ** ***** *
***** * *    *   *** **** * **         * 
  *  * *** *  **   **     ** **** ***** * 
*  * ** *  **  * *   *   ****  * *      *
**  *****  ** * * * *  *
 **  * **   **  **  ****** * ***  *** ****   *  **      is a prefix of %s",a,b);
    **    *  ** ** *     *
*   * * * *** ***  *** *         
*    **    **      ******  **
  ******      * * *  *  *   * *   **  * *      ***  ** ******   *   is not a prefix of %s",a,b);
   * ***   * *   *  *   *  * *
* **  ***  * * *  *     0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   ****  ** **
#include     * *   * * *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*****   * *** *    * i;
  ***  *      ****  * *   
  {
  ***   * *  ** *  *    * ** *** * *  * *  A[i]!='\0' && A[i]!=B[i]   )
      * **      ** ** ***  *  **   * * * * *** **  *     *       * *** 0;
*   ** *  *  ***  *** ** ****** ****    ** **  ** **  ****  
 **     *   ***** *   *     * **  * * *   *    * ***      ******* * * *****
  }
* * * **  ** *   * 1;
}


int main()
{
 * * *  **** *    * ***    **  *** * * a[n],b[n],c[n];
  *   * *    *   *  * ******   i;
***  *  **   ***  *** ****  ****** *  ** *** ***      * **  
   ** *  *    * *** * ****  *  * **  * *   * ** *  **
*  ****  ** **    ** *** (aa(a,b)){
****   *  * ** * ******  **   **   * *  *****    *    * *     * *   * 
** **  * ***  ** ** * ***   **  ** * ******  ** *  ***** *  *  ** *   **    *  *  *  *  
  *  **  * ***        *  **** *   *** ****  ***  **    * ***    *     ****   **   * * * ** ***** *    ** ***    
* ****   * *    * ** *     * *  ** *****  **   ** ****  *** **** *   **  *   *

* ******  ** *  ****** ** *  * * *    * * *** ***  *   ** *
**   *** *  *  ***  * **       ** **  *** ** **** * *       ** **  * * is a prefix of %s",c,b);
* ***  *  *   **  ***  *** 
 ****   ** *   ** *     * 
****   * ***   * *     *  * ** * * ****  ** **  * ** *  * *  * ******     is not a prefix of %s",a,b);
  ** ** *     * ** **** **   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *******  ** * *
    **     * * *** * ** *
int main (){
char * *    
char ** *    
 * *** *      *    string1: * **   
*  **   *  *  ** *******   * * *
** *** *     *  string2: **  *** 
    ****  * * *        * * *
** *    *  *     ****  
 ** **    **** *****  *  *   *     ** **  is *    *  * of  * ** *** ***   *  *  *
else
 * * * **** * *   * * **  ** **    is not prefix of **    ** *  *  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *      ** **
#include  * * ** *    
#include   **** **** * *** 
#include *  *     *   **
int prefix(char p[],char s[])
{
** *  ***  **  *     *  ***** * ***    * 
*** *** *  *  ***  **  * * ** * 0;
 * *** *    * **   if *** **** *  ***
* * *** * *    ***** **  **** *  1;
**** *** ** *** *  * *  *
 *** ** *  *** * *    * ** *** 0;
}

int main()
{
  ** *** *** * ***   * p[999],s[999];
* *     **  *   * * * *** * ***  ** ** **  *  
   ****  *  *    *** * **  ** ** *     *

    *****    *   * *    *  *
  * *  *    **  ***  ****   *    *** ** * is a prefix of %s",p,s);
   ******  *  *  * *  
***    * *  ** **** ***  ** * *** ** is not a prefix of  ******** **** 

* ** **** *** *          * * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *    ** *   * 
int main()
{
*   **   ** ** *  *   ***  length1,length2,c;
      *  * ***  *  ***** *   ** a[100];
**     * *  **    ***      ***  b[100];
  **    *     *****  *    * ** d[100];
 * **  * * *  ******    ** *      *   *** 
*    ***   * *      * **   ** ** *  *  * * *    
 *   **   ***   ****** *  *   ** 
** * ***  ** ** **   **   *  **   *   *  ** 
if (strcmp(a,d)==0)
 **  *** **   * *    ***
*** * *****  **   ** * * *******  * **** *******  **   ** * * *** is a prefix of %s",a,b);
* ***  **** * *       *   ***
  * *  **** ***** ** * *   ** 
 **  **     ***    **  * * * *
  ****** *  * ** ***** * *  * *  * ***   **  *   * * ** ****  *  * **  is not a prefix of %s",a,b);
*** ** *    *  *  * **  ** ** 
** **      * * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  **** * ****
#include   **  * ** *     ***

