1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*****     *    *** * *  *   **** 
* *  *  **    *** ****    * ** * * ** *      ***    **   
    {
   **  ** **  ****  **** ** *   ** **   * **     **  * (i=0; i<=strlen(string2)-1;i++)
* * *** ** **   * **  * * * ***** **   *  *  **** *******  *  
****  *  ****   *  ** **  *  *  *   *  * ** *     ***** * * *** ** **  * *   * ** ** * (string2[i]==string1[i])
* ** ***  *   **   * * * ** * *  **     **   *  ****    * ***      *   **   **** 
  *** *  ** *    *    * *     ***   ** *     **       ***    *   * *     **  *    * * ** ***  *  **   *  *   *  ** 
  ****** **** *  * * *  ***  ** ***** ***** * *   *     *           *    *** **  * *  ** *  
***  ** * ***  * *****  * * *  **   * * ** ** **  *  * ** ** *
 * ** **       ** * ** * ****  * **** ** * * *   *    *    
 * *   **  * **  *** ** **    ** ** * *   * ** *** *   ** * **
 ** *** * *   * *** *   *  * * *** *   * * * ***   * * ***** *       *   *        ** * ****    is a prefix of %s", string2, string1);
*  * * *  ** ** *   * * * ** * * *** * ****   *   *  
*** *** ********   ***** * *** **  ** **    ****   ***
     *   **** *   *  *** * *  **** ***   **  *****
*    **  **** ** **** *   **    * *  ** ***   **** ****  * * **  * * * * *  ** **  * *    is not a prefix of %s", string2, string1);
 *  * *  *  *****  ****  * ** ***  * *    *  * *** *****
    }
  ****   *    * *  * * * * * ****  **   *  * ******
    {
**** * *   ** *     *  ****    ** *** **   * **  ***   *  (i=0; i<=strlen(string1)-1;i++)
* **  *** ***   ***** ******      *    *  ***    * 
  * ** ****   *  ** * **  * * * *  * ** ** **     *  **  **  *    * *  * *  * *  **** ***   * * *  (string2[i]==string1[i])
 *  *    *** * * *** **** * *  *  *  * *** * *** *    **  ** ***   *  *  * 
 **  ***   ** *****   *** **  * ** *      ** *  * **  *  * ***  ****   **** ** *  * *  *    **** ***     ***  
* *     **     * * * ***   *  *  ****          ****  **** *  **  *** *** 
 *** ****    **   *****  * ** *  * *   *** * ** *    ** 
    **    **   *  *   ***** ****  *  * *  ***   * *         
*  **  **   *** *****     **     * *  ***** * * * ** *   
** *  * * ** **  ***** **** *    **    ******    *    *   *     *  * *  * ****  * ** ** * * ** is a prefix of %s", string1, string2);
**  *   *    *  ********   ****** * *** ***   
*     * * *   ****  *     **        **    **     * * * 
 **   *  **    *   *    *    ** * ***** ***  *  ****  ** 
***  * * *     * *   **  ** * * *    ** * ********   ***  *  ***    **  * *  ** *** ** * ***  ** *  *   is not a prefix of %s", string1, string2);
*** ** * ** ***   *  * * ****  ***   * *    **  * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   * *   ***  ** *  ** * **   *  * **  *   ** %s", chaine1,chaine2);
      ****  **     **   * *  * * * * ** * ***
  ** *  * * *  **  *  ***   0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*  ****   * *    ***  ******** lenght1,lenght2,c;
 *   ****  * *  ***  ** *  * b[100];
* ***  *      ** ** ** *  ** a[100];
*  * * *   *** * ***    *  * *  d[100];
*   ****     **  *** **  **   ** * *   * ***
 *   ***  *** ***  * **  *   **  *** *      *   **
  *** *    **    **   *   * * ***  * ***
**   *  * * **  **** **   ******  * 
 * * ** * ** *    **  * ***  * **  * *
  * **   *               ** * 
   *** ***  ** ******* ****    *  ** *  * **  *   * * * is a prefix of %s",a,b);
  * *** *  **  **    *** *   
* *  * * *   ** * * ** **  * **
 ** *  ***** **  *   * * 
 * ***  *   **   **** *****   *  ** *     ** ** ** * * **     *  *  is not a prefix of %s",a,b);
*   ***** *   *  **  *       
* *  **** * *** *  *     ** ** * ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * ***** **** 
#include      *** **   
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
**  *   ***    ** i;
 ** **   ***  ********  * *   * 
  {
**  ***** ** **  ** ****   * *  ****   A[i]!='\0' && A[i]!=B[i]   )
 *  *  ******   *    *  ******  ** ****   * *     ***    ****   * ****   **  *  0;
*   * *   ** ** *****  * ** *  **  ****  *    ** * * **
* *  * ***  *  * ***  ** * ***   *   **** **** * *    ***  **** *** ** *** * 
  }
**  *** ***  * *  1;
}


