1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* ** ** **   *    **** * ** *
   ** ***   * ****    * **** *  ** *  * ***    * ** **
    {
  *  ****  *  ** **** **  **** * * *       *    *  *  (i=0; i<=strlen(string2)-1;i++)
** *   ***   * ** * *** *  ***** * *   **   ***   
*  * *****     *****  *   ** ** * * *  ** *** *****   *  *  * * *  * * *** **   * **  (string2[i]==string1[i])
*  *  ****   * ****  ***   *  **   * *    * *  ***  **** *      * ** * * *       * **  * ** 
 **    ** * ***  * **** ** **  ****  * * * ********* **     *    * * **** *****  *    ***** ** *  ****  * * *  *  
**  *  * *     *    * ***    * ** ** ** *    ***   * **  **** *  ** ** * ***      ****   * ****  
 ** * ***    *  * * *   *   ***** *   ***** *  
*  * *  *** * ** *  * ****  *  *    **** *   *** * ****   
 *    **  *  *  * *****  *  ****     *    ****    *  * * *  
*  ** ****    * * *  * ** **** **   * **  ****  **  * *** **** *  **  *  * *** * **     ***  *      is a prefix of %s", string2, string1);
  * *    **   ** *  *   **   * * ** ****  * * * *** *  * 
 ** ** * * ** *    *  ***  * * * *** **  * * *   *   *  *
*   *** **     **   **** ** * ** ****   ** ** *  **** ** 
    * ** *** ** *** *   **  ** *** ** *     * ** *  *    * ***  ** * **   ** ** *  ****  * ***** is not a prefix of %s", string2, string1);
****  ** **** ****** ******  * *   **    *  *    * *** 
    }
  ** *** * ** **** *  *  *** *****    *** **    *     *
    {
** * ****** ***  ** * **    * ** *** *  *  ** *    *  (i=0; i<=strlen(string1)-1;i++)
   *    *  * * *** *  * **        ***    **  ***  
 ** *  *  * *  *   * *    * ** *  ****   **  ** *  *  **   **  *** **   * *   **  *** *  (string2[i]==string1[i])
   **    ** ***  ** * * *   *  *** ***  *   **    **** ***** *  *   * ** * *    *   
 ** *  * *  *  * *   *  * * ** ** **     *  *** **      **    *** ***     *** *   **   ***  * * *** *  *** ** ***      
*  ** *** *  * *    * ** *** *  ** ** *   * *  ** *   * * ** * *   *   *   *  *   ***  
 * ***  ***    * * ** *   ***  *      ** ** 
 * * **** ***    *     ***    *    *  *   * ***  ***  ***   *
** *  *** ******** **   * **  ** **  ** * * *  *** *  *** *      
*** * ***  *  **    * **  **   ** ** **** * * ** ****   ***  *** * *  **  *  *** ** ** ** * ** * is a prefix of %s", string1, string2);
  ** **** *   * *   *  ***  **** *   *   ** *** ****  * *
*  **** **   ****     *  ****** *   ****  *  *  **  * *  ***
  * * *  ***    *****     ** *********  *  ** * *   ** 
* *   *  **  * * * **** **** ** * *  ****  ** **  * * *  *   ** ****  *** * *   *    * * * is not a prefix of %s", string1, string2);
** *** **** ****   ** * *** ** *    * * *  **   *** ** ** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *   *   *    *  * * **       **  * **** %s", chaine1,chaine2);
**   **** ** *  ** * * ** *** * *  * *   * *
    * **** * * *     **   * *  *  ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
* * **** ** *  *   *     *   * lenght1,lenght2,c;
**  * **     ** *       **** b[100];
  *  ** * *      **  *  ***   a[100];
    * ****   **** ****    **** ** * d[100];
 ***     *** **     * *  **** ***  * * * * *      *
      * ***     * ** *   ** *       ****        ** 
  * * *** ** *** * *  *  *    **  * ** *****    
* ** **   *  **    *  * ******  * *  *
*    *      * ****  * *     ***   ** 
  *   *** **  ***   * ******
*  * * *     * ****  *    * **  ** * *   ** *     ** is a prefix of %s",a,b);
*** *  * ***    *  ***  * ** *
 *** *** *** **  * ******* *
* * ****   ** *** ***** * *** 
 ** **** *         *  ********  * **** ** ** * *****   **  *  *  ** *** is not a prefix of %s",a,b);
******     *   **  * ** 
**   *   * *  * **  * *  *    * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **       * *     
#include   * **** **     *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*** *** *  ** ** i;
 *  *   * *** ***  *    ** 
  {
 *** *  ******    *****     * * * *  **** *  * *   A[i]!='\0' && A[i]!=B[i]   )
 ** *** **** ** **** * * ** ** * ****  * *    **  *** * **  **    **** 0;
 ***   * ***   *  *   * ** ***    * **  **  *** *** * ** *
**** * *** *** *    ***    ** *** *   *  **      *  *  ** **  ** ***  ****
  }
    *** **    ** 1;
}


