1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
   **   * **   *** *   * * 
*     *** *** **** **    **   **   *        * *  *   *
    {
  * ****** *** *    ** *  ** ** *   * **   ***   *   * (i=0; i<=strlen(string2)-1;i++)
**** *******    **  *  * * *  *****  * **  *      *  **
   **** ****    *** ** *    *  *   ******* * *    * *** ** * * *  * *** * ******  ** (string2[i]==string1[i])
  ** *  * *  *  ****  * *  **  * * * *  *****   * **  * *     *  ** *    * * 
** ***        *   *  * * **  ** ** *** ***    ** *  * ** ** * ** * **** *****  *  ****  ***  ** * **** * ** *    * *  
*** **  *  ***  *** * *   ****   *    * ***  *  **  * **** **  *  *      **
*   **   * ****   **  ** * * ******   **    ****  **   **
  ** **  *******      *     *  **  ********** *** **
   *** ** * *  ** ** * **  * * ***  ***     * * *** *  
*  * * * **   *  **** ***  * * ********** ***   ****  * * * ** **   **    *     **  *   *   * is a prefix of %s", string2, string1);
    ***     ****    **  *** ****  *    *      *   *** **
*   * *  *    *   **** ****     * *** * **  *** ****  ** **
*   *  *      * ** *  * *** * ****     *  ****   * ****    *
* **  ** *** ***   ** *     * *  * * ***** ***  ** * * **      * ***     **  **  **    ** * is not a prefix of %s", string2, string1);
**** *  ***  * * * *   **       *** *           ***
    }
** * *  *  *     * *  *   ** *  **  *******  *   * * *   *  ****
    {
****       * **** ** ****** *  ** *** ***  **  ***** ** ****  (i=0; i<=strlen(string1)-1;i++)
   *  * *  **   * * ** ** * **      *  **      
* * ****** ***  * **   * ** *       ****  * ****    ** *  *   * **** * *** *****    *  * * (string2[i]==string1[i])
** * ** *  * ***    *  ** * ***   ***  *   **       ******   ** *  * *  **  * *   **   * 
    * **  ** * ** * **        *  **   ****    * *** *    *   ** ********** *     **  *** *   * *** *   ** * * * **  *       *  
 ** *** * **   ** **    ***** * ** ***   *** *  ** **  *   * *     *  *** **** * 
**** ** ** ** ***  ** * * * ** ** ** * * *   *  ***  
* ** * *    **   *  *  *      * *   * ** ***  ** * * **  *
  * ****    * **  ******    ****       * **  *** ****  
*  *    *  ** ** *  ** * * * **  **     ***  **      **  ******  *   **   ** *  *** ****  *  * is a prefix of %s", string1, string2);
*** * **** *****   *   * *   * *  *  * * * *  *      * * 
 * ****    *     ** * ** **    *   *  **** ** * ****** 
 **   * ****  * * *    *   **  **  ** * ***  * *** 
**   *****    ** * *   *   * ** *  *    **     **** * ** * ****   ***** *    **** *  *** * is not a prefix of %s", string1, string2);
**  *  *  **  * *  * ** *     * ***       * *   *****    ****
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* * *   **********    ** *** ****    * * %s", chaine1,chaine2);
*****  ** **  *  *  ** *    *** * ***  *  * 
 ****   **   *  * *** * *** **  ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*   *   *   **  * *  **    lenght1,lenght2,c;
   *      ****      *  ** ***  * b[100];
**   **         ** ** *  *  ** * a[100];
  *******    *   ** *    ***     d[100];
***  **     ***  * * *  *   *  * **   * * ** *
  ** ** ***** ******  ***  **  ** * *** **  ** *
** ***    * * * * ** *  ****    ***** ***
*   ** * ****     *   * *** *** *   **  ***  *  * 
   * *    * **  **** *    * **     ***  **
**  **** *   *   * **      ** 
* * * *   ** *  ***  *    **        * *** **    *    * is a prefix of %s",a,b);
**    ***** * *** *****    ** *
* *   *   *    ***** ** *   **
  **  *  * * ***    *    
   **  *    **** *  * *     **   *  *  * *  *** ** **        **** *   *    *   is not a prefix of %s",a,b);
    * **   ***** *  *  * * * 
 * *  * *         *      *   * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * ** ** *   **  
#include * **  ***  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 **  * *  * *   i;
* **  ***   *** * * *  **   **
  {
  * *  * * *  ********** *** **** **   ***  A[i]!='\0' && A[i]!=B[i]   )
* ***  *     *** ***  **     * *  * *  * ****   *   *         *    0;
*  ** ** *    **     *    * *       ***  ***    *   * **
     * * ****  **** ****    **   *    *        ***    ** **  ** ** **   
  }
 **     **   *  *  1;
}


