1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 * *********** * ****       * 
*   *****   *** ****** *  * *** *** **  * *****   ** *
    {
*  *  **  * * ****  **      *  ** *  *    ******  * ****  (i=0; i<=strlen(string2)-1;i++)
*   *  *   **** **  ****     ** **     ** **** * ** **
 ** ******     *** *  *  ***    ***   ****  ***  **   ** **  * *  ***** *  ** * **   (string2[i]==string1[i])
 * ** *   * *  *    * * ****** *  **    **  ***** * *** *  ** *  *** *      *   
* *** ****    *   **** * *  *  **** * * * **     *****  ***  * *     **   * *           *  **    *** * *  * 
 *  *  ****     **   * **  ***  **** ******    *** *   ** *** *****      * *    *
* *  *****  **** * * * * *  ***** ** **    *  *****  ** 
   ****  *   **** ******** * *** **     **    *  ****    
* **     ** ***     ***    **   *      ** **  ***    *  * 
* ***  **    ** *  ** **    *    **  ** *   *    * **  * ****  * ***    ** * * *  ***  ****  is a prefix of %s", string2, string1);
  *  * ****     *     *  *   ****   **   ** **      ** **
*  * *  * ****** * *  * **   *** ***     ** ********   
   *    *****       * *** ** **** **    ***  * *  
 *****  *      **  **** *  * * * **     ***  **** **  *    *  * **  ** *  * * *   * **** **   is not a prefix of %s", string2, string1);
     **** *   **** *** **    ** * *** ***     ***** * *     *
    }
**   *    ******* * ** **  ** * ** ******  *** * ** * * 
    {
         ****** ******   ***   *     *  ***** *    ****    * * * (i=0; i<=strlen(string1)-1;i++)
 ** *  * *** ** *****  ** *****     *  **   * ** *  
 *  **  * *** ***** **** *  ****   *****  * *  **     *   *  *  ** ****** *** *  *  ****   (string2[i]==string1[i])
 * **** ** **    *  * * *   ** ******* * ** * ***********  * * ****** * * ** * ***
   *** * * ** * *    * * ***   *** * **** ***      *  **    **** **    **  **** **** *   **** *  *  *      *
*  ****   ***** * * * *  * * * * * **  **** * *  ** *   ***   ****   **   *
***** ** *     **  ** * * ***** ** **  *****  * **   *****
*  * *** *     *    **  *  * ** * **  *    ****    ***** **
*   * **** *    *  ** *** *   *  ****  ** ** *  ******   
* *  * ** *    * ** **     **  ** **** * ***  ** *  *** ******** * **  * *** ** ** **   ** is a prefix of %s", string1, string2);
       * * ***     * **** * * *   ***  ********* *
    * **  *   ** *   *  ** *   **** * *   **  ** * 
* ***     **  * ***    ** ** * *  *** **     * *** * 
    *** * ** **           *** ** * *** ** **  *  *** ** * * *   ***   *     ***   *  ****     **    is not a prefix of %s", string1, string2);
  * ** * *    ****** *  * *       *** *** * ** *****  *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
    *   ** *****  *    *****  ******  %s", chaine1,chaine2);
 ** **  **  *   ***      *    ***   ** 
****  **  ***      * ** * *  *   * ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
    * ********** *******   ** **  lenght1,lenght2,c;
* ***   * **  * * *** * **** b[100];
 * * ***** ** *   *** **** *   ***   a[100];
*   *   ***  * ** **  * * * ****  ** * d[100];
 * ***  *   *** *    ***  **   *** **  **  ** ****
 * *** * ** * * **  ****  ***    **  ***    *  *   *
*      * ** *   ** *  **  **   *   **** * 
*     ***     **** ** * **   **   **** ***  *
 *          **    *  ** ***   *  *  * * 
* ***  ** *  * ****   ** 
** ** * *    * ** *  *** **     **  *   * * * ** ****    ****   * is a prefix of %s",a,b);
* ***** ** ** * * ** **   ** 
** ** * ***    **   ** *  **      
***   ****  *    *    *    *   *
* *   ** **** * **     *    *   * * *  * ** ***** ** *  **  ** is not a prefix of %s",a,b);
 **      ***** *  ****  *
 * * * * **   *    * * *     * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   **   *   * * * 
#include     ***  * *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 ***  *  **** * * i;
**  ** *  *  *   * *   * *   ** * 
  {
  * **    **  **  * ***  *     *** * * **  *   A[i]!='\0' && A[i]!=B[i]   )
*      *       ***  *  **   * *   **  **  **   * **      **   ** * ** * ** 0;
  * * *   ****   *  ****  *     *    * * *** *** ***
 **   **   ********* * * **   * *  *** *   **  ** * * *   * *  *****   **
  }
* *** *   ***  ***  ** 1;
}


