1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include     **    ** * * 
#include  *  *  ***** * *
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#define n 100
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}
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Hidden content!
#include ****** *      *
 *    ** *  * ***  ** 
int main (){
char * *  *** **
char  * * * 
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include  **   **** * ** *
#include ***    *** * 
#include * *** * *** *   * 
#include *  *** ******* 
int prefix(char p[],char s[])
{
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** *   **  * ** *   **   0;
}
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Hidden content!
#include <stdio.h>
#include      *****  * ** *
int main()
{
**** ****  * *    **  * length1,length2,c;
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}
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Hidden content!
#include  ***** *******  *
#include * * * *** *** ****

int prefix (char   *  * str2[])
{
  ***     ******* * **  *  length=0,      
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***  ** * *  *    ***  * ******* 0;
}
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#include * ** *  * * ** *** 
#include   * ******   *
#include   *** ** * ***

int main()
{
* **   ** ** *** ***  ***  *  prefix[100];
******   **** *       ***  *       word[100];
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*  **    ** ****** **        * 
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  ** ** * *    * * *  ***** *    *  *      is a prefix of %s", prefix, word);
* * ***   * * * ** *   ** * **** ** 0;
}
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Hidden content!
#include   * * * **  *   **
#include   * * * *     *
#include **  * * ** **  

int main()
{
* ** **   *   *    *   ****** **  prefix[100];
** * *  ****** **  ** *  ** ****  word[100];
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 *  *  * ***  ** * **  **      = 0; i< strlen(prefix); ++i)
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**   **  ***  ** *       * **** *** *   is a prefix of %s", prefix, word);
   ** **  *   ** *    * *  * 0;
}
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* ****  *  * *  **** *  
 *****    ** ** *  ****
****   ***   ** *   

int main()
{
* * *****  * **    char   * *    
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  **  ** *  *  }
 ** ***   **  * ******  ** ** is a prefix of * * ***      *  word);
**  * * * * * ***  0;
}
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