int main()
{
**  *** *   * * *****     ***   a[n],b[n],c[n];
**    ** * ****  *    ** *  * i;
 *  ** *   *  ******** * * ** * *   **     * * *****
  **  * ** ******   ** ** * *   *** **** * * * 
 **  ****   **    ****** * * (aa(a,b)){
* *     **  * * ** *     * *  * ** * *  * *       *  *    ** ** *  ******
   ** * **     **    ** **  *  **  ****  *** * * *** * ** *  * *  *   *****    *   *  *** *
 *   ****** **    * * ** **   ** ** **  *   *   * *******      **** ** *  *   *** *** * ***  *  *  * ***** ** *   * *   *     **   
   *  * *   **** ****  *  ****** *       **     * *   **    ***     * ** *  ***   ***

*   * * ** *  **       **** *** **   *  **  ***  * ***
 **  *****  * **   ***  *     **** *** ** ***   ** **** * **  ****  is a prefix of %s",c,b);
**** ****   ** *     ***  ** *
    **    ******  *** ** ** * **** *
**** **  * ** * * * ****  * ** ***     *   *     **** **** *** ****   is not a prefix of %s",a,b);
***** * *   *   *      ** *  ** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  * **** * **  ***
***   **  * ***  **  *
int main (){
char  * * * *
char  **    **
 *** ****   * string1: ** **  
 *   *****  *  *  *           * * 
 **** * * ****  string2: ** **  
******** **  **  *  *  
 *** *** ******  *
*     ** ***  *   *     ** *  * is **** ****    of **      *     *  * * 
else
   ***  ***   *     *   * *****  ******  is not prefix of  *    ******** *  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** ****  *   
#include ***  *  **  * * 
#include * *  * ** *  ****
#include *      *  ** *** 
int prefix(char p[],char s[])
{
 *   ** **  ***   ****** *   * *****  * 
* ***** * *** ** *** *   * ** 0;
 ** ******* **  ** *   * *** if * **   *     *   
** ** *     ***    **** *    * * * ** 1;
*    ** *** *  **  **  *
* ***  *   *   * *     *    **  0;
}

int main()
{
 **  * * *** * **** **  * p[999],s[999];
*  ** *  ** *  * **  ** * *  *      *
*   ** * ***   ***    * * *  * ********** * 

  * *      **   *** *     * ****  
** * *        * ** * *****    **  * * *** is a prefix of %s",p,s);
 ***    * *    *    **    
* ** *********** * **  *  ** *  * ** ***** is not a prefix of *      * *

* ** *** * * **** *  *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * *  **  *   *** 
int main()
{
   ** *     * *  *** *   **    length1,length2,c;
  *****   ** ** ****** * ****   a[100];
  ***  ***   *  **     * ***   b[100];
 *  ** **  *   *      * *  *  * d[100];
*    ** * * * **  ** *  *** *        ** * * **
* * * **** *  *  *   *     *****  *  ***** 
  * ** *** *   **   *  ****     **  **
* * * ****** *   **** * * ****   *    **    ** 
if (strcmp(a,d)==0)
   **  * **** *   * * * * 
*  *  * **  * *** ***   * **  **    ***  ** *  **** **   * * * *    * is a prefix of %s",a,b);
  ***  **    ** *  *** *** *  *
   ***  *  ** ***    * ** * *  
**    ** **          *    * *
 *   ** *  **** *** *  * * ** **  ** *  *** *  * *****      ** *  is not a prefix of %s",a,b);
*   *** ** * **   * **   
*       *  ***  ***  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   **  * *   *  *
#include   *   **  * 

