1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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{
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}
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#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
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}
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Hidden content!
#include ****   *  * 
  * **  * **  *  ***  *   *
int main (){
char *  * * ***
char      * **
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include *  * *****  **
#include   *  **  * ** *
#include  *  *****   * *** 
#include ** ****** *****  
int prefix(char p[],char s[])
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* **     *     *******  0;
}
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#include <stdio.h>
#include *  ****** *  ***
int main()
{
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}
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Hidden content!
#include ******   * 
#include   * ***   ***

int prefix (char  *****  * str2[])
{
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 * * * ***** *    * *         * 0;
}
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#include  *  **   *  ** 
#include *****    *  * * **    
#include ** ** **  *** ** 

int main()
{
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 *** *  * ** ***     * ****** 
*      *    * *   *  **          **  ** ** is a prefix of %s", prefix, word);
*     ** ****     *   * *   ** 0;
}
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Hidden content!
#include * *  ** ** *  *
#include *  * *** **  * **
#include    * * *      ***   

int main()
{
 * **    **** *** **  *** prefix[100];
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* *** ****  * ***  **  * **  * *  is a prefix of %s", prefix, word);
   * * * *  * **  *   **** *  *   0;
}
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* ** ** *     *  **  **
* ***  *   *   *** *   
      *  *** *  *** *

int main()
{
** * *  *    * ** char  * **** *
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  ****   *  *   *  0;
}
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