int main()
{
*  **  *  * **  **  * * * **    a[n],b[n],c[n];
     **    ** **  ****  **** **** i;
*     ** *  **    *  *   * ***     *** *** **  **
* *** * * **   ****   ****   *   * ****  *   ** *   *
***  *  ** * **  ** *  * **    (aa(a,b)){
 * *  ** * *    ***     *    ** ** * *   **  *  * ** ** *  *  * * *   
* *     *   ** * *** **   *   *  * **** **   ****** **   *  *  **  *  * **    *   **** ** *  
** * *   ** * * *   *** ****  *****  ***   * ** * ** **      ******  ***  *    ***  * *  * ** ***   *  **  *  *
 *  *** *** *  *  **  *  *** * *  * *   *   ****  ***       * ** *  ****    **  * 

*** ****  * *  *** *** ***   * ** **  *  * ** *   ****  **
* * ** **      * * **  **  *  *  ** *    *** *** ** *  **** ** * is a prefix of %s",c,b);
 ******   * * ** ***   * *    
 * *    ** * *  * ** * *   *
* * *  * * *  *     *  *      ***  * * ** **    ** *   * **      * **  is not a prefix of %s",a,b);
   * * ***** *  *******   ****    * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   ** *  * **
  ***      *   ****  **   
int main (){
char *  *   * 
char **    
** *   ***** * *  string1:   ***
  *      *  * *  *   * ** 
 *  ** **  ****  string2:  *  *  * *
 *   * * **** **    ****   * 
* * ** *** **   * **** *
*  * **  * *  ***   * * **** *   *   is   * **** *  of *** **      * *   *** *****
else
*    **  *** ****  *** **  **  *    is not prefix of **    *  * *** * **

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * * *** **  * 
#include **   **  * *  * *
#include  **    ** *
#include     *  * * ****** *
int prefix(char p[],char s[])
{
* * ** ***  **  * *   * *  *  ***** 
  ***     * *   *** *   * *    *  * 0;
** * *    * ** * * * *****   if  ** *   ** * **
  *  **********        * *** * 1;
   * *** *  ** *   *** *
**** *     **   **    *    ** * 0;
}

int main()
{
  **  **   * *  * **  ****  p[999],s[999];
*   **** *  ***   * ***    *  **   ** * **
  * ****   ** ******  *****  *   *         ***

* *  *  * * ***  *    * ***  * *
***  * **  * **  ** **   **** ****       ** is a prefix of %s",p,s);
*** * *****  ***  * ** *  *
**   *       *  * *  **   ***** **** * *  is not a prefix of *** **  **

**  *  ** *** **   ***   *  *** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ******  *     
int main()
{
* ** **   *** ** *  ***       * * length1,length2,c;
  ***  *  ** * ***    *** * * * a[100];
****  ***   **** **     *   b[100];
  *     * *** ***    **** **  d[100];
 ***  * * * * *** * **  * ***  *  *       *  **
 ***  **  *  **** *  **** **  **  **    * *   *
* *     * * ** **  ** ***    *     **
**** **    * *  *  ** ***  * ***  *      *** 
if (strcmp(a,d)==0)
*  ** *   ** *       *  **
 * **   * *   * * * **  *    *  * ***  **    * *    **** ** ** is a prefix of %s",a,b);
 **   **  **  *    *     
    * * *      ***   * *  **  * 
  *** * ** * *    * *      
***   ** ****  **    * *   *   *****    * **  **** ***  ** ** **  is not a prefix of %s",a,b);
   *   ** ***   * * ***** ***  
 **   **** *** *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *   **  *** ** 
#include * ** ***** **** 

