1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* * **    *****     * * **  *
*   *  **   **   **  ** * ** ***   ** ***  * *** *      
    {
***  **** *** ** ***** * ********** * *  *  * ** **      (i=0; i<=strlen(string2)-1;i++)
****  * * ***      * ** ** * ***  *    * *** *****    * 
** * ** **  * * *    *   *   *     ** ***  * *      * *    ***     *  (string2[i]==string1[i])
 *   * **    **  **** * **   ***  * ** *   *** * ***** * * ** **  **    * **  *  
 *****  ** ****   *    * ** * **  ** ****  **     **** **** ****    *  * * *     ** ****   * *     ** ***  * 
  * * *  * ***  *  * * **   **  * *  ***** * **  ****   *   ***** * *** ** * **** 
* ***** *** ** **      * * *      *  *     *  *  *   *  
* **** **     ** ***   *  * * ** *  *** ******        **  *
 **  ***  *** * *     *  * *   *   *  *** ***  ** ***
**  *  *    * * *  **    * * *  *** * *   *    * **   **   *** **** *  *  * *  * *   *** *  is a prefix of %s", string2, string1);
* **       *   *** **  *     *  ***** *** *  * **
**  * ***  *** ***   *   * ******   **    *   *** *** ****  
 ** ** **  *   **   *   ** ** *  ** *** * * *** **     ** 
*  * *  * ** *  * *** **   ***   *  *   ***  ***    *** ***** **    * *   *  *  * * ** *  * is not a prefix of %s", string2, string1);
   *****  *  *** * ****  *  ****    * * * ***      *
    }
  **  ** **** * *  **         * ***   * *** **       *** *
    {
**  * * **   * * *******     **   *****   * * *** ******** (i=0; i<=strlen(string1)-1;i++)
 * * *   ** * *   ***  *  *** *  **  * * ** *** ** ** *
  *   *   ** ***  ***  ****** **  *** *** * * **  * * ** * *    ** *    *  ****  (string2[i]==string1[i])
* *   * ****  *   *** ** **** *   ****    * **     * **   *   * *  * ***
  *  *    *  ***  ***        ** ** **           ****    * *** **  ***  **** *  ****  **       * *     **   ***    **** 
** ****    * * *  *    ***       *** *   **    *   ** *    *       **  ******** * *
  ** *** * *   ** * *  **   * *   **  ***  *** * *  * * 
 *****  *  ** * *** ** *       ** **   *   *** *** **** ****  * *
* * *    *  * *   *    *  **** *     * ***   *** * **  ** * 
* *     *     *  * **        ***    **  **   *** *  **  ***  *   *    * *  ** ******* **  **   ****    ** is a prefix of %s", string1, string2);
 ** *  * * * *   *    *     *    *  ** *** *   **    * * 
 **    *  *******   * ****     *    * **  *     ***  *   
 **      **  *** *****   * *  *****        * ** * ** *
*   ** ** ***  *      *** ******* ** * *   **     *  ** **   * ******* ***   **   ****  **** is not a prefix of %s", string1, string2);
* * ** ** *** **** *  *****    * ****    ***** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *  * ****    * **     ** *   *   ** %s", chaine1,chaine2);
 *****  *      **  * * ********* *   * *** 
 **  ** **  *****     **    0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 **   **    *     *** **  lenght1,lenght2,c;
  **  ****         **  * ** b[100];
***    *  * * ** * *** **   *** * a[100];
** *        *   *****     ****  d[100];
*  *** *  ** *    ** *  ********   *****  ****
*  * *   ***  * * *  ***  * *  **   **  ***    
 ** *** *   * *  * ***** *  **    *** * * *
* **********    **** *****  *  ***** *   
   * *   *** ** * *** **** ** **  ***  *
**  * ***  * *    ***
***** ****      * *     * ** **  * *  * * *   ** is a prefix of %s",a,b);
   *   **** * * *  * **** 
 **      * *   * *    *******
    ***    ***  ****   *   
  **  ***** * *  ** *     * **     * ** ****** ***    * * * ** is not a prefix of %s",a,b);
     * *  * ********** ******
 * *  ** **  **   * * ***  ** ** *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include     *   *  **
#include ****** *   *  *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* *  *  * *** * i;
 ****  * ** ****  *  * * * ** *
  {
 * *** *   *  *      **      * *** *  **  ***  A[i]!='\0' && A[i]!=B[i]   )
*      * * ****** *******  *   *   * * * *  * ** ** *  * * *  *** *  **   0;
* * ** ** *  **** * *  *    * ** *   *  * **  **  * * *
**   ** ** ** *      * * * * *  ****    *  *   *  *   ** *   ** *  ** 
  }
****  ** ** * **** 1;
}


