1-11 Exercise 3: Prefix of a string

0 like 0 dislike
14.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 14.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* **  ** *    **  * **** ***** ***
    * ****** * *** * * *** * ***  *  * *      ** * * **   
    {
  *  ** *     * ****  **  *  *   * * ***   *  * *  *  * (i=0; i<=strlen(string2)-1;i++)
**  * * ****  ******* ***   *   **      * *    *  
* * **   *  * * ** *** *********  **** *  ** *  *****    *  **   ***  **     ** (string2[i]==string1[i])
* *  **     *        **  * * ** ** ** * * ***  **    *      ***   *  **   ** ** 
*   * ** *    *   *   **     ******  * * * * * **** ** * ** * * * ***** * *    *   * * * ** **    ** ****** * 
  * * * * *** *** *    *     *    *** *   ** *** *** *    ** ** **  ** 
 *     * * *** *  *  *********** ***   *   **   * 
* ** **  * **   *** **  *  **   *** ****** **    * *** *
*  * ** * * * *  *  * * *** *  ** *** **   *  *   * * *  **
 * *  * **   **        * **  * * *    *  *    **  ***  *** *  ****** ***    ***  ** *  is a prefix of %s", string2, string1);
    ****  *  *** **  ** * ** *   * ***  *     * ** *   
  * * *  **** * **    * * ****   **   ** ***  *   **    *  
 *  * ***   ** *** *   ***  ** * **    ***  * *****   * ** 
**  * ****** **  * *  **** *  *  *     *    *** ** *  * * *   *** *  *** * * * * ***   * ***  is not a prefix of %s", string2, string1);
***   * * *******  **          *** * ********* **** *
    }
*  **** *   *   ********   * *    ** *****  ** **
    {
*    ****   ** * *   ***  * * ** **   ***  ** *       (i=0; i<=strlen(string1)-1;i++)
 **  *   * *    * * * * ** ** * *  * * **  ** *** * ** ***
   * * * ****  **    ** *   *  ** **      **** *** *** **  *    *  * *  * *  * * *   *  * (string2[i]==string1[i])
 **  * *          * * * * **   *    ***** *** *  ** * **    **** **    *     **
  *** *** * ** **    *    ***   ** **  ** *** ** **** * ** ** ****  **  **   *     *  ***** ***  ***** ** * ** ***  **
*** *   ***** *  **  * *  **   *  ** *** ***  *  * ***  **** ***** * **** * * *** *  *****   
*  *    * *    * *    *   **     * ***     * * *    **
***********  **  * ** * ** *    *    * *** **  * *****  ****   *
    ** * * ** **  ** *** ** **  *  *  * ***     * ***  ****   *
 *      *** *    * * *   ****** *  * * * *  ***   * **  *  ** * * *        *  * **  * * * ** * *  **  * is a prefix of %s", string1, string2);
***  **** **** ** *  *  ***    **** *  *  * * * 
  *  *   *     ** *  *  * * * * ** ***  * * *  *  **  *
** *  *  **  *        **      * **  *  * *    * * *
** * ******  **    ** *    *     ** **** ***    * * ******* ***   ** * **   **   *   *  * *  * *** * * is not a prefix of %s", string1, string2);
 ****  * *    ** *     ** ***  *****   *  *  *  *   
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
  * ** * *  ***  ** * ****  *** ***  ** ** %s", chaine1,chaine2);
 ******  ** * *****  ** ****  *    * ** ** 
 ** ** *******  ** * **  *  * * * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
   ****   ** * * * *     * lenght1,lenght2,c;
*     *  **   * **    * * ****     b[100];
*   * *** *  *  ** ******* a[100];
 *     *** **  ***    ****  ***      d[100];
 * *** ** **   *  ** * **  *  *  * **  * *  **  ** 
*  *** ***  ***    *** ** ** *  ** *     *** **** *
 *** *** * *** *******   *  * * * *   *  **  
   *   * *******  * * *   *  ** ***  
*      ***  * *** ***   * * * * * ******  
** * *      *   ** *  ***   
  **  *  *****    *     * *  * **  **   ** ** **  is a prefix of %s",a,b);
 *   *   * **   *  ** * *
 ** ** ** * *  ** ***   ***
*** *******    ** **** ** *  *   
 ****  *      *** * * ***** * ** **    *  * *   * **  *     *    * is not a prefix of %s",a,b);
 * *  ** *******    ****
*   ** ***    ** ***** *****  ** *  ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * *   *  * 
#include  ** *    **** *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 *** *    *** * * i;
   ***   * **    *** ***   ** **
  {
 * ****   **    * * *   * * ***   **   ** *  A[i]!='\0' && A[i]!=B[i]   )
*  * ** *  ***    *  ** ** *  *   **  ****** **** **     *** *  * *  * ** 0;
** *   ** ****** * *  *  *** * ** *  *      * * *   * **
  * *** * *  ***    ****** *    ***    * ********  * ** *  *  * *** *  *
  }
      **  *  * 1;
}