int prefix (char     ***  * str2[])
{
***** ***     *** *** ***  *  **   length=0, *******  *
*  ** *  *** * * * 
  *  *  *   *    ** ** *     * =   *****  * * 
*  *** **  **  **** **   
*  ** *     * *** *** *     **  * *********  *  * 
*   *     *     * * *  * **** **** ****
** * ** *  ******   *   ***    * ** * if   * *  ***  *
** ****  **    ** **  *        ***   **** * * *****  * *    
********    **   *     **  *     **  *   }
*   ** *          * **  *     * ***** 
 * ** * *** * **   *   * (count == length)
**  *    ****  ***  * ** *** *******   ** 1;
 **  ***** *  *** ** *  ** ** * else *     *   ***   0;   ** * **   ** *  *
*  **   ***** * ** *  **      
}
int main(void)
{
** **  * **  * ** ** ***  * * * *   **  *
** *    * ***  ** *** ***  
*  **  * *   **  *  * * ** *  *   *           * * str1, str2);

*  ** ** * *   **    **   * * ***  ** * * * 
** *    ****   {
*  **  * *  * ** ***      **    **** *   *  **    *      * ** *** * is a prefix of       * * str1, str2);
*** **  * * * **  ***    ** *
 ** ****   ***  **  *  ****  
 *   ****  **  * *   * *   ****   ***    *** **   *  ***  *** ***  is not a prefix of *       *** str1, str2);

***  ** **  * *** *  * *   *** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  * *** ****  * 
#include * *    ***** *** *
#include   **  ****  *   *

int main()
{
** *   *   ******* *    ***   prefix[100];
*     **** **** **    *  * *** word[100];
   **** **   *** *** **   ***     * * ** %s", prefix, word);
   ****  *** *** **** * **** * i;
***   **      **  *   **  ** = 0; i< strlen(prefix); ++i)
  ***  * ** **   **    ****
*  ***   * * * *    *   ***  *   *  ** * *****  *    ***  **** *  **   *     * 
    *   *****  * *** ****   * *** ** ** ***   * **  **  *   **  
  **   *  *   ** *   ** *  ** * ** *   ******* ***        *******     ****** * ** * * * **** ***   is not a prefix of %s", prefix, word);
**    **  * *  **  ********  *      *** ** ***       **  * **  *  * *** **  ** * **** *  * * 0;
***    ** ** ** *    *** *****   ** *  * ** * * ****   
  * ** *** *** *  *   ****   * 
 *  **** ** * ***    **   * ** *** ***  * is a prefix of %s", prefix, word);
**   * * *     * *   ** **** *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *    **   *
#include * **  * *  ** **   * 
#include  * * *  * * ****

int main()
{
**    *** *** *  *** ****  * *   prefix[100];
     * ***  * *   ** * * * ** *    * word[100];
* **  *** ** *     *****   ***** *    %s", prefix, word);
  *  * * **** * * *    ** *** *  *  i;
 *** *   *  * ****     * ****  = 0; i< strlen(prefix); ++i)
  *   **** *   ***     *  *  *
*    *     **  * * ***        ***** ****  * *** *  *  **  **  *** **     ***
  * *  * ** ** **  *  * *** * *   ***   ** * **    * * 
    * **** ** ** *** * * *  * *   * * *****  *** ** *****       ***** * *     ***  **   **  is not a prefix of %s", prefix, word);
   **  ** **  *    **      * *     *   ****** ****    * ** * *      *   ****  * ** 0;
*  * *    *   **    * * *  **     *  **   * *  ***** *
*     *  **  ** *  *   *  *  
 * ** ** *   *   *** ***     *   *  ** is a prefix of %s", prefix, word);
 * *** *   * * ***** *** *   * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**    ***** *  ** ******  
***** * *  *** * *   
 * *    ** *   * *   

int main()
{
*  *      *** char * *   
 *        * char * *  *
    *       * *     ***  * **  ***  *** word);
* ** ***  *  *  int i;
 *** * * ** for(i = 0; *** * **     ++i)
 * **** **  **  {
*  ** *  ****  *   *    *  **  **** *  **
**  **         *  * ** * *   *   {
  **      ***  *    ****  ******  *** **    * *      ** ** **  is not a  *** of ***** *  * *    word);
* **  * *  *  **      **  * ***  *  **  * ** *      * * 0;
 *   * * * *      **     * *  *  }
            *  ** }
*****  *    ****   **   ***   is a prefix of  * **  *    *  word);
    * **    ***  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.194.162
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 12.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.3k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 11.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users