int main()
{
* *  **** *    *** ***** * * **  a[n],b[n],c[n];
**  *  *   ** **** ** * **** * i;
   *** *******  *   *** *** *   ** ******** ** * * 
  **** ** ** * *  *   **   ***  ***** ****** ***
**  *  * * * ** * * **** * *  (aa(a,b)){
**** ** *  **   *     *  **  **  * * *  *** * * *  * * ****** *  *
     **    *** ***   *  ** *     * ***** *  * **  **    *       *    * *    *  **  ** * *  *
*    ***   * **  ** * ***** ***   ****  **  ** *** * ****   *  * *   * **  **     * * *   * *** *     * ******
 * *  **  * *** **   ** * ***   *** **       ***  * * *  **  * ** *  ***  *** **  

* * *     * ******  *** * *  ** **  *  ****  *    **** **  **
 * **  *  *  *  **  *  **  ** * * ** * * * ****   *** * *  *  * *  is a prefix of %s",c,b);
**     *** *  **  ***** **** 
  *****   *** *      ***** **
** *  *  **  *** * * *** **  *** **   ***   *  ******  * ***  is not a prefix of %s",a,b);
*  ***  ****  ** ** * ***   *  ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * *** * ** *** 
* * * *   * * ***** **   
int main (){
char **  *** 
char  *  ****
 *  * * *    * string1:  **    
** **** **    *     ***      **
    *  *******  string2:    ******
*  ** ***** ***** ***  **  **
* ***   * ***** *   **
 * * * * * *  *  *******  *  * * * is * * **  *  of  ****  **  ***     
else
**    ** *    *  * ** *        ******   is not prefix of *     * * ** ***** *  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     **  
#include      *  * *   * 
#include    **  ***  ***
#include   **   ** ** * * 
int prefix(char p[],char s[])
{
**   * *  ***  * *** *******  **  *   *  
**  *  *   **       * *** *  *** *  0;
** * **    **    *   *  if  *** *  * **  * *   
 * *  ** * *  ** * * *   *    * 1;
* ** * * *** *   *       
 * *** *  ***  *     *** ***    0;
}

int main()
{
  * ****  * *  ** *** p[999],s[999];
   ** * * *  *  **    *  ** *  **  * * * 
****  * **   * *  * *  *  ** ***** ** ***

 *  ** *** *  ** ** * *** ****
   * *  * *  *  ***    * ** * ****   is a prefix of %s",p,s);
 ***  **** **** *   **   **
**** * ** *  * **** * ***   ******  ****  is not a prefix of    *    *

*  **       *  * *  *  ** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   * **     ** 
int main()
{
*    *** * ***    *  **  * length1,length2,c;
*     ** *       **** *   **  a[100];
    *** *****   *  *  **  ****** b[100];
** *   * ** **  * *** ***  d[100];
*** *** ** * * * ** **** * *   * *  ** ** * *  * 
*   ** *   **    ** **   *  *  **** * *      *   * 
  ** **  * *   * ***   *** **** * *
  **** *  *  * **** **** *   *  **   ** * * 
if (strcmp(a,d)==0)
***  *** ** * * * **   **  ** **
**   **  *    **     * * *  ** * ***  ** ** ***    ***  **  * *     is a prefix of %s",a,b);
****  *  ***  *** **** * **
 * **  ***   ** * *    *** 
****  * *  *****      ** ***
* ** ** *    *  *** * * ** * * * * ** * *  *    * *** * * *  *  **** * * *   is not a prefix of %s",a,b);
*** * * *****  *  **  **  ** **
  * *****  * * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * ***** 
#include  ***   *    ****