int main()
{
    **   ** * **   ****  *  * * * a[n],b[n],c[n];
* *  **** ****** * ***** i;
*  * * ***    **    * *  **     **  ** **   *
   * *   **   *  **   ***** *** ***  * *  
**   *  * **  **     ** ** * * (aa(a,b)){
* ****  * *** * ***  *** *  *  ****    ***** ****** ****  *** ****   ******  ** *
** ** * ** *** *******  *  * ****     * *** * * ***  ****   *   * *  ***  *   ***** * 
*** *       * ******** ****  * ** ** **    *** ** *  * **   **   *  **  * **  *    ** **  * **  ****  * **  * 
 * * *    *   ** ***** ****  **** *** * ** *  *  **** *  * **     *    *** ** *****    * *

**  **   *  *      *   * *** * *** * *   * **      ***  ***
      *  **    ** *  *   *** *** * * * ** *   ** * * * *  * * ** ** * is a prefix of %s",c,b);
** *   * * *    * *   ** *   **
  * * **  * *  * **       * *** 
** * * *  *  ***** *  *  * * ** *  *  **  ****  **********    *** is not a prefix of %s",a,b);
   ***** **  ***    * * *  *  * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      ** ***  ***
 *  ** ***  **      *  
int main (){
char   *  ** 
char ** *** 
**    **  * *  string1:      * ** 
*  ***     **   **  **  **  *  *  
 ******   ***  * string2: *     
 * **** *** **    ***   
* *   *  * * * **  *
  *    **** *  *** *   * **   **  *   * is  *  *       of *   *   * *    *   ** 
else
 **  ** * ** * **  ** **** * * is not prefix of  *    *      *   ** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   *** * **  *
#include   * ** *  *   * **
#include  * *  *** ** ** 
#include      *    * * *
int prefix(char p[],char s[])
{
 * **    ** *******     * *  *  ******* * * 
  **        *  **  ****  ** * 0;
***  *   *   * * *** **  if  * **  ****  *** 
 *** * **    **       ** **  1;
 *   *   **  *  ****
  * ***  **   * **  * *        0;
}

int main()
{
*** ** ****** **** *** p[999],s[999];
** * * *   * *  * **** **   * *  * *  **  *
*   * **   *     **** **     *   ***** * **

 *****  *    *     ** *    *  * *  
 *   * *  *   *  * *   ** **      * ***  is a prefix of %s",p,s);
***  *  * *    *  *** *
**    * *  * *   ***  * ***    *** * ***** is not a prefix of  **     ****

***   *    * *   *** *** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * **  ** * * 
int main()
{
**  *        **  *  ***  **    length1,length2,c;
 *****   ** *   *** *** * * * *** a[100];
  * *  *   ** *   ****  *   * b[100];
*  * * * ****** * ** *   ** *  d[100];
* **    * *    * *  ******      ****  ***   *  **
  * **** * *  ** **   **   *   * *  * **** *    *
  ** * **** * *  **  * ** *      *   ** *
 * * ** ****  *   ** *  ** *   * ** 
if (strcmp(a,d)==0)
*  * ******     ***   ***  *
 ** **  **   * ** *****  ***  ***    * ****  *  ** **********     is a prefix of %s",a,b);
 *   * ***  * ** ** * 
 *  * **  **** * ** *  *  **   *  *
  ** **** *   ** * * *    * *
    *** *  *  **  *  ** * ****  * ** **  * *  *****      *   ***  *  is not a prefix of %s",a,b);
*    ***  * ***  ****   *** * *
   *  ** *   ****   *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** *** ** * *
#include   *** * * ***