int main()
{
*     *   * **** *  * * ***  a[n],b[n],c[n];
 ***** *   * * * * *  *  * * * **** i;
** *  *  *   **   * ***  ******* *  **     *** * 
 ** ** *  **   ** ** * *  *  *****  **   ******  
*   *      *   ******    **  (aa(a,b)){
* ***  * *       *  ***** *** * ** ***  *  ** *   **      ** *   *  **   
*  ** * * * ****** * * ***  ****  **  * *    * * *    * *   * ***   **** * * **   *   * 
 ** ***  * ***** ***  * ****      * * ***  ****    **    **  *  ** *** ** *  *  * ***    **      *** *  *   ** *** 
 *  *** ** *     * *  *   **  *      * *   ***  *****     **   **** ****    * *  * *** 

   * *** **  **  ***** ** * *    **  *** *   **  **   **
   ****** *** * * ** *    *       *  * * ***** *            ** is a prefix of %s",c,b);
*** ** *   *  ** * ** * ***** 
**  * * *     **    ** ******  
 * * *** ** *****  *  *** *** * * * *   **  * *  ****  *  ***    *    is not a prefix of %s",a,b);
 ***** ** ** ** ***   * *  ***  * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     ********
 ** ** ** * **      
int main (){
char    **  *
char * *  * 
* **   *  * **   string1: *  * *     
* *******    **  * * **   ** 
*   * *  *   ** *  string2:   * * **  *
 *** ****** *  * ***  **** 
   * **  *  ** **    *
*     ***  *  *   *  **   ***     **    is **  ***   of  *   * * ** * *   *
else
*   *   * ** *** ****   * * **   *  is not prefix of * * *  *** **** *  *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****   *  * ***
#include  *** ***    * *
#include * ***** *** *   
#include  ** * ***  **  
int prefix(char p[],char s[])
{
**    **  *    **  *** * **   ***  **** **  
 * * ** **  *   ** * **     0;
    *** *   **  * *  * if *     **** * * * **  
*     * ** *** * *   * ****  * 1;
  *     * *  **  *  **   
***** ***  ** ** *         0;
}

int main()
{
   ** * * *** *  ** ***   p[999],s[999];
** ** **     * *** * * * * *** **  * * * *
** * **  *  *** *** *   *  * * **  ****    *

 * *      **  * * *  **  *****
 *** **   *   * *  *   *  **  *   ***  *  * is a prefix of %s",p,s);
*** ***** ** *** * * *  
  * * *   *** **   **  ** **  *  ** ** is not a prefix of  ** * *  * 

* ** ** * *  ******    0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  **  ** *     *
int main()
{
* *  * *   **** * *  *   * ****  length1,length2,c;
** *****       *     *  **   a[100];
*  * **   *   *  *  ***    * b[100];
*    *****    **    * * ** * d[100];
** * *** * **** * ***  ** ***   * ***   * * 
   ***    *** * ** *  * ***   ***  *   **  * ** *
  *  * *  * *   *   ***  *  *** *  *  ****
   * ***** ** *  * *********  *     * * *
if (strcmp(a,d)==0)
**  * ** *  * * **     **  ***
** *** **    *      **  * *   *   * **   ****           **     ** is a prefix of %s",a,b);
* * **   * *****   **  *   
*    * *   **      *** * *  *  *
** *  *** * **  **  *  * 
    * **** ***   *   * ****  * *  ** * **** **  * *     *  *     ** *** * is not a prefix of %s",a,b);
  **  **** ***  ***** *  * * 
 **   **  * *****    0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *******   * *
#include * ** * *  **    