int prefix (char *  *      str2[])
{
  **** *   *    * * ** *  *  length=0, ******
***  *  ** * *    * 
*** ***   ******* *** * * *  *  =  *****  * ** *
 *    *** *****  * ***    
*** ***** *  * *   ** ** *  **  **  *******
***** * * *   *** *******   * **    **  *  
 * * *    *  * *** **     * if ** *  *** **
***** ****         *        ** *** **        * *  **** *   
*   *      ****  **   *   * ** **     }
 *  * **          *** **         **** 
 ** **  * *  *  **   *  (count == length)
 ****** *  **   ***      ***  ** *     *  1;
*** * ** **  **  *   *  ***  else **   *** 0;         * * ***  * **
***** *      **   **       * *  
}
int main(void)
{
* *  *   * ** ******  *  *********  *         *  
 **   ***** *     * ***** *  *
****  ***  * ** ** *  **  * *** *      ** *  ** str1, str2);

*  *    ***  **** * **** ****  ** **  **** *
 ****  *   ** * * {
    * *      * *  *****    * *   ** ***** * *  * ***       ** is a prefix of ** * * str1, str2);
 * ** ****** * ** * * ****  *
 **  * *  **  **** *  ***
***  * *  * **   *  ****    ** *  ****** * **  ******** * * is not a prefix of    *      * str1, str2);

** ***  **   * *  ******* * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** **  *  * *
#include *  *** *   *** **
#include *   **  * **  ***

int main()
{
   *** * ** * **** *   * *** prefix[100];
  ******* ** * ***  **    * * * word[100];
* **  ****** **  *  *** *   *    *  ***  %s", prefix, word);
*  **   *** *** * * *****  *  ** * i;
  * ** ***  *** * ** ** * = 0; i< strlen(prefix); ++i)
****  **** * * ******* ** 
  ***  * *   ******  ***  * ** *         ***** ** **** ****** * * 
**** * *  ** *  **  **    * **** *   ******* **   * 
 *    *** *  **      ** ***    * * *  ***  **  * *      * *    * * *   ** ** ** is not a prefix of %s", prefix, word);
 *  *****    *** ****   ** ***  ****       *  * ***    *    **  *  * **** * *  **   0;
*  *** *  * * *  * * **  * *  ****   *****  **
**    * *  * *** * * * * 
** ** *** *** *** *** * **   * * **   **** * *  is a prefix of %s", prefix, word);
  *  * ** *  *      * * *     0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * * *****  
#include *   * * * *  * 
#include ****  ** *****

int main()
{
* * ** * * **  * **  ** *** *   prefix[100];
* **   ** * ** * ** ** * *  ** word[100];
**   *** **  * * *     *  *  **      %s", prefix, word);
 *   *  **    * *** *  ** *  * i;
 **** * *  * *** *** *   *****      = 0; i< strlen(prefix); ++i)
 *   * * ** * *  ******** 
 *   * **  *  **** *******  ** * * * **   ***  **   *   *  *** **  
**     *   * * **  **  ***** **      *    *  ******* **
  *   ***   *  * ** *** ** ***  **      * * * **    ***  *  **  **  * * *  *  * * **  is not a prefix of %s", prefix, word);
*  * **    ****** * * *    * * ** *  ***  *   ****     * **    *       **   * ** 0;
 *  *  *** *   *  * *      ********* *  **  *  *  **  
 *  *   ** **  **** **  * *
* *  *  * ** * *   ****  *   ** *** is a prefix of %s", prefix, word);
 ** *  *  ** *****  *      * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***  *  *  *  * ***
  *  **** * ***     ***  
    **   **  *****

int main()
{
 *** **   ** char **    * *
*  **     * **  ** char   *   
*  ***  *  ***   *  ***** *        * * * * * word);
 *   ***   *****  int i;
*  ******  ** * for(i = 0; ** * ** *   *** ** ++i)
     ** * * * {
* * **       * * * ** *  * ***  ***** * * *
 *    *****   ***  * **   **  * ** {
   *      **    *  ***    *  ***  **  **   * *  **  ** * ** is not a ***  of ** ***   *  ** * word);
*    *   *   * *  **    ** * * *   *  *  *   *   **  * 0;
**   **    * * *********    * *   }
****     ** * }
**  *   ** * **    is a prefix of  **      *     ** word);
**** **    * *  *   0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.176
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users