int prefix (char   *   *   str2[])
{
*  **  *  **  ** **** *   length=0, **  ***
 * *  ** **   **  
  * ***       * **  *** ** **  * = *    *  **  *** 
*  *** **** ** * ****    ***  **
* **** * *** *   *  ** * *  *** **   * ****   * *  
 **** *   ****  ***  **** * ***** * *   ** **  
*** *  * *  * *   *             if  *      *
*  **      ** **  *   *        * *  * *   ** *  * **  **   
  *      * ****   * ***  * **  *     }
    ** *           *****  ****   **  *
**    *  **   * * *** (count == length)
 *** ** *   *   ****    ***     * * * 1;
 *  * ** *   * *    **** * *   * else *  ** * **  0; *   * **  ** *     * 
 * ****         * *       * **  
}
int main(void)
{
**   ** * *** * *  ****** * *  ** ** * ***  * 
** *     * *   ***      **    *
   ***  ** **** * ** *   * ** *    *    * * str1, str2);

** *  **** ** **  **     *** *    * *  *   
 *     **  *  {
   ***  ***    * *** *    **  *** ***   *** * **   ** ** *****    is a prefix of *  * * *  str1, str2);
**  * ******   * *     ***** * ****
* *** *   * *      * ***  
**  *    ***** **  *  *  **  ********   *     *** *** *   * * * is not a prefix of *  *** * str1, str2);

 **   *    ** *** **      * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    * **  * **  
#include ***     ** ***
#include *** *     * * *** 

int main()
{
*  *     ** * *** **  * *   *  prefix[100];
*   *  ** * ******     * word[100];
   *   **   *  * * *  * * *   *** * **  * %s", prefix, word);
      **   *****   ** * *** i;
***  ********** *   *   ***  * = 0; i< strlen(prefix); ++i)
*** ** ***     *       *
 ******      *  * ***  *** **  * * *    * *    ** *** *   ** *  * *  ***
*   * *  * ** ***  **    * * *  ** **  *    * * * * *
         ** *** ***** **  ** **  **  *   *****  ** ** * * *   *** *  *  *  ***    *   * **   is not a prefix of %s", prefix, word);
  *  * ** * **  **  **    * *  * **     *  * *  **** *  ****    * * * *  *********** 0;
 ***      **   *** *  * ** ***    **    *  ** *  
   *        *****  ** * *** **
 **    ** **  *   * **    *** *** *   * ** **  is a prefix of %s", prefix, word);
*  **   *   **  * * * ****  ***  * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  *  *   * 
#include *  **  * **   *
#include  ***   **** ***

int main()
{
 **   ** *  ****        *   prefix[100];
   ***  * ** **** *** *   word[100];
 *   * *   * ** * **  *       ****** *   %s", prefix, word);
* * ****   ****** * * **  *  *  **  i;
  *** *   ** * *        * *    = 0; i< strlen(prefix); ++i)
  *  * * *  *       *  ****
*   *  ***   *    ** * ****** ***    * **     ********  ** * * *   
*    *** *** *** *    ****** *  *** * ***  * ** *  *****   *
 **  ***    *** *******  * * *** **   *   *** *  *  *     ***  * ***  **     *** **   ** ** is not a prefix of %s", prefix, word);
  *  *    * *  *  *  * ** * ** *  **   * **** **  **   ******  **  ** *   **** *****    0;
**  * * **  * **   *  **  *    * ***   * *** * *  *** 
* *  * ** *   *  * **  *   ** 
 **  *****  * *  ** *** * * *  **   is a prefix of %s", prefix, word);
  **           *** *   *  * *  *  *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *  * * ***  **** *
  *** **  **   * ****  *    *
* ** *  *** *   *   *  

int main()
{
***    * * ** char   ****   *
***     *  **  char **  *  
* ****  *   * ** **   ** ****     **  * word);
 *** * *  ***  *  int i;
      **  ******  for(i = 0;      *   *     ** * ++i)
 * **     ** * ** {
**   *  **  *   ***      *  **  *     * 
  *******   *** **   * *  * ****  {
  ***  **   * * ****      * * **** ** *      ***  * *  * is not a *** of *   * *  * *** word);
 ******     ** *   ****    * *    * *    *  *****   *    0;
***   *       ** ***  *      * }
   **    ** ** * }
 * **  * **    *     ** **   *  is a prefix of  *****       word);
   *  *  *    * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 20.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 13.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 18.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users