int prefix (char   * * * str2[])
{
  **  ** * * ***   *****  length=0, *  *   
** **   * ****** **  **
***  ** *  ***   *** *** *    = **  * ** * * **
*  *  * **** *****  * ** * * 
    * * *   *****  *  *    *  *     ** * *** *
 **  **      *    ** *****  **** **  * ** ** *
*  *  **    * * *     ** **** ** if *    *  * * *
  *** *   * *    **            *  * * * *  *  ***   ***  *  
* ** *****     *** **   * *   * ****   }
 *** *            ***   *** *** **  
  **   ** **  *  **** (count == length)
***  *  * * * **     *      ********  **  1;
  ***   *** * ** * ****   ******* else ****   *** 0; *   *    *   ** * ** *
**       * ** **** * **  **  
}
int main(void)
{
*   ** **  * *  *   * ** *   *   ****  **** 
* *      **     ***      
  *** ** *** * *  *  * ** * *****  **** **    * str1, str2);

*** * *   ****** * *  * * * *   ** ** * * 
***  **    *   {
 ****  **  **   *  * * ***  ****** * *  *     **      *******    ** * * is a prefix of     ** ** str1, str2);
* ** ** ***      **   ** **
* * ** ** *  *****  **  * ** *
***   **       ** *** *** ** *    ******     *  ** * ** **   *****  is not a prefix of   *  * str1, str2);

*   ** **   * *  * ****       0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** **     ********  
#include **** ** ***** * 
#include   * *  **  ** *

int main()
{
** * *  * * * *  ** ****     * prefix[100];
*  *      ** *         ****       word[100];
**  *  *  *  ***  **  *  ** * **** *  %s", prefix, word);
 * **  *** *  * ***** * **    i;
 * * ** *  **  *  *    **     * * *  = 0; i< strlen(prefix); ++i)
* *** ** **  ***    **  ** *
**  ***  * * *   * *   ** ******* **  *** *   * * **  *  **** *** **
* *  *** * **  * ****** *    *** *  *** ** ** *  **  * *   
*     * * *       ***  *  * *** ***** ***  ***     * *****    *     ** * ** ** **   * * ***   ***  ****  is not a prefix of %s", prefix, word);
* * **  ** **    * * *** *** *** * * **** **  ***  *   ** ** ***    *   **  ** *   0;
* **      *  *** **    * ** **** ** *** * **  ***  *
* *  * ** * **  * * **** *
 *  *   ** *** * *  *** *****    *  *  is a prefix of %s", prefix, word);
* *    ***  ***   * ** *   ** ** *   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     * ** *  *
#include     *   * *
#include  ***   * * *    

int main()
{
**  *    * * * *** * *    *   *    prefix[100];
** *   *    **   ** ** *  ** **    *  word[100];
  *       *  * *  * * ** * *** *****      ** * %s", prefix, word);
   * * ****  **     **** * i;
 ***  **** * ****** *  ** * * * **   = 0; i< strlen(prefix); ++i)
** **  * ** ****  * ** **    * 
* *           *  *    *    * **** *** ***** * *  *******  * **  
 *** * ** ***  ** * * *   *   ****   **    **  
**  *   ** * ** * ** *  **  *  * ****  **    ** **  *  *** *   ** **  * *******  **   **  * *** is not a prefix of %s", prefix, word);
  ****  * * ** *    * * * ** ** * *   * * ** * ** * **     **  * *      ** *    **  * 0;
  *** ** ****        ***   ** ** ** ***   ** *  **** 
* * ** * *  *       * * * 
 * **  * ** *  * * * ***  *  ** ** *   is a prefix of %s", prefix, word);
*    ** ** *** ***  *     * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   ** ****  ************   
   **    ****  **    * *
**      ** ** ** * ****

int main()
{
  * * *    char ***   * *
 ** *  ** **  *  char  *   **
* *  **   * *  *** * ** ****      ** *    ***  word);
 **   *  * *   *  int i;
 *  * *    * *   for(i = 0;   **  ** * * *   ++i)
  *  *       **  {
** *  *  ***        ***  **  *   *      **  ** 
* *    *  *   * ***** * **   {
  **  * * * *  * * *** ***  **  *  *   *    * ****  ** is not a * * of * ******      word);
 * * ** *  *    *  ** *  *  ****  * *  ****  *   *    ** 0;
**  *** *    * **  *       * }
* *****  **    * }
 ***** *   **   *** ***   ** is a prefix of ***   *  *  *** word);
*  * * ***   ***  * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.176
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users