int main()
{
** *  ***** *  *      *   *** a[n],b[n],c[n];
** *    ** *      ** *     *** i;
** ****   * *   **  * * *   *     ***** *  * *
**     *    ** * **  ******* *****  * * **  * **  
**    *  * * * * *    ***  ** (aa(a,b)){
** * * **  ** *  * ***** ** ****** ** **  * ***  ** **  ***     ** **   
 **    * * *  * * **   ** *** ***   * *    *** *    * *  * ** *  * *    *** ***   *** * * 
 *  *      *    **** ** * *   *    * ***  * *** ***   *  * **     **         *** *   **  * *      ***** ********    
*  * *  *  ** * **** * ** ** *****   *  * ** * *  *** * ** **        *  

*    **  ***  ***   *   **     *** **    *   *** *
*  *   ** *  * * *   *   ** * **    ** *   ***         * ******* *** * is a prefix of %s",c,b);
  * * ** ***  ** *     **  
*    ****   * *** *  * **
     *****    *   **  * ***  * ** *  ***  *     *    * * ***    * is not a prefix of %s",a,b);
*  *   *   *  **** * *** *** *   **   * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *****  **   **
 ** ***  ** *  *  ***
int main (){
char    **
char  *     ****
* *** * *   **   string1: ***
   * * ***  ****** *   * *  * ****   
***     *  ** * string2: **    ** 
*   * *** ****  ***  **  ** 
    * **  ****  ** *   
*  * * **     *  **** ***   ****   *    is    * **  * of   ****  ** ** ****  **
else
** * *   ***** * **** *** * *   **     is not prefix of     ***** *  ** ** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *      *****  * 
#include   ***  * *    **
#include **   * ** ****
#include    **** ***
int prefix(char p[],char s[])
{
** *  *****  * ***  ** *   ** *  ** *   *
**  *  ** *    ** * *** * *  *  * 0;
    ** ** * *  *   *     if       **** * ***  *
** * * * *     *** *   *  *   ***   1;
**  ** ** **   ******
* * **  * ** *  * *  *  ** * 0;
}

int main()
{
* **  ** **** **       p[999],s[999];
   *  * * **  * *** * *** *  ***  *  *
    ***** ** **  *   **        *** *********  ** 

***  *** * *   ***  *  ** 
   ******* *  *  **  ***** ***** * **** **** *  is a prefix of %s",p,s);
 *   *  * ** *** *** **
**      ** *****  ***  * *** * ** *  ** is not a prefix of  *  ******* *

***  ********    *     **  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *     ***   * **
int main()
{
** * * * * *****   * * **  ***  * length1,length2,c;
*   *    * *** * *   ****  *   a[100];
   ***** **   ** * ** ***   * *  b[100];
**  ** ****  * **** ***  * *   *  d[100];
  *        ***** *  ****   *  ** * *   **    ****     *
***** *         ** *  *    * * *  * ******** *    *** 
** **** * * **  *** ************ ******* *
*** *  *    *  * **   *  ****       * ***** *
if (strcmp(a,d)==0)
*   **  *** * **  ** ***  *  
*  *  *       ****** ** * ** * ******** *** *     *           is a prefix of %s",a,b);
** *   **  ** *  * ** ** *   *
* *     * * *    **  ** * * 
   **   **  * *** * * **   *  ***
 ******* *  *****  ***      ******** * ***  *** * *** ** *   *** is not a prefix of %s",a,b);
* *** *** ***** *   *  *  * ** *
******  *    * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   ********* 
#include  ****        *   