int prefix (char  **    str2[])
{
 *  *  * **   *       *** ** ****   *  length=0, * ****
*** ****       *****  ** *
  ****  * * **   * **   * ***** =   *  * * * ***
 ****    ******** *   
  *  ** *     * ***   ****   *  ******   ***  **
     *     **   * *****  * ** ** **** **** *  
**   *****   ** * **    *  *  if ** ** * *   
**  **    ***  *   ** **            *  * ** *  ****  ** **  
*       * **   **  ******** *    }
 ** ** *         *** *****  ***  *    
** * ** *  *  *** *       **  (count == length)
   ****** **    *  ***   * ***  *   * *** *** ** 1;
* **   ***** *******   *  *  else   ** **    0;  ***  *****      *
 *****     *** **   ***  ** 
}
int main(void)
{
 *****   *  ** ****  **   *   * * ** * * *  **
 *  *   *   * **    ***  *    
* *  **** ***  **  ***** *  ** ******      ** * ** str1, str2);

*   *   *  *  *** *  *  *       *        *  
   *  **      *** {
* ***  *  * ***  ** ** *  ** *  **     ** * ***  * *  ** *****  is a prefix of  *    *   str1, str2);
***   **  ***   *  ***    *** 
  * *  * * * *  *       * ***
      **   **  ** ******** *     ** * * **  ** * *  ***  *****  is not a prefix of     **  ** str1, str2);

 * *    *** **  **  *   *        * *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   ****** *  
#include   **  ** * * *
#include   *** *** **    *   

int main()
{
**  ** ***  **** *** * * * *  * * prefix[100];
 *  ** *  ***** ***  * *   word[100];
 ******   ** **    **  **      ** *        %s", prefix, word);
  ********* * ** * ** *   * i;
*****   ** **  ****   *   * ***** = 0; i< strlen(prefix); ++i)
   *  *  ****  * ****    ** *
****** *      ** * * *   ***   * *   **** *   *  **  *****   ** *    
 ***   *     *** *  * ****   ******   * **** * ***   
 **** *  **  *  * ** * *    *    *  * *  ****** ******    **   * *** **    ** **     ***   is not a prefix of %s", prefix, word);
     *  **  *  *  *   * * ***********  * ***  * **  ***  ** *   **       ** ** * *  * 0;
*  *   *  ** ***  * *** *   *  ***  **  * *******   *
 *  * *      * ** *  ** *
   *    *  *  * *  *      * *  * ** ****  is a prefix of %s", prefix, word);
******** ** * *  * *   *  ***   *   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** *  ****  
#include  * *  * *** **  
#include  *  ** ********  *

int main()
{
   *******   **** *  *    * ***** prefix[100];
 **  ***      **** ** ** *  word[100];
* ***** *****  *     *  * * *     ** %s", prefix, word);
  ******   * *  * **  **   **** * i;
  * *      *    *   ** *  = 0; i< strlen(prefix); ++i)
 * *  ** *   *  ** * ***  
**       *** ***  *** ***** **     *  **   ** * ** * * *** ** * ***   *
* **   *       *    **  ***  ** *    ****  * **   * **** *   
   *  * ** ** *   ** * * *** * * ** ***    **   ** ***   **   *  * ** *   ***    * * *  * ** is not a prefix of %s", prefix, word);
*  ***      * **  **  ** * ** * ** ***    * **** ***   **    * * ****  ***** 0;
 *** *  *  ** *** *  *****  *******  * *** ** *    * 
*** * ** * *      ** *      
 * * *  * **** * ******** * *** **      * * is a prefix of %s", prefix, word);
  *   ******  * * * ***  **   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***** * * * ***   *   *
    *    ***    **   * 
****   ***** *  *    ** *

int main()
{
**      ****** char   *****
   **  * *** ** char   *   **
**   *  *   ***   *  *** *  * *  ***    *    word);
*    * **  **  ** int i;
 *   **    * for(i = 0;      * **    *    ++i)
*   ** ** * * {
  ** * * * **    *  * * ***   *   * * *      *** *
*   *   *  *    *            {
   * *   * ****  *  **  ****   **  * *** *  **** **  **  * *      * is not a *   of ** *  *  * *   word);
 * *  ** ***  ****** ** *  *  ** **  ** * ** 0;
 ** * *    ** *  * ***       ** }
* * * ***  ****  }
** * ***   * *  **    * *****  is a prefix of ** * **  * *  * word);
* * * ****  *     0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.129
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users