int prefix (char    *    str2[])
{
 ** **  ***  * * ***     ** length=0,  **  * 
  *** **** *  *  *** *  
  *** *  * * **** * *  * * * *  *  = *  ***    **  **
* **  * ***** **   ****** 
 *  ******* ** **  ***  *   * * * **  *  **
*** *** **       ** **   * *****    **   *  
 ***** *  * **     ** **   * *   if *    *     
   ***   *****     ** **          *   ** *   * * *  *    *  
**  **  **  *  **** ** **** * **    }
 * *  *           ** * * *** *    * ***
* *  ** *** * **     ** (count == length)
***     ** * **   *  *** **  ***    * * 1;
**   ***  * *  ****   *   else   * **    0; **   * * ****  *
 **     * *      *****  * ** * 
}
int main(void)
{
 *   * ** *     *    **** ** *  *** **  **  *
    * *******  * ** *   * 
 *  **** * * * *      *  * *  ** *   * ** * str1, str2);

* * *** **  *  *   *  *** * * *** * ***    
  * *  *   * {
  **  **  *   * * ******  * *  *  ***  * *   ***  ** ** **   **  *   is a prefix of   **  ** str1, str2);
   *  ******   *  *   * *
*  * * ** ***  *      **      *
***  **   **  *   *  **  **** *** **    *    *** * ***  *****  * is not a prefix of    ****  str1, str2);

 *******   *** *  *  *  **  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * * *   ** *  *
#include  *  *  * ***** *
#include  *  *  **** * * 

int main()
{
 * *     * *   ** **  *   * **** prefix[100];
  *** *** *   *****  ***   ***  word[100];
   * **  * *  ** ** * ****  *       *** * **  %s", prefix, word);
 *   *  *** **    * ***   * i;
 **      **  *** *** **** * = 0; i< strlen(prefix); ++i)
* **   **   **    * ******  * 
****  *****  ** *  *** *  * * *  * * *  **** *  * ****  ** * **** * *
  ** * *** *  * *  * *   *** ****  * **   *   **  
* ***   *** ** * *****  * *    ****  *   *     ** * * **  *  **** ** *   * *  ** ***  ***  *** * is not a prefix of %s", prefix, word);
  ***     *** *  *     ** ******* *****  *******  ** ***  *** * * *  * ******   0;
 *  *******  **  * *   ** **  **  ** *  ** ** **   *  *
 *  **** ****   * **  *   **
  * **** ****   * **   * ** *  * is a prefix of %s", prefix, word);
**   *** **  *       *   ****  * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ** *** ****
#include   ** *** * * ***
#include ****** *** ** *  *

int main()
{
 *  * *** *  **  * *       * **   prefix[100];
  ** *  ***   *   *  *     *  word[100];
   **     **  *  *  *   * *         *  ** %s", prefix, word);
    *** *     * *   *      i;
   *** *    **   ** *** **  * = 0; i< strlen(prefix); ++i)
 ** **  * * ****  * * ****
 **    * * * * *     * *   * ***** *****    *   * ***** ** ***  * ** 
* *  *  ** *  *      ***  *     *  *  **** ***** * * *
** ***       * *        **** * *****  * ** *   *****  *** **     ***  *    *** **** ***** ***  ** is not a prefix of %s", prefix, word);
   **  ** *      *  *  **** *  * *****   *  **  * * * * ****   * *  *  **  *  * 0;
 * *  *  **** *** *   ** ** *****  *** * **** ***** *  *
 **  * *         * *****
* ** *****  * ** * *  **** * * * **** ** is a prefix of %s", prefix, word);
* *   *** *   * *        * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *   **     * *  * *
       ** * *** 
******  *** **    *  *  * 

int main()
{
 ** ** * *****    char     *** 
***  *   * * *  char  *  *
 * *   *  * *   ** ***   * **    ***   * **** word);
*  *   *    * *  int i;
 * *** *    ** **   for(i = 0;  *   *      * **** ** ++i)
   *    *   ** {
     *     ** ** ***    **  *  * *  *** ** 
**  * *     *      *      {
  ** *   ** * *** **  * **   ***  ****  * *  * * ** ** *  * is not a * * * of *** ** *   *   word);
   ** *  *  **    ***       ** *    **  *  *    *** 0;
****    ** **  *  *   **  *  }
*  **      * *  }
******* **  **  * * *  *****  * is a prefix of **  **** *  *  word);
** ***  *** * *    *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.204
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 14.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 13.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users