int prefix (char  *  * str2[])
{
** *    * *      ***    * *    length=0, **   * *
*   *  **  ****     * 
 ** * *    ** * * * * **  = *     *   ***  
 **  * ***   * *  * * * *
  *  *** ***** *       *** * **  ** ** *
 *     **** *  *  ******   ** ***  * 
**    *      *   * * * * * if   * ** ** *  
**   **** *    *  ** *       * ****** * ***   * ****   
 **    *  ****   **  *****     *   }
* * ***           **    * * * ** * ***
 **       *   * *  *** (count == length)
 *  *    * **   *** *    **  ****  *****   1;
** *  ** *           *  * * **   else  *  ********  0; * **       * ** ** *
**    * ** *****   **     * ** *** 
}
int main(void)
{
 *** * * ***  *****     *   **     *** * *
* * * **** * *   ****** **
***  *** ****  * *  * *  * *** *  ****** * **   ****  str1, str2);

  *    **   *****  * *  ***  *   * *  *******
   * **  **  * {
    * ***       **  *  **** * ** ** **    ** ***   * *** **   ***  **** is a prefix of **  * * str1, str2);
   ***  *** **** ** * ***   **
 ***  * * *  ***** * ***  * 
 ****   ***    * ** **    **  *****   **** * *    *   * is not a prefix of  **** ** str1, str2);

 *  * **** ****         ** *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** ** *  * * *
#include   *******    **** 
#include ***** *** * * * *

int main()
{
 ** *  *   ***  * * *****   * prefix[100];
   * *** **  ****    ***** *   *****  word[100];
*  **  **   *     *      ** ** *  *** * *  %s", prefix, word);
 * *****  ***    *    *   i;
 ** * *** ***  * ** **   * *    ** = 0; i< strlen(prefix); ++i)
  *****   * **** ***  * *  *
   *  *  * *  ** **   ** ****  * ******   *   *** **       **    ****
  ** *  *    **  *    ** * **  * * **       ** ****** **
  *  ******   *** *  *  *   **    *  **    * ***  * * *  **     *** ****   ** ****   *** * * is not a prefix of %s", prefix, word);
 ***   *    *** *** * ** *   * *****  *** *    * ****    ** ** ** * ** *  * 0;
 *    * *** ****     ** * *  *  * **   ** * * ****** * ***    *  
*   *  *  * * ***  * *** * 
   * *  *  **  **    *  ****  *   *   * *  is a prefix of %s", prefix, word);
*  *   ****  **  * *  * ** * **** *    0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * **** **
#include   **  **  **** *
#include  **    * * *

int main()
{
 *  * * *   * *   **  ** prefix[100];
*      *   * **  *   *   word[100];
* *    *     **** *  * *  *  *  ***     %s", prefix, word);
*** ** *  *** * ** ** *** *  *** i;
 * ***  **         *  **       = 0; i< strlen(prefix); ++i)
 **  * *   ** *  *  ***** 
  *  * ***  * **  **  * * *****   ***   ** **  ****** ** *    ****      
 *****  **   *   *  *    * * ** ** *  *****  * * * * *
    * **   * *  * * *****  *  *  ***  ** **** *  *  * *  *     * * *  *  *  * * ** *** *  *** *  is not a prefix of %s", prefix, word);
** ***  *   ***  **         *  **** * ******    ***  ************   * **** **   *   *** *   0;
     ***    *** **  **  *    ****** **         *  **
       * **      *   *   ***   
 ** ** **   *  *  **      * * *** * *   is a prefix of %s", prefix, word);
   *        ** *  **  **      * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***    *  *  **  **
 * *     * **  * **
* **  * *  **         **

int main()
{
 *** *   * * * * char **     
   **  *  ** *   char   ***
*** *    * * * *  * * ***  **        **     word);
 *** *  * * ***   int i;
* ****   ** **  for(i = 0;        **** ** ++i)
  ***  * * ** {
 ** ***    * **   *   *    **   **** * ****   * *
* *  * *     ** *  *  ** **** {
   *  **   *** *   ** * * *** **    * *   * * *  ** *  ****  *  is not a    of ***** * *     word);
   **  * ***** * *     **  ****   *     *** ** *     0;
 ***  *    * *  *** **     ***  }
**     * ****  * * }
* *  **       ***    **  ** *  is a prefix of   * * **   * ** word);
* *****   ***       * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.111.116
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 9.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users