1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
    * * ** ** * *   ****  *  *
   *   *** ** **  **   * ** *  **  **** *  ** ***       **     
    {
** * * ** * *  * ** *      ***    ** **  *    * *** **** ** *   (i=0; i<=strlen(string2)-1;i++)
*  ** **** *    *   * ** *** * ** * * *  **** ** 
**** *  *** *     **  *  * ** **    ** * ****      ** * *  ** ** ** *** *** ***  (string2[i]==string1[i])
 *     ******  *    *** *  * **** **      * *    *** ** * ** * * **  *   ** *   *   **
   **  ** ** *  * *****  **    ** *   *   *  * * ***   * **    * * ******   * *    ** ***  *  ** *  * * * * ** * *
 *** * *** * *      *****   *  ** *** * * ****    **** *  * ***** ** ********
* *** * *** *   ***  **********  * ** **  * ***** **
** * *   **** * ****  *  **     * *****  *  *** ** **      
**  ****  ***       ***   *****  **  ****  ****  ** *  
**  *   *         *     ** *   *    * * ****  *** * **       ***   **   ** **  *  ***    is a prefix of %s", string2, string1);
  ******** *  *** **  ****   **  * *** ****  ********* **
 * ** **  *  * **   *** ***    **** * *****    **   *   * 
*  **   * *  **   *  *     *  * ** *  * ** ********  ** *  
**  ***     * ***  ****   ****** ** *  *** *  *  * *** **  * ** ** *   **** *  ***  *   **   * **** is not a prefix of %s", string2, string1);
**** **       *     * ** *  ** **** *** *     * **
    }
*  *       ** ** * *** *  * *   * ***  *** *  **  *  **  ** 
    {
** ***** ****** *** **  *   ** *  ****   * *     ** **   *  *   (i=0; i<=strlen(string1)-1;i++)
  **  *   *   *****  * ** ** * *  *   * * * *****  *   *
 *** *  * ** * **    ** *** * *    * * * * **  ****** ***  *   *   * * * * *   (string2[i]==string1[i])
**   * *    *****   * ** ** ***    * * * ** ***** * ***  ** *  ****  *  ****    *   
* * **    * ***  *  *   * *  * * * *     ***** * ******   **  * * **** * ** ** * ****   *  **      * *   ***  
**** *     ** * *     *   *  *** *****    *   *   **** *  * *     *  
 *   *  * *  *** * *   * * ** ** * ***   ****  *     
* **    * *    *  **      *    *** * ** * ** * *** *** 
**** * *** ** * ****    * *   *   * *  *  **  **
   *       *  *  * *  ****    *  *  **   * *  *  *           * ****  * ***    * ******** ***  *  *   ** is a prefix of %s", string1, string2);
* *****  *  *   *  ****** * ****  *  ***  * * * * *
  *  * *    ***  * *      **    **  ***  *** ******** 
 * * * ** *** * ** ***** ** ** *    ** * **  ****** 
  *  ****  ***  *     * * * * ***  *    ***** ***     * * * *** * *** *   **        *  ** **  **  * * *  is not a prefix of %s", string1, string2);
  **     **** **   **   * **  ****  *   *  * *** * ***
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
  ***** ** ****  * * **     * **    * ** *    %s", chaine1,chaine2);
** * ******      ** * ***   * *   * ***      *
* *  **  *****  *   * *** * * ***   0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  ** * *** * ********  * **     *  lenght1,lenght2,c;
   **  *** ***  ** * * *   *** * ** b[100];
* *******        *  **    ***  a[100];
 ** *    ***   **** * **  ***  * d[100];
*        **  *  * *** **  * *  ****  **  ***   
  * ***   *   **  * * ***  *** * * * * **     * *** *  
    ******       *    *** **** * * * * 
* * ****   ***    *   ***   *  *     *  ** *
** *    ***  *  ** ** **  *    * *     *
*   *** *   *** *   **  *  * 
 ***  **  *  ****  ** ** ***  ******  * * *** **   is a prefix of %s",a,b);
 *****    ****  * *** **
***  **   ***** * * *  * ** **
******* *    * ** *    **** *
 *** * * * ***** *** *  **  * * ****     **** *   * *    ** **  * **     * is not a prefix of %s",a,b);
  *** ****   ** * *    * 
   **  *   *    ** ****    *    *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include     **  * ****
#include  ***  ***      
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*  * *  *  **    i;
** **   *    ** **     * **  ***
  {
*  * *  **  *  ***** * * **  **    * ** *** * *  A[i]!='\0' && A[i]!=B[i]   )
 *** *  *   * *******       * *  *** *   *   * ** * ** * ** **  *  * 0;
* ** *  * ***  *   *    **  * * *     ** *  *** ****    *  
**  **  * *   ** **   *  **  * ***     ***** *    ***** * *    * * *   * * * *
  }
 * *     ** * * 1;
}


int main()
{
** * * * ***    *  ****  **     a[n],b[n],c[n];
***** *  * * *  *      * **** i;
******       *** *  **** * ** *    **  *  ** **    
  ********* ***       **** *     ***  *    ******   **   
* * *** *  **  *   *   ******  (aa(a,b)){
 *******   ** *     *****    *  **  * * *****  * *      ****    
**   * * * * ** *  *  **     *  ** *** *  * *****  * * * ** * ***    **   ** * *   ** *****  
*     *** ******  *  ***   *  *  *            ** *  * * *     *** **   *        *    ***       *     * *** *
** *    *  ** * *** ** * **  *  **   * * *** * *  *****     * ** ** ***  **       **    *

*  **    ******  **  ***  **     *      **   **** *** * 
** *****  * *  *  ** * *  ******   * ** *  *******  **  * * ** **   is a prefix of %s",c,b);
   ***   * * *  **** **** 
 * *   *  * *       * ** ** * *
  * **     ****  ** *  * * *** *  * * *    *** * **  ** ***  **** * is not a prefix of %s",a,b);
***    **  ***  ** * * *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     ***   *
 * *     **  ** * 
int main (){
char *****   
char  *   ** * * 
****   *  ***  string1:   **** *
*   ***  * *  ** ***** * ***    *  **
  *    ***  * *  string2: * * 
 * **** ** ****   * * **     *
** *     *  ** *****
**   * *** ***  *** *  *  * *   * **   **  is ***   *  of * * * ***  ** **  
else
* *   ****  * * *** *  **   **     *   is not prefix of *   * **** * **** *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  * * ***  *
#include *  *** **   * 
#include * ** ** * **** * 
#include * **** ** **** 
int prefix(char p[],char s[])
{
     * * * * *  * * ***  *  * * *  ** * ***
 ***** *  * * *  **  * *****  * ** 0;
*   *  *** *  **  ** * if ****  *   * * *** * 
 * **       * ** ** *    *******  1;
*** ** **  ******  * *
   ****  ***** **** * *  * ** * 0;
}

int main()
{
** **   * ** *  *** ** ** p[999],s[999];
 *    *  **  * *  *** **   *** ***** **
*   **  *** **     ** * *  **  * *  * *** 

 ** ***  **      * * **  ***** 
* **** *   *  * ******  * ***  *   is a prefix of %s",p,s);
**   *  * ***   ** ***** 
* ***  * *  * **   *  * *     ** ** *** * is not a prefix of ** *** *  **

***   **  ***** * **  * * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   * ***   *  *
int main()
{
***   ** * * **  * ** ****   *  length1,length2,c;
***    *  **  ** ** *** * *  a[100];
* ***  *  * ****   *   * * **** * b[100];
   ***     ****  * ** *  * ***   d[100];
   * **   * *** ****   **    * ** * * * **** *  
 *****  * * * *  ** * * * ***          ** *
*   * **  **  * *  *  *   *  ****** 
** * * *  * ****     **  * *   ****  *
if (strcmp(a,d)==0)
 *    * * * * ****  *     *  *  ***
** *** *    **  * *** **** ** * * * *   *  **  * ** ******** * ****   is a prefix of %s",a,b);
     * *  *    * ***   
* ***  * *** *  **** **** *** * * *
 *** ** *     ** ** *    * * *
***   **  * *    * *  ** *  *   *  * ***   **    ***  * * * ***  **  is not a prefix of %s",a,b);
** *   ** *   * *  * *   
* ** *    **** ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ** *   * **
#include *   ** * **   

int prefix (char ** **   str2[])
{
*** ****    ** *    *** * *  *** * length=0, **  * 
 *    **** ***  * ** * 
  ****  * * ** * ** * * ***   = *   *  ***** *   
** **  **** *** ** * ***  *
 ***  * * * *   *  *  *  * ** *  ***** ***    * **  
*  **  ** ** ***      *    ** *  *  *** **
 **    *      *   *     *    *   if * **  *     * 
*  *  * *    **  *****        **     *  ***      **  **   
* **   ** *     * * ****** *** ****   }
*     ***            * * * *   * *** 
** * * *    ***  ** ***** (count == length)
  * * ** ** *  **  ***** * **   * *     ** * 1;
*  * *      **   **   * * else *  **     * 0; **  ** * ***  *   
     *    * *    ** ***  *** ** *  
}
int main(void)
{
   *   * *** *** ** ** *****      * * *****  * **
  * ** *  * ****   * *** **
 ** *  * * *  *      * ** **  *  ** ** **  * * *   str1, str2);

 *   ****** *** * * **    *  ***   * **  
 ***   *   * **  * {
      *** * ** ***** * **             * *    *****    * * * * * *  ***  is a prefix of  ** **  * str1, str2);
 *    * **  *  ****  *    *  
* * *** *      *** ** ***    ***    *
 * ** * *  *  * *    **  * *   **  * *******   * * *     * ***  **     ** is not a prefix of *  * *** str1, str2);

   ** *     *  * ****   ***  ****  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   ***   
#include   ***    * **  ****
#include       ****  *

int main()
{
** ** * *** *      **  **** **   ** prefix[100];
*   * *   **    *   *  **  *  word[100];
  ** ** *  *** **    *   *  ***  ****  *** %s", prefix, word);
     **********    *** **  * ** i;
 *** **  **** * * **** ** ***** ** = 0; i< strlen(prefix); ++i)
      *     * ** ***  ****
 ** * * ***     *  * * *********  ** ** ** *** * *     ** *   * *   *    * *******
***** ****     * ***     *** * **  *** *** ***  ***** ** ***
  *   * *   ***  *  * **  * * *****  **     * *  **  ****   *    ** ****** ***** * *   is not a prefix of %s", prefix, word);
 * ***** **   * * *  * * **     *   *     **  *   **  * * * *  * *  **  **   * **   0;
   * *     ***   * * * * *** *    *  *    *****        
 ****     ***  *******  * *
* *  *   ***    ***** *****  *  *** is a prefix of %s", prefix, word);
* *   * *  **  *  **** *  **  *   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** * * * ***
#include * *  * * *      **
#include * * ********* 

int main()
{
 * ***  ** ** *    ** *   **  prefix[100];
   *   * *    ****** ** *    *** word[100];
  **   *  * *     * ************** * *** %s", prefix, word);
*   *    ** **** ****  * ** **  i;
 ** *  ***    *   ***   **    ** = 0; i< strlen(prefix); ++i)
* *** * ***   *  ****** *  *  
* ** ** * *** * ** * *  * *   ** ** ** * **  * * **  *    * ** *     *  
* * * * *    ** * *   *   ****  *    *  ***  *  **  ** **
*   *  ** * * **** * *  *   * **  *   ******  *  **      ***   **     *  ** ** **** *     **** * is not a prefix of %s", prefix, word);
* **** ***  *  * **** ***   *     *   ** **  * * *       ****  * ******* * *  ***    *  ** 0;
      *  **    * *  * ******  *  * *  **** ** *** *  
***  *** *    *  ** ****** * 
* ***   *  *  *          *      *  *** **  * is a prefix of %s", prefix, word);
 *** ** ***** ** * **  ** **  **   * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ** *   *   * ** *   * 
****  * ****** *    ***** *  
*  * * **       ******* *  

int main()
{
* *   **    char ***   
 ***    ****  char * * 
*  * * *  ***   *  * **  **  * ****** ***  word);
*****  ** ** int i;
* *         * for(i = 0; *     * *  ** **  ** ++i)
      * **  * *     {
   *    ***  *   *       ** **   *   *   ******
 ** *    * **   *        * **  {
* **  *    * *   **** **   **    ** ** * *  *     ** * *     is not a   *   of     * ***  * * * word);
*   *  **    ** *   ** * * * * *   * * *  ******     * ***** 0;
**** ****   *   ***   *****    }
*** * *  ** }
****     *  ** *   * *   ** * is a prefix of    ****   **  word);
* ***   **    *  *  * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.197
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users